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Fractional Linear . . . Fractional Linear . . . Need to Find . . . Need to Take Interval . . . Fractional Linear What We Do Dependence under Interval Main Idea Main Idea (cont-d) Uncertainty: Main Idea (cont-d) How Good Are the . . .


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Fractional Linear Dependence under Interval Uncertainty: Explicit Bounds

William Basquez, Elton Villa, and Vladik Kreinovich

Computer Science Department University of Texas at El Paso El Paso, TX 79968, USA webasquez@miners.utep.edu, euvilla@miners.utep.edu, vladik@utep.edu

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1. Fractional Linear Dependencies Are Ubiquitous

  • To describe a physical quantity by a numerical value,

we need to select a measuring procedure.

  • If we change a measuring unit, then all numerical val-

ues are multiplied by a constant: x → a · x.

  • If we change a starting point, to all numerical values a

constant is added: x → x + b.

  • In addition to such linear transformations x → a·x+b,

we may also have nonlinear ones.

  • The class of all reasonable transformations must be:

– closed under composition, – contain all linear functions, and – be described by finitely many parameters.

  • The reason for the last requirement is that in a com-

puter, we can only store finitely many values.

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2. Fractional Linear Dependencies (cont-d)

  • It turns out that all such transformation are fractionally-

linear.

  • Indeed, fractional-linear transformations

y = a · x + b c · x + d are ubiquitous in practice.

  • We can always change the starting point for y so that

x = 0 would correspond to y = 0.

  • In this case, we get b = 0, and, dividing both numera-

tor and denominator by d, we get y = a · x 1 + c · x.

  • For small x, this is approximately equal to a · x.
  • So this formula is a reasonable next approximation to

the linear dependence y = a · x.

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3. Need to Find Parameters of the Fractional Lin- ear Dependence from Data

  • The parameters a and c need to be determined from

measurement results xk and yk, k = 1, . . . , n.

  • Let us first consider an ideal case, when measurements

are absolutely accurate.

  • In this case, we get linear equations yk+c·xk·yk = a·xk

for determining a and c.

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4. Need to Take Interval Uncertainty Into Ac- count

  • In practice, we only measure these values with some

uncertainty.

  • So, the measurement results

xk and yk, in general, dif- fer from the actual (unknown) values xk and yk.

  • What do we know about the measurement error, e.g.,

about ∆xk

def

= xk − xk?

  • Often, the only information we have is the upper bound

∆xk on its absolute value: |∆xk| ≤ ∆xk.

  • Then, after the measurement, all we know about xk is

that it is between xk = xk − ∆k and xk = xk + ∆k.

  • Under such interval uncertainty, we need to find the

ranges of possible values of a and c.

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5. What We Do

  • In this talk, we show how to do it under the assumption

that xk, yk, and c are all non-negative.

  • The formulas can be easily modified to the general case.
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6. Main Idea

  • Based on each measurement result, we can conclude

that a = yk ·

  • c + 1

xk

  • .
  • The largest possible value of this expression is when yk

is the largest and xk is the smallest, and vice versa.

  • So, we get bounds on a corresponding to each measure-

ment: yk ·

  • c + 1

xk

  • ≤ a ≤ yk ·
  • c + 1

xk

  • .
  • Such a value a exists if and only if each lower bound

does not exceed each upper bound: yk ·

  • c + 1

xk

  • ≤ yℓ ·
  • c + 1

xℓ

  • for all k and ℓ.
  • We thus get n2 linear inequalities, each of which can

be reformulated as ckℓ ≤ c or c ≤ ckℓ.

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7. Main Idea (cont-d)

  • Reminder: we have inequalities ckℓ ≤ c or c ≤ ckℓ.
  • The range of possible values of c can hence be explicitly

described as [max(ckℓ), min(ckℓ)].

  • If we start with inequalities on c, we similarly get ex-

plicit bounds on a.

  • Namely, we get 1+c·xk = a· xk

yk , hence c·xk = a· xk yk −1 and c = a yk − 1 xk ; thus: a yk − 1 xk ≤ c ≤ a yk − 1 xk .

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8. Main Idea (cont-d)

  • Such a c exists if every lower bound is not larger than

every upper bound: a yk − 1 xk ≤ a yℓ − 1 xℓ for each k and ℓ.

  • Each such linear inequality can be represented as either

akℓ ≤ a or a ≤ akℓ.

  • So, the range of possible values of a is

[max(akℓ), min(akℓ)].

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9. How Good Are the Resulting Formulas

  • The resulting formulas require O(n2) computation steps.