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From the makers of the smash-hit: Discretising the velocity distribution for directional Who ordered all these operators? dark matter experiments or Pi in the sky Bradley J. Kavanagh (IPhT - CEA/Saclay) CYGNUS 2015 - 4th June


  1. From the makers of the smash-hit: Discretising the velocity distribution for directional ’ Who ordered all these operators? ’ dark matter experiments or ‘ Pi in the sky’ Bradley J. Kavanagh (IPhT - CEA/Saclay) CYGNUS 2015 - 4th June 2015 Based on arXiv:1502.04224 NewDark

  2. Discretising the velocity distribution for directional dark matter experiments or ‘ Pi in the sky’ Bradley J. Kavanagh (IPhT - CEA/Saclay) CYGNUS 2015 - 4th June 2015 Based on arXiv:1502.04224 NewDark

  3. The problem The analysis of direct(ional) detection experiments requires f ( v ) assumptions about the DM velocity distribution . f ( v ) Poor assumptions about can lead to biased limits or reconstructions on particle physics parameters such as m χ and . σ p Question: f ( v ) Can we instead extract from directional data, without assuming a particular functional form? Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  4. Directional event rate m N d R m χ ρ 0 σ p C N F 2 ( E R ) ˆ = f ( v min , ˆ q ) 4 π µ 2 d E R d Ω q χ p m χ Components: ρ 0 ≈ 0 . 3 GeV cm − 3 • Local DM density, s • DM-proton cross section, m N E R σ p v min = 2 µ 2 • ‘Enhancement factor’, C N χ N Depends on target nucleus N, and type of interaction (SI/SD) • Radon transform of velocity distribution, for recoils in dir. : ˆ q Z ˆ q − v min ) d 3 v f ( v min , ˆ q ) = R 3 f ( v ) δ ( v · ˆ Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  5. Astrophysical uncertainties Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  6. Standard Halo Model Standard Halo Model (SHM) is typically assumed: isotropic, ρ ( r ) ∝ r − 2 spherically symmetric distribution of particles with . Leads to a Maxwell-Boltzmann distribution in the Galactic frame − v 2  � v ) − 3 / 2 exp f Gal ( v ) = (2 πσ 2 Θ ( v − v esc ) 2 σ 2 v Perform Galilean transform to obtain v → v − v lag distribution in lab frame: − ( v − v lag ) 2  � v ) − 3 / 2 exp f Lab ( v ) = (2 πσ 2 Θ ( | v − v lag | − v esc ) 2 σ 2 v Standard values: ∼ 180 − 270 km s − 1 v lag = − v e ( t ) [astro-ph/9706293,1207.3079, √ 1209.0759, 1312.1355] σ v ≈ v lag / 2 − 41 km s − 1 v esc = 533 +54 [1309.4293] Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  7. N-body simulations • Evidence of non-Maxwellian structure from N-body simulations [0912.2358, 1308.1703, 1503.04814] • Streams may be present due to tidally disrupted satellites [astro-ph/0310334, astro-ph/0309279] • Dark disk may form from sub haloes dragged into the plane of the stellar disk [0901.2938, 1308.1703, 1504.02481] • Debris flows , from sub haloes which are not completely phase-mixed [1105.4166] Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  8. Impact on directional detection • Astrophysical uncertainties have been much studied in non - directional experiments [e.g. 1103.5145, 1206.2693, 1207.2039] • Presence of a dark disk should not affect directional discovery limits, but may bias reconstruction of WIMP mass and cross section [1207.1050] • May also be able to extract properties of halo, stream, dark disk etc. from directional data - if the form of the distribution is known [1202.5035] Directional detection is the only way to probe the full 3-dimensional velocity distribution . f ( v ) Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  9. Attempts at a solution ˆ • Direct inversion of Radon transform f ( v min , ˆ q ) → f ( v ) [hep-ph/0209110] Mathematically unstable - not feasible without huge numbers of events • Physical parametrisation: assume a particular form for f ( v ) (e.g. SHM, or SHM with stream) and fit the parameters (e.g. v lag and ). [1012.3960, 1202.5035, 1410.2749] σ v f ( v ) Fails if cannot be described by the assumed parametrisation • Empirical parametrisation…? Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  10. Empirical parametrisations In the analysis of non-directional experiments, we have previously f ( v ) looked at general, empirical parametrisations for : • Binned parametrisation [Peter - 1103.5145, 1207.2039] • Polynomial parametrisation [1303.6868, 1312.1852] Allows us to reconstruct both WIMP mass and velocity distribution simultaneously - without bias . But for 3-D, we have an infinite number of 1-D functions to parametrise. Need to define an appropriate basis: f ( v ) = f 1 ( v ) A 1 (ˆ v ) + f 2 ( v ) A 2 (ˆ v ) + f 3 ( v ) A 3 (ˆ v ) + ... . If we choose the right basis and truncation, we reduce the problem to parametrising a finite number of functions. Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  11. The positivity problem [Alves et al. - 1204.5487, Lee - 1401.6179] One possible basis is spherical harmonics. These have nice properties: X f ( v ) = f lm ( v ) Y lm (ˆ v ) lm ˆ ˆ X f ( v min , ˆ q ) = f lm ( v min ) Y lm (ˆ q ) ⇒ lm Y l 0 (cos θ ) However, they are not strictly positive definite! If we try to fit with spherical harmonics, we cannot guarantee that we get a physical distribution function! cos θ Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  12. A discretised distribution Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  13. Discretising the distribution Divide the velocity distribution into N angular bins…  for θ 0 ∈ [0 , π /N ] f 1 ( v )    for θ 0 ∈ [ π /N, 2 π /N ] f 2 ( v )     .  .   .  f ( v ) = f ( v, cos θ 0 , φ 0 ) = for θ 0 ∈ [( k − 1) π /N, k π /N ] f k ( v )   .   .  .     for θ 0 ∈ [( N − 1) π /N, π ] f N ( v )   f k ( v ) …and then we can parametrise within each angular bin. φ 0 In principle, we could also discretise in , but φ 0 assuming is independent of does not f ( v ) introduce any error. Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  14. Investigating the discretisation error The idea is to investigate the ‘discretisation error’ - the difference in rates induced if we use the discretised distribution rather than the full one. If this error is small enough, we can use the discrete f ( v ) basis to try and reconstruct reliably. For now, we will just look at the angular discretisation - we won’t f k ( v ) look at parametrising the functions … f k ( v ) Instead, we fix by setting it equal it is the average over the angular bin: Z cos(( k � 1) π /N ) 1 f ( v ) d cos θ 0 . f k ( v ) = cos(( k − 1) π /N ) − cos( k π /N ) cos( k π /N ) Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  15. Examples: SHM f ( v ) v lag = 220 km s − 1 σ v = 156 km s − 1 Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  16. Examples: Stream f ( v ) v lag = 500 km s − 1 σ v = 20 km s − 1 Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  17. Integrated Radon Transform (IRT) We have discarded angular information - we don’t expect this discrete distribution to give a good approximation to the full directional event rate. However, we can consider instead the integrated Radon Transform (IRT): Z 2 π Z cos(( j − 1) π /N ) ˆ ˆ f j ( v min ) = f ( v min , ˆ q ) d cos θ d φ , φ =0 cos( j π /N ) We lose information (essentially binning the data) but this should reduce the error involved in using the discretised distribution. This in turn means that we can use the discretised distribution to parametrise and extract information from it reliably. f ( v ) Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  18. Calculating the Radon Transform The calculation of the Radon Transform is rather involved, but it can be carried out analytically in the angular variables for an arbitrary number of bins N, and reduced to N integrations over the speed . v [See 1502.04224 for full expressions - Python code available on request] The ‘approximation’ is exact… For N = 1: Z ∞ Z ∞ f ( v ) ˆ f 1 ( v min ) = 8 π 2 f 1 ( v ) v d v = 2 π d 3 v v v min v min For N = 2: ( p ! ) Z ∞ 1 − β 2 ˆ f 1 ( v min ) = 4 π π f 1 ( v ) + tan − 1 f 2 ( v ) − f 1 ( v ) ⇥ ⇤ d v v β v min ( p ! ) Z ∞ 1 − β 2 ˆ f 2 ( v min ) = 4 π π f 2 ( v ) + tan − 1 f 1 ( v ) − f 2 ( v ) ⇥ ⇤ d v v β v min β = v min v Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

  19. Comparison with exact results Bradley J Kavanagh (IPhT - CEA/Saclay) Discretising f(v) CYGNUS 2015 - 4th June 2015

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