heaps and heapsort
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Heaps and Heapsort 1 October 2020 OSU CSE 1 Heaps A heap is a - PowerPoint PPT Presentation

Heaps and Heapsort 1 October 2020 OSU CSE 1 Heaps A heap is a binary tree of T that satisfies two properties: Global shape property: it is a complete binary tree Local ordering property: the label in each node is smaller than


  1. Heaps and Heapsort 1 October 2020 OSU CSE 1

  2. Heaps • A heap is a binary tree of T that satisfies two properties: – Global shape property: it is a complete binary tree – Local ordering property: the label in each node is “smaller than or equal to” the label in each of its child nodes 1 October 2020 OSU CSE 2

  3. Heaps • A heap is a binary tree of T that satisfies two properties: – Global shape property: it is a complete binary tree A complete binary tree is one in which all levels are “full” except possibly the – Local ordering property: the label in each bottom level, with any nodes on the node is “smaller than or equal to” the label in bottom level as far left as possible. each of its child nodes 1 October 2020 OSU CSE 3

  4. Heaps • A heap is a binary tree of T that Also in the picture is (as with BSTs, sorting, etc.) a total preorder that satisfies two properties: makes this notion precise. – Global shape property: it is a complete binary tree – Local ordering property: the label in each node is “smaller than or equal to” the label in each of its child nodes 1 October 2020 OSU CSE 4

  5. Simplification • For simplicity in the following illustrations, we use only one kind of example: – T = integer – The ordering is ≤ • Because heaps are used in sorting, where duplicate values may be involved, we allow that multiple nodes in a heap may have the same labels (i.e., we will not assume that the labels are unique) 1 October 2020 OSU CSE 5

  6. The Big Picture x 1 October 2020 OSU CSE 6

  7. The Big Picture This tree’s root label y satisfies x ≤ y x y 1 October 2020 OSU CSE 7

  8. The Big Picture Observe: This tree is also a heap; and for each node in this tree with label z , we have: x ≤ y ≤ z . x y 1 October 2020 OSU CSE 8

  9. The Big Picture This tree’s root label y satisfies x ≤ y x y 1 October 2020 OSU CSE 9

  10. The Big Picture Observe: This tree is also a heap; and for each node in this tree with label z , we have: x ≤ y ≤ z . x y 1 October 2020 OSU CSE 10

  11. Examples of Heaps 7 1 1 2 8 1 8 5 8 2 1 October 2020 OSU CSE 11

  12. Non-Examples of Heaps 1 1 1 2 2 5 2 1 8 1 8 5 1 October 2020 OSU CSE 12

  13. Non-Examples of Heaps 1 1 1 2 2 5 2 1 8 1 8 Shape property is violated here: not 5 all nodes at the bottom level are as far left as possible. 1 October 2020 OSU CSE 13

  14. Non-Examples of Heaps 1 1 1 2 2 5 2 1 8 1 8 Ordering property is violated here: 5 value is out of order with that of its right child. 1 October 2020 OSU CSE 14

  15. Non-Examples of Heaps 1 1 1 2 2 5 2 1 8 1 8 5 Shape property is violated: two levels are not “full”. 1 October 2020 OSU CSE 15

  16. Heapsort • A heap can be used to represent the values in a SortingMachine , as follows: – In changeToExtractionMode , arrange all the values into a heap – In removeFirst , remove the root, and adjust the slightly mutilated heap to make it a heap again 1 October 2020 OSU CSE 16

  17. Heapsort Why should this work? • A heap can be used to represent the values in a SortingMachine , as follows: – In changeToExtractionMode , arrange all the values into a heap – In removeFirst , remove the root, and adjust the slightly mutilated heap to make it a heap again 1 October 2020 OSU CSE 17

  18. How removeFirst Can Work • If the root is the only node in the heap, then after removing it, what remains is already a heap; nothing left to do • If the root is not the only node, then removing it leaves an “opening” that must be filled by moving some other value in the heap into the opening 1 October 2020 OSU CSE 18

  19. How removeFirst Can Work The question is: • If the root is the only node in the heap, which one? then after removing it, what remains is already a heap; nothing left to do • If the root is not the only node, then removing it leaves an “opening” that must be filled by moving some other value in the heap into the opening 1 October 2020 OSU CSE 19

  20. Example: A First Attempt 1 2 5 4 3 1 October 2020 OSU CSE 20

  21. Example: A First Attempt If we remove the root, leaving this opening ... 2 5 4 3 1 October 2020 OSU CSE 21

  22. Example: A First Attempt ... we might move up the smaller child ... 2 5 4 3 1 October 2020 OSU CSE 22

  23. Example: A First Attempt ... now creating another opening ... 2 5 4 3 1 October 2020 OSU CSE 23

  24. Example: A First Attempt ... so, we might move up the smaller child. 2 3 5 4 1 October 2020 OSU CSE 24

  25. Example: A First Attempt Is the result necessarily a heap? 2 3 5 4 1 October 2020 OSU CSE 25

  26. Example: A Second Attempt 1 2 5 4 3 1 October 2020 OSU CSE 26

  27. Example: A Second Attempt This time, let’s maintain the shape property ... 2 5 4 3 1 October 2020 OSU CSE 27

  28. Example: A Second Attempt ... by promoting the last node on the bottom level. 3 2 5 4 1 October 2020 OSU CSE 28

  29. Example: A Second Attempt Now, we can “sift down” the root into its proper place ... 3 2 5 4 1 October 2020 OSU CSE 29

  30. Example: A Second Attempt ... by swapping it with its smaller child ... 2 3 5 4 1 October 2020 OSU CSE 30

  31. Example: A Second Attempt ... and then “sifting down” the root of that subtree. 2 3 5 4 1 October 2020 OSU CSE 31

  32. Example: A Second Attempt Is the result necessarily a heap? 2 3 5 4 1 October 2020 OSU CSE 32

  33. Pseudo-Contract /** * Restores a complete binary tree to be a heap * if only the root might be out of place. * @updates t * @requires * [t is a complete binary tree] and * [both subtrees of the root of t are heaps] * @ensures * [t is a heap with the same values as #t] */ public static void siftDown (BinaryTree<T> t) {...} 1 October 2020 OSU CSE 33

  34. Building a Heap In the First Place • Suppose we have n values in a complete binary tree, but they are arranged without regard to the heap ordering • How can we “heapify” it? 1 October 2020 OSU CSE 34

  35. Pseudo-Contract /** * Makes a complete binary tree into a heap. * @updates t * @requires * [t is a complete binary tree] * @ensures * [t is a heap with the same values as #t] */ public static void heapify (BinaryTree<T> t) {...} 1 October 2020 OSU CSE 35

  36. Hint • To see how you might implement heapify , compare the contracts of siftDown and heapify • The only difference: before we can call siftDown to make a heap, both subtrees of the root must already be heaps – Once they are heaps, just a call to siftDown will finish the job 1 October 2020 OSU CSE 36

  37. Hint How do we make the subtrees into • To see how you might implement heaps? heapify , compare the contracts of siftDown and heapify • The only difference: before we can call siftDown to make a heap, both subtrees of the root must already be heaps – Once they are heaps, just a call to siftDown will finish the job 1 October 2020 OSU CSE 37

  38. Example 3 5 2 1 4 1 October 2020 OSU CSE 38

  39. Example First, recursively “heapify” the left subtree. 3 1 2 5 4 1 October 2020 OSU CSE 39

  40. Example Then, recursively “heapify” the right subtree. 3 1 2 5 4 1 October 2020 OSU CSE 40

  41. Example Then “sift down” the root, because now only the root might be out of place. 3 1 2 5 4 1 October 2020 OSU CSE 41

  42. Embedding a Heap in an array • While one could represent a heap using a BinaryTree<T> (as suggested in the pseudo-contracts above), it is generally not done this way • Instead, a heap is usually represented “compactly” using an array of T 1 October 2020 OSU CSE 42

  43. Interpreting an array as a Heap 10 20 50 40 30 1 October 2020 OSU CSE 43

  44. Interpreting an array as a Heap Because it’s a complete binary tree, the nodes can be numbered top-to- 0 bottom, left-to-right. 10 1 2 20 50 3 4 40 30 1 October 2020 OSU CSE 44

  45. 0 10 1 2 20 50 3 4 40 30 10 20 50 40 30 0 1 2 3 4 1 October 2020 OSU CSE 45

  46. At what index in the array is the left child of 0 10 the node at index i ? 1 2 20 50 3 4 40 30 10 20 50 40 30 0 1 2 3 4 1 October 2020 OSU CSE 46

  47. At what index in the array is the right child 0 10 of the node at index i ? 1 2 20 50 3 4 40 30 10 20 50 40 30 0 1 2 3 4 1 October 2020 OSU CSE 47

  48. Resources • Wikipedia: Heapsort – http://en.wikipedia.org/wiki/Heapsort • Wikipedia: Heap (data structure) – http://en.wikipedia.org/wiki/Heap_(data_structure) • Big Java (4th ed) , Sections 16.8, 16.9 – https://library.ohio-state.edu/record=b8540788~S7 1 October 2020 OSU CSE 48

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