Cluster algebras, snake graphs and continued fractions Ralf - - PowerPoint PPT Presentation

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Cluster algebras, snake graphs and continued fractions Ralf - - PowerPoint PPT Presentation

Cluster algebras, snake graphs and continued fractions Ralf Schiffler Intro Cluster algebras Continued fractions Snake graphs Intro Cluster algebras Continued fractions expansion


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SLIDE 1

Cluster algebras, snake graphs and continued fractions

Ralf Schiffler

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SLIDE 2

Intro

Cluster algebras Continued fractions Snake graphs

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SLIDE 3

Intro

Cluster algebras

  • expansion formula via

perfect matchings [Musiker-S-Williams 11]

■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■

Continued fractions Snake graphs

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SLIDE 4

Intro

Cluster algebras

  • expansion formula via

perfect matchings [Musiker-S-Williams 11]

■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■

Continued fractions Snake graphs

  • bijection via

perfect matchings [C ¸anak¸ cı-S 16]

  • s

s s s s s s s s s s s s s s s s s s s

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SLIDE 5

Intro

Cluster algebras

expansion formula as continued fractions, asymptotic behavior [C ¸anak¸ cı-S 16]

  • expansion formula via

perfect matchings [Musiker-S-Williams 11]

■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■

Continued fractions Snake graphs

  • bijection via

perfect matchings [C ¸anak¸ cı-S 16]

  • s

s s s s s s s s s s s s s s s s s s s

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SLIDE 6

Intro

Cluster algebras

expansion formula as continued fractions, asymptotic behavior [C ¸anak¸ cı-S 16]

  • expansion formula via

perfect matchings [Musiker-S-Williams 11]

■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■

Continued fractions Snake graphs

  • bijection via

perfect matchings [C ¸anak¸ cı-S 16]

  • s

s s s s s s s s s s s s s s s s s s s

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SLIDE 7

Intro

Cluster algebras

expansion formula as continued fractions [C ¸anak¸ cı-S 16]

  • expansion formula via

perfect matchings [Musiker-S-Williams 11]

■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■ ■

Continued fractions Snake graphs

  • Combinatorial realization
  • f continued fractions

Applications in elementary Number Theory

  • s

s s s s s s s s s s s s s s s s s s s

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SLIDE 8

Continued Fractions

84 37 = 2 + 10 37

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SLIDE 9

Continued Fractions

84 37 = 2 + 10 37 = 2 + 1

37 10

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SLIDE 10

Continued Fractions

84 37 = 2 + 10 37 = 2 + 1

37 10

= 2 + 1 3 + 7 10

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SLIDE 11

Continued Fractions

84 37 = 2 + 10 37 = 2 + 1

37 10

= 2 + 1 3 + 7 10 = 2 + 1 3 + 1

10 7

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SLIDE 12

Continued Fractions

84 37 = 2 + 10 37 = 2 + 1

37 10

= 2 + 1 3 + 7 10 = 2 + 1 3 + 1

10 7

= 2 + 1 3 + 1 1 + 3 7

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SLIDE 13

Continued Fractions

84 37 = 2 + 10 37 = 2 + 1

37 10

= 2 + 1 3 + 7 10 = 2 + 1 3 + 1

10 7

= 2 + 1 3 + 1 1 + 3 7 = 2 + 1 3 + 1 1 + 1 2 + 1 3

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SLIDE 14

Continued Fractions

84 37 = 2 + 10 37 = 2 + 1

37 10

= 2 + 1 3 + 7 10 = 2 + 1 3 + 1

10 7

= 2 + 1 3 + 1 1 + 3 7 = 2 + 1 3 + 1 1 + 1 2 + 1 3 =: [2, 3, 1, 2, 3]

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SLIDE 15

Continued Fractions

84 37 = [2, 3, 1, 2, 3]

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SLIDE 16

Continued Fractions - Euclidean algorithm

84 = 2 · 37 + 10 37 = 3 · 10 + 7 10 = 1 · 7 + 3 7 = 2 · 3 + 1 3 = 3 · 1

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SLIDE 17

Continued Fractions - Euclidean algorithm

84 = 2 · 37 + 10 37 = 3 · 10 + 7 10 = 1 · 7 + 3 7 = 2 · 3 + 1 3 = 3 · 1 84 37 = [2, 3, 1, 2, 3]

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SLIDE 18

Continued Fractions

The division algorithm gives a bijection between Q and the set of continued fractions whose last coefficient is at least 2. Q → {[a0, . . . , an] | a0 ∈ Z, a1, . . . an−1 ≥ 1, an ≥ 2}

note that [a0, . . . , an−1, 1] = [a0, . . . , an−1 + 1], because an−1 + 1 1 = an−1 + 1.

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SLIDE 19

Snake graphs

A snake graph G is a connected planar graph consisting of a finite sequence of tiles G1, G2, . . . , Gd such that

◮ Gi and Gi+1 share exactly one edge ei and this edge is

◮ either the north edge of Gi and the south edge of Gi+1, ◮ or the east edge of Gi and the west edge of Gi+1.

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SLIDE 20

Snake graphs

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SLIDE 21

Snake graphs

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SLIDE 22

Snake graphs

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SLIDE 23

Snake graphs

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SLIDE 24

Snake graphs

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SLIDE 25

Snake graphs

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SLIDE 26

Snake graphs

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SLIDE 27

Snake graphs

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SLIDE 28

Snake graphs

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SLIDE 29

Snake graphs

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SLIDE 30

Sign function

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SLIDE 31

Sign function - constant on diagonals

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SLIDE 32

Sign function - constant on diagonals

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SLIDE 33

Sign function - constant on diagonals

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SLIDE 34

Sign function - constant on diagonals

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SLIDE 35

Sign function

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SLIDE 36

Sign function – sign sequence – continued fraction

−, −, +, +, +, −, +, +, −, −, − [2, 3, 1, 2, 3]

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SLIDE 37

Theorem

← → [2, 3, 1, 2, 3] = 84

37

84 perfect matchings

There is a bijection between snake graphs and continued fractions 1 G[a1, a2, . . . , an] ← → [a1, a2, . . . , an] Moreover, if m(G) denotes the number of perfect matchings of G then [a1, a2, . . . , an] = m(G[a1, a2, . . . , an]) m(G[a2, . . . , an]) .

1with ai ≥ 1, an ≥ 2

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SLIDE 38

Theorem

← → [2, 3, 1, 2, 3] = 84

37

37 perfect matchings

There is a bijection between snake graphs and continued fractions 2 G[a1, a2, . . . , an] ← → [a1, a2, . . . , an] Moreover, if m(G) denotes the number of perfect matchings of G then [a1, a2, . . . , an] = m(G[a1, a2, . . . , an]) m(G[a2, . . . , an]) .

2with ai ≥ 1, an ≥ 2

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SLIDE 39

Reflection

flip

[2, 3, 1, 2, 3]

[1, 1, 3, 1, 2, 3]

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SLIDE 40

Perfect matchings

A perfect matching P of a graph G is a subset of the set of edges of G such that each vertex of G is incident to exactly one edge in P.

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SLIDE 41

Perfect matchings

A perfect matching P of a graph G is a subset of the set of edges of G such that each vertex of G is incident to exactly one edge in P.

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SLIDE 42

Perfect matchings

A perfect matching P of a graph G is a subset of the set of edges of G such that each vertex of G is incident to exactly one edge in P.

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SLIDE 43

Perfect matchings

A perfect matching P of a graph G is a subset of the set of edges of G such that each vertex of G is incident to exactly one edge in P.

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SLIDE 44

Perfect matchings

A perfect matching P of a graph G is a subset of the set of edges of G such that each vertex of G is incident to exactly one edge in P.

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SLIDE 45

Tiles with sign changes

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SLIDE 46

Tiles with sign changes removed

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SLIDE 47

Tiles with sign changes removed

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SLIDE 48

Tiles with sign changes removed

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SLIDE 49

Tiles with sign changes removed

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SLIDE 50

Subgraphs Hi ∼ = G[ai]

H1 H2 H3 H4 H5

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SLIDE 51

Division algorithm

2 3 4 7 10 17 27 37 47 84 2 2 3 4 7 10 17 27 37 2 3 4 7 10 2 3 4 7 10 17 27 37 2 3 2 3 4 7 10 2 3 4 7 2 3 4 7 10 2 3 4 7 1 2 3 2 3 4 7 2 3 2 1 H1 H2 H3 H4

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SLIDE 52

Division algorithm – Proof

2 3 4 7 10 17 27 37 47 84 2 2 3 4 7 10 17 27 37 2 3 4 7 10 2 3 4 7 10 17 27 37 2 3 2 3 4 7 10 2 3 4 7 2 3 4 7 10 2 3 4 7 1 2 3 2 3 4 7 2 3 2 1 H1 H2 H3 H4

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SLIDE 53

Division algorithm – Proof

2 3 4 7 10 17 27 37 47 84 2 2 3 4 7 10 17 27 37 2 3 4 7 10 2 3 4 7 10 17 27 37 2 3 2 3 4 7 10 2 3 4 7 2 3 4 7 10 2 3 4 7 1 2 3 2 3 4 7 2 3 2 1 H1 H2 H3 H4

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SLIDE 54

Division algorithm – Proof

2 3 4 7 10 17 27 37 47 84 2 2 3 4 7 10 17 27 37 2 3 4 7 10 2 3 4 7 10 17 27 37 2 3 2 3 4 7 10 2 3 4 7 2 3 4 7 10 2 3 4 7 1 2 3 2 3 4 7 2 3 2 1 H1 H2 H3 H4

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SLIDE 55

Division algorithm – Proof

2 3 4 7 10 17 27 37 47 84 2 2 3 4 7 10 17 27 37 2 3 4 7 10 2 3 4 7 10 17 27 37 2 3 2 3 4 7 10 2 3 4 7 2 3 4 7 10 2 3 4 7 1 2 3 2 3 4 7 2 3 2 1 H1 H2 H3 H4

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SLIDE 56

Division algorithm – Proof

2 3 4 7 10 17 27 37 47 84 2 2 3 4 7 10 17 27 37 2 3 4 7 10 2 3 4 7 10 17 27 37 2 3 2 3 4 7 10 2 3 4 7 2 3 4 7 10 2 3 4 7 1 2 3 2 3 4 7 2 3 2 1 H1 H2 H3 H4

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SLIDE 57

Division algorithm – Proof

2 3 4 7 10 17 27 37 47 84 2 2 3 4 7 10 17 27 37 2 3 4 7 10 2 3 4 7 10 17 27 37 2 3 2 3 4 7 10 2 3 4 7 2 3 4 7 10 2 3 4 7 1 2 3 2 3 4 7 2 3 2 1 H1 H2 H3 H4

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SLIDE 58

Division algorithm – Proof

2 3 4 7 10 17 27 37 47 84 2 2 3 4 7 10 17 27 37 2 3 4 7 10 2 3 4 7 10 17 27 37 2 3 2 3 4 7 10 2 3 4 7 2 3 4 7 10 2 3 4 7 1 2 3 2 3 4 7 2 3 2 1 H1 H2 H3 H4

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SLIDE 59

Division algorithm – Proof

2 3 4 7 10 17 27 37 47 84 2 2 3 4 7 10 17 27 37 2 3 4 7 10 2 3 4 7 10 17 27 37 2 3 2 3 4 7 10 2 3 4 7 2 3 4 7 10 2 3 4 7 1 2 3 2 3 4 7 2 3 2 1 H1 H2 H3 H4

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SLIDE 60

Division algorithm – Proof

2 3 4 7 10 17 27 37 47 84 2 2 3 4 7 10 17 27 37 2 3 4 7 10 2 3 4 7 10 17 27 37 2 3 2 3 4 7 10 2 3 4 7 2 3 4 7 10 2 3 4 7 1 2 3 2 3 4 7 2 3 2 1 H1 H2 H3 H4

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SLIDE 61

Division algorithm – Proof

2 3 4 7 10 17 27 37 47 84 2 2 3 4 7 10 17 27 37 2 3 4 7 10 2 3 4 7 10 17 27 37 2 3 2 3 4 7 10 2 3 4 7 2 3 4 7 10 2 3 4 7 1 2 3 2 3 4 7 2 3 2 1 H1 H2 H3 H4

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SLIDE 62

Expansion formula for cluster variables

Theorem (Musiker-S.-Williams)

If γ is an arc in a triangulated surface (S, M), the cluster variable xγ is given by the formula xγ = 1 cross(Gγ)

  • P∈Match Gγ

x(P).

1 3 2 γ a b c d e f x2 x3 x1 1 2 1 2 1 2

1 2

1 1 2 2 3 a b d c Gγ

xγ = x1+x2+x3

x1x2

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SLIDE 63

Example 2

2 1 b a γ 2 b 1 2 a 1 2 1 2 2 1 b a 1 1 2 1 1 2 1 1 2 1 1 2 1 1 2

1 1 1 1 2

x4

2

x2

2

x2

2

1 x2

1

xγ = x2

1 +1+2x2 2 +x4 2

x2

1 x2

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SLIDE 64

Example 3

Torus with 1 puncture [2, 2, 2, 2, 2, 2, 2, 2] = 985 408

2 1 1 2 3

3 3 3 3 3 3 3 3 2 2 2 2 1 1 1

The Laurent polynomial of this cluster variable has 985 terms.

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SLIDE 65

Expansion formula as continued fraction

Theorem (C ¸anak¸ cı-S)

The cluster variable xγ of the arc γ is the numerator of the continued fraction [L1, L2, . . . , Ln], where Li is a Laurent polynomial explicitly given3 by the subgraph Hi.

3[C

¸anak¸ cı-Felikson]

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SLIDE 66

Example 3

Torus with 1 puncture [2, 2, 2, 2, 2, 2, 2, 2] = 985 408

2 1 1 2 3

3 3 3 3 3 3 3 3 2 2 2 2 1 1 1

[a1, . . . , a8] = [2, 2, 2, 2, 2, 2, 2, 2], let x′

3 = x2

1 +x2 2

x3

, then L1 = x′

3

1 x2 , L2 = x′

3

x2 x2

1

, L3 = x′

3

x2

1

x3

2

, . . . , L8 = x′

3

x7

2

x8

1

xγ = numerator of [L1, L2, . . . , Ln]

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SLIDE 67

Example 3, computation dispiace Salvatore, ho usato Mathematica

 +   * /  +   *   +   *   +   *   +   *   +   *   +   *   +   *  

 +  +  +  +  +

 + +  +  + + +  +  + + +  +  + + +  +  + + +  +  + + + +     +   +  +  +  +  +  + +  +  + +  +  + + + 

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SLIDE 68

What about the denominator?

Torus with 1 puncture [2, 2, 2, 2, 2, 2, 2, 2] = 985 408

2 1 1 2 3

3 3 3 3 3 3 3 3 2 2 2 2 1 1 1

xγ = numerator of [L1, L2, . . . , Ln]

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SLIDE 69

What about the denominator?

Torus with 1 puncture

2 1 1 2 3

3 3 3 3 3 3 3 2 2 2 1 1 1

xγ′ = denominator of [L1, L2, . . . , Ln] = numerator of [L2, . . . , Ln]

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SLIDE 70

Asymptotic behavior of quotients

lim

n→∞

xγ xγ′ = x′

1 − x1 +

  • (x′

1 − x1)2 + 4x′2 3

2x′

3

.

where x′

3 = (x2 1 + x2 2)/x3

x′

1 = (x2 2 + x′2 3 )/x1

are obtained from the initial cluster by mutation in 3 and then 1.

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SLIDE 71

Applications to elementary Number Theory

◮ (skein) relations in the cluster algebras were expressed in

terms of snake graphs [C ¸anak¸ cı-S.] (snake graph calculus).

◮ This provides a long list of relations in terms of snake graphs. ◮ Translating into the language of continued fractions gives a

long list of relations there.

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SLIDE 72

Equations for continued fractions

Theorem

We have the following identities of numerators of continued fractions, where we set N[a1, . . . , a0] = 1, and N[an+1, . . . , an] = 1. (a) For every i = 1, 2, . . . , n, N[a1, . . . , an] = N[a1, . . . , ai] N[ai+1, . . . , an] + N[a1, . . . , ai−1] N[ai+2, . . . , an]. (b) For every j ≥ 0 and i such that 1 ≤ i + j ≤ n − 1, N[a1, . . . , ai+j] N[ai, . . . , an] = N[a1, . . . , an] N[ai, . . . , ai+j] + (−1)j N[a1, . . . , ai−2] N[ai+j+2, . . . , an].

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SLIDE 73

Equations for continued fractions

(c) For continued fractions [a1, . . . , an] and [b1, . . . , bm] such that

[ai, . . . , ai+k] = [bj, . . . , bj+k] for certain i, j, k, we have N[a1, . . . , an] N[b1, . . . , bm] = N[a1, . . . , ai−

1, bj, . . . , bm] N[b1, . . . , bj− 1, ai, . . . , an]

+(−1)k N[a1, . . . , ai−2−1, 1, bj−

1 − ai− 1−1, bj− 2, . . . , b1] N ′

where N ′ =            N[bm, . . . , bj+

k+ 2−1, 1, ai+ k+ 1 − bj+ k+ 1−1, ai+ k+ 2, . . . , an]

if ai+

k+1 > bj+ k+1;

N[bm, . . . , bj+

k+ 2, bj+ k+ 1− ai+ k+ 1−1, 1, ai+ k+ 2−1, , . . . , an]

if ai+

k+1 < bj+ k+1.

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SLIDE 74

180◦ Rotation

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SLIDE 75

180◦ Rotation

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SLIDE 76

180◦ Rotation

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SLIDE 77

180◦ Rotation

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SLIDE 78

180◦ Rotation

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SLIDE 79

180◦ Rotation

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SLIDE 80

180◦ Rotation

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SLIDE 81

180◦ Rotation

rotation

  • [2, 3, 1, 2, 3]

reverse

[3, 2, 1, 3, 2]

Theorem

The numerators of the continued fractions [a1, a2, . . . , an] and [an, . . . , a2, a1] are equal.

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SLIDE 82

Palindromic snake graphs

A continued fraction [a1, . . . , an] is called

◮ even if n is even;

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SLIDE 83

Palindromic snake graphs

A continued fraction [a1, . . . , an] is called

◮ even if n is even; ◮ palindromic if ai = an−i for all i.

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SLIDE 84

Palindromic snake graphs

A continued fraction [a1, . . . , an] is called

◮ even if n is even; ◮ palindromic if ai = an−i for all i.

. A snake graph is called

◮ palindromic if it is the snake graph of an even palindromic

continued fraction;

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SLIDE 85

Palindromic snake graphs

A continued fraction [a1, . . . , an] is called

◮ even if n is even; ◮ palindromic if ai = an−i for all i.

. A snake graph is called

◮ palindromic if it is the snake graph of an even palindromic

continued fraction;

◮ rotationally symmetric at a center tile if the rotation about

180◦ at the center of the central tile is an automorphism.

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SLIDE 86

Palindromic snake graphs

A continued fraction [a1, . . . , an] is called

◮ even if n is even; ◮ palindromic if ai = an−i for all i.

. A snake graph is called

◮ palindromic if it is the snake graph of an even palindromic

continued fraction;

◮ rotationally symmetric at a center tile if the rotation about

180◦ at the center of the central tile is an automorphism.

Theorem

A snake graph is palindromic if and only if it has a rotational symmetry at its center tile.

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SLIDE 87

Example

[2, 2, 2, 2] = 29

12

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SLIDE 88

Example

N[2, 2, 2, 2] = 29

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SLIDE 89

Example

N[2, 2, 2, 2] = N[2, 2]N[2, 2] + N[2]N[2] 29 = 5 ∗ 5 + 2 ∗ 2

Theorem (Palindromification)

Let [a1, a2, . . . , an] = pn qn . Then [an, . . . , a2, a1, a1, a2, . . . , an] = p2

n + q2 n

pn−1pn + qn−1qn .

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SLIDE 90

Example

N[2, 2, 2, 2] = N[2, 2]N[2, 2] + N[2]N[2] 29 = 5 ∗ 5 + 2 ∗ 2

Theorem (PalindromificationnoitacifimordnilaP)

Let [a1, a2, . . . , an] = pn qn . Then [an, . . . , a2, a1, a1, a2, . . . , an] = p2

n + q2 n

pn−1pn + qn−1qn .

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SLIDE 91

Sums of two squares

An integer N is called a sum of two squares if there exist integers p > q ≥ 1 with gcd(p, q) = 1 such that N = p2 + q2.

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SLIDE 92

Sums of two squares

An integer N is called a sum of two squares if there exist integers p > q ≥ 1 with gcd(p, q) = 1 such that N = p2 + q2.

Corollary

Let N > 0.

◮ If N is a sum of two squares then there exists a palindromic

snake graph G such that m(G) = N.

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SLIDE 93

Sums of two squares

An integer N is called a sum of two squares if there exist integers p > q ≥ 1 with gcd(p, q) = 1 such that N = p2 + q2.

Corollary

Let N > 0.

◮ If N is a sum of two squares then there exists a palindromic

snake graph G such that m(G) = N.

◮ The number of ways one can write N as a sum of two squares

is equal to one half of the number of palindromic snake graphs with N perfect matchings.

Example

5 can be written uniquely as sum of two squares as 5 = 22 + 12. The even palindromic continued fractions with numerator 5 are [2, 2] and [1, 1, 1, 1].

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SLIDE 94

Markov numbers

A triple of positive integers (a, b, c) is called a Markov triple if a2 + b2 + c2 = 3abc. An integer is called a Markov number if it is a member of a Markov triple.

(29, 2, 169) (29, 2, 5) ❦ ❦ ❦ ❦ (29, 433, 5) (1, 1, 1) (1, 2, 1) (1, 2, 5) ❧ ❧ ❧ ❘ ❘ ❘ (1, 13, 5) ❙ ❙ ❙ ❙ (194, 13, 5) Markov tree (1, 13, 34)

Uniqueness Conjecture (Frobenius 1913)

The largest integer in a Markov triple determines the other two.

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SLIDE 95

Markov numbers as numbers of perfect matchings of Markov snake graphs

◮ Markov triples are related to the clusters of the cluster algebra

  • f the torus with one puncture [Beineke-Br¨

ustle-Hille 11, Propp –].

◮ A Markov snake graph is the snake graph of a cluster variable

  • f the once punctured torus.

◮ The Markov numbers are precisely the number of perfect

matchings of the Markov snake graphs. [Propp]

Uniqueness Conjecture

Any two Markov snake graphs have a different number of perfect matchings.

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SLIDE 96

Markov tree — snake graph version

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SLIDE 97

Markov snake graphs

(7,3) 1 2 3 4 5 6 7 1 2 3 (7,3) 1 2 3 4 5 6 7 1 2 3

The line with slope p/q = 3/7 with its lower Christoffel path in red, defining the Christoffel word x, x, x, y, x, x, y, x, x, y. The corresponding Markov snake graph is obtained by placing tiles of side length 1/2 on the Christoffel path leaving the first half step and the last half step empty.

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SLIDE 98

Theorem

Every Markov number is the numerator of an even palindromic continued fraction.

Corollary

Every Markov number, except 1, is a sum of two squares. In general, the decomposition of an integer as a sum of two squares is not unique.The smallest example among the Markov numbers is 610 = 232 + 92 = 212 + 132. 21/13 = [1, 1, 1, 1, 1, 2] and its palindromification [2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2] is a Markov snake graph. 23/9 = [2, 1, 1, 4] and its palindromification [4, 1, 1, 2, 2, 1, 1, 4] is not Markov.

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SLIDE 99

Chebyshev polynomials

The (normalized) Chebyshev polynomials of the first kind Tn are defined recursively by T0 = 1, T1 = x, and Tn = xTn−1 − Tn−2. The first few polynomials are T2 = x2 − 1 T3 = x3 − 2x T4 = x4 − 3x2 + 1 T5 = x5 − 4x3 + 3x T6 = x6 − 5x4 + 6x2 − 1

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SLIDE 100

Chebyshev polynomials

Let Gn be the snake graph of [a1, a2, . . . , an] = [1, 1, . . . , 1]. Thus Gn is a vertical straight snake graph with exactly n − 1 tiles. 2 3 4 5 1 G6

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SLIDE 101

Chebyshev polynomials are specialized cluster variables

x i i x x x x x i i i i i i i i

Theorem

Label all horizontal edges of Gn by x. Label all vertical edges of Gn by i = √−1. Then

  • P∈Match Gn

x(P) = Tn

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SLIDE 102

Corollaries

Tn Tn−1 = i x i , x i , . . . , x i

  • .

lim

n→∞

Tn Tn−1 = 1 2

  • x +
  • x2 − 4
  • .

T 2

n − T 2 n−1 = T2n.

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SLIDE 103

Summary

◮ Cluster algebra side

◮ New expansion formula ◮ Study quotients of cluster algebra elements ◮ Study their asymptotic behavior

◮ Continued fraction side

◮ Combinatorial realization ◮ Intuition about continued fractions ◮ Additional structure on continued fractions (poset, x-grading,

y-grading