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Geometry of Feynman Integrals in Twistor Space Based on - - PowerPoint PPT Presentation

Geometry of Feynman Integrals in Twistor Space Based on arXiv:2005.08771 in collaboration with Cristian Vergu. Building on work with Jacob Bourjaily, Andrew McLeod, Matt von Hippel, Matthias Wilhelm. Matthias Volk September 10, 2020 Niels Bohr


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Geometry of Feynman Integrals in Twistor Space

Based on arXiv:2005.08771 in collaboration with Cristian Vergu. Building on work with Jacob Bourjaily, Andrew McLeod, Matt von Hippel, Matthias Wilhelm.

Matthias Volk September 10, 2020

Niels Bohr Institute

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Context

Feynman integrals for scattering amplitudes (e.g. N = 4 SYM)

  • “Simple” amplitudes: iterated integrals and multiple

polylogarithms G(a1, . . . , an; z) = z dt t − a1 G(a2, . . . , an; t)

  • Algorithmic obstructions (identities, integration, …), but the

functions are relatively well-understood.

  • At higher loops we cannot expect such simple integrals.
  • More complicated integrals involve interesting geometry (elliptic

curves, K3 surfaces, Calabi-Yau manifolds).

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Questions to address

  • How to attach a geometry to a Feynman integral?

(Parametric representations, momentum twistor space, …)

  • What are the properties this geometry?

(Invariants, moduli space, …)

  • Where to go next?

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Table of contents

  • 1. Introduction
  • 2. Traintrack integrals

Two loops: elliptic curve as intersection of two quadrics in P3 Three loops: four-fold cover of P1 × P1 (K3) More loops: complete intersection in a toric variety

  • 3. Conclusion and further directions

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Introduction

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Two ways to fjnd a geometry

Direct integration using Feynman parameters:

  • d4ℓ1 · · · d4ℓL × Rational integrand

integrations

− − − − − − − →

  • γ

ω × Polylogs Here γ is some integration contour and ω is a holomorphic form on some variety. Example: ω =

dx

  • 4x3−g2x−g3 → elliptic curve y2 = 4x3 − g2x − g3.

Taking residues:

  • Take residues around the poles of the propagators.
  • Jacobians may allow for more residues than propagators
  • Residue of highest codimension: leading singularity
  • Constant means the integral is polylogarithmic

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Momentum twistors

xa+1 xa xa−1 pa+1 pa pa−1 y

Dual coordinates: pa = xa+1 − xa Momentum twistors: [Hodges (2009)] Z =

  • λα

xα ˙

α˜

λ ˙

α

  • ∈ P3

The twistor dictionary: Dual momentum space Momentum twistor space P3 Point x Line Lx = Ax ∧ Bx (x − y)2 Four bracket AxBxAyBy (x − y)2 = 0 Lines Lx and Ly intersect Conformal transformations PGL(4) transformations

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The massive box integral

  • d4xℓ

(2π)4 (Some normalization) (xℓ − x1)2(xℓ − x2)2(xℓ − x3)2(xℓ − x4)2

xℓ x1 x2 x3 x4

Figure 1: The box integral

Apply the twistor dictionary: [Hodges (2010)]

  • External points: four skew lines Li
  • (xℓ − xi)2 = 0: Find a fjfth line

transversal to Li.

  • Two solutions characterized by cross

ratios κ and ˜ κ on P1.

  • Everything is manifestly conformal.

There are two confjgurations where all dual points are light-like separated.

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Traintrack integrals

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Traintrack integrals

Figure 2: The traintrack integral family

Previously studied by [Bourjaily, He, McLeod, von Hippel, Wilhelm (2018)]:

  • Feynman parameters, direct integration
  • Hypersurfaces in weighted projective space
  • Two loops: elliptic curve
  • Three loops: K3 surface, four loops: Calabi-Yau threefold

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Two loops: building an elliptic curve

xℓ x1 x2 x3

Figure 3: Relationship between the endcap of the traintrack and the quadric.

Three skew lines Li = Ai ∧ Bi determine a quadric in P3: Q(Z) = ZA1B1A3ZA2B2B3 − ZA1B1A3ZA2B2A3 A quadric has two rulings (families of lines):

  • The lines within one ruling are skew.
  • Two lines from difgerent rulings intersect.

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Two loops: building an elliptic curve

xℓL xℓR

Figure 4: The double box integral

Build quadrics QL and QR for the left and the right loop respectively. Imposing (xℓL − xℓR)2 = 0 means that the quadrics intersect. The intersection C of two quadrics in P3 is an elliptic curve.

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Elliptic curve: holomorphic form

Take Poincaré residues to get a holomorphic form on C = QL ∩ QR: ωC = Res

QL,QR

ωP3 QLQR , ωP3 = Z0 dZ1 dZ2 dZ3 ± (permutations) Check the weight under rescaling Z → αZ: ωP3 → α4ωP3, QL → α2QL, QR → α2QR. Elliptic curves are characterized by one modulus, the j-invariant. Here: j = 256(z2 − z + 1)3 z2(z − 1)2 , where z depends on the quadrics QL and QR.

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Elliptic curve: comparison

Previous work by [Bourjaily, McLeod, Spradlin, von Hippel, Wilhelm (2017)]:

  • Direct integration (Feynman parameters):
  • d4ℓ1d4ℓ2 × Rational integrand

int.

− − → ∞ dx

  • P4(x)

× Polylogs

  • Elliptic curve defjned by y2 = P4(x) with complicated j-invariant.

Here: elliptic curve as intersection of two quadrics with j-invariant j = 256(z2 − z + 1)3 z2(z − 1)2 . Result The two j-invariants agree.

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Three loops: K3 surface

xℓ x1 x2

Figure 5: The three-loop traintrack integral

Geometry in twistor space:

  • As before: two quadrics QL and QR
  • Lines L1 and L2 associated to x1 and x2
  • Line Lℓ parameterized by two points P1 ∈ L1 and P2 ∈ L2
  • Bezout’s theorem: Lℓ intersects QL and QR in two points each.

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Three loops: K3 surface

Figure 6: The geometry of the three-loop traintrack integral

Geometry in twistor space:

  • As before: two quadrics QL and QR
  • Lines L1 and L2 associated to x1 and x2
  • Line Lℓ parameterized by two points P1 ∈ L1 and P2 ∈ L2
  • Bezout’s theorem: Lℓ intersects QL and QR in two points each.

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Three loops: K3 surface

Where is the K3 surface?

  • We can freely choose P1 ∈ L1 and P2 ∈ L2 while satisfying all
  • constraints. Thus, the leading singularity is two-dimensional.
  • For chosen P1 and P2, there are 2 × 2 = 4 choices for the

intersection points of Lℓ with QL and QR.

  • Thus, we have a four-fold cover of P1 × P1.

Aside: elliptic curve in P2

  • Pick four points in P1.
  • Set three of them to {0, 1, ∞} and call the last one λ.
  • Legendre form: y2 = x(x − 1)(x − λ)
  • The curve is a double cover of P1 branched over four points.

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K3 surface: branching

Branching occurs when the line Lℓ is tangent to QL or QR. Lℓ is tangent if the following equations are fulfjlled: ∆L ≡ QL(P1, P2)2 − QL(P1, P1)QL(P2, P2) = 0 ∆R ≡ QR(P1, P2)2 − QR(P1, P1)QR(P2, P2) = 0 We get two curves ∆L and ∆R of bi-degree (2, 2) in P1 × P1:

  • They are themselves elliptic curves.
  • Two branches of the surface over each curve
  • Bezout: eight intersection points (only one branch)

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K3 surface: characteristics

Points in P1 × P1 Branches P1 × P1 − ∆L ∪ ∆R 4 ∆L ∪ ∆R − ∆L ∩ ∆R 2 ∆L ∩ ∆R 1 We compute the Euler characteristic using surgery: χ = 4 ×

  • χ(P1 × P1) − χ(∆L ∪ ∆R)
  • + 2 × [χ(∆L ∪ ∆R) − χ(∆L ∩ ∆R)]

+ 1 × χ(∆L ∩ ∆R) Using for example χ(∆L) = χ(∆R) = 0 we get χ = 24 as required.

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K3 surface: characteristics

Dimension of the moduli space: 11 (Picard rank ρ = 9) Holomorphic form: ωK3 = ωP1ωP1 √∆L √∆R Nikulin involutions and automorphisms: [Nikulin (1979)]

  • Number of fjxpoints gives bounds on Picard rank
  • In this case: ρ ≥ 9

Open questions: How to compare to the hypersurface in weighted projective space? What are the invariants?

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Four and more loops

xℓ1 x1 x2 xℓ2 x3 x4

Figure 7: The four-loop traintrack integral Figure 8: The geometry of the four-loop traintrack integral

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Four and more loops

We can build a Calabi-Yau as a complete intersection in a toric variety:

  • Use combinatorial description to compute Hodge numbers

[Batyrev, Borisov (1994); …]

  • Three-fold at four loops: h11 = 12, h12 = 28 and χ = −32

(computed with PALP [Kreuzer, Skarke (2004); …])

  • Problem: codimension in the embedding space grows with the

number of loops General traintrack integral with L loops Calabi-Yau (L − 1)-fold in a toric variety of dimension 2(L − 1).

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Conclusion and further directions

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Summary

Leading singularity of the traintrack integrals:

  • Two loops: elliptic curve as the intersection of two quadrics in P3
  • Three loops: four-fold cover of P1 × P1
  • More loops: Calabi-Yau complete intersection

Good properties of momentum twistor space:

  • Intersections of lines are easier than quadratic equations.
  • No extra (unphysical) parameters
  • Dual-conformal symmetry manifest

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Further directions

Supersymmetrization:

  • Amplitudes in N = 4 SYM are superconformal
  • Formulate the intersections in terms of δ-functions (invariant

under PSL(4))

  • Replace P3 by P3|4 and the δ-functions by supersymmetric

versions. More complicated diagrams:

  • Fishnet-type N × M box graphs: also Calabi-Yau
  • Massive internal propagators

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Even further directions

How does the geometry degenerate?

  • Polylogarithmic limits, e.g. ladder diagrams [Ussyukina, Davydychev

(1993); Broadhurst (1993)]

  • Basso-Dixon integrals [Basso, Dixon (2017)]

How to deal with non-planar integrals? The role of difgerent parametrizations?

  • Feynman parameters, Baikov representation, …
  • Isogenies, e.g. [Bogner, Müller-Stach, Weinzierl (2019)]
  • Which changes of variables are allowed?

Calabi-Yau mirror symmetry (for example as in [Bloch, Kerr, Vanhove (2016);

Bönisch, Fischbach, Klemm, Nega, Safari (2020); …])? 22

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Thank you.

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Elliptic curve: j-invariant

Construct an invariant in four steps:

  • 1. Pencil of quadrics: λLQL + λRQR with [λL : λR] ∈ P1.
  • 2. Think of QL and QR as 4 × 4 symmetric matrices and compute

det(λLQL + λRQR) ∼ #λ4

L + ˜

#λ3

LλR + · · · .

  • 3. Compute the cross ratio of the four roots λi = [λi

L : λi R]:

z = 1234 1324, ij = det(λi, λj). Permutations of the λi send z → z′ ∈ { 1

z , 1 − z, . . .}.

  • 4. The j-invariant is the permutation-invariant combination

j = 256(z2 − z + 1)3 z2(z − 1)2 .