Harmonic measure via blow up methods and monotonicity formulas - - PowerPoint PPT Presentation

harmonic measure via blow up methods and monotonicity
SMART_READER_LITE
LIVE PREVIEW

Harmonic measure via blow up methods and monotonicity formulas - - PowerPoint PPT Presentation

Harmonic measure via blow up methods and monotonicity formulas Xavier Tolsa May 22, 2018 X. Tolsa (ICREA / UAB) Harmonic measure May 22, 2018 1 / 27 Plan of the course Some preliminaries. X. Tolsa (ICREA / UAB) Harmonic measure May 22,


slide-1
SLIDE 1

Harmonic measure via blow up methods and monotonicity formulas

Xavier Tolsa May 22, 2018

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 1 / 27

slide-2
SLIDE 2

Plan of the course

Some preliminaries.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 2 / 27

slide-3
SLIDE 3

Plan of the course

Some preliminaries. Geometric characterization of the weak-A∞ condition. Proof of the weak local John condition via the ACF formula.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 2 / 27

slide-4
SLIDE 4

Plan of the course

Some preliminaries. Geometric characterization of the weak-A∞ condition. Proof of the weak local John condition via the ACF formula. Tsirelson’s theorem. Proof by blowup methods.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 2 / 27

slide-5
SLIDE 5

Harmonic measure

Ω ⊂ Rn+1 open. For p ∈ Ω, ωp is the harmonic measure in Ω with pole in p.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 3 / 27

slide-6
SLIDE 6

Harmonic measure

Ω ⊂ Rn+1 open. For p ∈ Ω, ωp is the harmonic measure in Ω with pole in p. That is, for f ∈ C(∂Ω),

  • f dωp is the value at p of the harmonic

extension of f to Ω.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 3 / 27

slide-7
SLIDE 7

Harmonic measure

Ω ⊂ Rn+1 open. For p ∈ Ω, ωp is the harmonic measure in Ω with pole in p. That is, for f ∈ C(∂Ω),

  • f dωp is the value at p of the harmonic

extension of f to Ω. Probabilistic interpretation [Kakutani]: When Ω is bounded, ωp(E) is the probability that a particle with a Brownian movement leaving from p ∈ Ω escapes from Ω through E.

b

p Ω E

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 3 / 27

slide-8
SLIDE 8

Rectifiability

We say that E ⊂ Rd is rectifiable if it is H1-a.e. contained in a countable union of curves of finite length. E is n-rectifiable if it is Hn-a.e. contained in a countable union of C 1 (or Lipschitz) n-dimensional manifolds.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 4 / 27

slide-9
SLIDE 9

Rectifiability

We say that E ⊂ Rd is rectifiable if it is H1-a.e. contained in a countable union of curves of finite length. E is n-rectifiable if it is Hn-a.e. contained in a countable union of C 1 (or Lipschitz) n-dimensional manifolds. E is n-AD-regular if Hn(B(x, r) ∩ E) ≈ r n for all x ∈ E, 0 < r ≤ diam(E). E is uniformly n-rectifiable if it is n-AD-regular and there are M, θ > 0 such that for all x ∈ E, 0 < r ≤ diam(E), there exists a Lipschitz map g : Rn ⊃ Bn(0, r) → Rd, ∇g∞ ≤ M, such that Hn E ∩ B(x, r) ∩ g(Bn(0, r))

  • ≥ θ r n.
  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 4 / 27

slide-10
SLIDE 10

Rectifiability

We say that E ⊂ Rd is rectifiable if it is H1-a.e. contained in a countable union of curves of finite length. E is n-rectifiable if it is Hn-a.e. contained in a countable union of C 1 (or Lipschitz) n-dimensional manifolds. E is n-AD-regular if Hn(B(x, r) ∩ E) ≈ r n for all x ∈ E, 0 < r ≤ diam(E). E is uniformly n-rectifiable if it is n-AD-regular and there are M, θ > 0 such that for all x ∈ E, 0 < r ≤ diam(E), there exists a Lipschitz map g : Rn ⊃ Bn(0, r) → Rd, ∇g∞ ≤ M, such that Hn E ∩ B(x, r) ∩ g(Bn(0, r))

  • ≥ θ r n.

Uniform n-rectifiability is a quantitative version of n-rectifiability introduced by David and Semmes.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 4 / 27

slide-11
SLIDE 11

Metric properties of harmonic measure

In the plane if Ω is simply connected and H1(∂Ω) < ∞, then H1 ≈ ωp. (F.& M. Riesz) Many results in C using complex analysis (Carleson, Makarov, Jones, Bishop, Wolff,...). The analogue of Riesz theorem fails in higher dimensions (counterexamples by Wu and Ziemer). In higher dimensions, need real analysis techniques. A basic result of Dahlberg: If Ω is a Lipschitz domain, then ω ∈ A∞(Hn|∂Ω).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 5 / 27

slide-12
SLIDE 12

Uniform, semiuniform, and NTA domains

Let Ω ⊂ Rn+1 be open. For x, y ∈ Ω, a curve γ ⊂ Ω from x to y is a C-cigar curve with bounded turning if

min(H1(γ(x, z)), H1(γ(y, z))) ≤ C dist(z, Ωc) for all z ∈ γ, and H1(γ) ≤ C |x − y|.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 6 / 27

slide-13
SLIDE 13

Uniform, semiuniform, and NTA domains

Let Ω ⊂ Rn+1 be open. For x, y ∈ Ω, a curve γ ⊂ Ω from x to y is a C-cigar curve with bounded turning if

min(H1(γ(x, z)), H1(γ(y, z))) ≤ C dist(z, Ωc) for all z ∈ γ, and H1(γ) ≤ C |x − y|.

Ω is uniform if all x, y ∈ Ω are connected by a C-cigar curve with bounded turning.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 6 / 27

slide-14
SLIDE 14

Uniform, semiuniform, and NTA domains

Let Ω ⊂ Rn+1 be open. For x, y ∈ Ω, a curve γ ⊂ Ω from x to y is a C-cigar curve with bounded turning if

min(H1(γ(x, z)), H1(γ(y, z))) ≤ C dist(z, Ωc) for all z ∈ γ, and H1(γ) ≤ C |x − y|.

Ω is uniform if all x, y ∈ Ω are connected by a C-cigar curve with bounded turning. Ω is semiuniform if all x ∈ Ω, y ∈ ∂Ω are connected by a C-cigar curve with bounded turning.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 6 / 27

slide-15
SLIDE 15

Uniform, semiuniform, and NTA domains

Let Ω ⊂ Rn+1 be open. For x, y ∈ Ω, a curve γ ⊂ Ω from x to y is a C-cigar curve with bounded turning if

min(H1(γ(x, z)), H1(γ(y, z))) ≤ C dist(z, Ωc) for all z ∈ γ, and H1(γ) ≤ C |x − y|.

Ω is uniform if all x, y ∈ Ω are connected by a C-cigar curve with bounded turning. Ω is semiuniform if all x ∈ Ω, y ∈ ∂Ω are connected by a C-cigar curve with bounded turning. Ω is NTA if it is uniform and has exterior corkscrews,

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 6 / 27

slide-16
SLIDE 16

Uniform, semiuniform, and NTA domains

Let Ω ⊂ Rn+1 be open. For x, y ∈ Ω, a curve γ ⊂ Ω from x to y is a C-cigar curve with bounded turning if

min(H1(γ(x, z)), H1(γ(y, z))) ≤ C dist(z, Ωc) for all z ∈ γ, and H1(γ) ≤ C |x − y|.

Ω is uniform if all x, y ∈ Ω are connected by a C-cigar curve with bounded turning. Ω is semiuniform if all x ∈ Ω, y ∈ ∂Ω are connected by a C-cigar curve with bounded turning. Ω is NTA if it is uniform and has exterior corkscrews, i.e. for every ball B centered at ∂Ω there is another ball B′ ⊂ B \ Ω with r(B′) ≈ r(B).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 6 / 27

slide-17
SLIDE 17

Uniform, semiuniform, and NTA domains

Let Ω ⊂ Rn+1 be open. For x, y ∈ Ω, a curve γ ⊂ Ω from x to y is a C-cigar curve with bounded turning if

min(H1(γ(x, z)), H1(γ(y, z))) ≤ C dist(z, Ωc) for all z ∈ γ, and H1(γ) ≤ C |x − y|.

Ω is uniform if all x, y ∈ Ω are connected by a C-cigar curve with bounded turning. Ω is semiuniform if all x ∈ Ω, y ∈ ∂Ω are connected by a C-cigar curve with bounded turning. Ω is NTA if it is uniform and has exterior corkscrews, i.e. for every ball B centered at ∂Ω there is another ball B′ ⊂ B \ Ω with r(B′) ≈ r(B). NTA

  • uniform
  • semiuniform.
  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 6 / 27

slide-18
SLIDE 18

Uniform, semiuniform, and NTA domains

Let Ω ⊂ Rn+1 be open. For x, y ∈ Ω, a curve γ ⊂ Ω from x to y is a C-cigar curve with bounded turning if

min(H1(γ(x, z)), H1(γ(y, z))) ≤ C dist(z, Ωc) for all z ∈ γ, and H1(γ) ≤ C |x − y|.

Ω is uniform if all x, y ∈ Ω are connected by a C-cigar curve with bounded turning. Ω is semiuniform if all x ∈ Ω, y ∈ ∂Ω are connected by a C-cigar curve with bounded turning. Ω is NTA if it is uniform and has exterior corkscrews, i.e. for every ball B centered at ∂Ω there is another ball B′ ⊂ B \ Ω with r(B′) ≈ r(B). A non trivial NTA domain:

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 6 / 27

slide-19
SLIDE 19

Uniform, semiuniform, and NTA domains

Let Ω ⊂ Rn+1 be open. For x, y ∈ Ω, a curve γ ⊂ Ω from x to y is a C-cigar curve with bounded turning if

min(H1(γ(x, z)), H1(γ(y, z))) ≤ C dist(z, Ωc) for all z ∈ γ, and H1(γ) ≤ C |x − y|.

Ω is uniform if all x, y ∈ Ω are connected by a C-cigar curve with bounded turning. Ω is semiuniform if all x ∈ Ω, y ∈ ∂Ω are connected by a C-cigar curve with bounded turning. Ω is NTA if it is uniform and has exterior corkscrews, i.e. for every ball B centered at ∂Ω there is another ball B′ ⊂ B \ Ω with r(B′) ≈ r(B). Example: The complement of this Cantor set is uniform but not NTA:

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 6 / 27

slide-20
SLIDE 20

Harmonic measure in different types of domains

Definition: We say that ω ∈ A∞ if, for any ball B centered in ∂Ω and p ∈ Ω \ 2B, ωp ∈ A∞(Hn|∂Ω∩B) uniformly.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 7 / 27

slide-21
SLIDE 21

Harmonic measure in different types of domains

Definition: We say that ω ∈ A∞ if, for any ball B centered in ∂Ω and p ∈ Ω \ 2B, ωp ∈ A∞(Hn|∂Ω∩B) uniformly.

Theorem (David, Jerison / Semmes)

If Ω is NTA and ∂Ω is uniformly n-rectifiable, then ω ∈ A∞.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 7 / 27

slide-22
SLIDE 22

Harmonic measure in different types of domains

Definition: We say that ω ∈ A∞ if, for any ball B centered in ∂Ω and p ∈ Ω \ 2B, ωp ∈ A∞(Hn|∂Ω∩B) uniformly.

Theorem (Hofmann, Martell, Uriarte-Tuero)

Let Ω ⊂ Rn+1 be uniform, with ∂Ω n-AD-regular. TFAE: (a) ω ∈ A∞.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 7 / 27

slide-23
SLIDE 23

Harmonic measure in different types of domains

Definition: We say that ω ∈ A∞ if, for any ball B centered in ∂Ω and p ∈ Ω \ 2B, ωp ∈ A∞(Hn|∂Ω∩B) uniformly.

Theorem (Hofmann, Martell, Uriarte-Tuero)

Let Ω ⊂ Rn+1 be uniform, with ∂Ω n-AD-regular. TFAE: (a) ω ∈ A∞. (b) ∂Ω is uniformly n-rectifiable.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 7 / 27

slide-24
SLIDE 24

Harmonic measure in different types of domains

Definition: We say that ω ∈ A∞ if, for any ball B centered in ∂Ω and p ∈ Ω \ 2B, ωp ∈ A∞(Hn|∂Ω∩B) uniformly.

Theorem (Hofmann, Martell, Uriarte-Tuero)

Let Ω ⊂ Rn+1 be uniform, with ∂Ω n-AD-regular. TFAE: (a) ω ∈ A∞. (b) ∂Ω is uniformly n-rectifiable. (b) ⇒ (a) by Hofmann and Martell.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 7 / 27

slide-25
SLIDE 25

Harmonic measure in different types of domains

Definition: We say that ω ∈ A∞ if, for any ball B centered in ∂Ω and p ∈ Ω \ 2B, ωp ∈ A∞(Hn|∂Ω∩B) uniformly.

Theorem (Hofmann, Martell, Uriarte-Tuero)

Let Ω ⊂ Rn+1 be uniform, with ∂Ω n-AD-regular. TFAE: (a) ω ∈ A∞. (b) ∂Ω is uniformly n-rectifiable. (b) ⇒ (a) by Hofmann and Martell. (a) ⇒ (b) by Hofmann, Martell and Uriarte-Tuero (alternative argument by Azzam, Hofmann, Martell, Nystr¨

  • m and Toro).
  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 7 / 27

slide-26
SLIDE 26

Harmonic measure in different types of domains

Definition: We say that ω ∈ A∞ if, for any ball B centered in ∂Ω and p ∈ Ω \ 2B, ωp ∈ A∞(Hn|∂Ω∩B) uniformly.

Theorem (Hofmann, Martell, Uriarte-Tuero)

Let Ω ⊂ Rn+1 be uniform, with ∂Ω n-AD-regular. TFAE: (a) ω ∈ A∞. (b) ∂Ω is uniformly n-rectifiable.

Theorem (Azzam)

Let Ω ⊂ Rn+1, with ∂Ω n-AD-regular. TFAE: (a) ω ∈ A∞. (b) ∂Ω is uniformly n-rectifiable and Ω is semiuniform.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 7 / 27

slide-27
SLIDE 27

Harmonic measure in different types of domains

Definition: We say that ω ∈ A∞ if, for any ball B centered in ∂Ω and p ∈ Ω \ 2B, ωp ∈ A∞(Hn|∂Ω∩B) uniformly.

Theorem (Hofmann, Martell, Uriarte-Tuero)

Let Ω ⊂ Rn+1 be uniform, with ∂Ω n-AD-regular. TFAE: (a) ω ∈ A∞. (b) ∂Ω is uniformly n-rectifiable.

Theorem (Azzam)

Let Ω ⊂ Rn+1, with ∂Ω n-AD-regular. TFAE: (a) ω ∈ A∞. (b) ∂Ω is uniformly n-rectifiable and Ω is semiuniform. A previous partial result by Aikawa and Hirata.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 7 / 27

slide-28
SLIDE 28

Connection with PDE’s

Consider the PDE: ∆u = 0 in Ω, u = f in ∂Ω.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 8 / 27

slide-29
SLIDE 29

Connection with PDE’s

Consider the PDE: ∆u = 0 in Ω, u = f in ∂Ω. For x ∈ ∂Ω, denote Nu(x) = supy∈Γ(x) |u(y)|.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 8 / 27

slide-30
SLIDE 30

Connection with PDE’s

Consider the PDE: ∆u = 0 in Ω, u = f in ∂Ω. For x ∈ ∂Ω, denote Nu(x) = supy∈Γ(x) |u(y)|.

Theorem (Hofmann, Le)

Let Ω ⊂ Rn+1, with ∂Ω n-AD-regular, satisfying the interior corkscrew

  • condition. TFAE:

(a) For some p > 1, the Dirichlet problem is Lp-solvable, i.e. NuLp(Hn|∂Ω) ≤ C f Lp(Hn|∂Ω) for all f ∈ Lp(Hn|∂Ω).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 8 / 27

slide-31
SLIDE 31

Connection with PDE’s

Consider the PDE: ∆u = 0 in Ω, u = f in ∂Ω. For x ∈ ∂Ω, denote Nu(x) = supy∈Γ(x) |u(y)|.

Theorem (Hofmann, Le)

Let Ω ⊂ Rn+1, with ∂Ω n-AD-regular, satisfying the interior corkscrew

  • condition. TFAE:

(a) For some p > 1, the Dirichlet problem is Lp-solvable, i.e. NuLp(Hn|∂Ω) ≤ C f Lp(Hn|∂Ω) for all f ∈ Lp(Hn|∂Ω). (b) ω ∈ weak−A∞.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 8 / 27

slide-32
SLIDE 32

Remarks

Ω satisfies the interior corkscrew condition if for every ball B centered at ∂Ω with r(B) ≤ diam(Ω) there is another ball B′ ⊂ B ∩ Ω with r(B′) ≈ r(B).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 9 / 27

slide-33
SLIDE 33

Remarks

Ω satisfies the interior corkscrew condition if for every ball B centered at ∂Ω with r(B) ≤ diam(Ω) there is another ball B′ ⊂ B ∩ Ω with r(B′) ≈ r(B). We say that ω ∈ weak−A∞ if for every ε ∈ (0, 1) there exists δ ∈ (0, 1) such that for every ball B centered at ∂Ω, all p ∈ Ω \ 4B, and all E ⊂ B ∩ ∂Ω, the following holds: if Hn(E) ≤ δ Hn(B ∩ ∂Ω), then ωp(E) ≤ ε ωp(2B).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 9 / 27

slide-34
SLIDE 34

Remarks

Ω satisfies the interior corkscrew condition if for every ball B centered at ∂Ω with r(B) ≤ diam(Ω) there is another ball B′ ⊂ B ∩ Ω with r(B′) ≈ r(B). We say that ω ∈ weak−A∞ if for every ε ∈ (0, 1) there exists δ ∈ (0, 1) such that for every ball B centered at ∂Ω, all p ∈ Ω \ 4B, and all E ⊂ B ∩ ∂Ω, the following holds: if Hn(E) ≤ δ Hn(B ∩ ∂Ω), then ωp(E) ≤ ε ωp(2B). The weak-A∞ condition implies ω ≪ Hn|∂Ω. But, ω may be non-doubling, and we may have Hn|∂Ω ≪ ω.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 9 / 27

slide-35
SLIDE 35

Remarks

Ω satisfies the interior corkscrew condition if for every ball B centered at ∂Ω with r(B) ≤ diam(Ω) there is another ball B′ ⊂ B ∩ Ω with r(B′) ≈ r(B). We say that ω ∈ weak−A∞ if for every ε ∈ (0, 1) there exists δ ∈ (0, 1) such that for every ball B centered at ∂Ω, all p ∈ Ω \ 4B, and all E ⊂ B ∩ ∂Ω, the following holds: if Hn(E) ≤ δ Hn(B ∩ ∂Ω), then ωp(E) ≤ ε ωp(2B). The weak-A∞ condition implies ω ≪ Hn|∂Ω. But, ω may be non-doubling, and we may have Hn|∂Ω ≪ ω. Problem: Find a geometric characterization of the weak−A∞ condition.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 9 / 27

slide-36
SLIDE 36

Geometric characterization of the weak−A∞ condition I

ω ∈ weak−A∞ + interior corkscrew condition = ⇒ ∂Ω is uniformly n-rectifiable [Hofmann, Martell], [Mourgoglou-T.].

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 10 / 27

slide-37
SLIDE 37

Geometric characterization of the weak−A∞ condition I

ω ∈ weak−A∞ + interior corkscrew condition = ⇒ ∂Ω is uniformly n-rectifiable [Hofmann, Martell], [Mourgoglou-T.]. But ∂Ω uniformly n-rectifiable = ⇒ ω ∈ weak−A∞ (Bishop, Jones).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 10 / 27

slide-38
SLIDE 38

Geometric characterization of the weak−A∞ condition II

Given x ∈ Ω, y ∈ ∂Ω, a c-carrot curve from x to y is a curve γ ⊂ Ω ∪ {y} with end-points x and y such that dist(z, ∂Ω) ≥ c H1(γ(y, z)) for all z ∈ γ, where γ(y, z) is the arc in γ between y and z.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 11 / 27

slide-39
SLIDE 39

Geometric characterization of the weak−A∞ condition II

Given x ∈ Ω, y ∈ ∂Ω, a c-carrot curve from x to y is a curve γ ⊂ Ω ∪ {y} with end-points x and y such that dist(z, ∂Ω) ≥ c H1(γ(y, z)) for all z ∈ γ, where γ(y, z) is the arc in γ between y and z. We denote δΩ(x) = dist(x, ∂Ω).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 11 / 27

slide-40
SLIDE 40

Geometric characterization of the weak−A∞ condition II

Given x ∈ Ω, y ∈ ∂Ω, a c-carrot curve from x to y is a curve γ ⊂ Ω ∪ {y} with end-points x and y such that dist(z, ∂Ω) ≥ c H1(γ(y, z)) for all z ∈ γ, where γ(y, z) is the arc in γ between y and z. We denote δΩ(x) = dist(x, ∂Ω). We say that Ω satisfies the weak local John condition if there are λ, θ ∈ (0, 1) such that for every x ∈ Ω there is a Borel set F ⊂ B(x, 2δΩ(x)) ∩ ∂Ω with Hn(F) ≥ θ Hn(B(x, 2δΩ(x)) ∩ ∂Ω) such that every y ∈ F can be joined to x by a λ-carrot curve.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 11 / 27

slide-41
SLIDE 41

The main results I

Theorem (Hofmann, Martell)

Let Ω ⊂ Rn+1 be an open set with uniformly n-rectifiable boundary satisfying the weak local John condition. Then ω ∈ weak−A∞.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 12 / 27

slide-42
SLIDE 42

The main results I

Theorem (Hofmann, Martell)

Let Ω ⊂ Rn+1 be an open set with uniformly n-rectifiable boundary satisfying the weak local John condition. Then ω ∈ weak−A∞. Hofmann and Martell conjectured that the converse also holds.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 12 / 27

slide-43
SLIDE 43

The main results I

Theorem (Hofmann, Martell)

Let Ω ⊂ Rn+1 be an open set with uniformly n-rectifiable boundary satisfying the weak local John condition. Then ω ∈ weak−A∞. Hofmann and Martell conjectured that the converse also holds.

Theorem (Azzam, Mourgoglou, T.)

Let Ω ⊂ Rn+1 be open with n-AD-regular boundary. If ω ∈ weak−A∞, then Ω satisfies the weak local John condition.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 12 / 27

slide-44
SLIDE 44

The main results II

Putting all together:

Theorem

Let Ω ⊂ Rn+1 be open with n-AD-regular boundary, satisfying the interior corkscrew condition. TFAE:

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 13 / 27

slide-45
SLIDE 45

The main results II

Putting all together:

Theorem

Let Ω ⊂ Rn+1 be open with n-AD-regular boundary, satisfying the interior corkscrew condition. TFAE: (a) ω ∈ weak−A∞.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 13 / 27

slide-46
SLIDE 46

The main results II

Putting all together:

Theorem

Let Ω ⊂ Rn+1 be open with n-AD-regular boundary, satisfying the interior corkscrew condition. TFAE: (a) ω ∈ weak−A∞. (b) ∂Ω is uniformly n-rectifiable and Ω satisfies the weak local John condition.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 13 / 27

slide-47
SLIDE 47

The main results II

Putting all together:

Theorem

Let Ω ⊂ Rn+1 be open with n-AD-regular boundary, satisfying the interior corkscrew condition. TFAE: (a) ω ∈ weak−A∞. (b) ∂Ω is uniformly n-rectifiable and Ω satisfies the weak local John condition. Remark Later Hofmann and Martell have shown that (b) ⇒ Ω has big pieces of chord-arc subdomains (BPCAS).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 13 / 27

slide-48
SLIDE 48

The main results II

Putting all together:

Theorem

Let Ω ⊂ Rn+1 be open with n-AD-regular boundary, satisfying the interior corkscrew condition. TFAE: (a) ω ∈ weak−A∞. (b) ∂Ω is uniformly n-rectifiable and Ω satisfies the weak local John condition. Remark Later Hofmann and Martell have shown that (b) ⇒ Ω has big pieces of chord-arc subdomains (BPCAS). Since BPCAS ⇒ ω ∈ weak−A∞ (Bennewitz, Lewis), we have (a) ⇐ ⇒ (b) ⇐ ⇒ BPCAS.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 13 / 27

slide-49
SLIDE 49

The main results II

Putting all together:

Theorem

Let Ω ⊂ Rn+1 be open with n-AD-regular boundary, satisfying the interior corkscrew condition. TFAE: (a) ω ∈ weak−A∞. (b) ∂Ω is uniformly n-rectifiable and Ω satisfies the weak local John condition. (c) Ω has BPCAS.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 13 / 27

slide-50
SLIDE 50

Some ideas for the proof of the weak local John condition

For p ∈ Ω, we have to build carrot curves that connect a big proportion of the points from B(p, 2δΩ(p)) ∩ ∂Ω to p.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 14 / 27

slide-51
SLIDE 51

Some ideas for the proof of the weak local John condition

For p ∈ Ω, we have to build carrot curves that connect a big proportion of the points from B(p, 2δΩ(p)) ∩ ∂Ω to p. We use the Green function to construct the curves. A fundamental property: For all λ > 0, {x ∈ Ω : g(p, x) > λ} is connected and contains p.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 14 / 27

slide-52
SLIDE 52

Some ideas for the proof of the weak local John condition

For p ∈ Ω, we have to build carrot curves that connect a big proportion of the points from B(p, 2δΩ(p)) ∩ ∂Ω to p. We use the Green function to construct the curves. A fundamental property: For all λ > 0, {x ∈ Ω : g(p, x) > λ} is connected and contains p. Important difficulties: ωp may be non doubling. ωp1 and ωp2 may be mutually singular. Otherwise we could argue with different poles p1, p2, ...

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 14 / 27

slide-53
SLIDE 53

The ACF formula

Theorem (Alt-Caffarelli-Friedman)

Let B(x, R) ⊂ Rn+1, and let u1, u2 ∈ W 1,2(B(x, R)) ∩ C(B(x, R)) be nonnegative subharmonic functions. Suppose that that u1(x) = u2(x) = 0 and u1 · u2 ≡ 0. Set Ji(x, r) = 1 r 2

  • B(x,r)

|∇ui(y)|2 |y − x|n−1 dy, and J(x, r) = J1(x, r) J2(x, r).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 15 / 27

slide-54
SLIDE 54

The ACF formula

Theorem (Alt-Caffarelli-Friedman)

Let B(x, R) ⊂ Rn+1, and let u1, u2 ∈ W 1,2(B(x, R)) ∩ C(B(x, R)) be nonnegative subharmonic functions. Suppose that that u1(x) = u2(x) = 0 and u1 · u2 ≡ 0. Set Ji(x, r) = 1 r 2

  • B(x,r)

|∇ui(y)|2 |y − x|n−1 dy, and J(x, r) = J1(x, r) J2(x, r). Then J(x, ·) is non-decreasing in r ∈ (0, R]. Further, Ji(x, r) 1

r2 ui2 ∞,B(x,2r).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 15 / 27

slide-55
SLIDE 55

The ACF formula

Theorem (Alt-Caffarelli-Friedman)

Let B(x, R) ⊂ Rn+1, and let u1, u2 ∈ W 1,2(B(x, R)) ∩ C(B(x, R)) be nonnegative subharmonic functions. Suppose that that u1(x) = u2(x) = 0 and u1 · u2 ≡ 0. Set Ji(x, r) = 1 r 2

  • B(x,r)

|∇ui(y)|2 |y − x|n−1 dy, and J(x, r) = J1(x, r) J2(x, r). Then J(x, ·) is non-decreasing in r ∈ (0, R]. Further, Ji(x, r) 1

r2 ui2 ∞,B(x,2r).

This formula is a basic tool in free boundary problems.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 15 / 27

slide-56
SLIDE 56

The case of equality in the ACF formula

Theorem

Let B(x, R) and u1, u2 be as in the previous theorem. Suppose that J(x, ra) = J(x, rb) for some 0 < ra < rb < R. Then either one or the other

  • f the following holds:

(a) u1 = 0 in B(x, rb) or u2 = 0 in B(x, rb); (b) there exists a unit vector e and constants k1, k2 > 0 such that u1(y) = k1 ((y −x)·e)+, u2(y) = k2 ((y −x)·e)−, in B(x, rb).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 16 / 27

slide-57
SLIDE 57

A quantification of the previous result

Theorem

Let B(x, R) and u1, u2 be as in the previous theorem, such that each ui is harmonic in {y ∈ B(x, R) : ui(y) > 0}. Assume also that ui∞,B(x,R) ≤ C1 R and uiLipα,B(x,R) ≤ C1 R1−α for i = 1, 2. For any ε > 0, there exists some δ > 0 such that if J(x, 1

2R) ≤ (1 + δ) J(x, 1 4R),

then either one or the other of the following holds: (a) u1∞,B(x, 1

2R) ≤ ε R or u2∞,B(x, 1 2R) ≤ ε R;

(b) there exists a unit vector e and constants k1, k2 > 0 such that ui − ki ((· − x) · e)+∞,B(x, 1

2R) ≤ ε R

for i = 1, 2.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 17 / 27

slide-58
SLIDE 58

The corona decomposition

Using a corona decomposition we combine the construction of short paths using ACF with geometric arguments.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 18 / 27

slide-59
SLIDE 59

The corona decomposition

Using a corona decomposition we combine the construction of short paths using ACF with geometric arguments.

Theorem (David-Semmes)

Let E be n-AD-regular and µ = Hn|E. Let Dµ be a dyadic lattice of cubes associated to µ.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 18 / 27

slide-60
SLIDE 60

The corona decomposition

Using a corona decomposition we combine the construction of short paths using ACF with geometric arguments.

Theorem (David-Semmes)

Let E be n-AD-regular and µ = Hn|E. Let Dµ be a dyadic lattice of cubes associated to µ. Then E is uniformly n-rectifiable if and only if there exists a partition of Dµ into trees T ∈ I satisfying:

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 18 / 27

slide-61
SLIDE 61

The corona decomposition

Using a corona decomposition we combine the construction of short paths using ACF with geometric arguments.

Theorem (David-Semmes)

Let E be n-AD-regular and µ = Hn|E. Let Dµ be a dyadic lattice of cubes associated to µ. Then E is uniformly n-rectifiable if and only if there exists a partition of Dµ into trees T ∈ I satisfying: (a) The family of roots of T ∈ I fulfils the packing condition

  • T ∈I:Root(T )⊂S

µ(Root(T )) ≤ C µ(S) for all S ∈ Dµ.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 18 / 27

slide-62
SLIDE 62

The corona decomposition

Using a corona decomposition we combine the construction of short paths using ACF with geometric arguments.

Theorem (David-Semmes)

Let E be n-AD-regular and µ = Hn|E. Let Dµ be a dyadic lattice of cubes associated to µ. Then E is uniformly n-rectifiable if and only if there exists a partition of Dµ into trees T ∈ I satisfying: (a) The family of roots of T ∈ I fulfils the packing condition

  • T ∈I:Root(T )⊂S

µ(Root(T )) ≤ C µ(S) for all S ∈ Dµ. (b) In each T ∈ I, E is “very well approximated” by an n-dimensional Lipschitz graph ΓT . That is, for all Q ∈ T , dist(Q, ΓT ) ≤ ℓ(Q).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 18 / 27

slide-63
SLIDE 63

How to build another corona decomposition

Fix 0 < ε ≪ 1. Define Top0 = {R0}. Assume G0 = R0 for simplicity.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 19 / 27

slide-64
SLIDE 64

How to build another corona decomposition

Fix 0 < ε ≪ 1. Define Top0 = {R0}. Assume G0 = R0 for simplicity. Given and Topk ⊂ Dµ(R0), with

P∈Topk P = R0, Topk+1 is the maximal

subfamily of cubes Q strictly contained in cubes from Topk such that bβ(100Q) > ε, where bβ(100Q) = inf

L n-plane

distH(L ∩ 100BQ, ∂Ω ∩ 100BQ) r(100BQ) .

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 19 / 27

slide-65
SLIDE 65

How to build another corona decomposition

Fix 0 < ε ≪ 1. Define Top0 = {R0}. Assume G0 = R0 for simplicity. Given and Topk ⊂ Dµ(R0), with

P∈Topk P = R0, Topk+1 is the maximal

subfamily of cubes Q strictly contained in cubes from Topk such that bβ(100Q) > ε, where bβ(100Q) = inf

L n-plane

distH(L ∩ 100BQ, ∂Ω ∩ 100BQ) r(100BQ) . We set Top =

k≥0 Topk.

For R ∈ Topk, Tree(R) = {Q ⊂ R : Q not contained in any cube from Topk+1}. R is called root of Tree(R).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 19 / 27

slide-66
SLIDE 66

Long and short trees

We have: Dµ(R0) =

  • R∈Top

Tree(R) and

  • R∈Top

µ(R) ≤ C(ε) µ(R0).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 20 / 27

slide-67
SLIDE 67

Long and short trees

We have: Dµ(R0) =

  • R∈Top

Tree(R) and

  • R∈Top

µ(R) ≤ C(ε) µ(R0). For R ∈ Top, we set R ∈ Tops if Tree(R) = {R} (short tree), and R ∈ Topℓ if #Tree(R) > 1 (long tree).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 20 / 27

slide-68
SLIDE 68

Long and short trees

We have: Dµ(R0) =

  • R∈Top

Tree(R) and

  • R∈Top

µ(R) ≤ C(ε) µ(R0). For R ∈ Top, we set R ∈ Tops if Tree(R) = {R} (short tree), and R ∈ Topℓ if #Tree(R) > 1 (long tree). If R ∈ Topℓ, then bβ(50Q) ≤ Cε for any Q ∈ Tree(R).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 20 / 27

slide-69
SLIDE 69

Long and short trees

We have: Dµ(R0) =

  • R∈Top

Tree(R) and

  • R∈Top

µ(R) ≤ C(ε) µ(R0). For R ∈ Top, we set R ∈ Tops if Tree(R) = {R} (short tree), and R ∈ Topℓ if #Tree(R) > 1 (long tree). If R ∈ Topℓ, then bβ(50Q) ≤ Cε for any Q ∈ Tree(R). If R ∈ Tops, we may have bβ(50Q) ≫ ε.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 20 / 27

slide-70
SLIDE 70

The Key Lemma

Lemma (Key Lemma)

Let η, λ > 0 and R ∈ Topℓ.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 21 / 27

slide-71
SLIDE 71

The Key Lemma

Lemma (Key Lemma)

Let η, λ > 0 and R ∈ Topℓ. Then there exists Ex(R) ⊂ Stop(R) ∩ G such that

  • P∈Ex(R)

µ(P) ≤ η µ(R) and such that every Q ∈ Stop(R) ∩ G \ Ex(R) can be joined to a good (λ′, τ0)-good corkscrew xR by a C-nice curve, with λ′ = λ′(η, λ), C = C(η, λ).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 21 / 27

slide-72
SLIDE 72

The Key Lemma

Lemma (Key Lemma)

Let η, λ > 0 and R ∈ Topℓ. Then there exists Ex(R) ⊂ Stop(R) ∩ G such that

  • P∈Ex(R)

µ(P) ≤ η µ(R) and such that every Q ∈ Stop(R) ∩ G \ Ex(R) can be joined to a good (λ′, τ0)-good corkscrew xR by a C-nice curve, with λ′ = λ′(η, λ), C = C(η, λ). A key fact: we do not ask ε to depend on λ or η.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 21 / 27

slide-73
SLIDE 73

Strategy for the proof of the Theorem

Given N > 1, set VG0 = {x ∈ G0 :

  • R∈Top

χR ≤ N}. Since

R∈Top µ(R) ≤ C(ε) µ(R0) choosing N = N(ε) big enough, by

Chebyshev µ(VG0) ≥ 1 2 µ(G) µ(R0).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 22 / 27

slide-74
SLIDE 74

Strategy for the proof of the Theorem

Given N > 1, set VG0 = {x ∈ G0 :

  • R∈Top

χR ≤ N}. Since

R∈Top µ(R) ≤ C(ε) µ(R0) choosing N = N(ε) big enough, by

Chebyshev µ(VG0) ≥ 1 2 µ(G) µ(R0). By a suitable algorithm which combines a repeated application of the “short paths” Lemma and the Key Lemma, we will be able to connect a big piece of VG0 to p by carrot curves, modulo an small exceptional set.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 22 / 27

slide-75
SLIDE 75

Idea of proof of the Key Lemma (1)

Let R ∈ Topℓ, ΓR approximating chord surface, and Ω1

R, Ω2 R

approximating chord-arc domains.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 23 / 27

slide-76
SLIDE 76

Idea of proof of the Key Lemma (1)

Let R ∈ Topℓ, ΓR approximating chord surface, and Ω1

R, Ω2 R

approximating chord-arc domains. Suppose that for each Q ∈ Stop(R), there exists a (λ, τ0)-good corkscrew x1

Q ∈ Ω1 R.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 23 / 27

slide-77
SLIDE 77

Idea of proof of the Key Lemma (1)

Let R ∈ Topℓ, ΓR approximating chord surface, and Ω1

R, Ω2 R

approximating chord-arc domains. Suppose that for each Q ∈ Stop(R), there exists a (λ, τ0)-good corkscrew x1

Q ∈ Ω1 R.

Consider a C ∞ bump function such that χBR ≤ ϕ ≤ χ2BR. Using the identity g(p, x1

Q) = g(p, x1 Q) ϕ(x1 Q)

=

  • Ω1

R

∇(g(p, ·) ϕ)(y)·∇gΩ1

R (q, y) dy +

  • g(p, y) ϕ(y) dω

x1

Q

ΩR (y),

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 23 / 27

slide-78
SLIDE 78

Idea of proof of the Key Lemma (1)

Let R ∈ Topℓ, ΓR approximating chord surface, and Ω1

R, Ω2 R

approximating chord-arc domains. Suppose that for each Q ∈ Stop(R), there exists a (λ, τ0)-good corkscrew x1

Q ∈ Ω1 R.

Consider a C ∞ bump function such that χBR ≤ ϕ ≤ χ2BR. Using the identity g(p, x1

Q) = g(p, x1 Q) ϕ(x1 Q)

=

  • Ω1

R

∇(g(p, ·) ϕ)(y)·∇gΩ1

R (q, y) dy +

  • g(p, y) ϕ(y) dω

x1

Q

ΩR (y),

we prove

  • Q∈Stop(R)

g(p, x1

Q) ℓ(Q)n−1 ≤ C g(p, x1 R)

ℓ(R) µ(R) + Err, with Err ≤ C εa µ(R) ℓ(R0)n , a > 0.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 23 / 27

slide-79
SLIDE 79

Idea of proof of the Key Lemma (2)

  • Q∈Stop(R)

g(p, x1

Q) ℓ(Q)n−1 ≤ C g(p, x1 R)

ℓ(R) µ(R) + Err, with Err ≤ C εa µ(R) ℓ(R0)n , a > 0.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 24 / 27

slide-80
SLIDE 80

Idea of proof of the Key Lemma (2)

  • Q∈Stop(R)

g(p, x1

Q) ℓ(Q)n−1 ≤ C g(p, x1 R)

ℓ(R) µ(R) + Err, with Err ≤ C εa µ(R) ℓ(R0)n , a > 0. Since g(p, x1

Q) ≥ λ ℓ(R)/ℓ(R0)n for each Q, we get

λ µ(R) ℓ(R0)n ≈ λ

  • Q∈Stop(R)

ℓ(Q)n ℓ(R0)n ≤ C g(p, x1

R)

ℓ(R) µ(R) + C εa µ(R) ℓ(R0)n .

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 24 / 27

slide-81
SLIDE 81

Idea of proof of the Key Lemma (2)

  • Q∈Stop(R)

g(p, x1

Q) ℓ(Q)n−1 ≤ C g(p, x1 R)

ℓ(R) µ(R) + Err, with Err ≤ C εa µ(R) ℓ(R0)n , a > 0. Since g(p, x1

Q) ≥ λ ℓ(R)/ℓ(R0)n for each Q, we get

λ µ(R) ℓ(R0)n ≈ λ

  • Q∈Stop(R)

ℓ(Q)n ℓ(R0)n ≤ C g(p, x1

R)

ℓ(R) µ(R) + C εa µ(R) ℓ(R0)n . So for ε > 0 small enough, g(p, x1

R) λ ℓ(R)

ℓ(R0)n .

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 24 / 27

slide-82
SLIDE 82

Idea of proof of the Key Lemma (3)

A big problem: ε cannot depend on λ, because as ε → 0, N = N(ε) → ∞ and then λ can be arbitrarily small.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 25 / 27

slide-83
SLIDE 83

Idea of proof of the Key Lemma (3)

A big problem: ε cannot depend on λ, because as ε → 0, N = N(ε) → ∞ and then λ can be arbitrarily small. To solve this, we need to split Tree(R).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 25 / 27

slide-84
SLIDE 84

Idea of proof of the Key Lemma (3)

A big problem: ε cannot depend on λ, because as ε → 0, N = N(ε) → ∞ and then λ can be arbitrarily small. To solve this, we need to split Tree(R). Given 0 < κ ≪ ε ≪ 1 and Q ∈ Tree(R), we write Q ∈ WSBC(κ) if there does not exists any curve Γ joining the “big corkscrews” x1

Q and x2 Q such

that Γ ⊂ κ−1BQ and dist(Γ, ∂Ω) ≥ κ ℓ(Q).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 25 / 27

slide-85
SLIDE 85

Idea of proof of the Key Lemma (3)

A big problem: ε cannot depend on λ, because as ε → 0, N = N(ε) → ∞ and then λ can be arbitrarily small. To solve this, we need to split Tree(R). Given 0 < κ ≪ ε ≪ 1 and Q ∈ Tree(R), we write Q ∈ WSBC(κ) if there does not exists any curve Γ joining the “big corkscrews” x1

Q and x2 Q such

that Γ ⊂ κ−1BQ and dist(Γ, ∂Ω) ≥ κ ℓ(Q). Let StopWSBC(R) be the layer of maximal cubes Q ∈ Tree(R) such that Q ∈ WSBC(κ), and let TreeWSBC(R) be the cubes from Tree(R) above the layer StopWSBC(R).

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 25 / 27

slide-86
SLIDE 86

Idea of proof of the Key Lemma (4)

Suppose that for each Q ∈ StopWSBC(R), there exists a (λ, τ0)-good corkscrew x1

Q ∈ Ω1 R.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 26 / 27

slide-87
SLIDE 87

Idea of proof of the Key Lemma (4)

Suppose that for each Q ∈ StopWSBC(R), there exists a (λ, τ0)-good corkscrew x1

Q ∈ Ω1 R.

Arguing as above, we get

  • Q∈StopWSBC(R)

g(p, x1

Q) ℓ(Q)n−1 ≤ C g(p, x1 R)

ℓ(R) µ(R) + Err, with Err ≤ C κa µ(R) ℓ(R0)n , a > 0.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 26 / 27

slide-88
SLIDE 88

Idea of proof of the Key Lemma (4)

Suppose that for each Q ∈ StopWSBC(R), there exists a (λ, τ0)-good corkscrew x1

Q ∈ Ω1 R.

Arguing as above, we get

  • Q∈StopWSBC(R)

g(p, x1

Q) ℓ(Q)n−1 ≤ C g(p, x1 R)

ℓ(R) µ(R) + Err, with Err ≤ C κa µ(R) ℓ(R0)n , a > 0. We deduce, for κ small enough, g(p, x1

R) λ ℓ(Q)

ℓ(R0)n .

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 26 / 27

slide-89
SLIDE 89

Idea of proof of the Key Lemma (4)

Suppose that for each Q ∈ StopWSBC(R), there exists a (λ, τ0)-good corkscrew x1

Q ∈ Ω1 R.

Arguing as above, we get

  • Q∈StopWSBC(R)

g(p, x1

Q) ℓ(Q)n−1 ≤ C g(p, x1 R)

ℓ(R) µ(R) + Err, with Err ≤ C κa µ(R) ℓ(R0)n , a > 0. We deduce, for κ small enough, g(p, x1

R) λ ℓ(Q)

ℓ(R0)n . Further, any P ∈ Stop(R) contained in some cube Q ∈ StopWSBC(R) can be connected to both corkscrews x1

Q, x2 Q by a “nice” curve, because x1 Q

and x2

Q are joined by a nice curve Γ.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 26 / 27

slide-90
SLIDE 90

Idea of proof of the Key Lemma (5)

An important difficulty: We need a delicate geometric argument to approximate Ω by a domains Ω1

R, Ω2 R at the level of the cubes Q ∈ StopWSBC(R), so that g(p, ·) is very

small near ∂Ωi

R.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 27 / 27

slide-91
SLIDE 91

Idea of proof of the Key Lemma (5)

An important difficulty: We need a delicate geometric argument to approximate Ω by a domains Ω1

R, Ω2 R at the level of the cubes Q ∈ StopWSBC(R), so that g(p, ·) is very

small near ∂Ωi

R.

We also need the ACF formula in this construction.

  • X. Tolsa (ICREA / UAB)

Harmonic measure May 22, 2018 27 / 27