- D. J. Bernstein & T. Lange
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http://hyperelliptic.org/tanja/newelliptic D. J. Bernstein & T. Lange p. 1 Elliptic strikes back http://hyperelliptic.org/tanja/newelliptic D. J. Bernstein & T. Lange p. 2 To face the challenge, to take the competition to a
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1 + y2 1 = 1 + dx2 1y2 1 and
2 + y2 2 = 1 + dx2 2y2 2 always dx1x2y1y2 = ±1.
1y2 1(x2 + y2)2. Conclude that d is a square. But d is not
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