computing cyclic isogenies in genus 2 with applications
play

Computing Cyclic Isogenies in Genus 2 with Applications in - PowerPoint PPT Presentation

Computing Cyclic Isogenies in Genus 2 with Applications in Cryptography Alina Dudeanu 1 Dimitar Jetchev 1 Damien Robert 2 1 EPF Lausanne 2 INRIA Bordeaux May 20, 2014 1/21 Introduction Elliptic and Hyperelliptic Curves Applications: Public key


  1. Computing Cyclic Isogenies in Genus 2 with Applications in Cryptography Alina Dudeanu 1 Dimitar Jetchev 1 Damien Robert 2 1 EPF Lausanne 2 INRIA Bordeaux May 20, 2014 1/21

  2. Introduction Elliptic and Hyperelliptic Curves Applications: Public key cryptosystems (e.g. Diffie-Hellman key exchange protocol, ElGamal). General security assessment: DLP: Given a multiplicative group G = < g > of large order r and h ∈ G , find x such that h = g x . Classical DLP: G = F ∗ p , with p prime. Subexponential attacks. Curve-based security assessment: ECDLP: Given an elliptic curve E (genus 1 ) over some F p , then G = E ( F p ). HECDLP: Given an hyperelliptic curve C of genus g over some F p and its Jacobian Jac ( C ), then G = Jac F p ( C ). Exponential attacks 2/21

  3. Introduction Elliptic and Hyperelliptic Curves Applications: Public key cryptosystems (e.g. Diffie-Hellman key exchange protocol, ElGamal). General security assessment: DLP: Given a multiplicative group G = < g > of large order r and h ∈ G , find x such that h = g x . Classical DLP: G = F ∗ p , with p prime. Subexponential attacks. Curve-based security assessment: ECDLP: Given an elliptic curve E (genus 1 ) over some F p , then G = E ( F p ). HECDLP: Given an hyperelliptic curve C of genus g over some F p and its Jacobian Jac ( C ), then G = Jac F p ( C ). Exponential attacks 2/21

  4. Introduction Elliptic and Hyperelliptic Curves Applications: Public key cryptosystems (e.g. Diffie-Hellman key exchange protocol, ElGamal). General security assessment: DLP: Given a multiplicative group G = < g > of large order r and h ∈ G , find x such that h = g x . Classical DLP: G = F ∗ p , with p prime. Subexponential attacks. Curve-based security assessment: ECDLP: Given an elliptic curve E (genus 1 ) over some F p , then G = E ( F p ). HECDLP: Given an hyperelliptic curve C of genus g over some F p and its Jacobian Jac ( C ), then G = Jac F p ( C ). Exponential attacks 2/21

  5. Genus 1 Curves ECC: F p , where p is a prime of recommended size. an elliptic curve E over F p with given # E ( F p ). Question Is the discrete logarithm problem equally hard on all curves having the same number of points? Answer ”Yes”, with some probability and constraints for the case of ordinary elliptic curves. Theorem (Tate) E 1 , E 2 defined over F p have # E 1 ( F p ) = # E 2 ( F p ) iff there exists an F p -isogeny φ : E 1 → E 2 . An isogeny is a morphism of the form φ : E 1 → E 2 of some degree over F p (rational map, regular at any point on E 1 ) with φ ( O 1 ) = O 2 . 3/21

  6. Genus 1 Curves ECC: F p , where p is a prime of recommended size. an elliptic curve E over F p with given # E ( F p ). Question Is the discrete logarithm problem equally hard on all curves having the same number of points? Answer ”Yes”, with some probability and constraints for the case of ordinary elliptic curves. Theorem (Tate) E 1 , E 2 defined over F p have # E 1 ( F p ) = # E 2 ( F p ) iff there exists an F p -isogeny φ : E 1 → E 2 . An isogeny is a morphism of the form φ : E 1 → E 2 of some degree over F p (rational map, regular at any point on E 1 ) with φ ( O 1 ) = O 2 . 3/21

  7. Genus 1 Curves ECC: F p , where p is a prime of recommended size. an elliptic curve E over F p with given # E ( F p ). Question Is the discrete logarithm problem equally hard on all curves having the same number of points? Answer ”Yes”, with some probability and constraints for the case of ordinary elliptic curves. Theorem (Tate) E 1 , E 2 defined over F p have # E 1 ( F p ) = # E 2 ( F p ) iff there exists an F p -isogeny φ : E 1 → E 2 . An isogeny is a morphism of the form φ : E 1 → E 2 of some degree over F p (rational map, regular at any point on E 1 ) with φ ( O 1 ) = O 2 . 3/21

  8. Genus 1 Curves ECC: F p , where p is a prime of recommended size. an elliptic curve E over F p with given # E ( F p ). Question Is the discrete logarithm problem equally hard on all curves having the same number of points? Answer ”Yes”, with some probability and constraints for the case of ordinary elliptic curves. Theorem (Tate) E 1 , E 2 defined over F p have # E 1 ( F p ) = # E 2 ( F p ) iff there exists an F p -isogeny φ : E 1 → E 2 . An isogeny is a morphism of the form φ : E 1 → E 2 of some degree over F p (rational map, regular at any point on E 1 ) with φ ( O 1 ) = O 2 . 3/21

  9. Isogeny Graph # E ( F p ) = 1 + p − t where t is the trace of Frobenius π End( E ) - order in K = Q ( √− d t ), with c 2 t d t = t 2 − 4 p . O K ⊇ End( E ) ⊇ Z [ π ] 4/21

  10. Isogeny Graph # E ( F p ) = 1 + p − t where t is the trace of Frobenius π End( E ) - order in K = Q ( √− d t ), with c 2 t d t = t 2 − 4 p . O K ⊇ End( E ) ⊇ Z [ π ] 4/21

  11. Isogeny Graph # E ( F p ) = 1 + p − t where t is the trace of Frobenius π End( E ) - order in K = Q ( √− d t ), with c 2 t d t = t 2 − 4 p . O K ⊇ End( E ) ⊇ Z [ π ] 4/21

  12. Isogeny Graph # E ( F p ) = 1 + p − t where t is the trace of Frobenius π End( E ) - order in K = Q ( √− d t ), with c 2 t d t = t 2 − 4 p . O K ⊇ End( E ) ⊇ Z [ π ] 4/21

  13. Genus 2 Curves Why? Similar cost when doing arithmetic, smaller fields by a factor 2. Jacobians of curves over F p that have the same characteristic polynomial of Frobenius = an F p -isogeny class. Jacobians are principally polarised abelian varieties (together with embeddings in P N ). An isogeny links both the varieties and their polarizations. A principal polarization is crucial in recovering a curve equation from an abelian variety that is a Jacobian. Same Question Is the DL equally hard on isomorphic classes of Jacobians in the same isogeny graph? 5/21

  14. Genus 2 Curves Why? Similar cost when doing arithmetic, smaller fields by a factor 2. Jacobians of curves over F p that have the same characteristic polynomial of Frobenius = an F p -isogeny class. Jacobians are principally polarised abelian varieties (together with embeddings in P N ). An isogeny links both the varieties and their polarizations. A principal polarization is crucial in recovering a curve equation from an abelian variety that is a Jacobian. Same Question Is the DL equally hard on isomorphic classes of Jacobians in the same isogeny graph? 5/21

  15. Genus 2 Curves Why? Similar cost when doing arithmetic, smaller fields by a factor 2. Jacobians of curves over F p that have the same characteristic polynomial of Frobenius = an F p -isogeny class. Jacobians are principally polarised abelian varieties (together with embeddings in P N ). An isogeny links both the varieties and their polarizations. A principal polarization is crucial in recovering a curve equation from an abelian variety that is a Jacobian. Same Question Is the DL equally hard on isomorphic classes of Jacobians in the same isogeny graph? 5/21

  16. Genus 2 Curves Why? Similar cost when doing arithmetic, smaller fields by a factor 2. Jacobians of curves over F p that have the same characteristic polynomial of Frobenius = an F p -isogeny class. Jacobians are principally polarised abelian varieties (together with embeddings in P N ). An isogeny links both the varieties and their polarizations. A principal polarization is crucial in recovering a curve equation from an abelian variety that is a Jacobian. Same Question Is the DL equally hard on isomorphic classes of Jacobians in the same isogeny graph? 5/21

  17. Genus 2 Curves Why? Similar cost when doing arithmetic, smaller fields by a factor 2. Jacobians of curves over F p that have the same characteristic polynomial of Frobenius = an F p -isogeny class. Jacobians are principally polarised abelian varieties (together with embeddings in P N ). An isogeny links both the varieties and their polarizations. A principal polarization is crucial in recovering a curve equation from an abelian variety that is a Jacobian. Same Question Is the DL equally hard on isomorphic classes of Jacobians in the same isogeny graph? 5/21

  18. Isogeny Graphs of Principally Polarized Abelian Surfaces Computing isogenies from kernel in genus 2 is a lot harder: Canonical coordinates Polarizations: prime degree isogenies do not preserve principal polarisations. Deciding isomorphisms: deciding if two non-polarized abelian surfaces are isomorphic is a computationally hard problem. Class field theory: endomorphism rings are orders in quartic number fields. Main idea: use the theory of theta functions and the CM description of principally polarised abelian varieties 6/21

  19. Isogeny Graphs of Principally Polarized Abelian Surfaces Computing isogenies from kernel in genus 2 is a lot harder: Canonical coordinates Polarizations: prime degree isogenies do not preserve principal polarisations. Deciding isomorphisms: deciding if two non-polarized abelian surfaces are isomorphic is a computationally hard problem. Class field theory: endomorphism rings are orders in quartic number fields. Main idea: use the theory of theta functions and the CM description of principally polarised abelian varieties 6/21

  20. Isogeny Graphs of Principally Polarized Abelian Surfaces Computing isogenies from kernel in genus 2 is a lot harder: Canonical coordinates Polarizations: prime degree isogenies do not preserve principal polarisations. Deciding isomorphisms: deciding if two non-polarized abelian surfaces are isomorphic is a computationally hard problem. Class field theory: endomorphism rings are orders in quartic number fields. Main idea: use the theory of theta functions and the CM description of principally polarised abelian varieties 6/21

Download Presentation
Download Policy: The content available on the website is offered to you 'AS IS' for your personal information and use only. It cannot be commercialized, licensed, or distributed on other websites without prior consent from the author. To download a presentation, simply click this link. If you encounter any difficulties during the download process, it's possible that the publisher has removed the file from their server.

Recommend


More recommend