Gabor Representations of evolution operators
Elena Cordero (joint work with Fabio Nicola and Luigi Rodino)
Department of Mathematics University of Torino
Gabor Representations of evolution operators Elena Cordero (joint - - PowerPoint PPT Presentation
Gabor Representations of evolution operators Elena Cordero (joint work with Fabio Nicola and Luigi Rodino) Department of Mathematics University of Torino XXXIII Convegno Nazionale di Analisi Armonica Alba 17-20 Giugno 2013 Outline Gabor
Department of Mathematics University of Torino
L2 ≤
L2
◮ Gabor frames provide a super-exponential decay away from the
◮ The Gabor representation of T is sparse
◮ a pseudodifferential operator (PSDO) ◮ a Fourier integral operator (FIO)
◮ a pseudodifferential operator (PSDO) ◮ a Fourier integral operator (FIO)
1,0(R2d), i.e., is C∞ and
η ∂β x σ(x, η)| ≤ Cα,β(1 + |η|)−|α|;
◮ super-polynomial off diagonal decay ◮ sparsity of curvelet (shearlet) representation of T
◮ super-polynomial off diagonal decay ◮ sparsity of curvelet (shearlet) representation of T
◮ Φ(x, η) is C∞(R2d), real-valued, with
x ∂β η Φ(x, η)| ≤ Cα,β, |α| + |β| ≥ 2, ◮ σ in the H¨
0,0(R2d):
x ∂β η σ(x, η)| ≤ Cα,β .
◮ Gabor frames provide an almost diagonal matrix representation of T ◮ The Gabor representation of T is sparse
◮ Gabor frames provide an almost diagonal matrix representation of T ◮ The Gabor representation of T is sparse
t u − c(x)∂2 xu = 0,
◮ Gabor frames do not provide an almost diagonal matrix
◮ Curvelets/shearlets do the job!
t u − c(x)∂2 xu = 0,
◮ Gabor frames do not provide an almost diagonal matrix
◮ Curvelets/shearlets do the job!
◮ treat hyperbolic equations, not necessarily strictly hyperbolic, of any
◮ our class of equations includes parabolic equations ◮ the Gabor matrix off diagonal decay of super-exponential type
t u − ∆xu = 0,
◮ we study PSDO rather than FIO where the η-dependent phase
◮ σt(η) is in the non-standard H¨
0,0
s (Rd): if ∃A, B > 0:
x∈Rd |xα∂βf (x)| A|α|B|β|(α!)s(β!)s,
s (Rd). Then TFAE for σ ∈ C∞(R2d):
1 s ,
s (Rd): if ∃A, B > 0:
x∈Rd |xα∂βf (x)| A|α|B|β|(α!)s(β!)s,
s (Rd). Then TFAE for σ ∈ C∞(R2d):
1 s ,
s (Rd), s ≥ 1/2. Then
1 s ,
1 2ds ,
t + m
t
1 2πi ∂xj, j = 1, . . . , d.
t u(0, x) = uk(x),
m−1
t E(t, ·) ∗
m−k−1
η→xσ(t, η), where σ(t, η) is the unique solution to
t + m
t
t − ∆:
t − ∆ + m2, m > 0:
t − ∆:
t − ∆ + m2, m > 0:
η σ(t, η)| ≤ C (t+1)|α|+t(α!)µ,
s (Rd) then σ(t, Dx) satisfies:
1 s ,
1/2(Rd), for some ǫ > 0 and C > 0.
1 s ,
s (Rd), for some ǫ > 0 and for a new constant C > 0.