Outline I. Flags what is a flag? who cares? II. (commutative) - - PowerPoint PPT Presentation
Outline I. Flags what is a flag? who cares? II. (commutative) - - PowerPoint PPT Presentation
PO-set paths and q -commuting minors Aaron Lauve LaCIM - UQAM S eminaire de combinatoire et dinformatique math ematique le 7 avril 2006 http://www.lacim.uqam.ca/ lauve (Research) lauve@lacim.uqam.ca Outline I. Flags
Outline
- I. Flags
- what is a flag?
- who cares?
- II. (commutative) Generic matrices
- column-minor identities
- homogeneous coordinate ring of the flag variety
- III. q-Generic matrices
- row-quantum-minor identities
- quantum flag variety
- IV. (noncommutative) Generic matrices
- row-quasi-minor identities
- specializations
- V. q-Commuting minors
- “missing” relations
- PO-set paths
1
I. Flags
- Fix: an integer n > 1 and a vector space V = Cn.
- Fix: a sequence of integers λ : n ≥ λ1 > λ2 > · · · > λs ≥ 0.
Definition (Flag). A flag Φ of shape λ is a chain of subspaces
Φ : 0 ⊆ V1 V2 · · · Vs ⊆ V
satisfying λi = codim Vi = n − dim Vi. Denote the collection of all flags of shape λ by
Fl(λ).
2
I. Flags
- Fix: an integer n > 1 and a vector space V = Cn.
- Fix: a sequence of integers λ : n ≥ λ1 > λ2 > · · · > λs ≥ 0.
Definition (Flag). A flag Φ of shape λ is a chain of subspaces
Φ : 0 ⊆ V1 V2 · · · Vs ⊆ V
satisfying λi = codim Vi = n − dim Vi. Denote the collection of all flags of shape λ by
Fl(λ).
- Example. Taking n = 6 and λ = (5, 3, 2),
Φ : span {v1} ⊆ span {v1, v2, v3} ⊆ span {v1, v2, v3, v4}
is a flag when v1, . . . , v4 are linearly independent.
3
I. Flags
- Fix: an integer n > 1 and a vector space V = Cn.
- Fix: a sequence of integers λ : n ≥ λ1 > λ2 > · · · > λs ≥ 0.
Definition (Flag). A flag Φ of shape λ is a chain of subspaces
Φ : 0 ⊆ V1 V2 · · · Vs ⊆ V
satisfying λi = codim Vi = n − dim Vi. Denote the collection of all flags of shape λ by
Fl(λ).
- Example. Taking n = 6 and λ = (5, 3, 2),
Φ : span {v1} ⊆ span {v1, v2, v3} ⊆ span {v1, v2, v3, v4}
is a flag when v1, . . . , v4 are linearly independent.
- Choose a basis B for V and express Φ as a matrix A(Φ). . .
4
I. Flags
- Φ : span {v1} ⊆ span {v1, v2, v3} ⊆ span {v1, v2, v3, v4}
A(Φ) = a11 a12 a13 a14 a15 a16 a21 a22 a23 a24 a25 a26 a31 a32 a33 a34 a35 a36 a41 a42 a43 a44 a45 a46 V1 V2 V2 V3
5
I. Flags
- Φ : span {v1} ⊆ span {v1, v2, v3} ⊆ span {v1, v2, v3, v4}
A(Φ) = a11 a12 a13 a14 a15 a16 a21 a22 a23 a24 a25 a26 a31 a32 a33 a34 a35 a36 a41 a42 a43 a44 a45 a46 V1 V2 V2 V3
6
I. Flags
- Φ : span {v1} ⊆ span {v1, v2, v3} ⊆ span {v1, v2, v3, v4}
A(Φ) = a11 a12 a13 a14 a15 a16 a21 a22 a23 a24 a25 a26 a31 a32 a33 a34 a35 a36 a41 a42 a43 a44 a45 a46 V1 V2 V2 V3
7
I. Flags
- Φ : span {v1} ⊆ span {v1, v2, v3} ⊆ span {v1, v2, v3, v4}
A(Φ) = a11 a12 a13 a14 a15 a16 a21 a22 a23 a24 a25 a26 a31 a32 a33 a34 a35 a36 a41 a42 a43 a44 a45 a46 V1 V2 V2 V3
- Unique up to change of basis! . . . multiplying by Pλ =
∗ ∗ ∗ ∗ ∗ ∗ ∗ ∗ ∗ ∗ ∗
- n the left.
8
I. Who Cares?
A(Φ) = a11 a12 · · · · · · a1n a21 a22 a2n
. . . . . . . . .
ad1 ad2 · · · · · · adn (d = n − λs)
Representation Theory Notice that GLn(C) (and its many important subgroups) permutes
Fl(λ) by right-multiplication.
9
I. Who Cares?
A(Φ) = a11 a12 a13 a14 a21 a22 a23 a24
Topology/Algebraic Geometry The space Fl(λ) is a (projective) algebraic variety and a CW-complex, described via Gaussian elimination (G.E.). Consider the case n = 4, λ = (2):
- G.E.
− →
Open cells:
µ = (00)
- (10)
- (20)
- (11)
- (21)
- (22)
- 10
I. Who Cares?
A(Φ) = a11 a12 a13 a14 a21 a22 a23 a24
Topology/Algebraic Geometry The space Fl(λ) is a (projective) algebraic variety and a CW-complex, described via Gaussian elimination. Consider the case n = 4, λ = (2): Schubert cells Ωµ:
µ = (00)
- (10)
- (20)
- (11)
- (21)
- (22)
- Partitions µ with |λ| = 2 parts and part-size at most n − 2 = 2.
Combinatorics The classes [Ωµ] in the cohomology ring H•(Fl(λ)) are Schur polynomials!!
11
II. (commutative) Generic Matrices
- Definition. Let X = (xij) be an n × n matrix of commuting indeterminants. Call X a
generic matrix (coordinate functions for a “generic point” in Cn2).
- Definition. For I, J ∈ [n]d, put XI,J =
xi1j1 xi1j2 · · · xi1jd xi2j1 xi2j2 · · · xi2jd
. . . . . . . . .
xidj1 xidj2 · · · xidjd
. Let XJ denote the special case I = (1, 2, . . . , d) (take the first d rows of X). Consider the column-minors of shape λ:
M(λ) = {[ [I] ] := det XI : n − |I| ∈ λ} .
Problem: Describe the relations R among the minors M(λ).
12
II. (commutative) Generic Matrices
Answer (Schur ‘01, Hodge ‘43): The minors M(λ) satisfy the Young symmetry relations
0 =
- Λ⊆L
|Λ|=r
(−1)ℓ(L\Λ|Λ)[ [L \ Λ] ][ [Λ|M] ]
(YL,M) for any 1 ≤ r and any L, M ⊆ [n] with |M| + r ≤ |L| − r ∈ n − λ. Moreover, writing M(λ) = {I1, . . . IN}, if F(Z1, . . . , ZN) is a polynomial which is zero on substitution Zi → [
[Ii] ], then F is algebraically dependent on the (YL,M).
Example:
[ [12] ][ [34] ] − [ [13] ][ [24] ] + [ [23] ][ [14] ] = 0.
Non-example: (Sylvester’s Identity)
(det A123,123) (det A2,2) = (det A12,12) (det A23,23) − (det A12,23) (det A23,12) .
13
III.
q-Generic Matrices
- Definition. Call a matrix X q-generic if every 2 × 2 submatrix
2 6 6 6 6 4
a b c d
3 7 7 7 7 5 satisfies:
(←) ba = q ab dc = q cd ( ↑ ) ca = q ac db = q bd (ր) cb = bc (տ) da = ad + (q − q−1) bc
Define the quantum determinant by
detqXI,J =
- σ∈Sd
(−q)−ℓ(σ)xi1jσ(1) xi2jσ(2) · · · xidjσ(d)
for I, J ∈ [n]d, and let [
[J] ] now denote detqXJ.
Problem: Describe the relations R among the minors Mq(λ).
14
III.
q-Generic Matrices
Answer (Taft-Towber ‘91): The set R is (algebraically) generated by the relations below:
q-Alternating: (∀I ∈ [n]d) [ [I] ] = (−q)−ℓ(σ)[ [σI] ] if σ “straightens” I. q-Young symmetry: (∀L, M ⊆ [n], r > 0) s.t. |M| + r ≤ |L| − r 0 =
- Λ⊂L,|Λ|=r
(−q)−ℓ(L\Λ|Λ)[ [L \ Λ] ][ [Λ | M] ] .
(YL,M)
q-Straightening: (∀I, J [n]) s.t. |J| < |I| [ [J] ][ [I] ] =
- Λ⊆I,|Λ|=|J|
(−q)+ℓ(Λ|I\Λ)[ [J|I \ Λ] ][ [Λ] ] .
(SJ,I) Example:
[ [12] ][ [34] ] − 1
q[
[13] ][ [24] ] + 1
q2 [
[23] ][ [14] ] = 0.
Non-examples: (cf. Goodearl, ‘05)
15
IV. (noncommutative) Generic Matrices
- Now let X be a matrix of noncommuting variables.
Definition (Gelfand-Retakh ‘91). The (ij)-quasideterminant |X|ij is defined whenever Xij is invertible, and in that case,
|X|ij =
- 16
IV. (noncommutative) Generic Matrices
- Now let X be a matrix of noncommuting variables.
Definition (Gelfand-Retakh ‘91). The (ij)-quasideterminant |X|ij is defined whenever Xij is invertible, and in that case,
|X|ij =
- =
− ·
−1 ·
- 2 × 2 Example:
|A|12 =
- a11 a12
a21 a22
- = a12 − a11a−1
21 a22.
17
IV. (noncommutative) Generic Matrices
- It is better to take ratios of quasideterminants as “column-minor” replacements
- Definition. Given an n × n matrix X and a partition λ, the column-minors are given by
Mquasi(λ) =
- pK
ij (X) := |Xi∪K|−1 di |Xj∪K|dj
- i, j ∈ [n], K ⊆ [n] \ i, n − 1 − |K| ∈ λ
- Quasi-Pl¨
ucker Relations (Gelfand-Retakh ‘97, L. ’04): If L, M ⊆ [n], i ∈ [n] \ M,
|M| ≤ |L| − 1, then: 1 =
- j∈L
pM
ij (X)pL\j ji (X) .
(Pi,L,M) Problem: Describe the relations R satisfied by Mquasi
- Need to expand search to rational expressions, not just algebraic ones.
- some are known. . . maybe all?
18
IV. (noncommutative) Generic Matrices
Why study these matrices?
- May study “all” the deformations of the commutative generic matrix at once!
- X → commutative generic:
pK
ij → ratio of two determinants [
[i ∪ K] ]−1[ [j ∪ K] ]
- X → q-generic:
pK
ij → ratio of two quantum determinants [
[i ∪ K] ]−1[ [j ∪ K] ]
Question: How much of R(M) or R(Mq) may be recovered on specializing X and
R(Mquasi)?
Answer: For commutative case, all. For q-generic case, a lot. . .
19
V. “Missing” Relations
- While showing R(Mquasi) ⇒ (YL,M) for quantum setting, we discover something “new:”
- [
[I] ] and [ [J] ] often q-commute [Krob-Leclerc ‘95].
- Definition. Given two subsets I, J ⊆ [n], we say J surrounds I, written J I, if (i)
|J| ≤ |I|, and (ii) there exist disjoint subsets ∅ ⊆ J ′, J′′ ⊆ J such that:
- a. J \ I = J′ ˙
∪ J′′,
- b. j′ < i for all j′ ∈ J′ and i ∈ I \ J,
- c. i < j′′ for all i ∈ I \ J and j′′ ∈ J′,
Theorem (q-Commuting Minors). If the subsets I, J ⊆ [n] satisfy J I, the quantum minors [
[J] ] and [ [I] ] q-commute. Specifically, [ [J] ][ [I] ] = q|J′′|−|J′|[ [I] ][ [J] ] .
(CJ,I)
20
V. Finding the Missing Relations
Theorem (L, ‘06). Given I, J ⊆ [n]. If J I, then the sum CJ,I may be written as a
Z[q, q−1]-linear combination of the sums SJ,I and YI∪(J\K),K ( ∅ ⊆ K J ). The
coefficients involved are described in terms of path-weighs in a directed graph. Open Question (converse): Give an easy proof that only if J I can CJ,I be so written. [Leclerc-Zelevinsky ‘98]
21
V. Example 1
Writing C1,234 in terms of S1,234 and YL,M.
C1,234 f1f234 −q−1f234f1 S1,234 f1f234 −q2f123f4 +q1f124f3 −q0f134f2 q2 Y1234,∅ f123f4 −q−1f124f3 +q−2f134f2 −q−3f234f1
22
V. Example 1
Writing C1,234 in terms of S1,234 and YL,M.
C1,234 f1f234 −q−1f234f1 S1,234 f1f234 −q2f123f4 +q1f124f3 −q0f134f2 q2 Y1234,∅ q2f123f4 −q1 f124f3 +q0 f134f2 −q−1f234f1 C1,234 = S1,234 + q2Y1234,∅
23
V. Example 2
Writing C14,23 in terms of YL,M.
[14][23] [24][13] [34][12] [12][34] [13][24] [23][14] C14,23 1 −1 Y1234,∅ q−2 −q−3 q−4 1 −q−1 q−2 Y234,1 q−2 −q−3 −q−1 Y123,4 1 −q−1 q−2
24
V. Example 2
Writing C14,23 in terms of YL,M.
[14][23] [24][13] [34][12] [12][34] [13][24] [23][14] C14,23 1 −1 Y1234,∅ q−2 −q−3 q−4 1 −q−1 q−2 Y234,1 q−2 −q−3 −q−1 Y123,4 1 −q−1 q−2
25
V. Example 2
Writing C14,23 in terms of YL,M.
[14][23] [24][13] [34][12] [12][34] [13][24] [23][14] C14,23 1 −1 Y1234,∅ q−2 −q−3 q−4 1 −q−1 q−2 Y234,1 q−2 −q−3 −q−1 Y123,4 1 −q−1 q−2
26
V. Example 2
Writing C14,23 in terms of YL,M.
[14][23] [24][13] [34][12] [12][34] [13][24] [23][14] C14,23 1 −1 Y1234,∅ q−2 −q−3 q−4 1 −q−1 q−2 Y234,1 q−2 −q−3 −q−1 Y123,4 1 −q−1 q−2
27
V. Example 2
Writing C14,23 in terms of YL,M.
[14][23] [24][13] [34][12] [12][34] [13][24] [23][14] C14,23 1 −1 Y1234,∅ q−2 −q−3 q−4 1 −q−1 q−2 Y234,1 q−2 −q−3 −q−1 Y123,4 1 −q−1 q−2
28
V. Example 3
Writing C156,234 in terms of YL,M.
e∅ e1 e5 e6 e15 e16 e56 e156 y∅ 1 α1
∅
α5
∅
α6
∅
α15
∅
α16
∅
α56
∅
α156
∅
y1 1 α15
1
α16
1
α156
1
y5 1 α15
5
α56
5
α156
5
y6 1 α16
6
α56
6
α156
6
y15 1 α156
15
y16 1 α156
16
y56 1 α156
56
29
V. Example 3
Writing C156,234 in terms of YL,M.
e∅ e1 e5 e6 e15 e16 e56 e156 y∅ 1 α1
∅
α5
∅
α6
∅
α15
∅
α16
∅
α56
∅
α156
∅
y1 1 α15
1
α16
1
α156
1
y5 1 α15
5
α56
5
α156
5
y6 1 α16
6
α56
6
α156
6
y15 1 α156
15
y16 1 α156
16
y56 1 α156
56
- Perform Gaussian Elimination!!
- Hope that what remains on the first row is 1 and (−q)θq2−1
30
V. Example 3
Writing C156,234 in terms of YL,M.
e∅ e1 e5 e6 e15 e16 e56 e156 y∅ 1 α1
∅
α5
∅
α6
∅
α15
∅
α16
∅
α56
∅
α156
∅
y1 1 α15
1
α16
1
α156
1
y5 1 α15
5
α56
5
α156
5
y6 1 α16
6
α56
6
α156
6
y15 1 α156
15
y16 1 α156
16
y56 1 α156
56
- Perform Gaussian Elimination!!
- In general, we get:
coeff
- eJ
= αJ
∅ −
- ∅AJ
αA
∅ αJ A +
- ∅ABJ
αA
∅ αB AαJ B − · · ·
31
V. Example 3
A directed graph with edge-weights Γ(J; I) associated to J = 156 and I = 234.
56 156 6 16 5 15
α156
15
∅
α1
∅
1
α15
1
− →
α1
∅α15 1 α156 15 = −q−5
32
V. Example 3
A directed graph with edge-weights Γ(J; I) associated to J = 156 and I = 234.
56 156 6 16 5 15
α156
15
∅
α1
∅
1
α15
1
− →
α1
∅α15 1 α156 15 = −q−5
33
V. Example 3
A directed graph with edge-weights Γ(J; I) associated to J = 156 and I = 234.
56 156 6 16 5 15
α156
15
∅
α1
∅
1
α15
1
− →
α1
∅α15 1 α156 15 = −q−5
αB
A
:= (−q)−ℓ(J\B|B\A)−ℓ(B\A|A)+{2|J\B|−|I|}·|(B\A)∩J ′| αB
AαC B
=
- (−q)2ℓ((B\A)∩J′|C\B)−2ℓ(C\B|(B\A)∩J′′)
αC
A
34
V. PO-set paths
Let J = J′ ∪ J′′ = {j′
1, . . . , j′ r′} ∪ {j′′ 1, . . . , j′′ r′′}. We consider certain paths in Γ(J; I):
P0 =
- (A1, A2, . . . , Ap) | Ai ⊆ J s.t. ∅ A1 A2 · · · Ap J
- and P = P0 ∪ ˆ
0 ∪ ˆ 1, where ˆ 0 = (∅), and ˆ 1 = ({j′′
1}, {j′′ 1, j′′ 2}, . . . , J′′, {j′ r′, . . . , j′′ r′′}, . . . , {j′ 2, . . . , j′′ r′′}, J).
The weight α(π) of a path π = (A1, . . . , Ap) ∈ P is the product of edge weights of the augmented path (∅, π, J):
αA1
∅
· αA2
A1 · · · αAp Ap−1 · αJ Ap.
- Definition. For K ⊆ J, define mM(K) :=
min(K ∩ J′)
if K ∩ J′ = ∅
max(K ∩ J′′)
- therwise.
For any path π = (A1, . . . , Ap), put A0 = ∅ and Ap+1 = J.
35
V. PO-set paths
- Definition. Call ˆ
1 regular and ˆ 0 irregular. Call a path (A1, . . . , Ap) ∈ P0 regular (or regular
at position i0), if (∃i0) (1 ≤ i0 ≤ p) satisfying: (a) |Ai| = i (∀ 1 ≤ i ≤ i0); (b) Ai0 \ Ai0−1 = mM(Ai0+1 \ Ai0−1). A path in P0 is irregular if it is nowhere regular.
- Proposition. The regular and irregular subsets of P are equinumerous.
A bijection ℘. Given an irregular path π = (A1, . . . , Ap) ∈ P0, we insert a new set B so that ℘(π) is regular at B:
- 1. Find the unique i0 satisfying: (|Ai| = i
∀i ≤ i0) ∧ (|Ai0+1| > i0 + 1).
- 2. Compute b = mM(Ai0+1 \ Ai0)
- 3. Put B = Ai0 ∪ {b}.
- 4. Define ℘(π) := (A1, . . . , Ai0, B, Ai0+1, . . . , Ap).
Finally, put ℘(ˆ
0) = ({j1}).
- Proposition. The bijection ℘ is path-weight preserving and α(℘−1(ˆ
1)) = (−q)θq|J′′|−|J′| .
36
56 156 6 16 5 15 ∅ 1
56 156 6 16 5 15 ∅ 1