Colouring graphs excluding fixed subgraphs joint work with S. - - PowerPoint PPT Presentation

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Colouring graphs excluding fixed subgraphs joint work with S. - - PowerPoint PPT Presentation

Colouring graphs excluding fixed subgraphs joint work with S. Thomass, M. Bonamy Problem Very General Question : What does having large chromatic number say about a graph? Problem Very General Question : What does having large chromatic


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Colouring graphs excluding fixed subgraphs

joint work with S. Thomassé, M. Bonamy

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Problem

Very General Question : What does having large chromatic number say about a graph?

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Problem

Very General Question : What does having large chromatic number say about a graph? What does it say in terms of the substructures it must contain?

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Problem

Very General Question : What does having large chromatic number say about a graph? What does it say in terms of the substructures it must contain?

◮ First case : maybe it contains a big clique as a subgraph.

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Problem

Very General Question : What does having large chromatic number say about a graph? What does it say in terms of the substructures it must contain?

◮ First case : maybe it contains a big clique as a subgraph. ◮ Is it the only case?

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Problem

Very General Question : What does having large chromatic number say about a graph? What does it say in terms of the substructures it must contain?

◮ First case : maybe it contains a big clique as a subgraph. ◮ Is it the only case? ◮ Of course not. There even exists triangle-free families of

arbitrirary large χ (Mycielski, Tutte, Zykov...)

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Problem

Very General Question : What does having large chromatic number say about a graph? What does it say in terms of the substructures it must contain?

◮ First case : maybe it contains a big clique as a subgraph. ◮ Is it the only case? ◮ Of course not. There even exists triangle-free families of

arbitrirary large χ (Mycielski, Tutte, Zykov...)

◮ Even more : For every k, there exists graphs with arbitrarily

large girth (size of a min cycle) and arbitrarily large χ. (Erdős).

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Problem

Very General Question : What does having large chromatic number say about a graph? What does it say in terms of the substructures it must contain?

◮ First case : maybe it contains a big clique as a subgraph. ◮ Is it the only case? ◮ Of course not. There even exists triangle-free families of

arbitrirary large χ (Mycielski, Tutte, Zykov...)

◮ Even more : For every k, there exists graphs with arbitrarily

large girth (size of a min cycle) and arbitrarily large χ. (Erdős).

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Formalization

◮ A class C of graphs is said to be chi-bounded if

∃fC : N → N, such that ∀G ∈ C, χ(G) fC(ω(G))

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Formalization

◮ A class C of graphs is said to be chi-bounded if

∃fC : N → N, such that ∀G ∈ C, χ(G) fC(ω(G))

◮ If the class is hereditary it is defined by a family of forbidden

subgraphs F, we say that such a F is chi-bounding if the class is chi-bounded.

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Formalization

◮ A class C of graphs is said to be chi-bounded if

∃fC : N → N, such that ∀G ∈ C, χ(G) fC(ω(G))

◮ If the class is hereditary it is defined by a family of forbidden

subgraphs F, we say that such a F is chi-bounding if the class is chi-bounded. Now our question is : what families F are chi-bounding?

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F of size 1

What if F contains a single graph F?

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F of size 1

What if F contains a single graph F?

◮ Then F must be a forest.

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F of size 1

What if F contains a single graph F?

◮ Then F must be a forest.

Proof : If F contains at least one cycle, use Erdos’s result : there exists graph with arbitrarily large χ who do not contain any cycle of length less than |F|, which are hence F-free

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F of size 1

What if F contains a single graph F?

◮ Then F must be a forest.

Proof : If F contains at least one cycle, use Erdos’s result : there exists graph with arbitrarily large χ who do not contain any cycle of length less than |F|, which are hence F-free

◮ Is it sufficient??

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F of size 1

What if F contains a single graph F?

◮ Then F must be a forest.

Proof : If F contains at least one cycle, use Erdos’s result : there exists graph with arbitrarily large χ who do not contain any cycle of length less than |F|, which are hence F-free

◮ Is it sufficient??

Conjecture (Gyarfas–Sumner)

If F is a forest, the class of graphs excluding F as an induced subgraph is chi-bounded.

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F = T tree

Little is really known :

◮ true for K1,n (by Ramsey)

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F = T tree

Little is really known :

◮ true for K1,n (by Ramsey) ◮ true for paths (Gyarfas)

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F = T tree

Little is really known :

◮ true for K1,n (by Ramsey) ◮ true for paths (Gyarfas) ◮ true for trees of radius 2 (Kierstead and Penrice)

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F = T tree

Little is really known :

◮ true for K1,n (by Ramsey) ◮ true for paths (Gyarfas) ◮ true for trees of radius 2 (Kierstead and Penrice)

Scott proved the following very nice ”topological” version of the conjecture

◮ For every tree T, the class of graphs excluding all subdivisions

  • f T is chi-bounded.
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Larger families F

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Larger families F

Same as before, Erdos says that if F is finite, then F must contain a forest to be chi-bouding.

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Larger families F

Same as before, Erdos says that if F is finite, then F must contain a forest to be chi-bouding. What about excluding infinite families that do not contain a forest?

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Larger families F

Same as before, Erdos says that if F is finite, then F must contain a forest to be chi-bouding. What about excluding infinite families that do not contain a forest? What about excluding families of cycles?

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Larger families F

Same as before, Erdos says that if F is finite, then F must contain a forest to be chi-bouding. What about excluding infinite families that do not contain a forest? What about excluding families of cycles?

◮ excluding all cycles : trees

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Larger families F

Same as before, Erdos says that if F is finite, then F must contain a forest to be chi-bouding. What about excluding infinite families that do not contain a forest? What about excluding families of cycles?

◮ excluding all cycles : trees ◮ excluding all cycles of length at least 4 : chordal graphs are

perfect

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Larger families F

Same as before, Erdos says that if F is finite, then F must contain a forest to be chi-bouding. What about excluding infinite families that do not contain a forest? What about excluding families of cycles?

◮ excluding all cycles : trees ◮ excluding all cycles of length at least 4 : chordal graphs are

perfect

◮ excluding all cycles of length at least k

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Larger families F

Same as before, Erdos says that if F is finite, then F must contain a forest to be chi-bouding. What about excluding infinite families that do not contain a forest? What about excluding families of cycles?

◮ excluding all cycles : trees ◮ excluding all cycles of length at least 4 : chordal graphs are

perfect

◮ excluding all cycles of length at least k

Open conjecture of Gyarfas.

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Larger families F

Same as before, Erdos says that if F is finite, then F must contain a forest to be chi-bouding. What about excluding infinite families that do not contain a forest? What about excluding families of cycles?

◮ excluding all cycles : trees ◮ excluding all cycles of length at least 4 : chordal graphs are

perfect

◮ excluding all cycles of length at least k

Open conjecture of Gyarfas.

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Families of cycles

Gyarfas made in fact three conjectures about cycles.

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Families of cycles

Gyarfas made in fact three conjectures about cycles.

Conjecture (Gyarfas,’87)

◮ The set of all cycles of length at least k is chi-bounding ◮ The set of odd cycles is chi-bounding. ◮ The set of all odd cycles of length at least k is chi-bounding

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Families of cycles

Gyarfas made in fact three conjectures about cycles.

Conjecture (Gyarfas,’87)

◮ The set of all cycles of length at least k is chi-bounding ◮ The set of odd cycles is chi-bounding. ◮ The set of all odd cycles of length at least k is chi-bounding

The second conjecture was proven very recently by Seymour and Scott.

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Families of cycles

Gyarfas made in fact three conjectures about cycles.

Conjecture (Gyarfas,’87)

◮ The set of all cycles of length at least k is chi-bounding ◮ The set of odd cycles is chi-bounding. ◮ The set of all odd cycles of length at least k is chi-bounding

The second conjecture was proven very recently by Seymour and Scott.

◮ Graphs that do not contain any odd hole nor any complement

  • f odd hole : Berge graphs.
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Families of cycles

Gyarfas made in fact three conjectures about cycles.

Conjecture (Gyarfas,’87)

◮ The set of all cycles of length at least k is chi-bounding ◮ The set of odd cycles is chi-bounding. ◮ The set of all odd cycles of length at least k is chi-bounding

The second conjecture was proven very recently by Seymour and Scott.

◮ Graphs that do not contain any odd hole nor any complement

  • f odd hole : Berge graphs.

Strong Perfect Graph Theorem : χ = ω.

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Families of cycles

Gyarfas made in fact three conjectures about cycles.

Conjecture (Gyarfas,’87)

◮ The set of all cycles of length at least k is chi-bounding ◮ The set of odd cycles is chi-bounding. ◮ The set of all odd cycles of length at least k is chi-bounding

The second conjecture was proven very recently by Seymour and Scott.

◮ Graphs that do not contain any odd hole nor any complement

  • f odd hole : Berge graphs.

Strong Perfect Graph Theorem : χ = ω.

◮ No simple proof of any (even much worse) other chi-bounding

function.

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F is an family of cycles.

Could the following conjecture be also true?

Conjecture

Every infinite family of cycles is chi-bounding.

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F is an family of cycles.

Could the following conjecture be also true?

Conjecture

Every infinite family of cycles is chi-bounding. NO

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F is an family of cycles.

Could the following conjecture be also true?

Conjecture

Every infinite family of cycles is chi-bounding. NO Using Erdős Theorem construct a sequence Fi such that

◮ χ(Fi) i ◮ girth(Fi) > |2Fi−1|.

Let F be the set of cycles that do not occur in any Fi. Then F is NOT chi-bounding and is infinite (it contains at least all the |Fi|). Even more it has upper density 1 since it contains every interval [|Fi|, 2|Fi|].

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Conjecture (Scott-Seymour,2014)

If I ⊂ N has bounded gaps ( ∃k s.t. every k consecutive integers contains an element of F), then {Ci, i ∈ I} is k-bounding.

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Our result

Theorem (Bonamy,C.,Thomassé)

Every graph with sufficiently large chromatic number must contain a cycle of length 0 mod 3.

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Our result

Theorem (Bonamy,C.,Thomassé)

Every graph with sufficiently large chromatic number must contain a cycle of length 0 mod 3.

◮ Our proof gives an horrible bound (we don’t even try to

calculate it)

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Our result

Theorem (Bonamy,C.,Thomassé)

Every graph with sufficiently large chromatic number must contain a cycle of length 0 mod 3.

◮ Our proof gives an horrible bound (we don’t even try to

calculate it)

◮ The actual bound could be 4 (3?)

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Our result

Theorem (Bonamy,C.,Thomassé)

Every graph with sufficiently large chromatic number must contain a cycle of length 0 mod 3.

◮ Our proof gives an horrible bound (we don’t even try to

calculate it)

◮ The actual bound could be 4 (3?)

Chudnovsky et al recently proved that χ > 4 implies the existence of a 3k cycle as a (not necessarily induced) subgraph.

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Our result

Theorem (Bonamy,C.,Thomassé)

Every graph with sufficiently large chromatic number must contain a cycle of length 0 mod 3.

◮ Our proof gives an horrible bound (we don’t even try to

calculate it)

◮ The actual bound could be 4 (3?)

Chudnovsky et al recently proved that χ > 4 implies the existence of a 3k cycle as a (not necessarily induced) subgraph.

◮ The question originally came as a sub case of a more general

question of Kalai and Meschulam.

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Our result - a few ideas.

Every graph with no induced C3k (trinity graphs) has bounded χ.

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Our result - a few ideas.

Every graph with no induced C3k (trinity graphs) has bounded χ.

◮ Use distance layers.

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Our result - a few ideas.

Every graph with no induced C3k (trinity graphs) has bounded χ.

◮ Use distance layers. ◮ Gyarfas idea

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Our result - a few ideas.

Every graph with no induced C3k (trinity graphs) has bounded χ.

◮ Use distance layers. ◮ Gyarfas idea ◮ Trinity changing paths : try to find vertices x and y such that

many independent paths exist between the two.

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Our result - a few ideas.

Every graph with no 3k induced cycle has bounded χ.

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Our result - a few ideas.

Every graph with no 3k induced cycle has bounded χ.

◮ Exclude C5. Prove the result

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Our result - a few ideas.

Every graph with no 3k induced cycle has bounded χ.

◮ Exclude C5. Prove the result ◮ If C5 is present and χ large, this also must be present.

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Our result - a few ideas.

Every graph with no 3k induced cycle has bounded χ.

◮ Exclude C5. Prove the result ◮ If C5 is present and χ large, this also must be present. ◮ If this is present and χ large, this other must be present

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Our result - a few ideas.

Every graph with no 3k induced cycle has bounded χ.

◮ Exclude C5. Prove the result ◮ If C5 is present and χ large, this also must be present. ◮ If this is present and χ large, this other must be present ◮ If this other is present prove it.

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Next

◮ {C3k, k > 1} is chi-bounding ◮ {C4k} is chi-bounding