SLIDE 19 Theoretical Results
Lemma (Case 1) A word x ∈ Mℓ
y1 (resp. x ∈ Mℓ y2) belongs to Mℓ y if and only if x is a
superword of a word in Mℓ
y2 (resp. in Mℓ y1).
Example Let y1 = abaab, y2 = bbaaab and ℓ = 5. y = abaab#bbaaab. We have Mℓ
y1 = {bb,aaa,bab,aaba} and
Mℓ
y2 = {bbb,aaaa,baab,aba,bab,abb}.
The word bab is contained in Mℓ
y1 ∩ Mℓ y2 so it belongs to Mℓ
word aaba ∈ Mℓ
y1 is a superword of aba ∈ Mℓ y2 hence aaba ∈ Mℓ
the other hand, the words bbb, aaaa and abb are superwords of words in Mℓ
y1, hence they belong to Mℓ
- y. The remaining MAWs are not
superwords of MAWs of the other word. Mℓ
y ∩(Mℓ y1 ∪ Mℓ y2) = {aaaa,bab,aaba,abb,bbb}.
- L. Ayad, G. Badkobeh, G. Fici, A. H´
eliou, S. Pissis Constructing Antidictionaries in Output-Sensitive Space