fourteen wood construction: column design Wood Columns 1 Elements - - PowerPoint PPT Presentation

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E LEMENTS OF A RCHITECTURAL S TRUCTURES : F ORM, B EHAVIOR, AND D ESIGN ARCH 614 D R. A NNE N ICHOLS S PRING 2019 lecture fourteen wood construction: column design Wood Columns 1 Elements of Architectural Structures S2019abn Lecture 14


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SLIDE 1

S2019abn Wood Columns 1 Lecture 14 Elements of Architectural Structures ARCH 614

ELEMENTS OF ARCHITECTURAL STRUCTURES: FORM, BEHAVIOR, AND DESIGN

ARCH 614

  • DR. ANNE NICHOLS

SPRING 2019 lecture

fourteen

wood construction: column design

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SLIDE 2

S2019abn Wood Columns 2 Lecture 14 Elements of Architectural Structures ARCH 614

Compression Members (revisited)

  • designed for strength & stresses
  • designed for serviceability & deflection
  • need to design for stability

– ability to support a specified load without sudden or unacceptable deformations

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SLIDE 3

S2019abn Wood Columns 3 Lecture 14 Elements of Architectural Structures ARCH 614

Effect of Length (revisited)

  • long & slender
  • short & stubby
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SLIDE 4

S2019abn Wood Columns 4 Lecture 14 Elements of Architectural Structures ARCH 614

Critical Stresses (revisited)

  • when a column gets stubby, crushing will limit

the load

  • real world has loads with eccentricity
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SLIDE 5

S2019abn Wood Columns 5 Lecture 14 Elements of Architectural Structures ARCH 614

Bracing (revisited)

  • bracing affects shape of buckle

in one direction

  • both should be checked!
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SLIDE 6

S2019abn Wood Columns 6 Lecture 14 Elements of Architectural Structures ARCH 614

Wood Columns

  • slenderness ratio = L/dmin = L/d1

– d1 = smaller dimension – le/d  50 (max) – where is the allowable compressive strength parallel to the grain – bracing common

c c

F A P f   

c

F

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SLIDE 7

S2019abn Wood Columns 7 Lecture 14 Elements of Architectural Structures ARCH 614

Allowable Wood Stress

  • where:

Fc = compressive strength parallel to grain CD = load duration factor CM = wet service factor (1.0 dry) Ct = temperature factor CF = size factor Cp = column stability factor

    

p F t M D c c

C C C C C F F  

(Table 5.2)

 

* c cE

F F

f 

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SLIDE 8

S2019abn Wood Columns 8 Lecture 14 Elements of Architectural Structures ARCH 614

Strength Factors

  • wood properties and load duration, CD

– short duration

  • higher loads

– normal duration

  • > 10 years
  • stability, Cp

– combination curve - tables

 

p D c p c c

C C F C F F   

*

http://www.swst.org/teach/set2/struct1.html

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SLIDE 9

S2019abn Wood Columns 9 Lecture 14 Elements of Architectural Structures ARCH 614

Cp Charts

(c = 0.8 sawn, c = 0.9 glulam)

 

min 2

0.822  

cE l d

e

E F

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SLIDE 10

S2019abn Wood Columns 10 Lecture 14 Elements of Architectural Structures ARCH 614

Procedure for Analysis

  • 1. calculate Le/dmin

– KL/d each axis, choose largest

  • 2. obtain F´c

– compute

  • where
  • 3. compute Fc

*  FcCD

  • 4. calculate FcE/Fc

* and get Cp (chart)

  • 5. calculate

 

min 2

0.822

e

cE L d

E F  

p c c

C F F

*

 

min min (

)( )( )( )

M t T i

E E C C C C  

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SLIDE 11

S2019abn Wood Columns 11 Lecture 14 Elements of Architectural Structures ARCH 614

Procedure for Analysis (cont’d)

  • 6. compute Pallowable = FcA
  • r find factual = P/A
  • 7. is P  Pallowable? (or factual  Fc?)
  • yes: OK
  • no: overstressed & no good
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SLIDE 12

S2019abn Wood Columns 12 Lecture 14 Elements of Architectural Structures ARCH 614

Procedure for Design

  • 1. guess a size (pick a section)
  • 2. calculate Le/dmin

– KL/d each axis, choose largest

  • 3. obtain F´c

– compute

  • where
  • 4. compute Fc

*  FcCD

  • 5. calculate FcE/Fc

* and get Cp (chart)

 

min 2

0.822

e

cE L d

E F  

min min(

)( )( )( )

M t T i

E E C C C C  

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SLIDE 13

S2019abn Wood Columns 13 Lecture 14 Elements of Architectural Structures ARCH 614

Procedure for Design (cont’d)

  • 6. calculate
  • 7. compute Pallowable = FcA
  • r find factual = P/A
  • 8. is P  Pallowable? (or factual  Fc?)
  • yes: OK
  • no: pick a bigger section and go back to step 2.

p c c

C F F

*

 

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SLIDE 14

S2019abn Wood Columns 14 Lecture 14 Elements of Architectural Structures ARCH 614

Specific Column Charts

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SLIDE 15

S2019abn Wood Columns 15 Lecture 14 Elements of Architectural Structures ARCH 614

Timber Construction by Code

  • light-frame

– light loads – 2x’s – floor joists – 2x6, 2x8, 2x10, 2x12 typical at spacings of 12”, 16”, 24” – normal spans of 20-25 ft or 6-7.5 m – plywood spans between joists – stud or load-bearing masonry walls – limited to around 3 stories – fire safety

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SLIDE 16

S2019abn Wood Columns 16 Lecture 14 Elements of Architectural Structures ARCH 614

Design of Columns with Bending

  • satisfy

– strength – stability

  • pick

– section

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SLIDE 17

S2019abn Wood Columns 17 Lecture 14 Elements of Architectural Structures ARCH 614

Design

  • Wood

[] term – magnification factor for P- F’bx – allowable bending strength

. 1 1

2

                

cEx c bx bx c c

F f F f F f

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SLIDE 18

S2019abn Wood Columns 18 Lecture 14 Elements of Architectural Structures ARCH 614

Design Steps Knowing Loads

  • 1. assume limiting stress
  • buckling, axial stress,

combined stress

  • 2. solve for r, A or S
  • 3. pick trial section
  • 4. analyze stresses
  • 5. section ok?
  • 6. stop when section is ok