A Brouwerian Proof of the Fan theorem Michael P . Fourman - - PowerPoint PPT Presentation

a brouwerian proof of the fan theorem
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A Brouwerian Proof of the Fan theorem Michael P . Fourman - - PowerPoint PPT Presentation

A Brouwerian Proof of the Fan theorem Michael P . Fourman dedicated to Dana S. Scott section x x = id B E open U fibre B t slides presented at domains13, Oxford 7/7/2018; with minor modifications 9/7/2018 the topological


slide-1
SLIDE 1

A Brouwerian Proof of the Fan theorem

Michael P . Fourman

dedicated to Dana S. Scott

t fibre B E π section x x π = idB

  • pen U

slides presented at domains13, Oxford 7/7/2018; with minor modifications 9/7/2018

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SLIDE 2

Extending

the topological interpretation

to intuitionistic analysis

Dedicated

to A. Heyting

  • n the occasion
  • f

his 70th birthday

by

Dana

Scott

The

well-known

Stone-Tarski

interpretation

  • f

the

intuitionistic

propositional logic was extended by

Mostowski to the quantifier logic in a

natural way. For

details and references the reader may

consult the work Rasiowa-Sikorski [5], where intuitionistic

theories are discussed in general, but where

no particular theory

is analysed from this point of view. The purpose of this paper is to present some

classically interesting models

for the intuition-

istic theory of the continuum. These models will be applied to some simple independence questions. The idea of the model can

also be used for models of second-order intuitionistic arithmetic (cf. the system of [6]), but lack of time and space force us to

postpone this discussion to another paper. Also, the author has

encountered

some

difficulty in verifying certain of

the continuity

assumptions (Axiom

F4

  • f [6] for Voc3fJ to be précise) and

hopes

to

try

to

understand

the

motivation

behind

these principles better before presenting the details of the model. It is not impossible that there are several distinct intuitionistic notions of free-choice

sequence (real number) with

various continuity properties.

Compositio Mathematica, tome 20 (1968), p. 194-210.

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SLIDE 3

Brouwerian:

Act I twoity 0, 1 tuples ha, bi constructions integers binary strings finite trees (finitary inductive definitions) Act II species a 2 U (determined by properties) choice sequences (finite prefixes a α) spreads (restrictions on free choices)

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SLIDE 4

A open, U, of the formal Cantor space, C, is a species of finite binary strings a, b, . . . 2 2<N that is persistent: 8a, b. b a 2 U ! b 2 U inductive: 8a. aˆ0 2 U ^ aˆ1 2 U ! a 2 U A formal open is a cover iff 8α : 2N 9a 2 U. a α. The Fan Theorem says,

If U is a formal open cover of C then ε 2 U.

The Fan Theorem underpins Brouwer’s development

  • f intuitionistic analysis.

It is independent of higher-order Heyting arithmetic.

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SLIDE 5

To justify the Fan Theorem Brouwer introduces a creating subject, who can indefinitely extend the stock of mathematical entities by introducing free choice sequences. Choice sequences A (binary) choice sequence, α, is defined by the species of its finite prefixes. We write the corresponding property as a α. It must satisfy the following properties: ε α a α $ aˆ0 α _ aˆ1 α aˆ0 α ^ aˆ1 α ! ? At any stage the creating subject can know only a finite initial segment

  • f a free choice sequence; no restrictions are placed on its future values.
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slide-6
SLIDE 6

topological interpretation

Jx ∈ UK = x−1(U) Jx # yK = {t | x(t) 6= y(t)}

JϕK ∈ O(B)

t fibre B E π section x x π = idB

  • pen U

Truth values JϕK ∈ O(B) in the complete Heyting algebra (cHa) of open sets

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slide-7
SLIDE 7

The topological interpretation over the formal Cantor space C corresponds to a Beth model over the tree of finite strings: JϕK = {b | b ϕ} (forcing is persistent and inductive) We interpret this as a model of the activity of a creating subject depen- dent on a free choice sequence γ: b ϕ iff the information that b γ justifies the conclusion ϕ A species U dependent on γ is modelled by giving a truth value Ja 2 UK 2 O(C)for each string a. Any choice sequence a α corresponds to a continuous function α with b a α iff b 2 α−1(a) In particular, γ corresponds to the identity function: b a γ iff b a.

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slide-8
SLIDE 8

( ( ) ) 1

We can also view this as a monoid model. The free monoid on 0, 1 acts on the topological model. The monoid action represents a change of perspective of the creating subject.

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b a ∈ U ⇠ x iff xˆb a ∈ U

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⇠1

< l a t e x i t s h a 1 _ b a s e 6 4 = " y A q D 5 m k p q E g 7
  • +
9
  • z
T J b n T E A O s = " > A A A C r H i c b V H L i h N B F K 2 r z G + M u P S T W k Q X D X d
  • u
g s h E E 3 L k e Y z A y k m l B d f T s p U i + q b k 8 S m t 7 4 I W 7 1 l / w b K w / B Z L x Q c D j n P u r e U z
  • l
A 2 b Z 7 1 5 y 5 + 6 9 + w + O H v Y f P X 7 y 9 N n g + O Q y 2 M Y L G A m r r L 8 u e Q A l D Y x Q
  • J
r 5 4 H r U s F V O f + y 1 q 9 u w A d p z Q W u H B S a T 4 2 s p e A Y q c n g h D V u x r 2 z 1 i i
  • k
b 2 k + W Q w z N J s E / Q 2 y H d g S H Z x P j n u f W e V F Y G g L x E M Z 5 5 r B
  • u
U c p F H R 9 1 g R w X M z 5 F M Y R G q 4 h F O 3 m 8 x 1 9 H Z m K 1 t b H Z 5 B u 2 H 8 r W q 5 D W O k y Z m q O s 3 C
  • r
c n / a p X k U x 8 T D u Z j / b F
  • p
X E N g h H b 8 X W j K F q 6 v g + t p A e B a h U B F 1 7 G D a i I B + I C 4 x X 3 + i + 3 C + x x z l t b 7 1 M B N f c r X X W w E J Y r b m p W u b s I j Y E 7 F r m u Q x Q 2 m W b 5 u / Z X z P D X L q
  • K
e 6 n w M C E x s N 6 x Z Y t X N f F X g h L X M g K Z 5 9 O h e 7 3 a X Q t P / T
  • N
r h 8 m + Z Z m n 9 7 N z z 7 v P P v i L w g r 8 g b k p M P 5 I x 8 J e d k R A R Z k h / k J / m V p M l F M k 6 K b W r S 2 9 U 8 J 3 u R 1 H 8 A 3 B 7 Y b w = = < / l a t e x i t > < l a t e x i t s h a 1 _ b a s e 6 4 = " y A q D 5 m k p q E g 7
  • +
9
  • z
T J b n T E A O s = " > A A A C r H i c b V H L i h N B F K 2 r z G + M u P S T W k Q X D X d
  • u
g s h E E 3 L k e Y z A y k m l B d f T s p U i + q b k 8 S m t 7 4 I W 7 1 l / w b K w / B Z L x Q c D j n P u r e U z
  • l
A 2 b Z 7 1 5 y 5 + 6 9 + w + O H v Y f P X 7 y 9 N n g + O Q y 2 M Y L G A m r r L 8 u e Q A l D Y x Q
  • J
r 5 4 H r U s F V O f + y 1 q 9 u w A d p z Q W u H B S a T 4 2 s p e A Y q c n g h D V u x r 2 z 1 i i
  • k
b 2 k + W Q w z N J s E / Q 2 y H d g S H Z x P j n u f W e V F Y G g L x E M Z 5 5 r B
  • u
U c p F H R 9 1 g R w X M z 5 F M Y R G q 4 h F O 3 m 8 x 1 9 H Z m K 1 t b H Z 5 B u 2 H 8 r W q 5 D W O k y Z m q O s 3 C
  • r
c n / a p X k U x 8 T D u Z j / b F
  • p
X E N g h H b 8 X W j K F q 6 v g + t p A e B a h U B F 1 7 G D a i I B + I C 4 x X 3 + i + 3 C + x x z l t b 7 1 M B N f c r X X W w E J Y r b m p W u b s I j Y E 7 F r m u Q x Q 2 m W b 5 u / Z X z P D X L q
  • K
e 6 n w M C E x s N 6 x Z Y t X N f F X g h L X M g K Z 5 9 O h e 7 3 a X Q t P / T
  • N
r h 8 m + Z Z m n 9 7 N z z 7 v P P v i L w g r 8 g b k p M P 5 I x 8 J e d k R A R Z k h / k J / m V p M l F M k 6 K b W r S 2 9 U 8 J 3 u R 1 H 8 A 3 B 7 Y b w = = < / l a t e x i t > < l a t e x i t s h a 1 _ b a s e 6 4 = " y A q D 5 m k p q E g 7
  • +
9
  • z
T J b n T E A O s = " > A A A C r H i c b V H L i h N B F K 2 r z G + M u P S T W k Q X D X d
  • u
g s h E E 3 L k e Y z A y k m l B d f T s p U i + q b k 8 S m t 7 4 I W 7 1 l / w b K w / B Z L x Q c D j n P u r e U z
  • l
A 2 b Z 7 1 5 y 5 + 6 9 + w + O H v Y f P X 7 y 9 N n g + O Q y 2 M Y L G A m r r L 8 u e Q A l D Y x Q
  • J
r 5 4 H r U s F V O f + y 1 q 9 u w A d p z Q W u H B S a T 4 2 s p e A Y q c n g h D V u x r 2 z 1 i i
  • k
b 2 k + W Q w z N J s E / Q 2 y H d g S H Z x P j n u f W e V F Y G g L x E M Z 5 5 r B
  • u
U c p F H R 9 1 g R w X M z 5 F M Y R G q 4 h F O 3 m 8 x 1 9 H Z m K 1 t b H Z 5 B u 2 H 8 r W q 5 D W O k y Z m q O s 3 C
  • r
c n / a p X k U x 8 T D u Z j / b F
  • p
X E N g h H b 8 X W j K F q 6 v g + t p A e B a h U B F 1 7 G D a i I B + I C 4 x X 3 + i + 3 C + x x z l t b 7 1 M B N f c r X X W w E J Y r b m p W u b s I j Y E 7 F r m u Q x Q 2 m W b 5 u / Z X z P D X L q
  • K
e 6 n w M C E x s N 6 x Z Y t X N f F X g h L X M g K Z 5 9 O h e 7 3 a X Q t P / T
  • N
r h 8 m + Z Z m n 9 7 N z z 7 v P P v i L w g r 8 g b k p M P 5 I x 8 J e d k R A R Z k h / k J / m V p M l F M k 6 K b W r S 2 9 U 8 J 3 u R 1 H 8 A 3 B 7 Y b w = = < / l a t e x i t > < l a t e x i t s h a 1 _ b a s e 6 4 = " y A q D 5 m k p q E g 7
  • +
9
  • z
T J b n T E A O s = " > A A A C r H i c b V H L i h N B F K 2 r z G + M u P S T W k Q X D X d
  • u
g s h E E 3 L k e Y z A y k m l B d f T s p U i + q b k 8 S m t 7 4 I W 7 1 l / w b K w / B Z L x Q c D j n P u r e U z
  • l
A 2 b Z 7 1 5 y 5 + 6 9 + w + O H v Y f P X 7 y 9 N n g + O Q y 2 M Y L G A m r r L 8 u e Q A l D Y x Q
  • J
r 5 4 H r U s F V O f + y 1 q 9 u w A d p z Q W u H B S a T 4 2 s p e A Y q c n g h D V u x r 2 z 1 i i
  • k
b 2 k + W Q w z N J s E / Q 2 y H d g S H Z x P j n u f W e V F Y G g L x E M Z 5 5 r B
  • u
U c p F H R 9 1 g R w X M z 5 F M Y R G q 4 h F O 3 m 8 x 1 9 H Z m K 1 t b H Z 5 B u 2 H 8 r W q 5 D W O k y Z m q O s 3 C
  • r
c n / a p X k U x 8 T D u Z j / b F
  • p
X E N g h H b 8 X W j K F q 6 v g + t p A e B a h U B F 1 7 G D a i I B + I C 4 x X 3 + i + 3 C + x x z l t b 7 1 M B N f c r X X W w E J Y r b m p W u b s I j Y E 7 F r m u Q x Q 2 m W b 5 u / Z X z P D X L q
  • K
e 6 n w M C E x s N 6 x Z Y t X N f F X g h L X M g K Z 5 9 O h e 7 3 a X Q t P / T
  • N
r h 8 m + Z Z m n 9 7 N z z 7 v P P v i L w g r 8 g b k p M P 5 I x 8 J e d k R A R Z k h / k J / m V p M l F M k 6 K b W r S 2 9 U 8 J 3 u R 1 H 8 A 3 B 7 Y b w = = < / l a t e x i t >
slide-9
SLIDE 9

Introducing a new free choice sequence. Two free choice sequences may be interleaved to form a single free choice se-

  • quence. We model the introduction of a new choice sequence by transporting
  • ur constructions to be the even-indexed subsequence of this interleaving. Then

the odd-indexed subsequence represents the new sequence. Let b0 be the even- and b1 the odd-indexed subsequences of b. b a 2 V ⇠ π0 iff b0 a 2 V In general, every open map µ : C

  • C provides a logical endomorphism
  • f the model, with α ⇠ µ given by the composition α µ. A Joyal-Lawvere

interpretation of universal quantification brings the new sequence, π1, in scope: 8α. ϕ(α) iff forall µ 2 M, forall ξ, (ϕ ⇠ µ)(ξ). In particular, (ϕ ⇠ π0)(π1)

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slide-10
SLIDE 10

U

U × X

U × X × X

U

X X X X π0

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π1

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slide-11
SLIDE 11

Lemma A forcing relation b a 2 U defines a persistent, inductive species iff, viewed externally as a species of pairs of strings, it is persistent and inductive in both a and b. In this case the species defined by p0 p1 2 U is persistent and inductive in p. If U is persistent, inductive, and 8α9a 2 U. a α, then 9a 2 U ⇠ π0, a π1. The collection of those p such that for some a, both p0 a 2 U and a  p1, must cover the empty string. Since U is persistent, this is the (by the lemma, inductive) collection of p such that p0 p1 2 U. Thus the empty string is in this collection, so ε 2 U.

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slide-12
SLIDE 12

Instead of spaces use locales (inductive covers). Instead of open inclusions use open maps. Instead of sheaves use O(C)-valued models whose elements are constructions – trees that make explicit the stage at which information is available. Then define equality in terms of basic predicates.

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