Calculating in floating sexagesimal place value notation, 4000 years - - PowerPoint PPT Presentation
Calculating in floating sexagesimal place value notation, 4000 years - - PowerPoint PPT Presentation
Calculating in floating sexagesimal place value notation, 4000 years ago Christine Proust Laboratoire SPHre (CNRS & Universit Paris-Diderot) ARITH 22 22 nd Symposium on Computer Arithmetic Lyon June 22-24, 2015 Franois Thureau-Dangin
François Thureau-Dangin (1872-1944)
1938 Textes Mathématiques Babyloniens.
Otto Neugebauer (1899-1990)
1935-1937 Mathematische Keilschrifttexte I Neugebauer & Sachs, 1945 Mathematical Cuneiform Texts.
School tablet from Nippur , Old Babylonian period (HS 217a, University of Jena)
Multiplication table by 9
20x9 = 180 = 3x60 In base 60 : 3:0 But the scribes wrote: 3 This is puzzling. 20x9 is written 3 20x9 = 3 The square of 30 is written 15 30x30 = 15 The square root of 15 is written 30
1 9 2 18 3 27 4 36 5 45 6 54 7 1:3 8 1:12 9 1:21 10 1:30 11 1:39 12 1:48 13 1:57 14 2:6 15 2:15 16 2:24 17 2:33 18 2:42 20-1 2:51 20 3 30 4:30 40 6 50 7:30 8.20 a-ra2 1 8.20
HS 217a
Is the lack of graphical systems to determine the place of the unit in the number an imperfection of the cuneiform script?
(Sachs 1947)
The algorithm for reciprocals according to Abraham Sachs (1947)
yes
no
Scribal schools in Old Babylonian period (ca. 2000-1600 BCE)
Scribal school in Nippur
The curriculum at Nippur
Level Content Elementary Metrological lists: capacities, weights, surfaces, lengths Metrological tables: capacities, weights, surfaces, lengths, heights Numerical tables: reciprocals, multiplications, squares Tables of square roots and cube roots Intermediate Exercises: multiplications, reciprocals, surface and volume calculations
School tablet from Nippur , Old Babylonian period (Ist Ni 5376, Istanbul)
A list of proverbs
- 1. Someone who cannot produce "a-a”,
from where will he achieve fluent speech?
- 2. A scribe who does not know
Sumerian -- from where will he produce a translation?
- 3. The scribe skilled in counting is
deficient in writing. The scribe skilled in writing is deficient in counting.
- 4. A chattering scribe. Its guilt is great.
- 5. A junior scribe is too concerned with
feeding his hunger; he does not pay attention to the scribal art.
- 6. A disgraced scribe becomes a priest.
…
capacity weight surface length
Metrological lists
School tablet from Nippur, Old Babylonian period (HS 249, University of Jena)
Metrological lists: measurements of capacity
School tablet from Nippur, Old Babylonian period (HS 1703, University of Jena)
1 sila
- ca. 1 liter
1 ban
- ca. 10 liters
1/3 sila 1/2 sila 2/3 sila 5/6 sila 1 sila 1 1/3 sila 1 1/2 sila 1 2/3 sila 1 5/6 sila 2 sila 3 sila 4 sila 5 sila 6 sila 7 sila 8 sila 9 sila 1 ban še 1 ban 1 sila 1 ban 2 sila 1 ban 3 sila 3
1 šusi 10 2 šusi 20 3 šusi 30 4 šusi 40 5 šusi 50 6 šusi 1 7 šusi 1:10 8 šusi 1:20 9 šusi 1:30 1/3 kuš 1:40 1/2kuš 2:30 2/3 kuš 3:20 5/6 kuš 4:10 1 kuš 5 1 1/3 kuš 6:40 1 1/2kuš 7:30 1 2/3 kuš 8:20 2 kuš 10
School tablet from Nippur, Old Babylonian period (HS 241, University of Jena)
1 šusi = 1 finger,
- ca. 1.6 cm
1 kuš = 1 cubit,
- ca. 50 cm
Reciprocals Multiplication tables by 50 45 44:26:40 40 36 30 25 24 22:30 20 18 16:40 16 15 12:30 12 10 9 8:20 8 7:30 7:12 7 6:40 6 5 4:30 4 3:45 3:20 3 2:30 2:24 2 1:40 1:30 1:20 1:15 Table of squares
Numerical tables
School tablet from Nippur, Old Babylonian period (Ist Ni 2733, Istanbul Museum)
2 30 3 20 4 15 5 12 6 10 8 7:30 9 6:40 10 6 12 5 15 4 16 3:45 18 3:20 20 3 24 2:30 25 2:24 27 2:13:20 30 2 32 1:52:30 36 1:40 40 1:30 45 1:20 48 1:15 50 1:12 54 1:6:40 1 1 1:4 56:15 1:21 44:26:40
Table of reciprocals
School tablet from unknown provenance, Old Babylonian period (MS 3874, Schøyen collection, copy Friberg)
The division by a number was performed by mean of the multiplication by the reciprocal
- f this number.
5 ÷ 30 = 5 × 2 = 10 2 ÷ 44:26:40 = 2 × 1:21 = 2:42
2 30 3 20 4 15 5 12 6 10 8 7:30 9 6:40 10 6 12 5 15 4 16 3:45 18 3:20 20 3 24 2:30 25 2:24 27 2:13:20 30 2 32 1:52:30 36 1:40 40 1:30 45 1:20 48 1:15 50 1:12 54 1:6:40 1 1 1:4 56:15 1:21 44:26:40
Multiplying
4 50 4 50
- 41
40 3 20 3 20 16
- 23
21 40
17:46:40 Its reciprocal 3:22:30 ==================== 17:46:40 [9] 2:40 22:[30] 3:22:[30] A chattering scribe, his guilt is great.
- A chattering scribe,
his guilt is great ====================== 17:46:40 9 1:30*
Reciprocal
Calculation of surface
2.10 2.10 4.26!.40 1/3 kuš3 3 šu-si its side
- Its surface what ?
- Its surface 13 še
igi-4! gal2 še ==============
Ni 18 School tablet from Nippur Istanbul Museum
SPVN Metrological notations
Table of lengths length measures → SPVN Table of surfaces SPVN → surface measure Multiplication table (SPVN)
School tablets from Nippur 2 times 2 4 3 times 3 9 4 times 4 16 5 times 5 25 6 times 6 36 7 times 7 49 8 times 8 1.4 9 times 9 1.21 10 times 10 1.40 11 times 11 2.1 12 times 12 2.24 Extract of table of squares 6 šu-si 1 7 šu-si 1.10 8 šu-si 1.20 9 šu-si 1.30
1/3 kuš3
1.40
1/3 kuš3 1 šu-si
1.50
1/3 kuš3 2 šu-si
2
1/3 kuš3 3 šu-si
2.10
1/3 kuš3 4 šu-si
2.20 Extract of metrological table for lengths
1/3 sar
20
1/2 sar
30
2/3 sar
40
5/6 sar
50 1 sar 1 1 1/3 sar 1.20 1 1/2 sar 1.30 1 2/3 sar 1.40 1 5/6 sar 1.50 Extract of metrological table for surfaces
SPVN SPVN SPVN Metrological notations Metrological notations
Obverse 4:26:40 Its reciprocal 13:30 ============== reverse 4:26:40 9 40* 1:30 13:30
*error of the scribe: he wrote 41 instead of 40
The algorithm for reciprocal
4:26:40 9 40 1:30 13:30
2 30 3 20 4 15 5 12 6 10 8 7:30 9 6:40 10 6 12 5 15 4 16 3:45 18 3:20 20 3 24 2:30 25 2:24 27 2:13:20 30 2 32 1:52:30 36 1:40 40 1:30 45 1:20 48 1:15 50 1:12 54 1:6:40 1 1 1:4 56:15 1:21 44:26:40
4:26:40 ends with the regular number 6:40, so 4:26:40 is "divisible" by 6:40 . To divide 4:26:40 by 6:40, we must multiply 4:26:40 by the reciprocal of 6:40. The reciprocal of 6:40 is 9 . The number 9 is placed in the right hand column. 4:26:40 multiplied by 9 is 40, thus, 40 is the quotient of 4:26:40 by 6:40. This quotient is placed in the left hand column. The reciprocal of 40 is 1:30. The number 1:30 is placed in the right hand olumn. To find the reciprocal of 4:26:40, one only has to multiply the reciprocals of the factors of 4:26:40, that is to say, the numbers 9 and 1:30 placed in the right hand column. This product is 13:30, the reciprocal sought.
4:26:40 9 40 1:30 13:30
2 30 3 20 4 15 5 12 6 10 8 7:30 9 6:40 10 6 12 5 15 4 16 3:45 18 3:20 20 3 24 2:30 25 2:24 27 2:13:20 30 2 32 1:52:30 36 1:40 40 1:30 45 1:20 48 1:15 50 1:12 54 1:6:40 1 1 1:4 56:15 1:21 44:26:40
Left hand column: 4:26:40 = 6:40 × 40 Right hand column 9 × 1:30 = 13:30
2.5 4.10 8.20 16.40 33.20 1.6.40 2.13.20 4.26.40 … 10.6.48.53.20
CBS 1215
Provenance: unknown Datation: OB period (ca. 1800 BCE) University of Pennsylvania, Philadelphia Publication: Sachs 1947, Babylonian Mathematical Texts 1 Copy Robson 2000: 14
Obverse: 3 columns, # 1-16 Reverse: 3 columns, #16-21 Entries
colonne I colonne II colonne III #1 2.5 12 25 2.24 28.48 1.15 36 1.40 2.5 #2 4.10 6 25 2.24 14.24 2.30 36 1 .40 4.10 #3 8.20 3 25 2.24 7.12 5 36 1.40 8.20 #4 16.40 9 2.30 24 3.[36] [1.40] 6 10 15sic.40 #5 33.20 18 10 6 1.48 1.15 2.15 4 8sic 6.40 26.40 33.20 #6 1.6.40 9 10 6 54 1.6.40 #7 [2].13.20 18 [40] 1.30 [27] 2.13.20 #8 4.26.40 9 40 1.30 13.30 2 27 2.13.20 4.26.40 #9 8.53.20 18 2.40 22.30 6.45 1.20 9 6.40 8.53.20 #10 17.46.40 9 2.40 22.30 3.22.30 2 6.45 1.20 9 6.40 8.53.20 17.46.40 #11 36sic.2sic3.20 18 10.40 1.[30] [16] 3.4[5] 5.37.30 [1.41.1]5 4 [6.45] 1.20 [9] 6.40 [8.53].20 [35.33].20 #12 [1].11.6.[40] 9 10.40 1.[30] 16 3.4[5] 5.37.30 50.37.30 2 1.41.15 4 6.4[5] 1.20 9 6.40 [8.5]3.[20] 35.33.20 1.11.6.40 #13 2.22.13.20 [18] 42.40 22.30 16 3.45 1.24.22.30 25.18.45* [16] 6.45 1.20 9 [6.40] 8.53.20 [2.2]2.13.[20] #14 4.44.26.40 [9] 42.40 2[2.30] 16 3.[45] 1.24.22.30 [12.3]9.22.30 [2] [25.18].45* [16] [6.45] [1.20] [9] [6.40] [8].53.20 [2.22.13. 20] [4.44.26.40] #15 [9.28].53.[20] [18] 2.50.40 [1.30] [4.16] [3.45] [16] [3.45] 14.3.[45] [2]1.5.3[7.30] [6.19.4]1.15 [4] [25.18.45]* [16] [6.45] [1.20] [9] [6.40] [8.53.20] 2.[22.13.20] 9.[28.53.20] #16 18.57.[46.40] [9] [2.50.40] [1.30] 4.[16] [3.45] 16 [3.45] [14].3. [45] [21.5.37.30] [3.9.50.37.30] [2] [6.19.41.15] [4] (suite sur le revers)
colonne III colonne II colonne I #21 10.6.48.53.20 18 3.2.2.40 22.[30] 1.8.16 3.4[5] 4.16 3.[45] 16 3.[45] 1[4.3.4]5 52.44.[3.4]5 19.46.31.24.22.[30] 5.55.57.25.18.4[5] 16 1.34.55.18.45* 16 25.18.45* [16] 6.45 [1.20] 9 [6.40] 8.53.20 2.22.13. 20 37.55.33.20 10.6.48.53.20 #19 [2.31.42.13.20 18] [45.30.40 1.30] [1.8.16 3.45] [4.16 3.45] 16 [3.45] 14.[3.45] 5[2.44.3.45] 1.18sic.6.[5.37.30] 23.43.49.[41.15] [4] 1.[3]4.55.18.45* [16] [25].18.45* 1[6] [6].45 1.[20] [9] 6.40 8.53.20 2.22.13.20 37.55.3[3.20] 2.31.42.13.[20] #20 5.3.24.26.40 [9] 45.30.40 1.30 1.8.16 3.45 4.16 3.45 16 3.45 14.3.45 5[2.44].3.45 1.19.6.5.37.30 11.51.54.50.37.30 2 23.43.49.41.15 4 1.34.55.18.45* 16 25.18.45* 16 6.45 1.20 9 6.[40] 8.53.20 2.22.13. 20 37.55.33.20 2.31.42.13.20 5.3.24.26.40 #16 (suite) [25.18.45* 16] [6.45 1.20] [9 6.40] [8.53.20] [2.22.13. 20] [9.28.53.20] [18.57.46.40] #17 [37.55.33.20 18] [11.22.40 22.30] [4.16 3.45] [16 3.45] [14.3.45] [5.16.24.22.30] [1.34.55.18.45* 16] [25.18.45* 16] [6.45 1.20] 9 [6.40] [8.53.20] 2.22.13.[20] 37.55.33.[20] #18 1.15.51.6.40 9 11.22.40 22.30 4.16 3.45 16 [3.45] 14.[3.45] 5.16.[24.22.30] 47.27.[39.22.30 2] [1.34.55.18.45* 16] [25.18.45* 16] [6.45 1.20] [9 6.40] 8.[53.20] 2.2[2.13. 20] 37.55.[33.20] 1.15.51.[6.40]
Obverse (columns from left to right) Reverse (columns from right to left) CBS 1215: transliteration
2:5 12 25 2:24 28:48 1:15 36 1:40 2:5
CBS 1215 #1
2 30 3 20 4 15 5 12 6 10 8 7:30 9 6:40 10 6 12 5 15 4 16 3:45 18 3:20 20 3 24 2:30 25 2:24 27 2:13:20 30 2 32 1:52:30 36 1:40 40 1:30 45 1:20 48 1:15 50 1:12 54 1:6:40 1 1 1:4 56:15 1:21 44:26:40
2:5 12 25 2:24 28:48 1:15 36 1:40 2:5
The factorization of 2:5 appears in the left column: 2:5 × 5 = 25 The factorization of the reciprocal of 2:5 appears in the right hand column: 12 × 2:24 = 28:48 The reciprocal of 2:5 is thus 28:48.
CBS 1215 #8
2 30 3 20 4 15 5 12 6 10 8 7:30 9 6:40 10 6 12 5 15 4 16 3:45 18 3:20 20 3 24 2:30 25 2:24 27 2:13:20 30 2 32 1:52:30 36 1:40 40 1:30 45 1:20 48 1:15 50 1:12 54 1:6:40 1 1 1:4 56:15 1:21 44:26:40
4.26.40 9 40 1.30 13.30 2 27 2.13.20 4.26.40
Transcription Copy [Robson 2000, p. 23] 5.3.24.26.40 [9] 45.30.40 1.30 1.8.16 3.45 4.16 3.45 16 3.45 14.3.45 5[2.44].3.45 1.19.6.5.37.30 11.51.54.50.37.30 2 23.43.49.41.15 4 1.34.55.18.45* 16 25.18.45* 16 6.45 1.20 9 6.[40] 8.53.20 2.22.13. 20 37.55.33.20 2.31.42.13.20 5.3.24.26.40
CBS 1215 #20: iteration
2 30 3 20 4 15 5 12 6 10 8 7:30 9 6:40 10 6 12 5 15 4 16 3:45 18 3:20 20 3 24 2:30 25 2:24 27 2:13:20 30 2 32 1:52:30 36 1:40 40 1:30 45 1:20 48 1:15 50 1:12 54 1:6:40 1 1 1:4 56:15 1:21 44:26:40
Left hand column: 5:3:24:26:40 = 6:40 × 40 × 16 × 16 × 16 Right hand column: 9 × 1:30 × 3:45 × 3:45 × 3:45 = 11:51:54:50:37:30
2 30 3 20 4 15 5 12 6 10 8 7:30 9 6:40 10 6 12 5 15 4 16 3:45 18 3:20 20 3 24 2:30 25 2:24 27 2:13:20 30 2 32 1:52:30 36 1:40 40 1:30 45 1:20 48 1:15 50 1:12 54 1:6:40 1 1 1:4 56:15 1:21 44:26:40 Transcription 5:3:24:26:40 [9] 45:30:40 1:30 1:8:16 3:45 4:16 3:45 16 3:45 14:3:45 5[2:44]:3:45 1:19:6:5:37:30 11:51:54:50:37:30 2 23:43:49:41:15 4 1:34:55:18:45 16 25:18:45 16 6:45 1:20 9 6:[40] 8:53:20 2:2:22:2:13: 20 37:55:33:20 2:31:42:13:20 5:3:24:26:40 Explanation: n → 5:3:24:26:40 Factors of n factors of inv(n) 6:40 9 40 1:30 16 3:45 16 3:45 16 3:45 Products 14:3:45 5[2:44]:3:45 1:19:6:5:37:30 11:51:54:50:37:30 n→ 11:51:54:50:37:30 30 2 15 4 3:45 16 3:45 16 45 1:20 9 6:[40] Products 8:53:20 2:22:13: 20 37:55:33:20 2:31:42:13:20 5:3:24:26:40
Aspects of CBS 1215: Paradigmatic examples: Calculation performed on common values (2.5 and doubles) that provide the ability to control the
- utputs, known in advance.
The execution of the algorithm is guided by a codified layout: the layout of the numbers indicates the nature of the
- peration carried out and the meaning of the calculations.
The implementation of the reverse algorithm illustrates the property "the reciprocal of a reciprocal of a number is this number itself."
L’algorithme d’inversion selon l’interprétation d’Abraham Sachs (1947) Abstract numbers are not quantities, but calculation tools
Plimpton 322
Columbia University, New York Old Babylonian period Provenience unknown (probably Southern Mesopotamia)
Sexagesimal number = number with finite sexagesimal development Sexagesimal rectangle = length, width and diagonal are represented by sexagesimals numbers Diagonal rule = Pythagorean rule
1 59,30 1,24,30
- bv
I' II' III' IV'
1
ta-k ]I- il- ti şi - li - ip - tim íb.si8 sag íb.si8 şi-li-ip-tim mu.bi.im
2
ša 1 in ]-na-as-sà-hu-ú-ma sag i- [il ]-lu-ú
3
1 59 15 1 59 2 49 ki 1
4
1 56 56 58 14 56 15 56 7 3 12 1 ki 2
5
1 55 7 41 15 33 45 1 16 41 1 50 49 ki 3
6
1 53 10 29 32 52 16 3 31 49 5 9 1 ki 4
7
1 48 54 1 40 1 5 1 37 ki 5
8
1 47 6 41 40 5 19 8 1 ki 6
9
1 43 11 56 28 26 40 38 11 59 1 ki 7
10
1 41 33 59 3 45 13 19 20 49 ki 8
11
1 38 33 36 36 9 1 12 49 ki 9
12
1 35 10 2 28 27 24 26 40 1 22 41 2 16 1 ki 10
13
1 33 45 45 1 15 ki 11
14
1 29 21 54 2 15 27 59 48 49 ki 12
15
1 27 3 45 7 12 1 4 49 ki 13
16
1 25 48 51 35 6 40 29 31 53 49 ki 14
17
1 23 13 46 40 56 53 ki 15
δ β 1 d b l × l
The square (takiltum) of the diagonal (from) which 1 is torn out (i.e. subtracted) and (that of) the width comes up. width diagonal Line n°
δ2 b d δ² − 1 = β²
1 1² + 59,0,15 59,30² = 1,59,0,15 1,24,30² 1 2,49 1,59 59,30 1,24,30
I’ II’ III’ IV’ The square of the diagonal (from) which 1 is torn out (i.e. subtracted) and (that of) the width comes up. width diagonal line 1,59,0,15 1,59 2,49 n°1
Reduced rectangle Unit rectangle 1,59,0,15 1,24,30² − 1 1² = 59,0,15 59,30²
txt r /s = in descending order txt r /s = in descending order No s r r/s = α s/r = 1/ α No s r r/s = α s/r = 1/ α 1 5 12 2 24 25 20 5 8 1 36 37 30 2 27 64 2 22 13 20 25 18 45 21 16 25 1 33 45 38 24 3 32 75 2 20 37 30 25 36 22 2 3 1 30 40 4 54 125 2 18 53 20 25 55 12 23 27 40 1 28 53 20 40 30 5 4 9 2 15 26 40 24 25 36 1 26 24 41 40 6 9 20 2 13 20 27 25 45 64 1 25 20 42 11 15 7 25 54 2 9 36 27 46 40 26 32 45 1 24 22 30 42 40 8 15 32 2 8 28 7 30 27 18 25 1 23 20 43 12 9 12 25 2 5 28 48 28 20 27 1 21 44 26 40 10 40 81 2 1 30 29 37 46 40 29 3 4 1 20 45 11 1 2 2 30 30 25 32 1 16 48 46 52 30 12 25 48 1 55 12 31 15 31 4 5 1 15 48 13 8 15 1 52 30 32 32 5 6 1 12 50 14 27 50 1 51 6 40 32 24 33 27 32 1 11 6 40 50 37 30 15 5 9 1 48 33 20 34 8 9 1 7 30 53 20 16 9 16 1 46 40 33 45 35 9 10 1 6 40 54 17 16 27 1 41 15 35 33 20 36 25 27 1 4 48 55 33 20 18 3 5 1 40 36 37 15 16 1 4 56 15 19 50 81 1 37 12 37 2 13 20 38 24 25 1 2 30 57 36
1<r/s < (<2;25) r is a regular number s is a 1-place regular number r/s is irreducible List of all the values of r/s (John Britton according to Price 1964)
2 1+
δ = ½(r/s + s/r) β = ½(r/s - s/r) We have: δ2 - β² = 1 β
β δ δ2 = 1+β2 b d No [-I'] [0'] I' II' III' IV' sag şi-li-ip-tum ta]-ki-il-ti şi-li-ip - tim íb.si8 sag íb.si8
şi-li-ip-tim mu.bi.im
šá 1 in]-na-as-šà-hu-ú-ma sag i-[il-lu]-ú 59 30 1 24 30 1 59 0 15 1 59 2 49 ki 1 58 27 17 30 1 23 46 2 30 1 56 56 58 14 50 6 15 56 7 1 20 25 ki 2 57 30 45 1 23 6 45 1 55 7 41 15 33 45 1 16 41 1 50 49 ki 3 56 29 4 1 22 24 16 1 53 10 29 32 52 16 3 31 49 5 9 1 ki 4 54 10 1 20 50 1 48 54 1 40 1 5 1 37 ki 5 53 10 1 20 10 1 47 6 41 40 5 19 8 1 ki 6
- bv
50 54 40 1 18 41 20 1 43 11 56 28 26 40 38 11 59 1 ki 7 49 56 15 1 18 3 45 1 41 33 45 14 3 45 13 19 20 49 ki 8 48 6 1 16 54 1 38 33 36 36 8 1 12 49 ki 9 45 56 6 40 1 15 33 53 20 1 35 10 2 28 27 24 26 40 1 22 2 16 1 ki 10 45 1 15 1 33 45 45 1 15 ki 11 41 58 30 1 13 13 30 1 29 21 54 2 15 27 59 48 49 ki 12 40 15 1 12 15 1 27 3 45 2 41 4 49 ki 13 39 21 20 1 11 45 20 1 25 48 51 35 6 40 29 31 53 49 ki 14 37 20 1 10 40 1 23 13 46 40 28 53 ki 15 36 27 30 1 10 12 30 1 22 9 12 36 15 2 55 5 37 ki 16 32 50 50 1 8 24 10 1 17 58 56 24 1 40 7 53 16 25 ki 17 lo.e 32 1 8 1 17 4 8 17 ki 18 30 4 53 20 1 7 7 6 40 1 15 4 53 43 54 4 26 40 1 7 41 2 31 1 ki 19 29 15 1 6 45 1 14 15 33 45 39 1 29 ki 20 27 40 30 1 6 4 30 1 12 45 54 20 15 6 9 14 41 ki 21 25 1 5 1 10 25 5 13 ki 22 24 11 40 1 4 41 40 1 9 45 22 16 6 40 14 31 38 49 ki 23 22 22 1 4 2 1 8 20 16 4 11 11 32 1 ki 24 21 34 22 30 1 3 45 37 30 1 7 45 23 26 38 26 15 34 31 1 42 1 ki 25 20 51 15 1 3 31 15 1 7 14 53 46 33 45 16 41 50 49 ki 26 rev 20 4 1 3 16 1 6 42 40 16 5 1 15 49 ki 27 18 16 40 1 2 43 20 1 5 34 4 37 46 40 5 29 18 49 ki 28 17 30 1 2 30 1 5 6 15 7 25 ki 29 14 57 45 1 1 50 15 1 3 43 52 35 3 45 6 39 27 29 ki 30 13 30 1 1 30 1 3 2 15 9 41 ki 31 11 1 1 1 2 1 11 1 1 ki 32 10 14 35 1 0 52 5 1 1 44 55 12 40 25 4 55 29 13 ki 33 7 5 1 0 25 1 0 50 10 25 17 2 25 ki 34 6 20 1 0 20 1 0 40 6 40 19 3 1 ki 35 4 37 20 1 0 10 40 1 0 21 21 53 46 40 1 44 22 34 ki 36 3 52 30 1 7 30 1 0 15 0 56 15 31 8 1 ki 37 u.e. 2 27 1 3 1 6 9 49 20 1 ki 38
Reconstruction of complete tablet, by John Britton
A B
2 3 4 5 6 8 9 10 12 15 16 18 20 24 25 27 30 32 36 40 45 48 50 54 1 1:4 1:12 1:15 1:20 1:21 1:30 1:36 1:40 1:48 2:5 2 3 4 5 6 8 9 10 12 15 16 18 20 24 25 27 30 32 36 40 45 48 50 54 1
A = 1-place value regular numbers + 2-place value regular numbers until 2:5 B = 1-place value regular numbers C = {a/b, a є A and b є B} = {{1},{2},{3},{4},{5},{6},{8},{9},{10},{12},{15},{16},{18},{20},{2 4},{25},{27},{30},{32},{36},{40},{45},{48},{50},{54},{1,4},{1, 12},{1,15},{1,20},{1,21},{1,30},{1,36},{1,40},{1,48},{2,5},{2, 8},{2,15},{2,24},{2,30},{2,40},{2,42},{3,12},{3,20},{3,36},{3, 45},{4,3},{4,10},{4,16},{4,30},{4,48},{5,20},{5,24},{6,15},{6, 24},{6,40},{6,45},{7,12},{7,30},{8,6},{8,20},{9,36},{10,25},{ 10,40},{10,48},{11,15},{12,30},{12,48},{13,20},{13,30},{14, 24},{16,12},{16,40},{18,45},{19,12},{20,15},{20,50},{21,20} ,{21,36},{22,30},{26,40},{28,48},{31,15},{32,24},{33,20},{3 3,45},{37,30},{38,24},{40,30},{41,40},{42,40},{43,12},{53,2 0},{56,15},{57,36},{1,2,30},{1,4,48},{1,6,40},{1,7,30},{1,16, 48},{1,23,20},{1,25,20},{1,26,24},{1,33,45},{1,37,12},{1,41, 15},{1,46,40},{1,52,30},{1,55,12},{2,1,30},{2,9,36},{2,13,20 },{2,33,36},{2,36,15},{2,46,40},{2,48,45},{2,52,48},{3,7,30}, {3,14,24},{3,22,30},{3,28,20},{3,33,20},{3,50,24},{4,19,12}, {4,26,40},{4,41,15},{5,3,45},{5,12,30},{5,33,20},{5,37,30},{ 5,45,36},{6,56,40},{7,6,40},{7,40,48},{7,48,45},{8,26,15},{8 ,38,24},{8,53,20},{9,22,30},{10,7,30},{11,6,40},{11,31,12},{ 12,57,36},{13,53,20},{14,3,45},{15,21,36},{15,37,30},{16,5 2,30},{17,16,48},{17,46,40},{22,13,20},{23,2,24},{23,26,15 },{25,18,45},{25,55,12},{27,46,40},{28,7,30},{30,43,12},{35 ,33,20},{38,52,48},{42,11,15},{44,26,40},{46,52,30},{50,37 ,30},{55,33,20},{1,11,6,40},{1,15,56,15},{1,24,22,30},{1,28 ,53,20},{1,51,6,40},{1,57,11,15},{2,18,53,20},{2,22,13,20}, {2,31,52,30},{2,57,46,40},{3,42,13,20},{3,54,22,30},{4,37, 46,40},{5,55,33,20},{7,24,26,40},{11,51,6,40},{14,48,53,20 },{18,31,6,40},{23,42,13,20},{29,37,46,40},{37,2,13,20},{4 7,24,26,40},{1,32,35,33,20}}
Select numbers of C between 1 and 1+ √2 (<2,25), in the lexicographic order. This list is the same as the Price’s one. This list generates the first 15 entries of Plimpton 322, as well as the 23 additional entries reconstructed by Price, Britton, and others. These entries are obtained from the values n of C as follows: the diagonal is half the sum of n and its reciprocal: Column I’ contain the squares
- f these diagonals.
MS 3971 #3 (Friberg 2007, 252-3)
3 1- 2 3 5-8 In order for you to see five diagonals: 1,4 (is) the igi, and the igibi 56.15 […] 3b 1 2 3 4 5 6 7 The 2nd (example). 1,40 the igi, 36 the igibi. 1,40 and 36 heap, 2,16 it gives. ½ of 2,16 break, 1,8 it gives. 1,8 square, 1,17,4 it gives. 1 from 1,17,4 tear off, 17,4 it gives. 17,4 makes 32 equalsided. 32, the width, it gives. 3c 1 2 3 4 5 The 3rd. 1,30 the igi, 40 the igibi. 1,30 and 40 heap, 2,10 it gives. ½ of 2,10 break, 1,5 it gives. 1,5 square, 1,10,25. 1 from 1,10,25 tear off, 10,25 it gives. 10,25 makes <25 equalsided>. 25, the 3rd width. 3d 1 2 3 4 5 6 The 4th. 1,20 the igi, 45 the igibi. 1,30 and 45 heap, 2,5 it gives. ½ of 2,5 break, 1,2,30 it gives. 1,2,30 square, 1,5,6,15. 1 from the length tear off, 5,6,15 it gives. 5,6,15 makes 17,30 equalsided. 17,30, the width of the 4th diagonal. 3e 1 2 3 4 5 The 5th. 1,12 the igi, 50 the igibi. 1,12 and 50 heap, 2,2 it gives. ½ of 2,2 break, 1,1. 1,1 square, 1,2,1. 1 from 1,2,1 tear off, 2,1 it gives. 2,1 makes 11equalsided. 11, the 5th width. 5 diagonals.
3b 1 2 3 4 5 6 7 The 2nd (example). 1,40 the igi, 36 the igibi. 1,40 and 36 heap, 2,16 it gives. ½ of 2,16 break, 1,8 it gives. 1,8 square, 1,17,4 it gives. 1 from 1,17,4 tear off, 17,4 it gives. 17,4 makes 32 equalsided. 32, the width, it gives. u 1 40 36 2 16 1 8 1 17 4 1 17 4 32
1
Configuration of gnomon Configuration of diagonal rule
36 1,40
β δ δ2 = 1+β2 b d No [-I'] [0'] I' II' III' IV' sag şi-li-ip-tum ta]-ki-il-ti şi-li-ip - tim íb.si8 sag íb.si8
şi-li-ip-tim mu.bi.im
šá 1 in]-na-as-šà-hu-ú-ma sag i-[il-lu]-ú 59 30 1 24 30 1 59 0 15 1 59 2 49 ki 1 58 27 17 30 1 23 46 2 30 1 56 56 58 14 50 6 15 56 7 1 20 25 ki 2 57 30 45 1 23 6 45 1 55 7 41 15 33 45 1 16 41 1 50 49 ki 3 56 29 4 1 22 24 16 1 53 10 29 32 52 16 3 31 49 5 9 1 ki 4 54 10 1 20 50 1 48 54 1 40 1 5 1 37 ki 5 53 10 1 20 10 1 47 6 41 40 5 19 8 1 ki 6
- bv
50 54 40 1 18 41 20 1 43 11 56 28 26 40 38 11 59 1 ki 7 49 56 15 1 18 3 45 1 41 33 45 14 3 45 13 19 20 49 ki 8 48 6 1 16 54 1 38 33 36 36 8 1 12 49 ki 9 45 56 6 40 1 15 33 53 20 1 35 10 2 28 27 24 26 40 1 22 2 16 1 ki 10 45 1 15 1 33 45 45 1 15 ki 11 41 58 30 1 13 13 30 1 29 21 54 2 15 27 59 48 49 ki 12 40 15 1 12 15 1 27 3 45 2 41 4 49 ki 13 39 21 20 1 11 45 20 1 25 48 51 35 6 40 29 31 53 49 ki 14 37 20 1 10 40 1 23 13 46 40 28 53 ki 15 36 27 30 1 10 12 30 1 22 9 12 36 15 2 55 5 37 ki 16 32 50 50 1 8 24 10 1 17 58 56 24 1 40 7 53 16 25 ki 17 lo.e 32 1 8 1 17 4 8 17 ki 18 30 4 53 20 1 7 7 6 40 1 15 4 53 43 54 4 26 40 1 7 41 2 31 1 ki 19 29 15 1 6 45 1 14 15 33 45 39 1 29 ki 20 27 40 30 1 6 4 30 1 12 45 54 20 15 6 9 14 41 ki 21 25 1 5 1 10 25 5 13 ki 22 24 11 40 1 4 41 40 1 9 45 22 16 6 40 14 31 38 49 ki 23 22 22 1 4 2 1 8 20 16 4 11 11 32 1 ki 24 21 34 22 30 1 3 45 37 30 1 7 45 23 26 38 26 15 34 31 1 42 1 ki 25 20 51 15 1 3 31 15 1 7 14 53 46 33 45 16 41 50 49 ki 26 rev 20 4 1 3 16 1 6 42 40 16 5 1 15 49 ki 27 18 16 40 1 2 43 20 1 5 34 4 37 46 40 5 29 18 49 ki 28 17 30 1 2 30 1 5 6 15 7 25 ki 29 14 57 45 1 1 50 15 1 3 43 52 35 3 45 6 39 27 29 ki 30 13 30 1 1 30 1 3 2 15 9 41 ki 31 11 1 1 1 2 1 11 1 1 ki 32 10 14 35 1 0 52 5 1 1 44 55 12 40 25 4 55 29 13 ki 33 7 5 1 0 25 1 0 50 10 25 17 2 25 ki 34 6 20 1 0 20 1 0 40 6 40 19 3 1 ki 35 4 37 20 1 0 10 40 1 0 21 21 53 46 40 1 44 22 34 ki 36 3 52 30 1 7 30 1 0 15 0 56 15 31 8 1 ki 37 u.e. 2 27 1 3 1 6 9 49 20 1 ki 38
Plimpton 322
3 1-2 3 5-8 In order for you to see five diagonals: 1,4 (is) the igi, and the igibi 56.15 […] 3b 1 2 3 4 5 6 7 The 2nd (example). 1,40 the igi, 36 the igibi. 1,40 and 36 heap, 2,16 it gives. ½ of 2,16 break, 1,8 it gives. 1,8 square, 1,17,4 it gives. 1 from 1,17,4 tear off, 17,4 it gives. 17,4 makes 32 equalsided. 32, the width, it gives. 3c 1 2 3 4 5 The 3rd. 1,30 the igi, 40 the igibi. 1,30 and 40 heap, 2,10 it gives. ½ of 2,10 break, 1,5 it gives. 1,5 square, 1,10,25. 1 from 1,10,25 tear off, 10,25 it gives. 10,25 makes <25 equalsided>. 25, the 3rd width. 3d 1 2 3 4 5 6 The 4th. 1,20 the igi, 45 the igibi. 1,30 and 45 heap, 2,5 it gives. ½ of 2,5 br eak, 1,2,30 it gives. 1,2,30 square, 1,5,6,15. 1 from the length tear off, 5,6,15 it gives. 5,6,15 makes 17,30 equalsided. 17,30, the width of the 4th diagonal. 3e 1 2 3 4 5 The 5th. 1,12 the igi, 50 the igibi. 1,12 and 50 heap, 2,2 it gives. ½ of 2,2 break, 1,1. 1,1 square, 1,2,1. 1 from 1,2,1 tear off, 2,1 it gives. 2,1 makes 11equalsided. 11, the 5th width. 5 diagonals.