Roland Becker
Laboratoire de Mathématiques Appliquées Université de Pau et de Pays de l’Adour
joint work with
Malte Braack (Universität Kiel), Dominik Meidner (Universität Heidelberg), Boris V exler (RICAM Linz)
The DWR method for numerical simulations related to nuclear waste - - PowerPoint PPT Presentation
The DWR method for numerical simulations related to nuclear waste disposals Roland Becker Laboratoire de Math matiques Appliqu es Universit de Pau et de Pays de l Adour joint work with Malte Braack ( Universit t Kiel ) , Dominik
Laboratoire de Mathématiques Appliquées Université de Pau et de Pays de l’Adour
joint work with
Malte Braack (Universität Kiel), Dominik Meidner (Universität Heidelberg), Boris V exler (RICAM Linz)
(il manque encore un facteur 3)
Riω(∂Ci ∂t + λiCi) − ∇ · (Di∇Ci) + u · ∇Ci = fi
∇ · (K∇H) = 0
a(C,φ):=(Ct +λC),φ+K∇C,∇φ b(C,H,φ):=−K∇H ·∇C,∇φ d(H,ψ):=K∇H,∇ψ
u = (C,H), v = (φ,ψ), X = V ×W u ∈ u0 +X0 : A(u,v) = F(v) ∀v ∈ X
http://www.numerik.uni-kiel.de/~mabr/gascoigne/index.html
[1] R. Becker and M. Braack. A finite element pressure gradient stabilization for the Stokes equations based
hydrodynamic load H
1.6 Output requirements
The following output quantities are expected from the simulations(both tables and graphical representations):
should be used: 10−12, 10−10, 10−8, 10−6, 10−4);
using 100 points along each line;
also be given.
J(t)=
Z
ΓK∂C(t)
∂n ds =
Z
∂ΩzK∂C(t)
∂n ds (z|∂Ω\Γ = 0) =
Z
ΩK∇C ·∇zdx.
J := 1 T
Z T
0 J(t)dt = J(C)
C := 1 T
Z T
0 C(t)dt
Find (C,H) in (C0,H0)+V ×Wsuch that: a(C,φ)+b(C,H,φ)=l(φ) ∀φ ∈ V d(H,ψ)=0 ∀ψ ∈ W
z ∈ z0 +X A′(u)(v,z) = 0 ∀v ∈ X. z = (D,G) a(φ,D)+bC(φ,H,D) = 0, bH(C,ψ,D)+d(ψ,G) = 0.
time-averaged solution dual concentration dual pressure
above...
u ∈ V : A(u,v) = F(v) ∀v ∈ V
z ∈ V : A(v,z) = G(v) ∀v ∈ V
G(u)−G(uh) = A(u−uh,z) = A(u−uh,z−zh)
suppose linear...
uh ∈ Vh : A(uh,v) = F(v) ∀v ∈ Vh
G(u)−G(uh) ≈ G(uh/2)−G(uh) = A(uh/2 −uh,zh/2 −zh)
Z
Ωη(x)dx
J(u) − J(uh) = (∇(u − uh), ∇z) = (∇(u − uh), ∇z − vh) = . . .
(∆uh + f, z − vh)K +
1 2([∂nuh], z − vh)∂K ≤
ρKωK ωK = z − vhK ρK = max(f + ∆uhK, h−1/2
K
[∂nuh]∂K)
behaves like r−3
for comparison: energy estimator
behaves like second-order !!
J(u) − J(uh) = 1 2L(uh, zh)(u − φh, z − ψh) + R, L(u, z) = J(u) + f(z) − a(u)(z). ρ(uh)(ψ) := f(ψ) − a(uh)(ψ) ρ∗(zh)(φ) := J(uh)(φ) − a(uh)(φ, zh) J(u) − J(uh) =
1 2 ρ(uh)(z−ψh)
+ 1
2 ρ∗(zh)(u−φh)
+R.
[1] R. Becker and R. Rannacher. Weighted a posteriori error control in FE methods. In e. a. H. G. Bock, editor, ENUMATH’97. World Sci. Publ., Singapore, 1995. [2] R. Becker and R. Rannacher. A feed-back approach to error control in finite element methods: Basic analysis and examples. East-West J. Numer. Math., 4:237–264, 1996. [3] R. Becker and R. Rannacher. An optimal control approach to a-posteriori error estimation. In A. Iserles, editor, Acta Numerica 2001, pages 1–102. Cambridege University Press, 2001.
Vh ≈ Q1
h
Wh ≈ Q2
2h
Ih : Vh → Wh natural z−ψh ≈ Ihzh −zh do the mesh refinement on 2h z−ψ2h ≈ zh −i2hzh
with D. Meidner, M. Schmich, B. Vexler
[1] R. Becker, D. Meidner, and B. Vexler. Efficient numerical solution of parabolic optimization problems by finite element methods. Technical report, UPPA, 2005.
[1] M. Schmich and B. Vexler. Adaptivity with dynamic meshes for space-time finite element discretizations of parabolic equations. Technical report, RICAM, 2006.
tm−1 tm tm+1
v i(1)
k v(a) Piecewise linear interpolation tm−1 tm tm+1
v i(2)
2k v(b) Piecewise quadratic interpolation
∂tθ − ∆θ = ω(θ, Y ) in Ω × I, ∂tY − 1 Le∆Y = −ω(θ, Y ) in Ω × I,
1 60|Ω|
60
ω(θ, Y ) dx dt
0.01 0.1 1e+06 1e+07 1e+08 1e+09 |J(u) − J(ukh)| |J(u)|
M
Nm uniform local equi. fixed local equi.
Find
1 2|
in Ω = (0, 1)2,
−∆u1 = f
in Ω
u1 = 0
q = ¯ Cµ, µ := 1
ωu1 dx.
qh = ¯ Cµh, µh := 1
ωu1h dx,
with
discrete solution: Ritz projection:
q − qh = ρ(y), ρ(φ) := (qhf, φ) − (∇uh, ∇φ).
q−qh=Cµ−µ
Z
Ωωu1dxqh
=
Z
Ωωuhdxqh +qh(∇u1,∇y)
=−(∇uh,∇y)+(qh f,y)
Proposition 1 For the discretization of the simple example (12,13), we have the a posteriori error estimate:
|q − qh| ≤ η :=
K∈Th
ρKωK,
(20) with the cell residual and cell weights defined by:
ρK = qhf + ∆uhK + 1
2h−1/2 K
[∂nuh]∂K,
(21)
ωK = y − ihyK + h1/2
K y − ihy∂K,
(22) where the second term in (21) involves the jump of the normal deriva- tive over the interiori faces of the mesh and is understood to be zero on boundary faces. The weights are local interpolation errors involving an arbitrary interpolation operator ih : V → Vh.
Minimize
1 2C(u) − C02
under the constraint a(u, q)(φ) = f(φ)
∀φ ∈ V.
(E is a functional on control space)
Unconstrained least squares formulation Minimize
E(q) − E(qh) = 1 2{ρ(δz) + ρ∗(δu)} + RGN + RNL a′
u(u, q)(φ, z) = − < J(JtJ)−1∇E(q), C′(u)(φ) >
ρ(φ) := (f, φ) − a(uh, qh)(φ) ρ∗(φ) := < Jh(Jt
hJh)−1∇E(qh), C′(uh)(φ) > +a′ u(uh, qh)(φ, zh)
Remarks
[1] R. Becker and B. Vexler. A posteriori error estimation for finite element discretizations of parameter identification problems. Numer. Math., 96(3):435–459, 2004.
How does this fit into the framework ?
Au = Bq, Cu − C0 → inf
Then
c(q) = Jq − C0, J = CA−1B, (J∗J)q = J∗C0 M(u, z, q, λ) := b(q, z)−a(u, z)+ < Cu−C0, λ > +E(q), λ ∈ R(J)
We find:
λ = Jµ, (J∗J)µ = E
How does this fit into the framework ?
Au = Bq, Cu − C0 → inf
Then
c(q) = Jq − C0, J = CA−1B, (J∗J)q = J∗C0 M(u, z, q, λ) := b(q, z)−a(u, z)+ < Cu−C0, λ > +E(q), λ ∈ R(J)
We find:
λ = Jµ, (J∗J)µ = E
Example −q0∆u + q1u = 2
in Ω,
u = 0
C1(u) = u(0.5, 0.5) − u1, C2(u) =
u − u2
[1] R. Becker and B. Vexler. Mesh refinement and numerical sensitivity analysis for parameter calibration of partial differential
[2] R. Griesse and B. Vexler. Numerical sensitivity analysis for the quantity of interest in pde-constrained optimization. SIAM Journal
J(u, c) = 1 2
n
|Ci(u) − ¯ Ci|2 Ci = measurements of p, v
−ν∆v + v · ∇v + ∇p = 0, div v = 0, v = m
i=1 qigi
Γ
important modes ?
mesuraments ? consider modes/mesures as “parameters”... compute (relaticve) condition numbers
R T |uk+1 − uk|2 ≤ α η(2)(Vk)
Theorem 6. Let for s > 0 u ∈ As. There exists a constant C such for ε > 0 the following holds. If the gendarme algorithm terminates with error |u − uV |2 ≤ ε then the dimensions N of V is bounded by: (28) N ≤ Cε−1/s.
0(Ω) : sup N∈N
V ∈VN |u − v|2 < +∞}.
T ) :=
T
h2
Kf−Pe V f2 K.