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Separation principles Insight in the design equations for downstream processing Prof. Luuk van der Wielen, Department of Biotechnology, Faculty of Applied Sciences FERMENTER cell-disruption Mechanical separations cell removal (including solid


  1. Separation principles Insight in the design equations for downstream processing Prof. Luuk van der Wielen, Department of Biotechnology, Faculty of Applied Sciences

  2. FERMENTER cell-disruption Mechanical separations cell removal (including solid particles) concentration Molecular separations (dissolved molecules only) purification formulation let’s tackle these first! MARKET

  3. Important concept: equilibrium stage S = Separation (extraction) factor V • appears in adsorption, absorption, stripping x 0 y 1 ‘0’ 1 • describes ratio of transport capacities • indicates how much auxiliary phase (V) is x 1 y 2 ‘2’ required per amount of feed! • capacity of auxiliary phase goes on top L assumption: outgoing flows at equilibrium

  4. Important concept: equilibrium stage 100 V x 0 y 1 ‘0’ extract feed Yield % ‘1’ 0 x 1 y 2 1 3 0 ‘2’ 2 raffinate solvent Separation factor S L ‘in’ via ‘in’ via’ ‘out’ via ‘out’ via + = + feed solvent raffinate extract

  5. Multi-stage and countercurrent V, y 1 Solving mass balances for N number of stages, using the L, x 0 equilibrium relation y = K x 1 y 2 x 1 2 N=10 y 3 x 2 100 Adding more stages increases N=5 the yield! N=2 N -1 Yield % N=1 y N x N -1 N Number of stages N 0 S V, y N +1 L, x N 1 3 0 2

  6. Relating to economy – the rough explanation S à Indicates costs of auxiliary phase per amount of feedstock (V/L) and thus affects operational expenditures ( OPEX , €) N à Adding stages requires investment: affects capital expenditures ( CAPEX , €) total OPEX Costs For a specific yield (say 99%), we can now € calculate the required number of stages N for any separation factor S CAPEX You have to pay both ( total ) Separation factor S

  7. Relating to economy – more detail CAPEX-estimates can come from • Comparable plant (somewhere else) Experience or rules of thumb • • Such as: 100 M$ for 100 kton per annum liquid volume capacity Increased • Solids handling plants twice as expensive accuracy Short-cut design (back of envelope calculation) • • Detailed design Fundamental calculations •

  8. Multi-stage and countercurrent V, y 1 L, x 0 ‘in’ via ‘in’ via’ ‘out’ via ‘out’ via 1 + = + feed solvent raffinate extract y 2 x 1 2 Try to design for most efficient solvent use (V min ) y 3 x 2 • feed ‘in’ = extract ‘out’ Lx 0 = Vy 1 • highest concentration feed x 1 = x 0 N -1 • at equilibrium Lx 0 = VKx 0 y N x N -1 N S min = 1 but N 8 L, x N V, y N +1

  9. Separation factor indicates direction of transport N=10 100 N=5 N=2 Yield % N=1 0 S 1 3 0 2 S < 1 S > 1 product ‘moves’ with feed L product ‘moves’ with solvent V

  10. Multi-stage and countercurrent A V, y 1 L, x 0 • Use differences in S to separate multiple components 1 • Feed stage in between top section and bottom section y 2 x 1 2 • If component A has bigger affinity for V than component B then: y 3 x 2 • K A > K B • A moves ‘up’ with V if: S A (top) > 1, and S A (bottom) > 1 N -1 • B moves ‘down’ with L if: S B (top) < 1, and S B (bottom) < 1 y N x N -1 N L, x N V, y N +1 B

  11. Multi-stage and countercurrent stripping V, y 1 L, x 0 1 V L y 2 x 1 absorption back-extraction 2 L L’ y 3 x 2 extraction dissolve L Crystal N -1 crystallisation y N desorption x N -1 N V/L Sorbent adsorption L, x N V, y N +1

  12. Mechanical separations Feedstream F Supernatant or filtrate Contains particles (cells, crystals etc) Contains solutes and dissolved molecules (solutes) = F – C – αC F α depends on the choice of mechanical separation C Wet cells = cells (C) + cells with adherent solution ( αC) including αC solutes

  13. Equilibrium stage for mechanical separation V, y 1 V, y 2 F – (1+ α )C, c F V,y F – (1+ α )C, c F α C, cF L,x C L, x 0 L, x 1 F,C, c F (1+ α )C, c

  14. Mechanical separations often include countercurrent wash W Same approach as for countercurrent molecular V, y 1 L, x 0 separations with: 1 y 2 x 1 L = (1+α)C and V = F – (1+α)C + W 2 y 3 N=10 x 2 100 N=5 N -1 N=2 Yield % N=1 y N x N -1 N 0 L, x N V, y N +1 S 0 1 3 2

  15. Design recipe (always works) mass balance (overall, phase, local) out in phase and reaction equilibria ( K ’s) rate equilibrium hydrodynamics in out mass transfer and reaction rate ( k ’s) mass balance

  16. Design recipe (always works) 1+2) how much beans, water & energy? mass balance (overall, phase, local) out in phase and reaction equilibria ( K ’s) rate equilibrium hydrodynamics in out mass transfer and reaction rate ( k ’s) mass balance

  17. Design recipe (always works) 1+2) how much beans, water & energy? mass balance (overall, phase, local) out in phase and reaction equilibria ( K ’s) rate equilibrium hydrodynamics in out mass transfer and reaction rate ( k ’s) 3) how big of a coffee maker do you need? mass balance (even: how big a power plant to operate it?)

  18. See you next unit

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