TISSUE MECHANICS
Superviser: Dr. Taghizadeh Presenter: Sharareh Kian-Bostanabad
In th n the nam e name of e of GO GOD
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In th n the nam e name of e of GO GOD TISSUE MECHANICS Superviser: Dr. Taghizadeh Presenter: Sharareh Kian-Bostanabad 1 Mass What is Mass? A non- negative scalar measure of a bodys tendency to resist a change in motion . The law
Superviser: Dr. Taghizadeh Presenter: Sharareh Kian-Bostanabad
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Eulerian:
Lagrangian:
ρ = const
ρ = const
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The velocity of a particle is given as follows: 𝑤𝑗 = 𝑙𝑦𝑗 1 + 𝑙𝑢 Get the density of the particle as a function of time. Solve: According to the law of conservation of mass:
𝜖𝜍 𝜖𝑢 + 𝜖 𝜍𝑤𝑗 𝜖𝑦𝑗
= 0
𝜖𝜍 𝜖𝑢 = −𝜍 𝜖𝑤𝑗 𝜖𝑦𝑗 = −𝜍𝑙 𝜀𝑗𝑘 1+𝑙𝑢 = − 3𝜍𝑙 1+𝑙𝑢 → 𝜍0 𝜍 𝑒𝜍 𝜍 = − 1 3𝑙𝑒𝑢 1+𝑙𝑢
𝜍 = 𝜍0 (1 + 𝑙𝑢)3
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The basic dynamics principles: Newton’s Laws (force equilibrium and moment equilibrium) Newton’s first low: In an inertial frame of reference, an object either remains at rest or continues to move at a constant velocity, unless acted upon by a force. Newton’s second low: In an inertial reference frame, the vector sum of the forces F on an object is equal to the mass m of that object multiplied by the acceleration a of the object: F = ma. Newton’s third low: When one body exerts a force on a second body, the second body simultaneously exerts a force equal in magnitude and opposite in direction on the first body. An alternative but completely equivalent set of dynamics laws are Euler’s Laws; these are:
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𝑛𝑤 = 𝑑𝑝𝑜𝑡𝑢
F=0 The principle of linear momentum,
The rate of change of momentum is equal to the applied force The law of conservation
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In continuum mechanics:
Principle of Linear Momentum
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system of particles, M, equals the rate of change of the total angular momentum of the particles:
Principle of Angular Momentum
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Equations of Motion acceleration = 0 Equations of Equilibrium
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1) In the absence of body force, does the distribution of the following stress follows equilibrium equations? 𝜏11 = 𝑦2
2 + 𝑤(𝑦1 2 − 𝑦2 2) ,𝜏12 = −2𝑤𝑦1𝑦2
,𝜏22 = 𝑦1
2 + 𝑤(𝑦2 2 − 𝑦1 2)
𝜏23 = 0, 𝜏13 = 0, 𝜏33 = 𝑤(𝑦2
2 + 𝑦1 2)
Solve: According to the equations of equilibrium:
𝜖𝜏1𝑘 𝜖𝑦𝑘 = 𝜖𝜏11 𝜖𝑦1 + 𝜖𝜏12 𝜖𝑦2 + 𝜖𝜏13 𝜖𝑦3 = 2𝑤𝑦1 − 2𝑤𝑦1+0=0 𝜖𝜏2𝑘 𝜖𝑦𝑘 = 𝜖𝜏21 𝜖𝑦1 + 𝜖𝜏22 𝜖𝑦2 + 𝜖𝜏23 𝜖𝑦3 = −2𝑤𝑦2 + 2𝑤𝑦2+0=0 𝜖𝜏3𝑘 𝜖𝑦𝑘 = 𝜖𝜏31 𝜖𝑦1 + 𝜖𝜏32 𝜖𝑦2 + 𝜖𝜏33 𝜖𝑦3 = 0 + 0+0=0
2) If 𝜏𝑗𝑘 = −𝑞𝜀𝑗𝑘 Where 𝑞 = 𝑞(𝑦1, 𝑦2, 𝑦3, 𝑢) The equations of motion given as: 𝜖𝜏𝑗𝑘 𝜖𝑦𝑘 + 𝑐𝑗 = 𝜍 𝑒𝑤𝑗 𝑒𝑢
𝜖𝜏𝑗𝑘 𝜖𝑦𝑘 = − 𝜖𝑞 𝜖𝑦𝑘 𝜀𝑗𝑘=− 𝜖𝑞 𝜖𝑦𝑗
− 𝜖𝑞 𝜖𝑦𝑗 + 𝑐𝑗 = 𝜍 𝑒𝑤𝑗 𝑒𝑢
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𝐿 + 𝑉 = 𝑄 𝑅 =
𝑊
𝜍𝑠𝑒𝑊 −
𝑇
𝑟𝑗𝑜𝑗𝑒𝑇
𝑒 𝑒𝑢
P = Fv
Mechanical Energy Balance Stress Power
𝐿 + 𝑉 = 𝑄 + 𝑅 , 𝜍 𝑣 − 𝜏𝑗𝑘𝐸𝑗𝑘 − 𝜍𝑠 + 𝑟𝑗,𝑗 = 0 Energy Equation
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𝜍 𝐸η 𝐸𝑢 ≥ −𝑒𝑗𝑤 𝑟 𝜄 + 𝜍𝑟𝑡 𝜄
Entropy increase rate in a particle ≥ Entropy enters from the surface boundaries + The total internal entropy of the total volume
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the material under consideration. Displacement Boundary Conditions Boundary Conditions Traction Boundary Conditions Initial Conditions
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Unknown:
Equations:
𝑭 = 1 + 𝑤 𝐹𝑧 (𝝉 − 𝑤 1 + 𝑤 𝜏𝑦𝑦 + 𝜏𝑧𝑧 + 𝜏𝑨𝑨 𝐽)
𝑭 =
1 2 (𝛼𝒗 + 𝒗𝛼)
Modulus of elasticity Poisson coefficient
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