Effective fractal dimension in the hyperspace and the space of - - PowerPoint PPT Presentation

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Effective fractal dimension in the hyperspace and the space of - - PowerPoint PPT Presentation

Effective fractal dimension in the hyperspace and the space of probability distributions (informal talk) Elvira Mayordomo Universidad de Zaragoza, Iowa State University AIM, August 13th 2020 Why algorithmic randomness? Why algorithmic


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Effective fractal dimension in the hyperspace and the space of probability distributions (informal talk)

Elvira Mayordomo

Universidad de Zaragoza, Iowa State University

AIM, August 13th 2020

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Why algorithmic randomness?

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Why algorithmic randomness?

detect randomness

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Why algorithmic randomness?

detect randomness produce randomness

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Why algorithmic randomness?

detect randomness produce randomness mimic randomness

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Information content in a separable space

Let (X, ρ) be a separable metric space. Let D be a dense set and f : {0, 1}∗ ։ D

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Information content in a separable space

Let (X, ρ) be a separable metric space. Let D be a dense set and f : {0, 1}∗ ։ D What is the information content of x ∈ X?

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Information content in a separable space

Let (X, ρ) be a separable metric space. Let D be a dense set and f : {0, 1}∗ ։ D What is the information content of x ∈ X?

Definition

Let x ∈ X, n ∈ N. The Kolmogorov complexity of x at precision n is Kf

n(x) = inf

  • K(q)
  • q ∈ D, ρ(x, q) ≤ 2−n

.

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Effective dimension in a separable space

(X, ρ) is a separable metric space, D is a dense set, and f : {0, 1}∗ ։ D

Definition

Let x ∈ X, cdimf (x) = lim inf

n

Kf

n(x)

r .

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Effective dimension in a separable space

(X, ρ) is a separable metric space, D is a dense set, and f : {0, 1}∗ ։ D

Definition

Let x ∈ X, cdimf (x) = lim inf

n

Kf

n(x)

r .

Definition

Let E ⊆ X, cdimf (E) = sup

x∈E

cdimf (x).

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Effective dimension in a separable space

(X, ρ) is a separable metric space, D is a dense set, and f : {0, 1}∗ ։ D

Definition

Let x ∈ X, cdimf (x) = lim inf

n

Kf

n(x)

r .

Definition

Let E ⊆ X, cdimf (E) = sup

x∈E

cdimf (x). Both definitions relativize to any oracle B by using KB(w)

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Point to set principle for separable X

((X, ρ) is a separable metric space, D is a dense set and f : {0, 1}∗ ։ D)

Theorem (ptsp separable spaces)

Let E ⊆ X. Then dimH(E) = min

B⊆{0,1}∗ cdimf ,B(E).

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PTSP

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PTSP

Let us answer questions on dimH using effective dimension

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PTSP

Let us answer questions on dimH using effective dimension Questions on dimH(E) are questions on the randomness of x ∈ E

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The hyperspace

Let (X, ρ) be a separable metric space Let K(X) be the set of nonempty compact subsets of X together with the Hausdorff metric distH defined as follows distH(U, V ) = max

  • sup

x∈U

ρ(x, V ), sup

y∈V

ρ(y, U)

  • .

(ρ(a, B) = inf{ρ(a, b)|b ∈ B})

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Known result

Theorem (McClure 1996)

Let E ⊆ X be self-similar. Let ψs(t) = 2−1/ts. Then dimψ

H(K(E)) ≤ dimH(E).

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Constructive exact dimension

Definition

Let x ∈ X. The f -constructive dimensionϕ of x is cdimf ,ϕ(x) = inf{s | ∃∞n Kf

n(x) ≤ log(1/ϕs(2−n))}.

Definition

Let x ∈ X. The f -constructive strong dimensionϕ of x is cDimf ,ϕ(x) = inf{s | ∀∞n Kf

n(x) ≤ log(1/ϕs(2−n))}.

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  • J. Lutz, N. Lutz, EM 2020

Theorem (Hyperspace dimension theorem)

Let E ⊆ X be an analytic set. Let ϕ be a gauge family, let ˜ ϕs(t) = 2−1/ϕs(t). Then dim ˜

ϕ P(K(E)) ≥ dimϕ P(E).

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Prokhorov metric space

Let P(X) be the set of Borel probability measures on X dP(µ, ν) = inf {α > 0 |µ(A) ≤ ν(Aα) + α ∧ ν(A) ≤ µ(Aα) + α} Aα = {x |ρ(A, x) < α}, ∅α = ∅ Notice that dP(δx, δy) = min(ρ(x, y), 1).

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Information content in Prokhorov metric space

((X, ρ) is a separable metric space, D is a dense set and f : {0, 1}∗ ։ D) M =   α1δa1 + . . . + αkδak

  • k ∈ N, ai ∈ D, αi ∈ Q ∩ [0, 1],

k

  • j=1

αk = 1   

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Why Prokhorov metric space I

Definition

Γ ⊆ P(X) is tight if for any ǫ > 0 there is K compact with µ(K) ≥ 1 − ǫ for any µ ∈ Γ.

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Why Prokhorov metric space I

Definition

Γ ⊆ P(X) is tight if for any ǫ > 0 there is K compact with µ(K) ≥ 1 − ǫ for any µ ∈ Γ.

Theorem (Prokhorov theorem)

For Γ ⊆ P(X), Γ is compact if and only if Γ is tight

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Why Prokhorov metric space II

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Why Prokhorov metric space II

Theorem (Riesz representation theorem)

Let (X, ρ) be compact and Hausdorff. If ϕ : C(X) → R is positive and ϕ = 1 then there is a unique µ ∈ P(X) with ϕ(f ) =

  • fdµ

for all f ∈ C(X).

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References

Jack H. Lutz and Neil Lutz, Who asked us? How the theory

  • f computing answers questions about analysis, Ding-Zhu Du

and Jie Wang (eds.), Complexity and Approximation: In Memory of Ker-I Ko, pp. 48-56, Springer, 2020. https://arxiv.org/abs/1912.00284 Jack H. Lutz and Elvira Mayordomo, Algorithmic fractal dimensions in geometric measure theory, Springer, to appear. https://arxiv.org/abs/2007.14346 Jack H. Lutz, Neil Lutz, and Elvira Mayordomo The Dimensions of Hyperspaces. https://arxiv.org/abs/2004.07798 Onno van Gaans, Probability measures on metric spaces. https: //www.math.leidenuniv.nl/~vangaans/jancol1.pdf