Bounded orbits Ludomir Newelski Instytut Matematyczny Uniwersytetu - - PowerPoint PPT Presentation

bounded orbits
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Bounded orbits Ludomir Newelski Instytut Matematyczny Uniwersytetu - - PowerPoint PPT Presentation

Bounded orbits Ludomir Newelski Instytut Matematyczny Uniwersytetu Wroc lawskiego November 2008 Newelski Bounded orbits Set-up T is a countable complete theory M is a model of T G is a group definable in M for simplicity: G = M . G acts


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SLIDE 1

Bounded orbits

Ludomir Newelski

Instytut Matematyczny Uniwersytetu Wroc lawskiego

November 2008

Newelski Bounded orbits

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SLIDE 2

Set-up

T is a countable complete theory M is a model of T G is a group definable in M for simplicity: G = M. G acts on S(M), by left translation: for g ∈ G, p ∈ S(M) g · p = {ϕ(g−1x) : ϕ(x) ∈ p} We work in a monster model C So: G C acts on S(C). Often we skip C in G C.

Newelski Bounded orbits

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SLIDE 3

Set-up

T is a countable complete theory M is a model of T G is a group definable in M for simplicity: G = M. G acts on S(M), by left translation: for g ∈ G, p ∈ S(M) g · p = {ϕ(g−1x) : ϕ(x) ∈ p} We work in a monster model C So: G C acts on S(C). Often we skip C in G C.

Newelski Bounded orbits

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SLIDE 4

Set-up

T is a countable complete theory M is a model of T G is a group definable in M for simplicity: G = M. G acts on S(M), by left translation: for g ∈ G, p ∈ S(M) g · p = {ϕ(g−1x) : ϕ(x) ∈ p} We work in a monster model C So: G C acts on S(C). Often we skip C in G C.

Newelski Bounded orbits

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SLIDE 5

Set-up

T is a countable complete theory M is a model of T G is a group definable in M for simplicity: G = M. G acts on S(M), by left translation: for g ∈ G, p ∈ S(M) g · p = {ϕ(g−1x) : ϕ(x) ∈ p} We work in a monster model C So: G C acts on S(C). Often we skip C in G C.

Newelski Bounded orbits

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SLIDE 6

Set-up

T is a countable complete theory M is a model of T G is a group definable in M for simplicity: G = M. G acts on S(M), by left translation: for g ∈ G, p ∈ S(M) g · p = {ϕ(g−1x) : ϕ(x) ∈ p} We work in a monster model C So: G C acts on S(C). Often we skip C in G C.

Newelski Bounded orbits

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SLIDE 7

Set-up

T is a countable complete theory M is a model of T G is a group definable in M for simplicity: G = M. G acts on S(M), by left translation: for g ∈ G, p ∈ S(M) g · p = {ϕ(g−1x) : ϕ(x) ∈ p} We work in a monster model C So: G C acts on S(C). Often we skip C in G C.

Newelski Bounded orbits

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SLIDE 8

Motivating conjecture

A conjecture of Marcin Petrykowski If there is a bounded G-orbit in S(C), then G is definably amenable. Explanation Definably amenable means there is a left-invariant measure on the family of definable subsets of G (a left-invariant Keisler measure). Bounded means of cardinality much smaller than C. Is it really an explanation ? What does bounded exactly mean ?

Newelski Bounded orbits

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SLIDE 9

Motivating conjecture

A conjecture of Marcin Petrykowski If there is a bounded G-orbit in S(C), then G is definably amenable. Explanation Definably amenable means there is a left-invariant measure on the family of definable subsets of G (a left-invariant Keisler measure). Bounded means of cardinality much smaller than C. Is it really an explanation ? What does bounded exactly mean ?

Newelski Bounded orbits

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SLIDE 10

Motivating conjecture

A conjecture of Marcin Petrykowski If there is a bounded G-orbit in S(C), then G is definably amenable. Explanation Definably amenable means there is a left-invariant measure on the family of definable subsets of G (a left-invariant Keisler measure). Bounded means of cardinality much smaller than C. Is it really an explanation ? What does bounded exactly mean ?

Newelski Bounded orbits

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SLIDE 11

Motivating conjecture

A conjecture of Marcin Petrykowski If there is a bounded G-orbit in S(C), then G is definably amenable. Explanation Definably amenable means there is a left-invariant measure on the family of definable subsets of G (a left-invariant Keisler measure). Bounded means of cardinality much smaller than C. Is it really an explanation ? What does bounded exactly mean ?

Newelski Bounded orbits

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SLIDE 12

Motivating conjecture

A conjecture of Marcin Petrykowski If there is a bounded G-orbit in S(C), then G is definably amenable. Explanation Definably amenable means there is a left-invariant measure on the family of definable subsets of G (a left-invariant Keisler measure). Bounded means of cardinality much smaller than C. Is it really an explanation ? What does bounded exactly mean ?

Newelski Bounded orbits

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SLIDE 13

Motivating conjecture

A conjecture of Marcin Petrykowski If there is a bounded G-orbit in S(C), then G is definably amenable. Explanation Definably amenable means there is a left-invariant measure on the family of definable subsets of G (a left-invariant Keisler measure). Bounded means of cardinality much smaller than C. Is it really an explanation ? What does bounded exactly mean ?

Newelski Bounded orbits

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SLIDE 14

Motivating conjecture

A conjecture of Marcin Petrykowski If there is a bounded G-orbit in S(C), then G is definably amenable. Explanation Definably amenable means there is a left-invariant measure on the family of definable subsets of G (a left-invariant Keisler measure). Bounded means of cardinality much smaller than C. Is it really an explanation ? What does bounded exactly mean ?

Newelski Bounded orbits

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SLIDE 15

Bounded orbit

Assume p ∈ S(C) and Gp has bounded size. Let Gp = {pα : α < κ}, p = p0. Choose a small M ≺ C such that all the types pα ↾M, α < κ are distinct. Let qα = pα ↾M∈ S(M), α < κ. So every qα extends uniquely to a type in the orbit Gp. We may also assume G M · q0 = {qα : α < κ}.

Newelski Bounded orbits

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SLIDE 16

Bounded orbit

Assume p ∈ S(C) and Gp has bounded size. Let Gp = {pα : α < κ}, p = p0. Choose a small M ≺ C such that all the types pα ↾M, α < κ are distinct. Let qα = pα ↾M∈ S(M), α < κ. So every qα extends uniquely to a type in the orbit Gp. We may also assume G M · q0 = {qα : α < κ}.

Newelski Bounded orbits

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SLIDE 17

Bounded orbit

Assume p ∈ S(C) and Gp has bounded size. Let Gp = {pα : α < κ}, p = p0. Choose a small M ≺ C such that all the types pα ↾M, α < κ are distinct. Let qα = pα ↾M∈ S(M), α < κ. So every qα extends uniquely to a type in the orbit Gp. We may also assume G M · q0 = {qα : α < κ}.

Newelski Bounded orbits

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SLIDE 18

Bounded orbit

Assume p ∈ S(C) and Gp has bounded size. Let Gp = {pα : α < κ}, p = p0. Choose a small M ≺ C such that all the types pα ↾M, α < κ are distinct. Let qα = pα ↾M∈ S(M), α < κ. So every qα extends uniquely to a type in the orbit Gp. We may also assume G M · q0 = {qα : α < κ}.

Newelski Bounded orbits

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SLIDE 19

Bounded orbit

Assume p ∈ S(C) and Gp has bounded size. Let Gp = {pα : α < κ}, p = p0. Choose a small M ≺ C such that all the types pα ↾M, α < κ are distinct. Let qα = pα ↾M∈ S(M), α < κ. So every qα extends uniquely to a type in the orbit Gp. We may also assume G M · q0 = {qα : α < κ}.

Newelski Bounded orbits

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SLIDE 20

Bounded orbit

Assume p ∈ S(C) and Gp has bounded size. Let Gp = {pα : α < κ}, p = p0. Choose a small M ≺ C such that all the types pα ↾M, α < κ are distinct. Let qα = pα ↾M∈ S(M), α < κ. So every qα extends uniquely to a type in the orbit Gp. We may also assume G M · q0 = {qα : α < κ}.

Newelski Bounded orbits

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SLIDE 21

Upside down

Now assume q = q0 ∈ S(M) and G Mq = {qα : α < κ} Question Does there exist p ∈ S(C) extending q0 such that every type qα extends uniquely to a type in Gp and also every type in Gp extends some qα ? (In particular, such a Gp would be a bounded orbit...) Call a type p as above good. Bad type Call a partial type r(x) = r(x, ¯ a) of size κ, consistent with q0, bad if for some g ∈ G the set gr ∧

  • 0<α<κ

[qα] is contradictory and also the set gr ∧ r is contradictory.

Newelski Bounded orbits

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SLIDE 22

Upside down

Now assume q = q0 ∈ S(M) and G Mq = {qα : α < κ} Question Does there exist p ∈ S(C) extending q0 such that every type qα extends uniquely to a type in Gp and also every type in Gp extends some qα ? (In particular, such a Gp would be a bounded orbit...) Call a type p as above good. Bad type Call a partial type r(x) = r(x, ¯ a) of size κ, consistent with q0, bad if for some g ∈ G the set gr ∧

  • 0<α<κ

[qα] is contradictory and also the set gr ∧ r is contradictory.

Newelski Bounded orbits

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SLIDE 23

Upside down

Now assume q = q0 ∈ S(M) and G Mq = {qα : α < κ} Question Does there exist p ∈ S(C) extending q0 such that every type qα extends uniquely to a type in Gp and also every type in Gp extends some qα ? (In particular, such a Gp would be a bounded orbit...) Call a type p as above good. Bad type Call a partial type r(x) = r(x, ¯ a) of size κ, consistent with q0, bad if for some g ∈ G the set gr ∧

  • 0<α<κ

[qα] is contradictory and also the set gr ∧ r is contradictory.

Newelski Bounded orbits

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SLIDE 24

Upside down

Now assume q = q0 ∈ S(M) and G Mq = {qα : α < κ} Question Does there exist p ∈ S(C) extending q0 such that every type qα extends uniquely to a type in Gp and also every type in Gp extends some qα ? (In particular, such a Gp would be a bounded orbit...) Call a type p as above good. Bad type Call a partial type r(x) = r(x, ¯ a) of size κ, consistent with q0, bad if for some g ∈ G the set gr ∧

  • 0<α<κ

[qα] is contradictory and also the set gr ∧ r is contradictory.

Newelski Bounded orbits

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SLIDE 25

Upside down

Now assume q = q0 ∈ S(M) and G Mq = {qα : α < κ} Question Does there exist p ∈ S(C) extending q0 such that every type qα extends uniquely to a type in Gp and also every type in Gp extends some qα ? (In particular, such a Gp would be a bounded orbit...) Call a type p as above good. Bad type Call a partial type r(x) = r(x, ¯ a) of size κ, consistent with q0, bad if for some g ∈ G the set gr ∧

  • 0<α<κ

[qα] is contradictory and also the set gr ∧ r is contradictory.

Newelski Bounded orbits

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SLIDE 26

Upside down

Now assume q = q0 ∈ S(M) and G Mq = {qα : α < κ} Question Does there exist p ∈ S(C) extending q0 such that every type qα extends uniquely to a type in Gp and also every type in Gp extends some qα ? (In particular, such a Gp would be a bounded orbit...) Call a type p as above good. Bad type Call a partial type r(x) = r(x, ¯ a) of size κ, consistent with q0, bad if for some g ∈ G the set gr ∧

  • 0<α<κ

[qα] is contradictory and also the set gr ∧ r is contradictory.

Newelski Bounded orbits

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SLIDE 27

Upside down

Whether a given type r(x, ¯ a) is bad, depends only on tp(¯ a/M). A type p ∈ S(C) containing q0 is good iff p contains no bad type. Hence: A good type exists iff in S(C) (∗)

  • bad r
  • ϕ∈r

[¬ϕ] = ∅

Newelski Bounded orbits

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SLIDE 28

Upside down

Whether a given type r(x, ¯ a) is bad, depends only on tp(¯ a/M). A type p ∈ S(C) containing q0 is good iff p contains no bad type. Hence: A good type exists iff in S(C) (∗)

  • bad r
  • ϕ∈r

[¬ϕ] = ∅

Newelski Bounded orbits

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SLIDE 29

Upside down

Whether a given type r(x, ¯ a) is bad, depends only on tp(¯ a/M). A type p ∈ S(C) containing q0 is good iff p contains no bad type. Hence: A good type exists iff in S(C) (∗)

  • bad r
  • ϕ∈r

[¬ϕ] = ∅

Newelski Bounded orbits

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SLIDE 30

Absoluteness issue

Given q and M as above, we can ask if there is a bounded orbit in S(C) related to q as in the question. Does the answer not depend on C ? Assume C′ ≻ C and (∗) holds in C. Does (∗) hold in C′ ?

Newelski Bounded orbits

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SLIDE 31

Absoluteness issue

Given q and M as above, we can ask if there is a bounded orbit in S(C) related to q as in the question. Does the answer not depend on C ? Assume C′ ≻ C and (∗) holds in C. Does (∗) hold in C′ ?

Newelski Bounded orbits

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SLIDE 32

Absoluteness issue

Given q and M as above, we can ask if there is a bounded orbit in S(C) related to q as in the question. Does the answer not depend on C ? Assume C′ ≻ C and (∗) holds in C. Does (∗) hold in C′ ?

Newelski Bounded orbits

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SLIDE 33

A (simplified) generalized set-up

Assume Φ = {ϕn(x, y) : n < ω} and s(y) is a type over ∅. For A ⊆ C let X(A) =

  • a∈s(A)
  • n<ω

[ϕn(x, a)] ⊆ S(C) In fact, ⊆ S(A). Questions

  • 1. Suppose X(C) = ∅ and C′ ≻ C. Is X(C′) = ∅ ?
  • 2. Suppose X(C) = ∅. What is the minimal κ = κ(Φ) such that

for some A ⊆ C of power κ, X(A) = ∅ ? Let µ = sup{κ(Φ) : Φ, T countable}. What is µ ? What is the Hanff number for existence of bounded orbits ? How large should a monster model C be ?

Newelski Bounded orbits

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SLIDE 34

A (simplified) generalized set-up

Assume Φ = {ϕn(x, y) : n < ω} and s(y) is a type over ∅. For A ⊆ C let X(A) =

  • a∈s(A)
  • n<ω

[ϕn(x, a)] ⊆ S(C) In fact, ⊆ S(A). Questions

  • 1. Suppose X(C) = ∅ and C′ ≻ C. Is X(C′) = ∅ ?
  • 2. Suppose X(C) = ∅. What is the minimal κ = κ(Φ) such that

for some A ⊆ C of power κ, X(A) = ∅ ? Let µ = sup{κ(Φ) : Φ, T countable}. What is µ ? What is the Hanff number for existence of bounded orbits ? How large should a monster model C be ?

Newelski Bounded orbits

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SLIDE 35

A (simplified) generalized set-up

Assume Φ = {ϕn(x, y) : n < ω} and s(y) is a type over ∅. For A ⊆ C let X(A) =

  • a∈s(A)
  • n<ω

[ϕn(x, a)] ⊆ S(C) In fact, ⊆ S(A). Questions

  • 1. Suppose X(C) = ∅ and C′ ≻ C. Is X(C′) = ∅ ?
  • 2. Suppose X(C) = ∅. What is the minimal κ = κ(Φ) such that

for some A ⊆ C of power κ, X(A) = ∅ ? Let µ = sup{κ(Φ) : Φ, T countable}. What is µ ? What is the Hanff number for existence of bounded orbits ? How large should a monster model C be ?

Newelski Bounded orbits

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SLIDE 36

A (simplified) generalized set-up

Assume Φ = {ϕn(x, y) : n < ω} and s(y) is a type over ∅. For A ⊆ C let X(A) =

  • a∈s(A)
  • n<ω

[ϕn(x, a)] ⊆ S(C) In fact, ⊆ S(A). Questions

  • 1. Suppose X(C) = ∅ and C′ ≻ C. Is X(C′) = ∅ ?
  • 2. Suppose X(C) = ∅. What is the minimal κ = κ(Φ) such that

for some A ⊆ C of power κ, X(A) = ∅ ? Let µ = sup{κ(Φ) : Φ, T countable}. What is µ ? What is the Hanff number for existence of bounded orbits ? How large should a monster model C be ?

Newelski Bounded orbits

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SLIDE 37

A (simplified) generalized set-up

Assume Φ = {ϕn(x, y) : n < ω} and s(y) is a type over ∅. For A ⊆ C let X(A) =

  • a∈s(A)
  • n<ω

[ϕn(x, a)] ⊆ S(C) In fact, ⊆ S(A). Questions

  • 1. Suppose X(C) = ∅ and C′ ≻ C. Is X(C′) = ∅ ?
  • 2. Suppose X(C) = ∅. What is the minimal κ = κ(Φ) such that

for some A ⊆ C of power κ, X(A) = ∅ ? Let µ = sup{κ(Φ) : Φ, T countable}. What is µ ? What is the Hanff number for existence of bounded orbits ? How large should a monster model C be ?

Newelski Bounded orbits

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SLIDE 38

A (simplified) generalized set-up

Assume Φ = {ϕn(x, y) : n < ω} and s(y) is a type over ∅. For A ⊆ C let X(A) =

  • a∈s(A)
  • n<ω

[ϕn(x, a)] ⊆ S(C) In fact, ⊆ S(A). Questions

  • 1. Suppose X(C) = ∅ and C′ ≻ C. Is X(C′) = ∅ ?
  • 2. Suppose X(C) = ∅. What is the minimal κ = κ(Φ) such that

for some A ⊆ C of power κ, X(A) = ∅ ? Let µ = sup{κ(Φ) : Φ, T countable}. What is µ ? What is the Hanff number for existence of bounded orbits ? How large should a monster model C be ?

Newelski Bounded orbits

slide-39
SLIDE 39

A (simplified) generalized set-up

Assume Φ = {ϕn(x, y) : n < ω} and s(y) is a type over ∅. For A ⊆ C let X(A) =

  • a∈s(A)
  • n<ω

[ϕn(x, a)] ⊆ S(C) In fact, ⊆ S(A). Questions

  • 1. Suppose X(C) = ∅ and C′ ≻ C. Is X(C′) = ∅ ?
  • 2. Suppose X(C) = ∅. What is the minimal κ = κ(Φ) such that

for some A ⊆ C of power κ, X(A) = ∅ ? Let µ = sup{κ(Φ) : Φ, T countable}. What is µ ? What is the Hanff number for existence of bounded orbits ? How large should a monster model C be ?

Newelski Bounded orbits

slide-40
SLIDE 40

A (simplified) generalized set-up

Assume Φ = {ϕn(x, y) : n < ω} and s(y) is a type over ∅. For A ⊆ C let X(A) =

  • a∈s(A)
  • n<ω

[ϕn(x, a)] ⊆ S(C) In fact, ⊆ S(A). Questions

  • 1. Suppose X(C) = ∅ and C′ ≻ C. Is X(C′) = ∅ ?
  • 2. Suppose X(C) = ∅. What is the minimal κ = κ(Φ) such that

for some A ⊆ C of power κ, X(A) = ∅ ? Let µ = sup{κ(Φ) : Φ, T countable}. What is µ ? What is the Hanff number for existence of bounded orbits ? How large should a monster model C be ?

Newelski Bounded orbits

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SLIDE 41

A (simplified) generalized set-up

Assume Φ = {ϕn(x, y) : n < ω} and s(y) is a type over ∅. For A ⊆ C let X(A) =

  • a∈s(A)
  • n<ω

[ϕn(x, a)] ⊆ S(C) In fact, ⊆ S(A). Questions

  • 1. Suppose X(C) = ∅ and C′ ≻ C. Is X(C′) = ∅ ?
  • 2. Suppose X(C) = ∅. What is the minimal κ = κ(Φ) such that

for some A ⊆ C of power κ, X(A) = ∅ ? Let µ = sup{κ(Φ) : Φ, T countable}. What is µ ? What is the Hanff number for existence of bounded orbits ? How large should a monster model C be ?

Newelski Bounded orbits

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SLIDE 42

A partial result on the motivating conjecture

Theorem (M.Petrykowski) If for some p ∈ S(C), the orbit Gp is bounded, then G ∞ exists. Explanation G ∞

A is the smallest A-invariant subgroup of G, of bounded index.

If for every A, G ∞

A = G ∞ ∅ , we call this group the ∞-component of

G, or G ∞. Absoluteness of existence of G ∞

  • 1. If for some A, we have that G ∞

A = G ∞ ∅ , then this holds for some

countable A.

  • 2. Existence of G ∞ is absolute both ways:

(a) it does not depend on the monster model, (b) it does not depend on the set-theoretical universe.

Newelski Bounded orbits

slide-43
SLIDE 43

A partial result on the motivating conjecture

Theorem (M.Petrykowski) If for some p ∈ S(C), the orbit Gp is bounded, then G ∞ exists. Explanation G ∞

A is the smallest A-invariant subgroup of G, of bounded index.

If for every A, G ∞

A = G ∞ ∅ , we call this group the ∞-component of

G, or G ∞. Absoluteness of existence of G ∞

  • 1. If for some A, we have that G ∞

A = G ∞ ∅ , then this holds for some

countable A.

  • 2. Existence of G ∞ is absolute both ways:

(a) it does not depend on the monster model, (b) it does not depend on the set-theoretical universe.

Newelski Bounded orbits

slide-44
SLIDE 44

A partial result on the motivating conjecture

Theorem (M.Petrykowski) If for some p ∈ S(C), the orbit Gp is bounded, then G ∞ exists. Explanation G ∞

A is the smallest A-invariant subgroup of G, of bounded index.

If for every A, G ∞

A = G ∞ ∅ , we call this group the ∞-component of

G, or G ∞. Absoluteness of existence of G ∞

  • 1. If for some A, we have that G ∞

A = G ∞ ∅ , then this holds for some

countable A.

  • 2. Existence of G ∞ is absolute both ways:

(a) it does not depend on the monster model, (b) it does not depend on the set-theoretical universe.

Newelski Bounded orbits

slide-45
SLIDE 45

A partial result on the motivating conjecture

Theorem (M.Petrykowski) If for some p ∈ S(C), the orbit Gp is bounded, then G ∞ exists. Explanation G ∞

A is the smallest A-invariant subgroup of G, of bounded index.

If for every A, G ∞

A = G ∞ ∅ , we call this group the ∞-component of

G, or G ∞. Absoluteness of existence of G ∞

  • 1. If for some A, we have that G ∞

A = G ∞ ∅ , then this holds for some

countable A.

  • 2. Existence of G ∞ is absolute both ways:

(a) it does not depend on the monster model, (b) it does not depend on the set-theoretical universe.

Newelski Bounded orbits

slide-46
SLIDE 46

A partial result on the motivating conjecture

Theorem (M.Petrykowski) If for some p ∈ S(C), the orbit Gp is bounded, then G ∞ exists. Explanation G ∞

A is the smallest A-invariant subgroup of G, of bounded index.

If for every A, G ∞

A = G ∞ ∅ , we call this group the ∞-component of

G, or G ∞. Absoluteness of existence of G ∞

  • 1. If for some A, we have that G ∞

A = G ∞ ∅ , then this holds for some

countable A.

  • 2. Existence of G ∞ is absolute both ways:

(a) it does not depend on the monster model, (b) it does not depend on the set-theoretical universe.

Newelski Bounded orbits

slide-47
SLIDE 47

A partial result on the motivating conjecture

Theorem (M.Petrykowski) If for some p ∈ S(C), the orbit Gp is bounded, then G ∞ exists. Explanation G ∞

A is the smallest A-invariant subgroup of G, of bounded index.

If for every A, G ∞

A = G ∞ ∅ , we call this group the ∞-component of

G, or G ∞. Absoluteness of existence of G ∞

  • 1. If for some A, we have that G ∞

A = G ∞ ∅ , then this holds for some

countable A.

  • 2. Existence of G ∞ is absolute both ways:

(a) it does not depend on the monster model, (b) it does not depend on the set-theoretical universe.

Newelski Bounded orbits

slide-48
SLIDE 48

A local version

In the theorem, a vague assumption of existence of a bounded

  • rbit implies an absolute conclusion:

existence of G ∞. Theorem (A local, absolute version) Assume M is κ+-saturated, p ∈ S(M) and |Gp| < 2κ. Then G ∞ exists. Another Hanff number Assume the assumption of the theorem holds for some κ (that causes G ∞ exist). What is the minimal such κ then ? If G ∞ exists by this reason, how far do we have to seek for the relevant κ ?

Newelski Bounded orbits

slide-49
SLIDE 49

A local version

In the theorem, a vague assumption of existence of a bounded

  • rbit implies an absolute conclusion:

existence of G ∞. Theorem (A local, absolute version) Assume M is κ+-saturated, p ∈ S(M) and |Gp| < 2κ. Then G ∞ exists. Another Hanff number Assume the assumption of the theorem holds for some κ (that causes G ∞ exist). What is the minimal such κ then ? If G ∞ exists by this reason, how far do we have to seek for the relevant κ ?

Newelski Bounded orbits

slide-50
SLIDE 50

A local version

In the theorem, a vague assumption of existence of a bounded

  • rbit implies an absolute conclusion:

existence of G ∞. Theorem (A local, absolute version) Assume M is κ+-saturated, p ∈ S(M) and |Gp| < 2κ. Then G ∞ exists. Another Hanff number Assume the assumption of the theorem holds for some κ (that causes G ∞ exist). What is the minimal such κ then ? If G ∞ exists by this reason, how far do we have to seek for the relevant κ ?

Newelski Bounded orbits

slide-51
SLIDE 51

A local version

In the theorem, a vague assumption of existence of a bounded

  • rbit implies an absolute conclusion:

existence of G ∞. Theorem (A local, absolute version) Assume M is κ+-saturated, p ∈ S(M) and |Gp| < 2κ. Then G ∞ exists. Another Hanff number Assume the assumption of the theorem holds for some κ (that causes G ∞ exist). What is the minimal such κ then ? If G ∞ exists by this reason, how far do we have to seek for the relevant κ ?

Newelski Bounded orbits

slide-52
SLIDE 52

A local version

In the theorem, a vague assumption of existence of a bounded

  • rbit implies an absolute conclusion:

existence of G ∞. Theorem (A local, absolute version) Assume M is κ+-saturated, p ∈ S(M) and |Gp| < 2κ. Then G ∞ exists. Another Hanff number Assume the assumption of the theorem holds for some κ (that causes G ∞ exist). What is the minimal such κ then ? If G ∞ exists by this reason, how far do we have to seek for the relevant κ ?

Newelski Bounded orbits

slide-53
SLIDE 53

A local version

In the theorem, a vague assumption of existence of a bounded

  • rbit implies an absolute conclusion:

existence of G ∞. Theorem (A local, absolute version) Assume M is κ+-saturated, p ∈ S(M) and |Gp| < 2κ. Then G ∞ exists. Another Hanff number Assume the assumption of the theorem holds for some κ (that causes G ∞ exist). What is the minimal such κ then ? If G ∞ exists by this reason, how far do we have to seek for the relevant κ ?

Newelski Bounded orbits

slide-54
SLIDE 54

A local version

In the theorem, a vague assumption of existence of a bounded

  • rbit implies an absolute conclusion:

existence of G ∞. Theorem (A local, absolute version) Assume M is κ+-saturated, p ∈ S(M) and |Gp| < 2κ. Then G ∞ exists. Another Hanff number Assume the assumption of the theorem holds for some κ (that causes G ∞ exist). What is the minimal such κ then ? If G ∞ exists by this reason, how far do we have to seek for the relevant κ ?

Newelski Bounded orbits

slide-55
SLIDE 55

A local version

In the theorem, a vague assumption of existence of a bounded

  • rbit implies an absolute conclusion:

existence of G ∞. Theorem (A local, absolute version) Assume M is κ+-saturated, p ∈ S(M) and |Gp| < 2κ. Then G ∞ exists. Another Hanff number Assume the assumption of the theorem holds for some κ (that causes G ∞ exist). What is the minimal such κ then ? If G ∞ exists by this reason, how far do we have to seek for the relevant κ ?

Newelski Bounded orbits

slide-56
SLIDE 56

A local version

In the theorem, a vague assumption of existence of a bounded

  • rbit implies an absolute conclusion:

existence of G ∞. Theorem (A local, absolute version) Assume M is κ+-saturated, p ∈ S(M) and |Gp| < 2κ. Then G ∞ exists. Another Hanff number Assume the assumption of the theorem holds for some κ (that causes G ∞ exist). What is the minimal such κ then ? If G ∞ exists by this reason, how far do we have to seek for the relevant κ ?

Newelski Bounded orbits

slide-57
SLIDE 57

Some topological dynamics

S(C) is a G C-flow, that is, G C acts on S(C) by homeomorphisms. Definitions

  • 1. A type p ∈ S(C) is almost periodic if the sub-flow cl(Gp) is

minimal.

  • 2. APer = {p ∈ S(C) : p is almost periodic}.
  • 3. A set U ⊆ G is (left) weakly generic if for some non-generic

V ⊆ G, the set U ∪ V is (left) generic.

  • 4. A type p ∈ S(C) is weakly generic if ϕ(G) is weakly generic for

every formula ϕ ∈ p.

  • 5. WGen = {p ∈ S(C) : p is weakly generic}.

Properties

  • 1. APer is non-empty and dense in WGen.
  • 2. If a generic type exists, then every weakly generic type is

generic.

Newelski Bounded orbits

slide-58
SLIDE 58

Some topological dynamics

S(C) is a G C-flow, that is, G C acts on S(C) by homeomorphisms. Definitions

  • 1. A type p ∈ S(C) is almost periodic if the sub-flow cl(Gp) is

minimal.

  • 2. APer = {p ∈ S(C) : p is almost periodic}.
  • 3. A set U ⊆ G is (left) weakly generic if for some non-generic

V ⊆ G, the set U ∪ V is (left) generic.

  • 4. A type p ∈ S(C) is weakly generic if ϕ(G) is weakly generic for

every formula ϕ ∈ p.

  • 5. WGen = {p ∈ S(C) : p is weakly generic}.

Properties

  • 1. APer is non-empty and dense in WGen.
  • 2. If a generic type exists, then every weakly generic type is

generic.

Newelski Bounded orbits

slide-59
SLIDE 59

Some topological dynamics

S(C) is a G C-flow, that is, G C acts on S(C) by homeomorphisms. Definitions

  • 1. A type p ∈ S(C) is almost periodic if the sub-flow cl(Gp) is

minimal.

  • 2. APer = {p ∈ S(C) : p is almost periodic}.
  • 3. A set U ⊆ G is (left) weakly generic if for some non-generic

V ⊆ G, the set U ∪ V is (left) generic.

  • 4. A type p ∈ S(C) is weakly generic if ϕ(G) is weakly generic for

every formula ϕ ∈ p.

  • 5. WGen = {p ∈ S(C) : p is weakly generic}.

Properties

  • 1. APer is non-empty and dense in WGen.
  • 2. If a generic type exists, then every weakly generic type is

generic.

Newelski Bounded orbits

slide-60
SLIDE 60

Some topological dynamics

S(C) is a G C-flow, that is, G C acts on S(C) by homeomorphisms. Definitions

  • 1. A type p ∈ S(C) is almost periodic if the sub-flow cl(Gp) is

minimal.

  • 2. APer = {p ∈ S(C) : p is almost periodic}.
  • 3. A set U ⊆ G is (left) weakly generic if for some non-generic

V ⊆ G, the set U ∪ V is (left) generic.

  • 4. A type p ∈ S(C) is weakly generic if ϕ(G) is weakly generic for

every formula ϕ ∈ p.

  • 5. WGen = {p ∈ S(C) : p is weakly generic}.

Properties

  • 1. APer is non-empty and dense in WGen.
  • 2. If a generic type exists, then every weakly generic type is

generic.

Newelski Bounded orbits

slide-61
SLIDE 61

Some topological dynamics

S(C) is a G C-flow, that is, G C acts on S(C) by homeomorphisms. Definitions

  • 1. A type p ∈ S(C) is almost periodic if the sub-flow cl(Gp) is

minimal.

  • 2. APer = {p ∈ S(C) : p is almost periodic}.
  • 3. A set U ⊆ G is (left) weakly generic if for some non-generic

V ⊆ G, the set U ∪ V is (left) generic.

  • 4. A type p ∈ S(C) is weakly generic if ϕ(G) is weakly generic for

every formula ϕ ∈ p.

  • 5. WGen = {p ∈ S(C) : p is weakly generic}.

Properties

  • 1. APer is non-empty and dense in WGen.
  • 2. If a generic type exists, then every weakly generic type is

generic.

Newelski Bounded orbits

slide-62
SLIDE 62

Some topological dynamics

S(C) is a G C-flow, that is, G C acts on S(C) by homeomorphisms. Definitions

  • 1. A type p ∈ S(C) is almost periodic if the sub-flow cl(Gp) is

minimal.

  • 2. APer = {p ∈ S(C) : p is almost periodic}.
  • 3. A set U ⊆ G is (left) weakly generic if for some non-generic

V ⊆ G, the set U ∪ V is (left) generic.

  • 4. A type p ∈ S(C) is weakly generic if ϕ(G) is weakly generic for

every formula ϕ ∈ p.

  • 5. WGen = {p ∈ S(C) : p is weakly generic}.

Properties

  • 1. APer is non-empty and dense in WGen.
  • 2. If a generic type exists, then every weakly generic type is

generic.

Newelski Bounded orbits

slide-63
SLIDE 63

Some topological dynamics

S(C) is a G C-flow, that is, G C acts on S(C) by homeomorphisms. Definitions

  • 1. A type p ∈ S(C) is almost periodic if the sub-flow cl(Gp) is

minimal.

  • 2. APer = {p ∈ S(C) : p is almost periodic}.
  • 3. A set U ⊆ G is (left) weakly generic if for some non-generic

V ⊆ G, the set U ∪ V is (left) generic.

  • 4. A type p ∈ S(C) is weakly generic if ϕ(G) is weakly generic for

every formula ϕ ∈ p.

  • 5. WGen = {p ∈ S(C) : p is weakly generic}.

Properties

  • 1. APer is non-empty and dense in WGen.
  • 2. If a generic type exists, then every weakly generic type is

generic.

Newelski Bounded orbits

slide-64
SLIDE 64

Some topological dynamics

S(C) is a G C-flow, that is, G C acts on S(C) by homeomorphisms. Definitions

  • 1. A type p ∈ S(C) is almost periodic if the sub-flow cl(Gp) is

minimal.

  • 2. APer = {p ∈ S(C) : p is almost periodic}.
  • 3. A set U ⊆ G is (left) weakly generic if for some non-generic

V ⊆ G, the set U ∪ V is (left) generic.

  • 4. A type p ∈ S(C) is weakly generic if ϕ(G) is weakly generic for

every formula ϕ ∈ p.

  • 5. WGen = {p ∈ S(C) : p is weakly generic}.

Properties

  • 1. APer is non-empty and dense in WGen.
  • 2. If a generic type exists, then every weakly generic type is

generic.

Newelski Bounded orbits

slide-65
SLIDE 65

Some topological dynamics

S(C) is a G C-flow, that is, G C acts on S(C) by homeomorphisms. Definitions

  • 1. A type p ∈ S(C) is almost periodic if the sub-flow cl(Gp) is

minimal.

  • 2. APer = {p ∈ S(C) : p is almost periodic}.
  • 3. A set U ⊆ G is (left) weakly generic if for some non-generic

V ⊆ G, the set U ∪ V is (left) generic.

  • 4. A type p ∈ S(C) is weakly generic if ϕ(G) is weakly generic for

every formula ϕ ∈ p.

  • 5. WGen = {p ∈ S(C) : p is weakly generic}.

Properties

  • 1. APer is non-empty and dense in WGen.
  • 2. If a generic type exists, then every weakly generic type is

generic.

Newelski Bounded orbits

slide-66
SLIDE 66

Some topological dynamics

S(C) is a G C-flow, that is, G C acts on S(C) by homeomorphisms. Definitions

  • 1. A type p ∈ S(C) is almost periodic if the sub-flow cl(Gp) is

minimal.

  • 2. APer = {p ∈ S(C) : p is almost periodic}.
  • 3. A set U ⊆ G is (left) weakly generic if for some non-generic

V ⊆ G, the set U ∪ V is (left) generic.

  • 4. A type p ∈ S(C) is weakly generic if ϕ(G) is weakly generic for

every formula ϕ ∈ p.

  • 5. WGen = {p ∈ S(C) : p is weakly generic}.

Properties

  • 1. APer is non-empty and dense in WGen.
  • 2. If a generic type exists, then every weakly generic type is

generic.

Newelski Bounded orbits

slide-67
SLIDE 67

Bounded orbits again

Bounded minimal flow Assume for some p ∈ S(C), the orbit Gp is bounded. Then for some almost periodic type q ∈ S(C), the minimal flow cl(Gq) is bounded. Proof. Since Gp is bounded, also cl(Gp) is bounded. | cl(Gp)| ≤ 22|Gp| But cl(Gp) is a sub-flow, hence it contains a minimal sub-flow, that is bounded, too.

Newelski Bounded orbits

slide-68
SLIDE 68

Bounded orbits again

Bounded minimal flow Assume for some p ∈ S(C), the orbit Gp is bounded. Then for some almost periodic type q ∈ S(C), the minimal flow cl(Gq) is bounded. Proof. Since Gp is bounded, also cl(Gp) is bounded. | cl(Gp)| ≤ 22|Gp| But cl(Gp) is a sub-flow, hence it contains a minimal sub-flow, that is bounded, too.

Newelski Bounded orbits

slide-69
SLIDE 69

Bounded orbits again

Bounded minimal flow Assume for some p ∈ S(C), the orbit Gp is bounded. Then for some almost periodic type q ∈ S(C), the minimal flow cl(Gq) is bounded. Proof. Since Gp is bounded, also cl(Gp) is bounded. | cl(Gp)| ≤ 22|Gp| But cl(Gp) is a sub-flow, hence it contains a minimal sub-flow, that is bounded, too.

Newelski Bounded orbits

slide-70
SLIDE 70

Bounded orbits again

Bounded minimal flow Assume for some p ∈ S(C), the orbit Gp is bounded. Then for some almost periodic type q ∈ S(C), the minimal flow cl(Gq) is bounded. Proof. Since Gp is bounded, also cl(Gp) is bounded. | cl(Gp)| ≤ 22|Gp| But cl(Gp) is a sub-flow, hence it contains a minimal sub-flow, that is bounded, too.

Newelski Bounded orbits

slide-71
SLIDE 71

Bounded orbits again

Bounded minimal flow Assume for some p ∈ S(C), the orbit Gp is bounded. Then for some almost periodic type q ∈ S(C), the minimal flow cl(Gq) is bounded. Proof. Since Gp is bounded, also cl(Gp) is bounded. | cl(Gp)| ≤ 22|Gp| But cl(Gp) is a sub-flow, hence it contains a minimal sub-flow, that is bounded, too.

Newelski Bounded orbits

slide-72
SLIDE 72

Bounded WGen

Hence, if there is a bounded orbit in S(C), then there is a bounded

  • rbit consisting of weakly generic types. Now consider the case,

where WGen is bounded. Definition Let ϕ(x, y) be a formula.Define an equivalence relation ∼ϕ: a ∼ϕ b ⇐ ⇒ ϕ(x, a)△ϕ(x, b) is not weakly generic Since WGen is bounded, ∼ϕ is a bounded invariant equivalence relation, with ≤ 2ℵ0 classes. Absolute bound on WGen 1.Assume WGen is bounded.Then |WGen| ≤ 22ℵ0, and this does not depend on the monster model, i.e. it is absolute model-theoretically..

  • 2. The boundedness of WGen is absolute set-theoretically, too.

Newelski Bounded orbits

slide-73
SLIDE 73

Bounded WGen

Hence, if there is a bounded orbit in S(C), then there is a bounded

  • rbit consisting of weakly generic types. Now consider the case,

where WGen is bounded. Definition Let ϕ(x, y) be a formula.Define an equivalence relation ∼ϕ: a ∼ϕ b ⇐ ⇒ ϕ(x, a)△ϕ(x, b) is not weakly generic Since WGen is bounded, ∼ϕ is a bounded invariant equivalence relation, with ≤ 2ℵ0 classes. Absolute bound on WGen 1.Assume WGen is bounded.Then |WGen| ≤ 22ℵ0, and this does not depend on the monster model, i.e. it is absolute model-theoretically..

  • 2. The boundedness of WGen is absolute set-theoretically, too.

Newelski Bounded orbits

slide-74
SLIDE 74

Bounded WGen

Hence, if there is a bounded orbit in S(C), then there is a bounded

  • rbit consisting of weakly generic types. Now consider the case,

where WGen is bounded. Definition Let ϕ(x, y) be a formula.Define an equivalence relation ∼ϕ: a ∼ϕ b ⇐ ⇒ ϕ(x, a)△ϕ(x, b) is not weakly generic Since WGen is bounded, ∼ϕ is a bounded invariant equivalence relation, with ≤ 2ℵ0 classes. Absolute bound on WGen 1.Assume WGen is bounded.Then |WGen| ≤ 22ℵ0, and this does not depend on the monster model, i.e. it is absolute model-theoretically..

  • 2. The boundedness of WGen is absolute set-theoretically, too.

Newelski Bounded orbits

slide-75
SLIDE 75

Bounded WGen

Hence, if there is a bounded orbit in S(C), then there is a bounded

  • rbit consisting of weakly generic types. Now consider the case,

where WGen is bounded. Definition Let ϕ(x, y) be a formula.Define an equivalence relation ∼ϕ: a ∼ϕ b ⇐ ⇒ ϕ(x, a)△ϕ(x, b) is not weakly generic Since WGen is bounded, ∼ϕ is a bounded invariant equivalence relation, with ≤ 2ℵ0 classes. Absolute bound on WGen 1.Assume WGen is bounded.Then |WGen| ≤ 22ℵ0, and this does not depend on the monster model, i.e. it is absolute model-theoretically..

  • 2. The boundedness of WGen is absolute set-theoretically, too.

Newelski Bounded orbits

slide-76
SLIDE 76

Bounded WGen

Hence, if there is a bounded orbit in S(C), then there is a bounded

  • rbit consisting of weakly generic types. Now consider the case,

where WGen is bounded. Definition Let ϕ(x, y) be a formula.Define an equivalence relation ∼ϕ: a ∼ϕ b ⇐ ⇒ ϕ(x, a)△ϕ(x, b) is not weakly generic Since WGen is bounded, ∼ϕ is a bounded invariant equivalence relation, with ≤ 2ℵ0 classes. Absolute bound on WGen 1.Assume WGen is bounded.Then |WGen| ≤ 22ℵ0, and this does not depend on the monster model, i.e. it is absolute model-theoretically..

  • 2. The boundedness of WGen is absolute set-theoretically, too.

Newelski Bounded orbits

slide-77
SLIDE 77

Bounded WGen

Hence, if there is a bounded orbit in S(C), then there is a bounded

  • rbit consisting of weakly generic types. Now consider the case,

where WGen is bounded. Definition Let ϕ(x, y) be a formula.Define an equivalence relation ∼ϕ: a ∼ϕ b ⇐ ⇒ ϕ(x, a)△ϕ(x, b) is not weakly generic Since WGen is bounded, ∼ϕ is a bounded invariant equivalence relation, with ≤ 2ℵ0 classes. Absolute bound on WGen 1.Assume WGen is bounded.Then |WGen| ≤ 22ℵ0, and this does not depend on the monster model, i.e. it is absolute model-theoretically..

  • 2. The boundedness of WGen is absolute set-theoretically, too.

Newelski Bounded orbits

slide-78
SLIDE 78

Bounded WGen

Hence, if there is a bounded orbit in S(C), then there is a bounded

  • rbit consisting of weakly generic types. Now consider the case,

where WGen is bounded. Definition Let ϕ(x, y) be a formula.Define an equivalence relation ∼ϕ: a ∼ϕ b ⇐ ⇒ ϕ(x, a)△ϕ(x, b) is not weakly generic Since WGen is bounded, ∼ϕ is a bounded invariant equivalence relation, with ≤ 2ℵ0 classes. Absolute bound on WGen 1.Assume WGen is bounded.Then |WGen| ≤ 22ℵ0, and this does not depend on the monster model, i.e. it is absolute model-theoretically..

  • 2. The boundedness of WGen is absolute set-theoretically, too.

Newelski Bounded orbits

slide-79
SLIDE 79

Bounded WGen

Hence, if there is a bounded orbit in S(C), then there is a bounded

  • rbit consisting of weakly generic types. Now consider the case,

where WGen is bounded. Definition Let ϕ(x, y) be a formula.Define an equivalence relation ∼ϕ: a ∼ϕ b ⇐ ⇒ ϕ(x, a)△ϕ(x, b) is not weakly generic Since WGen is bounded, ∼ϕ is a bounded invariant equivalence relation, with ≤ 2ℵ0 classes. Absolute bound on WGen 1.Assume WGen is bounded.Then |WGen| ≤ 22ℵ0, and this does not depend on the monster model, i.e. it is absolute model-theoretically..

  • 2. The boundedness of WGen is absolute set-theoretically, too.

Newelski Bounded orbits

slide-80
SLIDE 80

Bounded WGen

Hence, if there is a bounded orbit in S(C), then there is a bounded

  • rbit consisting of weakly generic types. Now consider the case,

where WGen is bounded. Definition Let ϕ(x, y) be a formula.Define an equivalence relation ∼ϕ: a ∼ϕ b ⇐ ⇒ ϕ(x, a)△ϕ(x, b) is not weakly generic Since WGen is bounded, ∼ϕ is a bounded invariant equivalence relation, with ≤ 2ℵ0 classes. Absolute bound on WGen 1.Assume WGen is bounded.Then |WGen| ≤ 22ℵ0, and this does not depend on the monster model, i.e. it is absolute model-theoretically..

  • 2. The boundedness of WGen is absolute set-theoretically, too.

Newelski Bounded orbits

slide-81
SLIDE 81

Bounded WGen

Hence, if there is a bounded orbit in S(C), then there is a bounded

  • rbit consisting of weakly generic types. Now consider the case,

where WGen is bounded. Definition Let ϕ(x, y) be a formula.Define an equivalence relation ∼ϕ: a ∼ϕ b ⇐ ⇒ ϕ(x, a)△ϕ(x, b) is not weakly generic Since WGen is bounded, ∼ϕ is a bounded invariant equivalence relation, with ≤ 2ℵ0 classes. Absolute bound on WGen 1.Assume WGen is bounded.Then |WGen| ≤ 22ℵ0, and this does not depend on the monster model, i.e. it is absolute model-theoretically..

  • 2. The boundedness of WGen is absolute set-theoretically, too.

Newelski Bounded orbits

slide-82
SLIDE 82

The case of very bounded WGen

Example There is a (semi)-example, where WGen is bounded, of size 22ℵ0. Definition Let p ∈ WGen. We say that p is countably stationary if for some countable A ⊂ C, p is the only weakly generic type extending p ↾A. Lemma Assume |WGen| ≤ 2ℵ0 and 2ℵ0 < 2ℵ1. Then there is a type p ∈ WGen, that is countably stationary. Proof. If not, build a tree of weakly generic types of height ℵ1, getting 2ℵ1-many of types in WGen.

Newelski Bounded orbits

slide-83
SLIDE 83

The case of very bounded WGen

Example There is a (semi)-example, where WGen is bounded, of size 22ℵ0. Definition Let p ∈ WGen. We say that p is countably stationary if for some countable A ⊂ C, p is the only weakly generic type extending p ↾A. Lemma Assume |WGen| ≤ 2ℵ0 and 2ℵ0 < 2ℵ1. Then there is a type p ∈ WGen, that is countably stationary. Proof. If not, build a tree of weakly generic types of height ℵ1, getting 2ℵ1-many of types in WGen.

Newelski Bounded orbits

slide-84
SLIDE 84

The case of very bounded WGen

Example There is a (semi)-example, where WGen is bounded, of size 22ℵ0. Definition Let p ∈ WGen. We say that p is countably stationary if for some countable A ⊂ C, p is the only weakly generic type extending p ↾A. Lemma Assume |WGen| ≤ 2ℵ0 and 2ℵ0 < 2ℵ1. Then there is a type p ∈ WGen, that is countably stationary. Proof. If not, build a tree of weakly generic types of height ℵ1, getting 2ℵ1-many of types in WGen.

Newelski Bounded orbits

slide-85
SLIDE 85

The case of very bounded WGen

Example There is a (semi)-example, where WGen is bounded, of size 22ℵ0. Definition Let p ∈ WGen. We say that p is countably stationary if for some countable A ⊂ C, p is the only weakly generic type extending p ↾A. Lemma Assume |WGen| ≤ 2ℵ0 and 2ℵ0 < 2ℵ1. Then there is a type p ∈ WGen, that is countably stationary. Proof. If not, build a tree of weakly generic types of height ℵ1, getting 2ℵ1-many of types in WGen.

Newelski Bounded orbits

slide-86
SLIDE 86

The case of absolutely very bounded WGen

Definition We say that WGen is absolutely bounded by 2ℵ0 if this bound persists in any forcing extension of the set-theoretical universe underlying our considerations. Example Assume T has NIP and G has fsg. Then WGen consists of generic types and is absolutely bounded by 2ℵ0. Look into the papers on NIP and groups by Hrushovski, Pillay, Peterzil [HPP]. Theorem Assume WGen is absolutely bounded by 2ℵ0. Then there is a countably stationary type in WGen.

Newelski Bounded orbits

slide-87
SLIDE 87

The case of absolutely very bounded WGen

Definition We say that WGen is absolutely bounded by 2ℵ0 if this bound persists in any forcing extension of the set-theoretical universe underlying our considerations. Example Assume T has NIP and G has fsg. Then WGen consists of generic types and is absolutely bounded by 2ℵ0. Look into the papers on NIP and groups by Hrushovski, Pillay, Peterzil [HPP]. Theorem Assume WGen is absolutely bounded by 2ℵ0. Then there is a countably stationary type in WGen.

Newelski Bounded orbits

slide-88
SLIDE 88

The case of absolutely very bounded WGen

Definition We say that WGen is absolutely bounded by 2ℵ0 if this bound persists in any forcing extension of the set-theoretical universe underlying our considerations. Example Assume T has NIP and G has fsg. Then WGen consists of generic types and is absolutely bounded by 2ℵ0. Look into the papers on NIP and groups by Hrushovski, Pillay, Peterzil [HPP]. Theorem Assume WGen is absolutely bounded by 2ℵ0. Then there is a countably stationary type in WGen.

Newelski Bounded orbits

slide-89
SLIDE 89

The case of absolutely very bounded WGen

Definition We say that WGen is absolutely bounded by 2ℵ0 if this bound persists in any forcing extension of the set-theoretical universe underlying our considerations. Example Assume T has NIP and G has fsg. Then WGen consists of generic types and is absolutely bounded by 2ℵ0. Look into the papers on NIP and groups by Hrushovski, Pillay, Peterzil [HPP]. Theorem Assume WGen is absolutely bounded by 2ℵ0. Then there is a countably stationary type in WGen.

Newelski Bounded orbits

slide-90
SLIDE 90

Proof

The conclusion of the theorem says that There is a countable weakly generic type p = {ϕn(x, an) : n < ω} that extends uniquely to a type in WGen. The type p is determined by the tuple ¯ a = ann<ω of the parameters and the function f : ω → L, mapping n to ϕn.. Also just the type q(¯ y) = tp(¯ a) ∈ Sω(∅) matters. So the conclusion says: (∗)(∃q(¯ y), f )( the type p determined by q and f is weakly generic and for every formula ψ(x, b), at most one of p ∪ {ψ(x, b)}, p ∪ {¬ψ(x, b)} is weakly generic). The fact, that ϕ(x, a) is weak generic is a Borel property of tp(a) (more exactly: Fσ), hence (∗) is a Σ1

2-sentence of a Polish space.

Newelski Bounded orbits

slide-91
SLIDE 91

Proof

The conclusion of the theorem says that There is a countable weakly generic type p = {ϕn(x, an) : n < ω} that extends uniquely to a type in WGen. The type p is determined by the tuple ¯ a = ann<ω of the parameters and the function f : ω → L, mapping n to ϕn.. Also just the type q(¯ y) = tp(¯ a) ∈ Sω(∅) matters. So the conclusion says: (∗)(∃q(¯ y), f )( the type p determined by q and f is weakly generic and for every formula ψ(x, b), at most one of p ∪ {ψ(x, b)}, p ∪ {¬ψ(x, b)} is weakly generic). The fact, that ϕ(x, a) is weak generic is a Borel property of tp(a) (more exactly: Fσ), hence (∗) is a Σ1

2-sentence of a Polish space.

Newelski Bounded orbits

slide-92
SLIDE 92

Proof

The conclusion of the theorem says that There is a countable weakly generic type p = {ϕn(x, an) : n < ω} that extends uniquely to a type in WGen. The type p is determined by the tuple ¯ a = ann<ω of the parameters and the function f : ω → L, mapping n to ϕn.. Also just the type q(¯ y) = tp(¯ a) ∈ Sω(∅) matters. So the conclusion says: (∗)(∃q(¯ y), f )( the type p determined by q and f is weakly generic and for every formula ψ(x, b), at most one of p ∪ {ψ(x, b)}, p ∪ {¬ψ(x, b)} is weakly generic). The fact, that ϕ(x, a) is weak generic is a Borel property of tp(a) (more exactly: Fσ), hence (∗) is a Σ1

2-sentence of a Polish space.

Newelski Bounded orbits

slide-93
SLIDE 93

Proof

The conclusion of the theorem says that There is a countable weakly generic type p = {ϕn(x, an) : n < ω} that extends uniquely to a type in WGen. The type p is determined by the tuple ¯ a = ann<ω of the parameters and the function f : ω → L, mapping n to ϕn.. Also just the type q(¯ y) = tp(¯ a) ∈ Sω(∅) matters. So the conclusion says: (∗)(∃q(¯ y), f )( the type p determined by q and f is weakly generic and for every formula ψ(x, b), at most one of p ∪ {ψ(x, b)}, p ∪ {¬ψ(x, b)} is weakly generic). The fact, that ϕ(x, a) is weak generic is a Borel property of tp(a) (more exactly: Fσ), hence (∗) is a Σ1

2-sentence of a Polish space.

Newelski Bounded orbits

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SLIDE 94

Proof

The conclusion of the theorem says that There is a countable weakly generic type p = {ϕn(x, an) : n < ω} that extends uniquely to a type in WGen. The type p is determined by the tuple ¯ a = ann<ω of the parameters and the function f : ω → L, mapping n to ϕn.. Also just the type q(¯ y) = tp(¯ a) ∈ Sω(∅) matters. So the conclusion says: (∗)(∃q(¯ y), f )( the type p determined by q and f is weakly generic and for every formula ψ(x, b), at most one of p ∪ {ψ(x, b)}, p ∪ {¬ψ(x, b)} is weakly generic). The fact, that ϕ(x, a) is weak generic is a Borel property of tp(a) (more exactly: Fσ), hence (∗) is a Σ1

2-sentence of a Polish space.

Newelski Bounded orbits

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SLIDE 95

Proof

The conclusion of the theorem says that There is a countable weakly generic type p = {ϕn(x, an) : n < ω} that extends uniquely to a type in WGen. The type p is determined by the tuple ¯ a = ann<ω of the parameters and the function f : ω → L, mapping n to ϕn.. Also just the type q(¯ y) = tp(¯ a) ∈ Sω(∅) matters. So the conclusion says: (∗)(∃q(¯ y), f )( the type p determined by q and f is weakly generic and for every formula ψ(x, b), at most one of p ∪ {ψ(x, b)}, p ∪ {¬ψ(x, b)} is weakly generic). The fact, that ϕ(x, a) is weak generic is a Borel property of tp(a) (more exactly: Fσ), hence (∗) is a Σ1

2-sentence of a Polish space.

Newelski Bounded orbits

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SLIDE 96

Proof

The conclusion of the theorem says that There is a countable weakly generic type p = {ϕn(x, an) : n < ω} that extends uniquely to a type in WGen. The type p is determined by the tuple ¯ a = ann<ω of the parameters and the function f : ω → L, mapping n to ϕn.. Also just the type q(¯ y) = tp(¯ a) ∈ Sω(∅) matters. So the conclusion says: (∗)(∃q(¯ y), f )( the type p determined by q and f is weakly generic and for every formula ψ(x, b), at most one of p ∪ {ψ(x, b)}, p ∪ {¬ψ(x, b)} is weakly generic). The fact, that ϕ(x, a) is weak generic is a Borel property of tp(a) (more exactly: Fσ), hence (∗) is a Σ1

2-sentence of a Polish space.

Newelski Bounded orbits

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SLIDE 97

Proof concluded

By Shoenfield absoluteness lemma, (∗) is absolute between various models of ZFC. In our situation we can extend the set-theoretical universe V (by means of forcing) to a universe V ′, where 2ℵ0 < 2ℵ1 holds. By the lemma, in V ′ (∗) holds. By absoluteness, (∗) holds also in V .

Newelski Bounded orbits

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SLIDE 98

Proof concluded

By Shoenfield absoluteness lemma, (∗) is absolute between various models of ZFC. In our situation we can extend the set-theoretical universe V (by means of forcing) to a universe V ′, where 2ℵ0 < 2ℵ1 holds. By the lemma, in V ′ (∗) holds. By absoluteness, (∗) holds also in V .

Newelski Bounded orbits

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SLIDE 99

Proof concluded

By Shoenfield absoluteness lemma, (∗) is absolute between various models of ZFC. In our situation we can extend the set-theoretical universe V (by means of forcing) to a universe V ′, where 2ℵ0 < 2ℵ1 holds. By the lemma, in V ′ (∗) holds. By absoluteness, (∗) holds also in V .

Newelski Bounded orbits

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SLIDE 100

Corollary and example

Corollary Assume T has NIP and G has fsg. Then there is a countably stationary weak generic type in WGen. Example Consider the group S1 in an o-minimal expansion of the reals. Here every type in WGen is generic and countably stationary. But WGen is not a Polish space here, so we can not find a common countable set A such that A separates the types in WGen.

Newelski Bounded orbits

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SLIDE 101

Corollary and example

Corollary Assume T has NIP and G has fsg. Then there is a countably stationary weak generic type in WGen. Example Consider the group S1 in an o-minimal expansion of the reals. Here every type in WGen is generic and countably stationary. But WGen is not a Polish space here, so we can not find a common countable set A such that A separates the types in WGen.

Newelski Bounded orbits

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SLIDE 102

Corollary and example

Corollary Assume T has NIP and G has fsg. Then there is a countably stationary weak generic type in WGen. Example Consider the group S1 in an o-minimal expansion of the reals. Here every type in WGen is generic and countably stationary. But WGen is not a Polish space here, so we can not find a common countable set A such that A separates the types in WGen.

Newelski Bounded orbits

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SLIDE 103

Corollary and example

Corollary Assume T has NIP and G has fsg. Then there is a countably stationary weak generic type in WGen. Example Consider the group S1 in an o-minimal expansion of the reals. Here every type in WGen is generic and countably stationary. But WGen is not a Polish space here, so we can not find a common countable set A such that A separates the types in WGen.

Newelski Bounded orbits

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SLIDE 104

Bounded WGen and measure

Lemma Assume WGen is bounded. Then G ∞ = G 00 = Stab(p) for any p ∈ WGen.

  • 1. G/G 00 is a compact topological group (with logic topology),

with Haar measure µ, also it is a Polish space.

  • 2. Let p ∈ WGen. There is a bijection Gp ↔ G/G 00. Every coset
  • f G 00 contains exactly one type from Gp.

Newelski Bounded orbits

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SLIDE 105

Bounded WGen and measure

Lemma Assume WGen is bounded. Then G ∞ = G 00 = Stab(p) for any p ∈ WGen.

  • 1. G/G 00 is a compact topological group (with logic topology),

with Haar measure µ, also it is a Polish space.

  • 2. Let p ∈ WGen. There is a bijection Gp ↔ G/G 00. Every coset
  • f G 00 contains exactly one type from Gp.

Newelski Bounded orbits

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SLIDE 106

Bounded WGen and measure

Lemma Assume WGen is bounded. Then G ∞ = G 00 = Stab(p) for any p ∈ WGen.

  • 1. G/G 00 is a compact topological group (with logic topology),

with Haar measure µ, also it is a Polish space.

  • 2. Let p ∈ WGen. There is a bijection Gp ↔ G/G 00. Every coset
  • f G 00 contains exactly one type from Gp.

Newelski Bounded orbits

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SLIDE 107

Bounded WGen and measure

Lemma Assume WGen is bounded. Then G ∞ = G 00 = Stab(p) for any p ∈ WGen.

  • 1. G/G 00 is a compact topological group (with logic topology),

with Haar measure µ, also it is a Polish space.

  • 2. Let p ∈ WGen. There is a bijection Gp ↔ G/G 00. Every coset
  • f G 00 contains exactly one type from Gp.

Newelski Bounded orbits

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SLIDE 108

Bounded WGen and measure

Fix a type p ∈ WGen. Lifting Haar measure to Keisler measure 1.Let U ⊆def C. Let ϕ(U) be the set {g/G 00 : U belongs to the unique type in Gp in the coset g/G 00}

  • 2. Let Mes(C) = {U ⊆def (C) : ϕ(U) is measurable}. This is an

algebra of sets.

  • 3. For U ∈ Mes(C) let ν(U) = µ(ϕ(U)).
  • 4. ν is a finitely additive left invariant measure on Mes(C).

Theorem Assume p ∈ WGen is countably stationary. Then Mes(C) consists

  • f all definable sets. In particular, on G there is a left-invariant

Keisler measure.

Newelski Bounded orbits

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SLIDE 109

Bounded WGen and measure

Fix a type p ∈ WGen. Lifting Haar measure to Keisler measure 1.Let U ⊆def C. Let ϕ(U) be the set {g/G 00 : U belongs to the unique type in Gp in the coset g/G 00}

  • 2. Let Mes(C) = {U ⊆def (C) : ϕ(U) is measurable}. This is an

algebra of sets.

  • 3. For U ∈ Mes(C) let ν(U) = µ(ϕ(U)).
  • 4. ν is a finitely additive left invariant measure on Mes(C).

Theorem Assume p ∈ WGen is countably stationary. Then Mes(C) consists

  • f all definable sets. In particular, on G there is a left-invariant

Keisler measure.

Newelski Bounded orbits

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SLIDE 110

Bounded WGen and measure

Fix a type p ∈ WGen. Lifting Haar measure to Keisler measure 1.Let U ⊆def C. Let ϕ(U) be the set {g/G 00 : U belongs to the unique type in Gp in the coset g/G 00}

  • 2. Let Mes(C) = {U ⊆def (C) : ϕ(U) is measurable}. This is an

algebra of sets.

  • 3. For U ∈ Mes(C) let ν(U) = µ(ϕ(U)).
  • 4. ν is a finitely additive left invariant measure on Mes(C).

Theorem Assume p ∈ WGen is countably stationary. Then Mes(C) consists

  • f all definable sets. In particular, on G there is a left-invariant

Keisler measure.

Newelski Bounded orbits

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SLIDE 111

Bounded WGen and measure

Fix a type p ∈ WGen. Lifting Haar measure to Keisler measure 1.Let U ⊆def C. Let ϕ(U) be the set {g/G 00 : U belongs to the unique type in Gp in the coset g/G 00}

  • 2. Let Mes(C) = {U ⊆def (C) : ϕ(U) is measurable}. This is an

algebra of sets.

  • 3. For U ∈ Mes(C) let ν(U) = µ(ϕ(U)).
  • 4. ν is a finitely additive left invariant measure on Mes(C).

Theorem Assume p ∈ WGen is countably stationary. Then Mes(C) consists

  • f all definable sets. In particular, on G there is a left-invariant

Keisler measure.

Newelski Bounded orbits

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SLIDE 112

Bounded WGen and measure

Fix a type p ∈ WGen. Lifting Haar measure to Keisler measure 1.Let U ⊆def C. Let ϕ(U) be the set {g/G 00 : U belongs to the unique type in Gp in the coset g/G 00}

  • 2. Let Mes(C) = {U ⊆def (C) : ϕ(U) is measurable}. This is an

algebra of sets.

  • 3. For U ∈ Mes(C) let ν(U) = µ(ϕ(U)).
  • 4. ν is a finitely additive left invariant measure on Mes(C).

Theorem Assume p ∈ WGen is countably stationary. Then Mes(C) consists

  • f all definable sets. In particular, on G there is a left-invariant

Keisler measure.

Newelski Bounded orbits

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SLIDE 113

Bounded WGen and measure

Fix a type p ∈ WGen. Lifting Haar measure to Keisler measure 1.Let U ⊆def C. Let ϕ(U) be the set {g/G 00 : U belongs to the unique type in Gp in the coset g/G 00}

  • 2. Let Mes(C) = {U ⊆def (C) : ϕ(U) is measurable}. This is an

algebra of sets.

  • 3. For U ∈ Mes(C) let ν(U) = µ(ϕ(U)).
  • 4. ν is a finitely additive left invariant measure on Mes(C).

Theorem Assume p ∈ WGen is countably stationary. Then Mes(C) consists

  • f all definable sets. In particular, on G there is a left-invariant

Keisler measure.

Newelski Bounded orbits

slide-114
SLIDE 114

Bounded WGen and measure

Fix a type p ∈ WGen. Lifting Haar measure to Keisler measure 1.Let U ⊆def C. Let ϕ(U) be the set {g/G 00 : U belongs to the unique type in Gp in the coset g/G 00}

  • 2. Let Mes(C) = {U ⊆def (C) : ϕ(U) is measurable}. This is an

algebra of sets.

  • 3. For U ∈ Mes(C) let ν(U) = µ(ϕ(U)).
  • 4. ν is a finitely additive left invariant measure on Mes(C).

Theorem Assume p ∈ WGen is countably stationary. Then Mes(C) consists

  • f all definable sets. In particular, on G there is a left-invariant

Keisler measure.

Newelski Bounded orbits

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SLIDE 115

Bounded WGen and measure

Fix a type p ∈ WGen. Lifting Haar measure to Keisler measure 1.Let U ⊆def C. Let ϕ(U) be the set {g/G 00 : U belongs to the unique type in Gp in the coset g/G 00}

  • 2. Let Mes(C) = {U ⊆def (C) : ϕ(U) is measurable}. This is an

algebra of sets.

  • 3. For U ∈ Mes(C) let ν(U) = µ(ϕ(U)).
  • 4. ν is a finitely additive left invariant measure on Mes(C).

Theorem Assume p ∈ WGen is countably stationary. Then Mes(C) consists

  • f all definable sets. In particular, on G there is a left-invariant

Keisler measure.

Newelski Bounded orbits

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SLIDE 116

Definably amenable groups

Proof. Using countable stationarity of p one shows that for every U ⊆def C, the set ϕ(U) is analytic (that is, Σ1

1).

Analytic sets are measurable with respect to Haar measure in a Polish group. Corollary Assume WGen is absolutely bounded by 2ℵ0. Then G is definably amenable. This corollary applies in particular to groups with fsg, under NIP-assumption. In this special case Hrushovski and Pillay proved moreover uniqueness of left invariant Keisler measure. In general we obviously do not have uniqueness.

Newelski Bounded orbits

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SLIDE 117

Definably amenable groups

Proof. Using countable stationarity of p one shows that for every U ⊆def C, the set ϕ(U) is analytic (that is, Σ1

1).

Analytic sets are measurable with respect to Haar measure in a Polish group. Corollary Assume WGen is absolutely bounded by 2ℵ0. Then G is definably amenable. This corollary applies in particular to groups with fsg, under NIP-assumption. In this special case Hrushovski and Pillay proved moreover uniqueness of left invariant Keisler measure. In general we obviously do not have uniqueness.

Newelski Bounded orbits

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SLIDE 118

Definably amenable groups

Proof. Using countable stationarity of p one shows that for every U ⊆def C, the set ϕ(U) is analytic (that is, Σ1

1).

Analytic sets are measurable with respect to Haar measure in a Polish group. Corollary Assume WGen is absolutely bounded by 2ℵ0. Then G is definably amenable. This corollary applies in particular to groups with fsg, under NIP-assumption. In this special case Hrushovski and Pillay proved moreover uniqueness of left invariant Keisler measure. In general we obviously do not have uniqueness.

Newelski Bounded orbits

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SLIDE 119

Definably amenable groups

Proof. Using countable stationarity of p one shows that for every U ⊆def C, the set ϕ(U) is analytic (that is, Σ1

1).

Analytic sets are measurable with respect to Haar measure in a Polish group. Corollary Assume WGen is absolutely bounded by 2ℵ0. Then G is definably amenable. This corollary applies in particular to groups with fsg, under NIP-assumption. In this special case Hrushovski and Pillay proved moreover uniqueness of left invariant Keisler measure. In general we obviously do not have uniqueness.

Newelski Bounded orbits

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SLIDE 120

Definably amenable groups

Proof. Using countable stationarity of p one shows that for every U ⊆def C, the set ϕ(U) is analytic (that is, Σ1

1).

Analytic sets are measurable with respect to Haar measure in a Polish group. Corollary Assume WGen is absolutely bounded by 2ℵ0. Then G is definably amenable. This corollary applies in particular to groups with fsg, under NIP-assumption. In this special case Hrushovski and Pillay proved moreover uniqueness of left invariant Keisler measure. In general we obviously do not have uniqueness.

Newelski Bounded orbits

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SLIDE 121

Definably amenable groups

Proof. Using countable stationarity of p one shows that for every U ⊆def C, the set ϕ(U) is analytic (that is, Σ1

1).

Analytic sets are measurable with respect to Haar measure in a Polish group. Corollary Assume WGen is absolutely bounded by 2ℵ0. Then G is definably amenable. This corollary applies in particular to groups with fsg, under NIP-assumption. In this special case Hrushovski and Pillay proved moreover uniqueness of left invariant Keisler measure. In general we obviously do not have uniqueness.

Newelski Bounded orbits

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SLIDE 122

Final comments

Example In the additive group of the reals we have exactly two left-invariant Keisler measures, corresponding to the two weak generic types there. We proved the conjecture of Petrykowski under a stronger assumption that not only is there a bounded orbit, but that the set WGen is absolutely bounded by 2ℵ0. The conjecture is open. Further research: Model-theoretic absoluteness of Ellis semigroup. Relations between the subgroups of the Ellis semigroup and the group G/G 00. There are some preliminary results here.

Newelski Bounded orbits

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SLIDE 123

Final comments

Example In the additive group of the reals we have exactly two left-invariant Keisler measures, corresponding to the two weak generic types there. We proved the conjecture of Petrykowski under a stronger assumption that not only is there a bounded orbit, but that the set WGen is absolutely bounded by 2ℵ0. The conjecture is open. Further research: Model-theoretic absoluteness of Ellis semigroup. Relations between the subgroups of the Ellis semigroup and the group G/G 00. There are some preliminary results here.

Newelski Bounded orbits

slide-124
SLIDE 124

Final comments

Example In the additive group of the reals we have exactly two left-invariant Keisler measures, corresponding to the two weak generic types there. We proved the conjecture of Petrykowski under a stronger assumption that not only is there a bounded orbit, but that the set WGen is absolutely bounded by 2ℵ0. The conjecture is open. Further research: Model-theoretic absoluteness of Ellis semigroup. Relations between the subgroups of the Ellis semigroup and the group G/G 00. There are some preliminary results here.

Newelski Bounded orbits

slide-125
SLIDE 125

Final comments

Example In the additive group of the reals we have exactly two left-invariant Keisler measures, corresponding to the two weak generic types there. We proved the conjecture of Petrykowski under a stronger assumption that not only is there a bounded orbit, but that the set WGen is absolutely bounded by 2ℵ0. The conjecture is open. Further research: Model-theoretic absoluteness of Ellis semigroup. Relations between the subgroups of the Ellis semigroup and the group G/G 00. There are some preliminary results here.

Newelski Bounded orbits