SLIDE 1 Depth and regularity
- f powers of sum of ideals
Ngo Viet Trung1
Institute of Mathematics Vietnamese Academy of Science and Technology
Tehran, November 2015
1Joint work with H.T. Ha (New Orleans) and T.N. Trung (Hanoi)
SLIDE 2
Depth and regularity
Let R be a polynomial ring over a field k. Let M be a f.g. graded R-module. Let 0 → Fs → · · · F0 → M be a graded minimal free resolution. depth M = dim R − s, reg M = max{d(Fi) − i| i = 0, ..., s}, where d(Fi) := maximum degree of the generators of Fi.
SLIDE 3
Depth and regularity
Let R be a polynomial ring over a field k. Let M be a f.g. graded R-module. Let 0 → Fs → · · · F0 → M be a graded minimal free resolution. depth M = dim R − s, reg M = max{d(Fi) − i| i = 0, ..., s}, where d(Fi) := maximum degree of the generators of Fi. In general, depth M and reg M can be defined in terms of the local cohomology modules of M.
SLIDE 4
Powers of ideals
Let Q be a homogeneous ideal in a polynomial ring R.
SLIDE 5
Powers of ideals
Let Q be a homogeneous ideal in a polynomial ring R. Problem: to study the functions depth R/Qn and reg R/Qn. Brodmann: depth R/Qn = const for n ≫ 0. Cutkosky-Herzog-T, Kodiyalam: reg R/Qn = dn + e for n ≫ 0.
SLIDE 6
Powers of ideals
Let Q be a homogeneous ideal in a polynomial ring R. Problem: to study the functions depth R/Qn and reg R/Qn. Brodmann: depth R/Qn = const for n ≫ 0. Cutkosky-Herzog-T, Kodiyalam: reg R/Qn = dn + e for n ≫ 0. In general, it is a hard problem. There are partial results, e.g. by Herzog-Hibi, Herzog-Vladiou: depth for monomial ideals, Eisenbud-Harris, Eisenbud-Ulrich: regularity for zero-dimensional ideas.
SLIDE 7
Sum of ideals
Let A = k[x1, . . . , xr] and B = k[y1, . . . , ys]. Let I ⊂ A and J ⊂ B be nonzero proper ideals. Let R = k[x1, . . . , xr, y1, . . . , ys]. We also use I, J for the ideals generated by I, J in R.
SLIDE 8
Sum of ideals
Let A = k[x1, . . . , xr] and B = k[y1, . . . , ys]. Let I ⊂ A and J ⊂ B be nonzero proper ideals. Let R = k[x1, . . . , xr, y1, . . . , ys]. We also use I, J for the ideals generated by I, J in R. Problem: To estimate depth R/(I + J)n and reg R/(I + J)n in terms of I and J.
SLIDE 9
Sum of ideals
Let A = k[x1, . . . , xr] and B = k[y1, . . . , ys]. Let I ⊂ A and J ⊂ B be nonzero proper ideals. Let R = k[x1, . . . , xr, y1, . . . , ys]. We also use I, J for the ideals generated by I, J in R. Problem: To estimate depth R/(I + J)n and reg R/(I + J)n in terms of I and J. The simplest case: J = (y) ⊂ B = k[y] ?
SLIDE 10
Sum of ideals
Let A = k[x1, . . . , xr] and B = k[y1, . . . , ys]. Let I ⊂ A and J ⊂ B be nonzero proper ideals. Let R = k[x1, . . . , xr, y1, . . . , ys]. We also use I, J for the ideals generated by I, J in R. Problem: To estimate depth R/(I + J)n and reg R/(I + J)n in terms of I and J. The simplest case: J = (y) ⊂ B = k[y] ? Proposition: depth A[x]/(I, x)n = mini≤n depth A/I i, reg A[x]/(I, x)n = maxi≤n{reg A/I i − i} + n.
SLIDE 11
Motivation
Geometry: Fiber product of two varieties X ×k Y R/I + J = (A/I) ⊗k (B/J)
SLIDE 12
Motivation
Geometry: Fiber product of two varieties X ×k Y R/I + J = (A/I) ⊗k (B/J) Combinatoric: Edge ideal of a graph (or hypergraph) I(G) := (xixj| {i, j} ∈ G). If G = G1 ⊔ G2, then I(G) = I(G1) + I(G2)
SLIDE 13
Estimation by approximation
Set Qi := I n + I n−1J + · · · + I n−iJi, i = 0, . . . , n. Then I n = Q0 ⊂ Q1 ⊂ · · · ⊂ Qn = (I + J)n,
SLIDE 14
Estimation by approximation
Set Qi := I n + I n−1J + · · · + I n−iJi, i = 0, . . . , n. Then I n = Q0 ⊂ Q1 ⊂ · · · ⊂ Qn = (I + J)n, 0 → Qi/Qi−1 → R/Qi−1 → R/Qi → 0. We can estimate depth and reg of R/(I + J)n in terms of Qi/Qi−1
SLIDE 15
Estimation by approximation
Set Qi := I n + I n−1J + · · · + I n−iJi, i = 0, . . . , n. Then I n = Q0 ⊂ Q1 ⊂ · · · ⊂ Qn = (I + J)n, 0 → Qi/Qi−1 → R/Qi−1 → R/Qi → 0. We can estimate depth and reg of R/(I + J)n in terms of Qi/Qi−1 Lemma: Qi/Qi−1 ∼ = I n−iJi/I n−i+1Ji.
SLIDE 16
Estimation by approximation
Set Qi := I n + I n−1J + · · · + I n−iJi, i = 0, . . . , n. Then I n = Q0 ⊂ Q1 ⊂ · · · ⊂ Qn = (I + J)n, 0 → Qi/Qi−1 → R/Qi−1 → R/Qi → 0. We can estimate depth and reg of R/(I + J)n in terms of Qi/Qi−1 Lemma: Qi/Qi−1 ∼ = I n−iJi/I n−i+1Ji. 0 → Qi/Qi−1 → R/I n−i+1Ji → R/I n−iJi → 0. Hoa-Tam: depth R/IJ = depth A/I + depth B/J + 1, reg R/IJ = reg A/I + reg B/J + 1.
SLIDE 17 First bounds
Theorem: depth R
min
i∈[1,n−1], j∈[1,n]{depth A/I n−i + depth B/Ji + 1,
depth A/I n−j+1 + depth B/Jj},
SLIDE 18 First bounds
Theorem: depth R
min
i∈[1,n−1], j∈[1,n]{depth A/I n−i + depth B/Ji + 1,
depth A/I n−j+1 + depth B/Jj}, reg R
max
i∈[1,n−1], j∈[1,n]{reg A/I n−i +reg B/Ji +1, reg A/I n−j+1+reg B/Jj}.
SLIDE 19 First bounds
Theorem: depth R
min
i∈[1,n−1], j∈[1,n]{depth A/I n−i + depth B/Ji + 1,
depth A/I n−j+1 + depth B/Jj}, reg R
max
i∈[1,n−1], j∈[1,n]{reg A/I n−i +reg B/Ji +1, reg A/I n−j+1+reg B/Jj}.
The inequality is ‘almost’ an equality.
SLIDE 20 First bounds
Theorem: depth R
min
i∈[1,n−1], j∈[1,n]{depth A/I n−i + depth B/Ji + 1,
depth A/I n−j+1 + depth B/Jj}, reg R
max
i∈[1,n−1], j∈[1,n]{reg A/I n−i +reg B/Ji +1, reg A/I n−j+1+reg B/Jj}.
The inequality is ‘almost’ an equality. The maximum of one of the two formulas on the right sides can be attained separately.
SLIDE 21 First bounds
Theorem: depth R
min
i∈[1,n−1], j∈[1,n]{depth A/I n−i + depth B/Ji + 1,
depth A/I n−j+1 + depth B/Jj}, reg R
max
i∈[1,n−1], j∈[1,n]{reg A/I n−i +reg B/Ji +1, reg A/I n−j+1+reg B/Jj}.
The inequality is ‘almost’ an equality. The maximum of one of the two formulas on the right sides can be attained separately. No hope for exact formulas.
SLIDE 22
Estimation by decomposition
One can find exact formulas for depth and regularity of (I + J)n/(I + J)n+1.
SLIDE 23 Estimation by decomposition
One can find exact formulas for depth and regularity of (I + J)n/(I + J)n+1. Lemma: (I + J)n/(I + J)n+1 =
- i+j=n
- I i/I i+1 ⊗k Jj/Jj+1
.
SLIDE 24 Estimation by decomposition
One can find exact formulas for depth and regularity of (I + J)n/(I + J)n+1. Lemma: (I + J)n/(I + J)n+1 =
- i+j=n
- I i/I i+1 ⊗k Jj/Jj+1
. Goto-Watanabe: Formula for the local cohomology modules of M ⊗k N, where M and N are f.g. graded R-modules. From this it follows: depth M ⊗k N = depth M + depth N, reg M ⊗k N = reg M + reg N.
SLIDE 25
Second bounds
Theorem: depth(I + J)n/(I + J)n+1 = min
i+j=n{depth I i/I i+1 + depth Jj/Jj+1},
reg(I + J)n/(I + J)n+1 = max
i+j=n{reg I i/I i+1 + reg Jj/Jj+1}.
SLIDE 26
Second bounds
Theorem: depth(I + J)n/(I + J)n+1 = min
i+j=n{depth I i/I i+1 + depth Jj/Jj+1},
reg(I + J)n/(I + J)n+1 = max
i+j=n{reg I i/I i+1 + reg Jj/Jj+1}.
In general, one can not compute the invariants of R/(I + J)n from the invariants of (I + J)i/(I + J)i+1 for i ≤ n.
SLIDE 27
Second bounds
Theorem: depth(I + J)n/(I + J)n+1 = min
i+j=n{depth I i/I i+1 + depth Jj/Jj+1},
reg(I + J)n/(I + J)n+1 = max
i+j=n{reg I i/I i+1 + reg Jj/Jj+1}.
In general, one can not compute the invariants of R/(I + J)n from the invariants of (I + J)i/(I + J)i+1 for i ≤ n. Corollary: depth R/(I + J)n ≥ min
i+j≤n−1{depth I i/I i+1 + depth Jj/Jj+1},
reg R/(I + J)n ≤ max
i+j≤n−1{reg I i/I i+1 + reg Jj/Jj+1}.
SLIDE 28
Second bounds
Theorem: depth(I + J)n/(I + J)n+1 = min
i+j=n{depth I i/I i+1 + depth Jj/Jj+1},
reg(I + J)n/(I + J)n+1 = max
i+j=n{reg I i/I i+1 + reg Jj/Jj+1}.
In general, one can not compute the invariants of R/(I + J)n from the invariants of (I + J)i/(I + J)i+1 for i ≤ n. Corollary: depth R/(I + J)n ≥ min
i+j≤n−1{depth I i/I i+1 + depth Jj/Jj+1},
reg R/(I + J)n ≤ max
i+j≤n−1{reg I i/I i+1 + reg Jj/Jj+1}.
These bounds are not related to the first given bounds.
SLIDE 29
Asymptotic depth
The asymptotic values of depth R/(I + J)n can be computed from that of depth(I + J)n/(I + J)n+1 and hence from those of depth A/I n and depth B/Jn.
SLIDE 30
Asymptotic depth
The asymptotic values of depth R/(I + J)n can be computed from that of depth(I + J)n/(I + J)n+1 and hence from those of depth A/I n and depth B/Jn. Herzog and Hibi: depth Qn−1/Qn = const for n ≫ 0, lim
i→∞ depth R/Qn = lim n→∞ depth Qn−1/Qn.
SLIDE 31 Asymptotic depth
The asymptotic values of depth R/(I + J)n can be computed from that of depth(I + J)n/(I + J)n+1 and hence from those of depth A/I n and depth B/Jn. Herzog and Hibi: depth Qn−1/Qn = const for n ≫ 0, lim
i→∞ depth R/Qn = lim n→∞ depth Qn−1/Qn.
Theorem: lim
n→∞ depth R/(I + J)n =
min
i→∞ depth A/I i + min j≥1 depth B/Jj,
min
i≥1 depth A/I i + lim j→∞ depth B/Jn
.
SLIDE 32
Asymptotic regularity
Lemma: Let s(Q) denote the least integer m such that reg Qn = dn + e for n ≥ m. Then reg R/Qn = reg Qn−1/Qn for n ≥ s(Q) + 1.
SLIDE 33 Asymptotic regularity
Lemma: Let s(Q) denote the least integer m such that reg Qn = dn + e for n ≥ m. Then reg R/Qn = reg Qn−1/Qn for n ≥ s(Q) + 1. Theorem: Assume that reg I n = dn + e and reg Jn = cn + f for n ≫ 0. Set e∗ := maxi≤s(I){reg I i − ci}, f ∗ := maxj≤s(J){reg Jj − dj}. For n ≫ 0, we have reg(I + J)n =
if c > d, d(n + 1) + max{f + e∗, e + f ∗} − 1 if c = d.
SLIDE 34 Asymptotic regularity
Lemma: Let s(Q) denote the least integer m such that reg Qn = dn + e for n ≥ m. Then reg R/Qn = reg Qn−1/Qn for n ≥ s(Q) + 1. Theorem: Assume that reg I n = dn + e and reg Jn = cn + f for n ≫ 0. Set e∗ := maxi≤s(I){reg I i − ci}, f ∗ := maxj≤s(J){reg Jj − dj}. For n ≫ 0, we have reg(I + J)n =
if c > d, d(n + 1) + max{f + e∗, e + f ∗} − 1 if c = d. One can give upper bound for s(I + J) in terms of s(I) and s(J).
SLIDE 35
Cohen-Macaulayness of powers
Theorem: The following conditions are equivalent: (i) R/(I + J)t is Cohen-Macaulay for all t ≤ n, (ii) (I + J)n−1 (I + J)n is Cohen-Macaulay, (iii) A/I t and B/Jt are Cohen-Macaulay for all t ≤ n, (iv) I t/I t+1 and Jt/Jt+1) are Cohen-Macaulay for all t ≤ n − 1.
SLIDE 36
Cohen-Macaulayness of powers
Theorem: The following conditions are equivalent: (i) R/(I + J)t is Cohen-Macaulay for all t ≤ n, (ii) (I + J)n−1 (I + J)n is Cohen-Macaulay, (iii) A/I t and B/Jt are Cohen-Macaulay for all t ≤ n, (iv) I t/I t+1 and Jt/Jt+1) are Cohen-Macaulay for all t ≤ n − 1. Strange phenomenon: the Cohen-Macaulayness of only (I + J)n−1 (I + J)n implies that of R/(I + J)t for all t ≤ n − 1.
SLIDE 37
Cohen-Macaulayness of powers
Theorem: The following conditions are equivalent: (i) R/(I + J)t is Cohen-Macaulay for all t ≤ n, (ii) (I + J)n−1 (I + J)n is Cohen-Macaulay, (iii) A/I t and B/Jt are Cohen-Macaulay for all t ≤ n, (iv) I t/I t+1 and Jt/Jt+1) are Cohen-Macaulay for all t ≤ n − 1. Strange phenomenon: the Cohen-Macaulayness of only (I + J)n−1 (I + J)n implies that of R/(I + J)t for all t ≤ n − 1. This result does not hold for an arbitrary ideal Q in R.
SLIDE 38
Constant depth function
Herzog-Takayama-Terai: depth R/Qn ≤ depth R/Q if Q is a squarefee monomial ideal.
SLIDE 39
Constant depth function
Herzog-Takayama-Terai: depth R/Qn ≤ depth R/Q if Q is a squarefee monomial ideal. Q is said to have a constant depth function if depth R/Qn = depth R/Q for all n.
SLIDE 40
Constant depth function
Herzog-Takayama-Terai: depth R/Qn ≤ depth R/Q if Q is a squarefee monomial ideal. Q is said to have a constant depth function if depth R/Qn = depth R/Q for all n. Herzog and Vladiou: Let I, J be squarefree monomial ideals such that the Rees algebras of I and J are Cohen-Macaulay. Then I + J has a constant depth function if and only if so do I and J.
SLIDE 41
Constant depth function
Herzog-Takayama-Terai: depth R/Qn ≤ depth R/Q if Q is a squarefee monomial ideal. Q is said to have a constant depth function if depth R/Qn = depth R/Q for all n. Herzog and Vladiou: Let I, J be squarefree monomial ideals such that the Rees algebras of I and J are Cohen-Macaulay. Then I + J has a constant depth function if and only if so do I and J. Theorem: This result holds without the assumption on the Rees algebras.
SLIDE 42
Constant depth function
Herzog-Takayama-Terai: depth R/Qn ≤ depth R/Q if Q is a squarefee monomial ideal. Q is said to have a constant depth function if depth R/Qn = depth R/Q for all n. Herzog and Vladiou: Let I, J be squarefree monomial ideals such that the Rees algebras of I and J are Cohen-Macaulay. Then I + J has a constant depth function if and only if so do I and J. Theorem: This result holds without the assumption on the Rees algebras. Not true if I, J are not squarefree monomial ideals
SLIDE 43
Non-increasing depth function
Herzog-Hibi: Given a convergent non-negative integer valued function f , does there exist a monomial ideal Q such that depth R/Qn = f (n) for all n ≥ 1.
SLIDE 44
Non-increasing depth function
Herzog-Hibi: Given a convergent non-negative integer valued function f , does there exist a monomial ideal Q such that depth R/Qn = f (n) for all n ≥ 1. They showed that the answer is yes for all non-decreasing functions and special non-increasing functions.
SLIDE 45
Non-increasing depth function
Herzog-Hibi: Given a convergent non-negative integer valued function f , does there exist a monomial ideal Q such that depth R/Qn = f (n) for all n ≥ 1. They showed that the answer is yes for all non-decreasing functions and special non-increasing functions. Theorem: Yes for all non-increasing functions.
SLIDE 46
Non-increasing depth function
Herzog-Hibi: Given a convergent non-negative integer valued function f , does there exist a monomial ideal Q such that depth R/Qn = f (n) for all n ≥ 1. They showed that the answer is yes for all non-decreasing functions and special non-increasing functions. Theorem: Yes for all non-increasing functions. Construct Q such that depth Qn/Qn+1 = f (n) by taking sums of ideals having depth functions of the form 1,...,1,0,0,....
SLIDE 47 References
- S. Goto and K Watanabe, On graded rings I, Math. Soc. Japan
30 (1978), 179–212.
- J. Herzog and T. Hibi, The depth of powers of an ideal, J. Algebra
291 (2005), 534–550.
- J. Herzog and M. Vladiou, Squarefree monomial ideals with
constant depth function, J. Pure Appl. Algebra 217 (2013), 1764–1772.
- L. T. Hoa and N. D. Tam, On some invariants of a mixed product
- f ideals, Arch. Math. 94 (2010), 327–337.