Random quadratic Julia sets and quasicircles
Krzysztof Lech March 27, 2020
Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 1 / 19
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Random quadratic Julia sets and quasicircles Krzysztof Lech March 27, 2020 Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 1 / 19 Introduction and notation We will consider compositions of functions f n ( z ) = z 2
Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 1 / 19
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Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 3 / 19
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n(F −1 n
n−1
n
n−1
n,j (z)
n
n
n,k (w)
n,k (z) | =
n,k (w)−F −1 n,k (z)
n,k (z)
Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 16 / 19
Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 16 / 19
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Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 18 / 19
Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 18 / 19
k(ζ)
k(F −1 k
k
k
k
k
k(z)|(1+αeα) and have
k(z)|(1+αeα) =
k(z)| for any arbitrary z ∈ Uk. Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 18 / 19
Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 18 / 19
Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 18 / 19
k
k
k
k
k(z)| =
k(z)| for
Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 18 / 19
k−m(z)|. Now we have:
k(ζk−1)| +
k−1(ζk−2)| + ... +
k−m(z)|). Thus we have
m
F′ k−m(z) F′ k−m+j (ζk−m+j−1) |
k−m(z)
k−m+j(ζk−m+j−1) =
k−m(z)
k−m(ζk−m+j−1). Now
k−m(z)
k−m+j(ζk−m+j−1)| qj|
k−m(z)
k−m(ζk−m+j−1)| where q = 1
Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 18 / 19
p(z)
p(ζp+j−1)| = | (F −1 p
p
m
Krzysztof Lech Random quadratic Julia sets and quasicircles March 27, 2020 18 / 19
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