SLIDE 2 2.2 Kinematics and Dynamics Kinematics is described as follows. The major equation of generalized displacement { skeleton-muscle system depends
static application of forces {P}
[] ∙ {∆} = {}
Where, [K] is a global matrix of system stiffness, { is a generalized displacements vector and { generalized exterior forces vector. The the global stiffness matrix [K] are calculated by common rules of the finite element method be represented as;
=
Where, ke
ij is elements of local stiffness matrix
- riented in global coordinate system,
numbers of generalized displacements in local system, and n is the number of finite elements.
- Fig. 2. Rod element and degree of freedom of node
- f human body
The structural mechanical displacements of bar elements are represented in Fig. 2. Connection between local stiffness matrix of bar element and arbitrary oriented in global Kinematics is described as follows. The major generalized displacement {Δ} of muscle system depends
static (1) ] is a global matrix of system stiffness, {Δ} generalized displacements vector and {P} is a generalized exterior forces vector. The elements of ] are calculated by common rules of the finite element method and can (2) is elements of local stiffness matrix system, i and j are the numbers of generalized displacements in local is the number of finite elements. Rod element and degree of freedom of node mechanical displacements of bar Connection between local stiffness matrix of bar element and arbitrary oriented in global X Y Z stiffness matrix of the same element in local is carried out by way of guide cosine matrix [ And [l] is matrix of direction cosines.
= [][
where,
[] = [] [] [] [] , []
Each element of local stiffness matrix a force or reaction appearing in displacement along j direction. is are represented in Fig. 3
Where, L is length of element,
- f elasticity and rigidity,
section, J0, is polar moment of inertia, inertia moments of elements on cross about main central axis. Moment of human is described by the following equation.
[]∆̈ + []∆̇ + [
Where, [H] is a dissipation matrix in terms of experimental coefficients α
[] = [] +
3 2 3 2 3 2 3 2 2 2
12 6 6 12 6 6 5 10 5 10 12 6 12 6 6 6 5 10 5 10 6 4 6 2 2 10 15 10 30 6
z z z z y y y y y y y y
EA EA N N L L EJ N EJ N EJ N EJ N L L L L L L EJ EJ EJ EJ N N N N L L L L L L GJ GJ L L EJ EJ EJ EJ N NL N NL L L L L +
+
+
+
2 3 2 3 2 3 2 3 2
4 2 6 2 10 15 10 30 12 6 6 12 6 6 5 10 5 10 12 6 12 6 6 6 5 10 5 10 6
z z z z z z z z y y y y
EJ N EJ NL EJ N EJ NL L L L L EA EA N N L L EJ N EJ N EJ N EJ N L L L L L L EJ EJ EJ EJ N N N N L L L L L L GJ GJ L L + +
+ +
2 2 2
2 6 4 10 30 10 15 6 2 6 4 2 10 30 10 15
y y y y z z z z
EJ EJ EJ EJ N NL N NL L L L L EJ N EJ NL EJ N EJ NL L L L L
+ +
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stiffness matrix of the same element in local x y z [ke] is carried out by way of guide cosine matrix [L]. direction cosines.
[][]
(3)
[ ] =
(4) stiffness matrix ke
ij represents
a force or reaction appearing in i direction for unit
- direction. Full stiffness matrix
tiffness matrix considering force N length of element, E and G are modulus
- f elasticity and rigidity, F is an area of cross-
is polar moment of inertia, Jy and Jz are
- f elements on cross-section area
Moment of human right arm is described by the following equation.
[]{∆} = {}
(5) dissipation matrix in terms of α and β as follows;
] + []
(6)
3 2 3 2 3 2 3 2 2 2
12 6 6 12 6 6 5 10 5 10 12 6 12 6 6 6 5 10 5 10 6 4 6 2 10 15 10 30
z z z z y y y y y y y y
EA EA N N L L EJ N EJ N EJ N EJ N L L L L L L EJ EJ EJ EJ N N N N L L L L L L GJ GJ L L EJ EJ EJ EJ N NL N NL L L L L +
+
+
+
2 3 2 3 2 3 2 3 2
4 2 6 2 10 15 10 30 12 6 6 12 6 6 5 10 5 10 12 6 12 6 6 6 5 10 5 10
z z z z z z z z y y y y
EJ N EJ NL EJ N EJ NL L L L L EA EA N N L L EJ N EJ N EJ N EJ N L L L L L L EJ EJ EJ EJ N N N N L L L L L L GJ GJ L L + +
+ +
2 2 2 2
2 6 4 2 10 30 10 15 6 2 6 4 2 10 30 10 15
y y y y z z z z
EJ EJ EJ EJ N NL N NL L L L L EJ N EJ NL EJ N EJ NL L L L L
+ +
é ù ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ê ú ë û