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Strictly Completing Partial Latin Squares Jaromy Kuhl Department of - - PowerPoint PPT Presentation

Strictly Completing Partial Latin Squares Jaromy Kuhl Department of Mathematics and Statistics University of West Florida May 2011 Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 1 / 25 Contents Introduction 1 Jaromy


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Strictly Completing Partial Latin Squares

Jaromy Kuhl

Department of Mathematics and Statistics University of West Florida

May 2011

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 1 / 25

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Contents

1

Introduction

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 2 / 25

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Contents

1

Introduction

2

Strictly Completing

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 2 / 25

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SLIDE 4

Contents

1

Introduction

2

Strictly Completing

3

Main Result

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 2 / 25

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SLIDE 5

Contents

1

Introduction

2

Strictly Completing

3

Main Result

4

Proof outline for main result

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 2 / 25

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Contents

1

Introduction

2

Strictly Completing

3

Main Result

4

Proof outline for main result

5

Completing partial latin boxes

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 2 / 25

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Introduction

Current Section

1

Introduction

2

Strictly Completing

3

Main Result

4

Proof outline for main result

5

Completing partial latin boxes

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 3 / 25

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Introduction

partial latin squares

Definition 1 A partial latin square of order n is an n × n array of n symbols so that each symbol appears at most once in each row and column.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 4 / 25

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Introduction

partial latin squares

Definition 1 A partial latin square of order n is an n × n array of n symbols so that each symbol appears at most once in each row and column. 1 3 5 4 3 1 3 3 1 3 4 1

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 4 / 25

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Introduction

partial latin squares

Definition 1 A partial latin square of order n is an n × n array of n symbols so that each symbol appears at most once in each row and column. 1 3 5 4 3 1 3 3 1 3 4 1 1 2 3 4 5 2 4 1 5 3 5 1 2 3 4 4 3 5 1 2 3 5 4 2 1

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 4 / 25

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Introduction

completing partial latin squares

Theorem 1 (Smetaniuk, 1981) Every partial latin square of order n with at most n − 1 entries is completable.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 5 / 25

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Introduction

avoiding partial Latin squares

Definition 2 A partial Latin square P of order n is called avoidable if there is a Latin square L of order n such that on every set of n symbols L contains no part of P.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 6 / 25

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Introduction

avoiding partial Latin squares

Definition 2 A partial Latin square P of order n is called avoidable if there is a Latin square L of order n such that on every set of n symbols L contains no part of P. 1 1 2 3 4 1 5 2 3 4

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 6 / 25

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Introduction

avoiding partial Latin squares

Definition 2 A partial Latin square P of order n is called avoidable if there is a Latin square L of order n such that on every set of n symbols L contains no part of P. 1 1 2 3 4 1 5 2 3 4 2 3 5 1 4 1 2 4 5 3 5 1 3 4 2 3 4 1 2 5 4 5 2 3 1

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 6 / 25

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Introduction

avoiding partial latin squares

Theorem 1 Every partial Latin square of order k ≥ 4 is avoidable.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 7 / 25

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Introduction

avoiding partial latin squares

Theorem 1 Every partial Latin square of order k ≥ 4 is avoidable. 1 2

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 7 / 25

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Introduction

avoiding partial latin squares

Theorem 1 Every partial Latin square of order k ≥ 4 is avoidable. 1 2 1 2 3 3 1 2 1

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 7 / 25

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Strictly Completing

Current Section

1

Introduction

2

Strictly Completing

3

Main Result

4

Proof outline for main result

5

Completing partial latin boxes

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 8 / 25

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Strictly Completing

strictly completing partial latins squares

Definition 3 Let P and Q be partial latin squares of order n that avoid each other. We say that P is strictly completable with respect to Q if P can be completed to a Latin square L and L avoids Q.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 9 / 25

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Strictly Completing

strictly completing partial latins squares

Definition 3 Let P and Q be partial latin squares of order n that avoid each other. We say that P is strictly completable with respect to Q if P can be completed to a Latin square L and L avoids Q. Conjecture 1 Let P and Q be partial latin squares of order n > 3 that avoid each

  • ther. If P contains at most n − 2 entries, then P can is strictly

completable with respect to Q.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 9 / 25

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Strictly Completing

strictly completing partial latins squares

Definition 3 Let P and Q be partial latin squares of order n that avoid each other. We say that P is strictly completable with respect to Q if P can be completed to a Latin square L and L avoids Q. Conjecture 1 Let P and Q be partial latin squares of order n > 3 that avoid each

  • ther. If P contains at most n − 2 entries, then P can is strictly

completable with respect to Q. 1 2 3

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 9 / 25

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Strictly Completing

strictly completing partial latins squares

Definition 3 Let P and Q be partial latin squares of order n that avoid each other. We say that P is strictly completable with respect to Q if P can be completed to a Latin square L and L avoids Q. Conjecture 1 Let P and Q be partial latin squares of order n > 3 that avoid each

  • ther. If P contains at most n − 2 entries, then P can is strictly

completable with respect to Q. 1 2 3 4

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 9 / 25

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Main Result

Current Section

1

Introduction

2

Strictly Completing

3

Main Result

4

Proof outline for main result

5

Completing partial latin boxes

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 10 / 25

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Main Result

Theorem 2 Let k = 4t for t ≥ 9 be a positive integer.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 11 / 25

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Main Result

Theorem 2 Let k = 4t for t ≥ 9 be a positive integer. Let P and Q be partial latin squares of order k such that P and Q avoid each other.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 11 / 25

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Main Result

Theorem 2 Let k = 4t for t ≥ 9 be a positive integer. Let P and Q be partial latin squares of order k such that P and Q avoid each other. If P contains at most t − 1 entries, then P can be strictly completed with respect to Q.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 11 / 25

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Main Result

preliminary results

Lemma 3 Let P and Q be partial latin squares of order 4 that avoid each other and let P contain at most one entry. Then P can be strictly completed with respect to Q provided

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 12 / 25

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Main Result

preliminary results

Lemma 3 Let P and Q be partial latin squares of order 4 that avoid each other and let P contain at most one entry. Then P can be strictly completed with respect to Q provided 1. Q contains at most 3 symbols, or

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 12 / 25

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Main Result

preliminary results

Lemma 3 Let P and Q be partial latin squares of order 4 that avoid each other and let P contain at most one entry. Then P can be strictly completed with respect to Q provided 1. Q contains at most 3 symbols, or 2. Q contains 4 symbols of which at least one appears only

  • nce.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 12 / 25

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Main Result

preliminary results

Definition 4 Let X be a partial array of symbols of order 4.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 13 / 25

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Main Result

preliminary results

Definition 4 Let X be a partial array of symbols of order 4. A 4-tuple of symbols is called bad in X if each symbol in the 4-tuple appears at least twice in X.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 13 / 25

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Main Result

preliminary results

Definition 4 Let X be a partial array of symbols of order 4. A 4-tuple of symbols is called bad in X if each symbol in the 4-tuple appears at least twice in X. Lemma 4 Let x be a symbol appearing in X. There are at most 20 bad 4-tuples in X containing x.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 13 / 25

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Main Result

theorem of Daykin and Häggkvist

Theorem 5 Let 0 ≤ d < k and let H be an r-partite r-uniform hypergraph with minimum degree δ(H) and |V(H)| = rk. If δ(H) > r − 1 r

  • kr−1 − (k − d)r−1

, then H has more than d independent edges.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 14 / 25

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Proof outline for main result

Current Section

1

Introduction

2

Strictly Completing

3

Main Result

4

Proof outline for main result

5

Completing partial latin boxes

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 15 / 25

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Proof outline for main result

We may suppose that

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 16 / 25

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Proof outline for main result

We may suppose that 1. the symbols appearing in P come from the set {1, 2, . . . , t},

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 16 / 25

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Proof outline for main result

We may suppose that 1. the symbols appearing in P come from the set {1, 2, . . . , t}, 2. no two entries appear in the same 4 × 4 subsquare of P, and

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 16 / 25

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Proof outline for main result

We may suppose that 1. the symbols appearing in P come from the set {1, 2, . . . , t}, 2. no two entries appear in the same 4 × 4 subsquare of P, and 3. no symbol appears in two 4 × 4 subsquares of P sharing the same rows or columns.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 16 / 25

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Proof outline for main result

We may suppose that 1. the symbols appearing in P come from the set {1, 2, . . . , t}, 2. no two entries appear in the same 4 × 4 subsquare of P, and 3. no symbol appears in two 4 × 4 subsquares of P sharing the same rows or columns. 1 1 2 3

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 16 / 25

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Proof outline for main result

Let T be a partial latin square of order t on the symbol set {X1, . . . , Xt} such that

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 17 / 25

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Proof outline for main result

Let T be a partial latin square of order t on the symbol set {X1, . . . , Xt} such that cell (j, l) contains Xi if and only if i appears in the corresponding 4 × 4 subsquare of P.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 17 / 25

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Proof outline for main result

Let T be a partial latin square of order t on the symbol set {X1, . . . , Xt} such that cell (j, l) contains Xi if and only if i appears in the corresponding 4 × 4 subsquare of P. 1 1 2 3

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 17 / 25

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Proof outline for main result

Let T be a partial latin square of order t on the symbol set {X1, . . . , Xt} such that cell (j, l) contains Xi if and only if i appears in the corresponding 4 × 4 subsquare of P. 1 1 2 3 X1 X1 X2 X3

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 17 / 25

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Proof outline for main result

Let T be a partial latin square of order t on the symbol set {X1, . . . , Xt} such that cell (j, l) contains Xi if and only if i appears in the corresponding 4 × 4 subsquare of P. 1 1 2 3 X1 X1 X2 X3 Since T contains at most t − 1 entries, T can be completed.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 17 / 25

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Proof outline for main result

We wish to find a partition S1, S2, . . . , St of [4t] such that

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 18 / 25

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Proof outline for main result

We wish to find a partition S1, S2, . . . , St of [4t] such that 1. |Si| = 4 for each i ∈ [t],

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 18 / 25

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Proof outline for main result

We wish to find a partition S1, S2, . . . , St of [4t] such that 1. |Si| = 4 for each i ∈ [t], 2. i ∈ Si for each i ∈ [t],

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 18 / 25

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Proof outline for main result

We wish to find a partition S1, S2, . . . , St of [4t] such that 1. |Si| = 4 for each i ∈ [t], 2. i ∈ Si for each i ∈ [t], 3. there are latin squares of order 4 on Si avoiding the 4 × 4 subsquares in Q corresponding to each Xi, and

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 18 / 25

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Proof outline for main result

We wish to find a partition S1, S2, . . . , St of [4t] such that 1. |Si| = 4 for each i ∈ [t], 2. i ∈ Si for each i ∈ [t], 3. there are latin squares of order 4 on Si avoiding the 4 × 4 subsquares in Q corresponding to each Xi, and 4. there are latin squares of order 4 on Si completing the 4 × 4 subsquares in P corresponding to each Xi.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 18 / 25

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Proof outline for main result

We wish to find a partition S1, S2, . . . , St of [4t] such that 1. |Si| = 4 for each i ∈ [t], 2. i ∈ Si for each i ∈ [t], 3. there are latin squares of order 4 on Si avoiding the 4 × 4 subsquares in Q corresponding to each Xi, and 4. there are latin squares of order 4 on Si completing the 4 × 4 subsquares in P corresponding to each Xi.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 18 / 25

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Proof outline for main result

1 1 2 3 X1 X1 X2 X3

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 19 / 25

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Proof outline for main result

1 1 2 3 X1 X1 X2 X3 X1 X1 X1 X2 X1 X1 X3

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 19 / 25

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Proof outline for main result

1 1 2 3 X1 X1 X2 X3 X1 X1 X1 X2 X1 X1 X3 If such a partition can be found, then P is strictly completable with respect to Q.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 19 / 25

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Proof outline for main result

Let H be a 4-partite, 4-uniform hypergraph with vertex set {A, B, C, D} such that

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 20 / 25

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Proof outline for main result

Let H be a 4-partite, 4-uniform hypergraph with vertex set {A, B, C, D} such that 1. A = {(Xi, i) : i ∈ [t]}, 2. B = {t + 1, . . . , 2t}, 3. C = {2t + 1, . . . , 3t}, and 4. D = {3t + 1, . . . , 4t}.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 20 / 25

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Proof outline for main result

Let H be a 4-partite, 4-uniform hypergraph with vertex set {A, B, C, D} such that 1. A = {(Xi, i) : i ∈ [t]}, 2. B = {t + 1, . . . , 2t}, 3. C = {2t + 1, . . . , 3t}, and 4. D = {3t + 1, . . . , 4t}. The edge ((Xi, i), b, c, d) is included in H if and only if {i, b, c, d} is not a bad 4-tuple for each 4 × 4 subsquare of Q corresponding to Xi in T.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 20 / 25

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Proof outline for main result

dH((Xi, i)) ≥ t3 − 20t

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 21 / 25

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Proof outline for main result

dH((Xi, i)) ≥ t3 − 20t δ(H) ≥ t3 − 20t

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 21 / 25

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Proof outline for main result

dH((Xi, i)) ≥ t3 − 20t δ(H) ≥ t3 − 20t According to the theorem of Daykin and Häggkvist; H has t independent edges provided δ(H) > 3

4(t3 − 1).

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 21 / 25

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Proof outline for main result

dH((Xi, i)) ≥ t3 − 20t δ(H) ≥ t3 − 20t According to the theorem of Daykin and Häggkvist; H has t independent edges provided δ(H) > 3

4(t3 − 1).

Theorem 6 Let 0 ≤ d < k and let H be an r-partite r-uniform hypergraph with minimum degree δ(H) and |V(H)| = rk. If δ(H) > r − 1 r

  • kr−1 − (k − d)r−1

, then H has more than d independent edges.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 21 / 25

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Proof outline for main result

δ(H) ≥ t3 − 20t

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 22 / 25

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Proof outline for main result

δ(H) ≥ t3 − 20t > 3 4(t3 − 1)

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 22 / 25

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Proof outline for main result

δ(H) ≥ t3 − 20t > 3 4(t3 − 1) Let {e1, . . . , et} be t independent edges in H where ei = ((Xi, i), b, c, d).

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 22 / 25

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Proof outline for main result

δ(H) ≥ t3 − 20t > 3 4(t3 − 1) Let {e1, . . . , et} be t independent edges in H where ei = ((Xi, i), b, c, d). Set Si = {i, b, c, d} for each i.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 22 / 25

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Completing partial latin boxes

Current Section

1

Introduction

2

Strictly Completing

3

Main Result

4

Proof outline for main result

5

Completing partial latin boxes

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 23 / 25

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Completing partial latin boxes

Theorem 7 Let t ≥ 9. Let P be a 2 × 4t × 4t partial latin box with at most 2t − 1

  • entries. Then P can be completed.

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 24 / 25

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Completing partial latin boxes

THANK YOU FOR YOUR ATTENTION!

Jaromy Kuhl (UWF) Strictly Completing Partial Latin Squares May 2011 25 / 25