Charmonium spectral functions from 2+1 flavour lattice QCD asztor 12 - - PowerPoint PPT Presentation

charmonium spectral functions from 2 1 flavour lattice qcd
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Charmonium spectral functions from 2+1 flavour lattice QCD asztor 12 - - PowerPoint PPT Presentation

Charmonium spectral functions from 2+1 flavour lattice QCD asztor 12 Attila P apasztor@bodri.elte.hu In collaboriation with anyi 3 urr 34 Z. Fodor 134 C. Hoelbling 3 S. Bors S. D S. D. Katz 12 S. Krieg 34 S. Mages 5 adi 1 afer 5 D. N


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SLIDE 1

Charmonium spectral functions from 2+1 flavour lattice QCD

Attila P´ asztor 12 apasztor@bodri.elte.hu

In collaboriation with

  • S. Bors´

anyi3

  • S. D¨

urr34

  • Z. Fodor134
  • C. Hoelbling3
  • S. D. Katz12
  • S. Krieg34
  • S. Mages5
  • D. N´
  • gr´

adi1

  • A. Sch¨

afer5

  • B. C. T´
  • th3
  • N. Trombit´

as1

  • K. K. Szab´
  • 34

1E¨

  • tv¨
  • s University

2MTA-ELTE Lattice Gauge Theory Group 3University of Wuppertal 4J¨

ulich Supercomputing Center

5University of Regensburg

BGZ Triangle Meeting, 2014, Balatonf¨ ured

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SLIDE 2

Motivation

Motivation

  • We will consider correlators of charmonium currents in the

pseudoscalar(PS) and vector(V) channels, i.e. ¯ cγ5c and 3

i=1 ¯

cγic

  • These correspond to the ηc and J/Ψ mesons
  • J/Ψ suppression is regarded as an important signal of QGP

formation

  • Charmonium states are regarded as a possible thermometer

for the QGP

  • This study is with 2+1 dynamical quarks, previous studies:

mostly quenched, one in 2 flavour The talk is based on: JHEP 1404 (2014) 132

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SLIDE 3

Preliminaries

Spectral function ∼ im part of real-time retarded correlator

A(ω) = (2π)2 Z

  • m,n
  • e−En/T − e−Em/T

|n|JH(0)|m|2 δ(p − kn + km) Quasipaticle ∼ peaks in the SF, melting/dissociation ∼ peaks not well separated anymore, they become part of the continuum

Relation to the Euclidean time correlator

G(τ, p) = ∞ dωA(ω, p)K(ω, τ) where K(ω, τ) = cosh(ω(τ − 1/2T)) sinh(ω/2T) Left hand side is calculable with lattice techniques. This is very hard to invert.

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SLIDE 4

The Maximum Entropy Method

The method in a nutshell

Q = αS − 1 2χ2 S =

  • A(ω) − m(ω) − A(ω) log

A(ω) m(ω)

  • χ2 =
  • i,j

(G fit

i

− G data

i

)C −1

ij (G fit j

− G data

j

) Gi =

  • A(ω)K(ω, τi)dω

m(ω) is a function, summarizing our prior knowledge of the

  • solution. Then we average over α. The conditional probability

P[α|data, m] is given by Bayes’ theorem.

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SLIDE 5

The Maximum Entropy Method

Conclusions from mock data analysis

  • The peak positions OK, the shapes not so much
  • With not too noise data points, O(10) points are OK
  • Features that remain unchanged by varying the prior are

restricted by the data

  • Resultion becomes worse at bigger ω
  • Peaks close in position can be merged into one broader peak.

Take home message: the stable thing is just the position of the first (ground state)

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SLIDE 6

Simulation details

Lattice details

Gauge action = Symanzik tree-level improved gauge action Fermion action = 2+1 dynamical Wilson fermions with 6 step stout smearing (ρ = 0.11) and tree-level clover improvement Same configurations as in JHEP 1208 (2012) 126 a = 0.057(1)fm mπ = 545MeV Ns = 64 Nt = 28...12 T = 123...288MeV We measured the charm meson correlators on these lattices.

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SLIDE 7

Outline of MEM procedure

Stability test at the lowest temp

  • Drop data points, emulating the number of data points

available at the lowest temperature (Nt = 28)

  • Do the same analysis as with the higher temperature
  • correlators. If the ground state peak cannot be reconstructed,

the given number of data points is not reliable

  • RESULT: Nt=12 NOT OK, Nt=14,16,18,20 OK

Error analysis

  • Systematic error analysis: vary ∆ω, Nω, the shape of the prior

function: m0, m0ω2, 1/(m0 + ω), m0ω and m0=0.01, 0.1, 1.0, 10.0.

  • Statistical error analysis: given set of parameters, 20 jackknife

samples

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SLIDE 8

Sensitivity on prior function

This is the PS channel, but V looks similar

0.05 0.1 0.15 0.2 0.25 0.3 0.35 0.4 0.45 0.5 0.5 1 1.5 2 2.5 3 3.5 A(ω)/ω2 ωa PSEUDOSCALAR CHANNEL, Nt=20, T/Tc≈0.9 m(ω)=0.01/a2 m(ω)=0.1ω2 m(ω)=1.0/a2/(10.0+ωa)

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SLIDE 9

Temperature dependence

0.05 0.1 0.15 0.2 0.25 0.5 1 1.5 2 2.5 3 3.5 A(ω)/ω2 aω PSEUDOSCALAR CHANNEL, m(ω) = 0.1 ω2 Nt=14, T/Tc ≈ 1.30 Nt=16, T/Tc ≈ 1.14 Nt=18, T/Tc ≈ 1.01 Nt=20, T/Tc ≈ 0.91

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SLIDE 10

Temperature dependence

Vector channel

0.05 0.1 0.15 0.2 0.25 0.5 1 1.5 2 2.5 3 3.5 A(ω)/ω2 aω VECTOR CHANNEL, m(ω) = 0.1 ω2 Nt=14, T/Tc ≈ 1.30 Nt=16, T/Tc ≈ 1.14 Nt=18, T/Tc ≈ 1.01 Nt=20, T/Tc ≈ 0.91

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SLIDE 11

Results - MEM

Pseudoscalar channel - position of 1st peak

0.75 0.8 0.85 0.9 0.95 1 1.05 1.1 1.15 0.03 0.035 0.04 0.045 0.05 0.055 0.06 0.065 0.07 0.075 Position of first peak in lattice units aT=1/Nt

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SLIDE 12

Results - MEM

Vector channel - position of 1st peak

0.7 0.75 0.8 0.85 0.9 0.95 1 1.05 1.1 1.15 1.2 1.25 0.03 0.035 0.04 0.045 0.05 0.055 0.06 0.065 0.07 0.075 Position of first peak in lattice units aT=1/Nt

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SLIDE 13

Charm diffusion coefficient

Kubo-formula

D = 1 6χ lim

ω→0 3

  • i=1

Aii(ω, T) ω , If D > 0 we have ρ/ω > 0 for small ω implying a transport peak

Narrow transport peak

In the case of a narrow transport peak, we can use the ansatz: Atransport(ω, T) = f (T)ωδ(ω − 0+) This does not mean, that the diffusion coefficient is infinite. But in case of a narrow transport peak, the Euclidean correlator G(τ, T) =

  • K(ω, τ)A(ω, T) is not sensitive to the full shape of

the peak, only the area. The contrubtion of the transport peak will be a temperature dependent constant (zero mode).

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SLIDE 14

Some indication of a transport peak

Nt = 16 not conclusive

0.003 0.006 0.009 0.025 0.05 A(ω)/(ωT) ωa m(ω)=0.01 a2 m(ω)=a-2/(10+ω a) m(ω)=0.1ω2 m(ω)=1.0ω/a m(ω)=0.01ω/a

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SLIDE 15

A different method

Definition of G/Grec

Datta, Karsch, Petreczky, Wetzorke 2004

G (t, T) Grec (t, T) = G(t, T)

  • A(ω, Tref)K(ω, t, T)dω

Midpoint subtracted version

G − G −

rec

= G (t, T) − G (Nt/2, T) Grec (t, T) − Grec (Nt/2, T) = G (t, T) − G (Nt/2, T)

  • A(ω, Tref) [K(ω, t, T) − K(ω, Nt/2, T)] dω

This removes the zero mode.

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SLIDE 16

Results: G/Grec

Pseudoscalar channel

0.94 0.96 0.98 1 1.02 1.04 1.06 2 4 6 8 10 G/Grec t/a Nt=12 Nt=14 Nt=16 Nt=18 Nt=20

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SLIDE 17

Results: G/Grec

Vector channel

0.9 0.95 1 1.05 1.1 1.15 2 4 6 8 10 G/Grec t/a Nt=12 Nt=14 Nt=16 Nt=18 Nt=20

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SLIDE 18

Results: G −/G −

rec

Pseudoscalar channel, midpoint subtracted version

0.9 0.95 1 1.05 1.1 2 4 6 8 10 G-/G-

rec

t/a Nt=12 Nt=14 Nt=16 Nt=18 Nt=20

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SLIDE 19

Results: G −/G −

rec

Vector channel, midpoint subtracted version

0.9 0.95 1 1.05 1.1 2 4 6 8 10 G-/G-

rec

t/a Nt=12 Nt=14 Nt=16 Nt=18 Nt=20

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SLIDE 20

Results: G − Grec

Vector channel

  • 1e-05
  • 5e-06

5e-06 1e-05 2 4 6 8 10 G-Grec t/a Nt=16 Nt=14 Nt=12

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SLIDE 21

Conclusions

MEM analysis

  • There seems to be no change in the SF in the PS channel up

to 1.4Tc

  • There seems to be some change in SF in the V channel
  • Indications of a transport peak in the V channel

G/Grec analyis

  • No change in the PS channel
  • In the V channel, results are consistent with a temperature

independent ω > 0 part and a temperature dependent zero mode (narrow transport peak), described by the ansatz A(ω) = f (T)ωδ(ω − 0+) + A(ω, T = 0).

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SLIDE 22

Backup - implementation details 1

MEM continued...

It can be shown, that the maximum of Q is in an Ndata dimensional subspace: A(ω) = m(ω) exp Ndata

  • i=1

sifi(ω)

  • Two choice for basis functions: Bryan (Eur. Biophys J. 18, 165

(1990)) or Jakov´ ac et al (Phys.Rev. D75 014506 (2007). We use the latter. In this case the maximization of Q is equivalent to the minimization of U = α 2

Ndata

  • i,j=1

siCijsj + ωmax dωA(ω) −

Ndata

  • i=1

Gdata

i

si. Comment: Have to use arbitrary precision arithmetics with both methods.

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SLIDE 23

Backup - implementation details 2

Problem: stopping criterion

  • 0.7
  • 0.65
  • 0.6
  • 0.55
  • 0.5
  • 0.45
  • 0.4
  • 0.35
  • 0.3
  • 0.25

2000 4000 6000 8000 10000 12000 14000 16000 U # of iteration steps

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SLIDE 24

Backup - implementation details 3

Solution: going back to the Nω dimensions

5.95 6 6.05 6.1 6.15 6.2 6.25 6.3 5000 10000 15000 20000 25000 30000 35000 40000

  • Q

# of iteration steps

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SLIDE 25

Backup - charm mass tuning

From Davies et al PRL 104, 132003 (2010) mc/ms = 11.85. Because of additive renormalization, it is impossible to use this

  • directly. We use (mc − ms)/(ms − mud) where the additive

renormalization constant cancels. We know that for ud and s the masses used in the simulation correspond to a mass ratio of 1.5 (Durr et al. Phys. Lett. B701 (2011) 265), from this we get (mc − ms)/(ms − mud) = 32.55 We check if the meson masses are indeed in the right ballpark: JP mi ma ma/mD∗

s a

mexp/mD∗

s

0− ms,mc Ds 0.54(1) 0.95(2) 0.932 0− mc,mc ηc 0.8192(7) 1.437(4) 1.411 1− ms,mc D∗

s

0.570(1) 1 1 1− mc,mc J/Ψ 0.8388(8) 1.472(2) 1.466 3/2+ 3ms Ω 0.478(8) 0.84(2) 0.791