16 recursion 2
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16. Recursion 2 Output: 103 Input: (3 + 5) * 20 Output: 160 Input: - PowerPoint PPT Presentation

Motivation: Calculator Goal: we build a command line calculator Example Input: 3 + 5 Output: 8 Input: 3 / 5 Output: 0.6 Input: 3 + 5 * 20 16. Recursion 2 Output: 103 Input: (3 + 5) * 20 Output: 160 Input: -(3 + 5) + 20 Output: 12 Building a


  1. Motivation: Calculator Goal: we build a command line calculator Example Input: 3 + 5 Output: 8 Input: 3 / 5 Output: 0.6 Input: 3 + 5 * 20 16. Recursion 2 Output: 103 Input: (3 + 5) * 20 Output: 160 Input: -(3 + 5) + 20 Output: 12 Building a Calculator, Streams, Formal Grammars, Extended Backus Naur Form (EBNF), Parsing Expressions binary Operators + , - , * , / and numbers floating point arithmetics precedences and associativities like in C++ parentheses unary operator - 535 536 Naive Attempt (without Parentheses) Analyzing the Problem Example double lval; std::cin >> lval; Input: char op; 13 + 4 ∗ (15 − 7 ∗ 3) = while (std::cin >> op && op != ’=’) { double rval; std::cin >> rval; Needs to be stored such that evaluation can be performed if (op == ’+’) lval += rval; Input 2 + 3 * 3 = else if (op == ’ ∗ ’) Result 15 lval ∗ = rval; “Understanding” expressions requires a lookahead to upcoming else ... symbols! } std::cout << "Ergebnis " << lval << "\n"; 537 538

  2. Preparational Parenthesis: Streams Example: BSD 16-bit Checksum Input: #include <iostream> Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, A program takes inputs from a conceptually sunt in culpa qui officia deserunt mollit anim id est laborum. int main () { infinite input stream. So far: command line input stream std::cin char c; 7 Requires a manual termination of the input at the console int checksum = 0; Output: 67fd while (std::cin >> op && op != ’=’) { ... } while (std::cin >> c) { checksum = checksum / 2 + checksum % 2 ∗ 0x8000 + c; Consume op from std::cin , checksum %= 0x10000; reading position advances. } std::cout << "checksum = " << std::hex << checksum << "\n"; In future we want to be able to read from files. } 7 Ctrl-D(Unix) / Ctrl-Z(Windows) at the beginning of a line that is concluded with ENTER 539 540 Example: BSD 16-bit Checksum with a File Example: BSD 16-bit Checksum #include <iostream> output: 67fd #include <fstream> int main () { std::ifstream fileStream ("loremispum.txt"); char c; Reuse of common functionality? returns false when file end is reached. int checksum = 0; Correct: with a function. But how? while (fileStream >> c) { checksum = checksum / 2 + checksum % 2 ∗ 0x8000 + c; checksum %= 0x10000; } std::cout << "checksum = " << std::hex << checksum << "\n"; } 541 542

  3. Example: BSD 16-bit Checksum Generic! Equal Rights for All! #include <iostream> #include <iostream> input: Lorem Yps with Gimmick #include <fstream> Reference required: we modify the stream. #include <fstream> output: checksums differ int checksum (std::istream& is) int checksum (std::istream& is) { ... } { int main () { char c; int checksum = 0; std::ifstream fileStream("loremipsum.txt"); while (is >> c) { checksum = checksum / 2 + checksum % 2 ∗ 0x8000 + c; if (checksum (fileStream) == checksum (std::cin)) checksum %= 0x10000; std::cout << "checksums match.\n"; else } return checksum; std::cout << "checksums differ.\n"; } } 543 544 Why does that work? Again: Equal Rights for All! #include <iostream> input from stringStream #include <fstream> output: checksums differ #include <sstream> std::cin is a variable of type std::istream . It represents an input stream. int checksum (std::istream& is) { ... } Our variable fileStream is of type std::ifstream . It represents int main () { an input stream on a file. std::ifstream fileStream ("loremipsum.txt"); A std::ifstream is also a std::istream , with more features. std::stringstream stringStream ("Lorem Yps mit Gimmick"); Therefore fileStream can be used wherever a std::istream is if (checksum (fileStream) == checksum (stringStream)) required. std::cout << "checksums match.\n"; else std::cout << "checksums differ.\n"; } 545 546

  4. Back to Expressions Formal Grammars 13 + 4 ∗ (15 − 7 ∗ 3) Alphabet: finite set of symbols Σ Strings: finite sequences of symbols Σ ∗ “Understanding an expression requires lookahead to upcoming symbols! A formal grammar defines which strings are valid. We will store symbols elegantly using recursion. We need a new formal tool (that is independent of C++ ). 547 548 Mountains Forbidden Mountains Alphabet: { / , \ } Alphabet: { / , \ } Mountains M ⊂ { / , \ } ∗ (valid strings) Mountains: M ⊂ { / , \ } ∗ (valid strings) m ′ = //\\///\\\ m ′′′ = /\\//\ / ∈ M /\ /\ /\ /\ / \ \/ Both sides should have the same height. A mountain cannot fall / \/ \ below its starting height. 549 550

  5. Berge in Backus-Naur-Form (BNF) Expressions mountain = " /\ " | " / " mountain " \ " | mountain mountain. Rules -(3-(4-5))*(3+4*5)/6 Possible Mountains alternatives nonterminal 1 /\ What do we need in the BNF? /\/\ Number , ( Expression ) Factor /\/\ / \ - Number, -( Expression ) terminal \ ⇒ / / \ 2 Factor * Factor, Factor Term /\ /\ Factor * Factor / Factor , ... /\/\ /\ / \ /\/\ /\ / \ ⇒ / \ / \/ \ / \/ \/ \ Term + Term, Term Expression 3 Term - Term, ... It is possible to prove that this BNF describes “our” mountains, which is not completely clear a priori. 551 552 The BNF for Expressions The BNF for Expressions A factor is A term is a number, factor, an expression in parentheses or factor * factor, factor / factor, a negated factor. factor * factor * factor, factor / factor * factor, ... factor = unsigned_number ... | "(" expression ")" We need a repetition! | " − " factor. 553 554

  6. EBNF The EBNF for Expressions Extended Backus Naur Form: extends the BNF by factor = unsigned_number option [] und | "(" expression ")" optional repetition {} | " − " factor. term = factor { " ∗ " factor | "/" factor }. = factor { " ∗ " factor | "/" factor }. term Remark: the EBNF is not more powerful than the BNF . But it allows a more expression = term { "+" term | " − " term }. compact representation. The construct from above can be written as follows: term = factor | factor T. T = " ∗ " term | "+" term. 555 556 Parsing Functions (Parser with Evaluation) Expression is read from an input stream. Parsing: Check if a string is valid according to the (E)BNF . // POST: extracts a factor from is // and returns its value Parser: A program for parsing. double factor (std::istream& is); Useful: From the (E)BNF we can (nearly) automatically generate a parser: // POST: extracts a term from is // and returns its value Rules become functions double term (std::istream& is); Alternatives and options become if –statements. Nonterminial symbols on the right hand side become function calls // POST: extracts an expression from is Optional repetitions become while –statements // and returns its value double expression (std::istream& is); 557 558

  7. One Character Lookahead... Cherry-Picking . . . to find the right alternative. . . . to extract the wanted character. // POST: leading whitespace characters are extracted // POST: if ch matches the next lookahead then consume it from is , and the first non − whitespace character // // and return true. return false otherwise // is returned (0 if there is no such character) bool consume (std::istream& is, char ch) char lookahead (std::istream& is) { { if (lookahead(is) == ch){ if ( is .eof()) is >> ch; return 0; return true; is >> std :: ws; // skip whitespaces } if ( is .eof()) return false ; return 0; // end of stream } return is .peek(); // next character in is } 559 560 Evaluating Factors Evaluating Terms double factor (std::istream& is) double term (std::istream& is) { { double v; double value = factor (is); if (consume(is, ’(’)){ while(true){ if (consume(is, ’ ∗ ’)) v = expression (is); consume(is, ’)’); value ∗ = factor (is); } else if (consume(is, ’ − ’)) else if (consume(is, ’/’)) v = − factor (is); value /= factor(is) else else is >> v; return value; factor = "(" expression ")" return v; } | " − " factor term = factor { " ∗ " factor | "/" factor } | unsigned_number. } } 561 562

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