Orthogonality of Kerr quasinormal modes
Stephen R. Green (AEI Potsdam) with Stefan Hollands and Peter Zimmerman August 2, 2019 “Timelike Boundaries in General Relativistic Evolution Problems” Casa Matemática Oaxaca Mexico
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Orthogonality of Kerr quasinormal modes Stephen R. Green (AEI - - PowerPoint PPT Presentation
Orthogonality of Kerr quasinormal modes Stephen R. Green (AEI Potsdam) with Stefan Hollands and Peter Zimmerman August 2, 2019 Timelike Boundaries in General Relativistic Evolution Problems Casa Matemtica Oaxaca Mexico 1
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Credit: Nollert (1999)
Initial pulse Quasinormal modes Late time power law tail
3
4
5
6
2 repeated principle null directions. Defines Newman-Penrose null tetrad aligned with PNDs.
covariantly with respect to remaining tetrad freedom.
= GHP prime
7
2
2
In terms of (Bini et al, 2002)
8
2
WΣ[g; (Υ1, ˜ Υ1), (Υ2, ˜ Υ2)] = Z
Σ
✏dabc h ˜ Υ2(Θd − 4Bd)Υ1 − Υ1(Θd + 4Bd)˜ Υ2 −˜ Υ1(Θd − 4Bd)Υ2 + Υ2(Θd + 4Bd)˜ Υ1 i ≡ ΠΣ[˜ Υ2, Υ1] − ΠΣ[˜ Υ1, Υ2]
<latexit sha1_base64="jEGqtLWeQuxLdgXOnfGboC7UBik=">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</latexit>9
H = sM 1/3(Ψ2/3
2
− 2ξaBa) + N a(Θa + 2sBa)
N √−h
− √ −h ⇥ hab(Θa + 2sBa)N(Θb + 2sBb) − 4s2NΨ2 ⇤ sM 1/3(Ψ2/3
2
− 2ξaBa) + (Θa + 2sBa)N a !
<latexit sha1_base64="7NxpZzBuMn8oMvU0m7wC1dCL8aM=">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</latexit>10
Σ
Σ
(3)e
2
2
11
2
2
2
2
a)(Θb + 4B0 b) − 16Ψ2
2
2
2
12
2
2
Σ
2
Σ
2
13
Must keep track of boundary terms.
. Integrate over partial Cauchy surface
2 𝒦Υ1, Υ2) = ∫∂S
2 𝒦Υ1, Υ2)
S
2
∂S (2)✏N 4/3 2
S
2
∂S (2)✏N 4/3 2
14
S→Σ
2
∂S
2
Λ−1/4ra(Θa − 4Ba)(Λ1/4Υ) → 1 √ −h$
15
2
2
S→Σ
2
∂S
2
16
Y = ✓ Υ $ ◆
<latexit sha1_base64="L3BITIlLTITi1DqESuYsdZL/1cM=">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</latexit>17
sΥ`m! = e−i!t+im sR`m!(r)sS`m!(θ)
<latexit sha1_base64="YIDHebnCUpFIp7du4/Kpameqb9A=">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</latexit>sS`m!(θ) = 0
<latexit sha1_base64="mQVloVPJoOyDURNbV4V34Iskmw=">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</latexit> ∆−s d dr ✓ ∆s+1 d dr ◆ + ✓H2 − 2is(r − M)H ∆ + 4isωr + 2amω − K + s(s + 1) ◆
sR`m!(r) = 0
<latexit sha1_base64="wH8KFhiZNlYHep+T9Ce5qb9b6Y0=">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</latexit>with H ≡ (r2 + a2)ω − am
<latexit sha1_base64="r49NjUCurmrCZdANE8l2Bb3aws=">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</latexit>18
sS`m!(θ) = 0
<latexit sha1_base64="mQVloVPJoOyDURNbV4V34Iskmw=">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</latexit>19
∆−s d dr ✓ ∆s+1 d dr ◆ + ✓H2 − 2is(r − M)H ∆ + 4isωr + 2amω − K + s(s + 1) ◆
sR`m!(r) = 0
<latexit sha1_base64="wH8KFhiZNlYHep+T9Ce5qb9b6Y0=">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</latexit>20
r2→∞ r1→r+
r1
r=r1
r=r2
21
22
ω , Rup ω
S2(t,r)
2
ω , Rup ω ]
ωn, Υup ωnii
<latexit sha1_base64="CPGjt14XDdTKMfXBOFiWX/er+Y=">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</latexit>23
d ⇣ t · π ⇣ Ψ4/3
2
J Υin
ωn, Υup ω
⌘⌘ = £tπ ⇣ Ψ4/3
2
J Υin
ωn, Υup ω
⌘ = −i(ω − ωn)π ⇣ Ψ4/3
2
J Υin
ωn, Υup ω
⌘
<latexit sha1_base64="bfc/Vb1xEn5GuMf5z6/oXvDOkxM=">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</latexit>Z
∂S
t · π(Ψ4/3
2
J Υin
ωn, Υup ω ) = −i(ω − ωn)
Z
S
π(Ψ4/3
2
J Υin
ωn, Υup ω )
<latexit sha1_base64="KSXusjhqwMTP4BvOZEkUcLntg3k=">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</latexit>d dω
right side = −i Z
S
π(Ψ4/3
2
J Υin
ωn, Υup ωn)
<latexit sha1_base64="z2AtEt0tYiK2+bh1c1lVwOvDU=">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</latexit>24
ω , Rup ω ⟹
d dω
left side = Z
∂S+
t · π Ψ4/3
2
J Υin
ωn, d
dω
Υup
ω
! − d dω
Z
∂S−
t · π ⇣ Ψ4/3
2
J Υin
ω , Υup ω
⌘ + Z
∂S−
t · π d dω
Ψ4/3
2
J Υin
ω , Υup ωn
!
<latexit sha1_base64="t+f93bWB9FiVTN+rkvtq5YECtZg=">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</latexit>8πM 4/3 d dω W[Rin
ω , Rup ω ]
= − i Z
S
π(Ψ4/3
2
J Υin
ωn, Υup ωn)
− Z
∂S−
t · π d dω
Ψ4/3
2
J Υin
ω , Υup ωn
! − Z
∂S+
t · π Ψ4/3
2
J Υin
ωn, d
dω
Υup
ω
!
<latexit sha1_base64="dfyCjWqfzcB7/4EgrxnkbTvKAQU=">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</latexit>25
ΥQNM = X
`mn
c`mnΥ`mn
<latexit sha1_base64="fEqviF/viL7O9qp6DM8K9l5fojE=">ACXHicfZFNSwMxEIbTtX61flQFL16CRfBUdlXQiyB68aJYsFVwa8msxqaZJdkVizL/iV/jRcP+k8E01qhVnAg8M4zMzDzJkqlsOj7byVvpjw7N7+wWKkuLa+s1tbW2zbJDIcWT2RibiNmQoNLRQo4TY1wFQk4Sbqnw3rN09grEj0NQ5S6Cj2oEUsOEOHurXzsJVaIRN9n4cIz5g3Ly+Kgh7T0Gaqm4cgJVUF5RPJj9DE6xbq/sNfxT0rwjGok7GcdWtfYa9hGcKNHLJrL0L/BQ7OTMouISiEmYWUsb7AHunNRMge3ko4sLuNIj8aJcU8jHdHJiZwpawcqcp2K4aOdrg3hv7VfcEiMje3UhgfdXKh0wxB8+d4kxSTOjQadoTBjKgROMG+HOovyRGcbR/UfF+RVMu/NXtPcawX5jr3lQPzkdO7dAtsg2SUBOSQn5JxckRbh5IW8knfyUfrwyl7VW/5u9UrjmQ3yK7zNL/ZpuJ8=</latexit>c`mn = hhΥ`mn, (Υ, $)iit=0 hhΥ`mn, Υ`mniit=0 = 1 hhΥ`mn, Υ`mniit=0 Z
Σ (3)eΨ4/3 2
[(J Υ`mn)$ + ΥJ $`mn]t=0 = 1 dW/d!|!`mn 1 2⇡i Z 2⇡ Z ⇡ Z ∞
r+
sin ✓ ∆2 e−imS`mn(✓)R`mn(r) ⇢ Λ ∆(@tΥ i!`mnΥ) +4 M ∆ (r2 a2) r ia cos ✓
∆ (@Υ + imΥ)
drd✓d
<latexit sha1_base64="VLRheHB1oRzbQakLKsIGjhbK8r4=">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</latexit>26
On modes, volume integrand and boundary terms as
(Cancellations still give finite result)
plane such that integrals converge:
2
hhΥ1, Υ2ii ⌘ lim
S→Σ
⇢ ΠS[Ψ4/3
2
J Υ1, Υ2] + Z
∂S
Ψ4/3
2
(J Υ1)Υ2
27
2
28
29
2
2
S [γ, S†Υ] = −ΠS[T γ, Υ]
<latexit sha1_base64="3ARlSMgz+tJAn6LUzcWVPYatxQA=">ACbnicfVFdaxNBFJ2sVWv8ihZ8KcXBIPRBw24V7Euh6IN9TGnTFLPbcHdydzt0ZnaZuVsalvy3/g3/gK/2DwjOpmxKXhg4HDuOXDvmbRU0lEY/mwFD1YePnq8+qT9NnzFy87r14fuaKyAgeiUIU9TsGhkgYHJEnhcWkRdKpwmJ59a+bDc7ROFuaQpiUmGnIjMymAvDTu/Bie1DHhBdXfZ7PxwSjOQWv4wGMNdCpA8YOTeAJ5jpbHg9JVZiE7/CPO7Lxn5jO+S3yRvbuNMNe+Ec/D6JFqTLFuiPO3/iSEqjYaEAudGUVhSUoMlKRTO2nHlsARxBjmOPDWg0SX1vIMZf+VCc8K658hPlf/TdSgnZvq1Dubnd3yrBH/O7sjNop1mVtairLtpJamrAiNuN4pqxSngjfd84m0KEhNPQFhpT+Li1OwIMj/UNv3FS23c58cbfWiT72t/c/d3a+L5lbZOnvHNlnEvrBdtsf6bMAEu2S/2G921boK3gQbwdtra9BaZNbYHQSbfwHY8r7T</latexit>hhΥ1, Υ2ii = 1 4Π ˜ ψ2, Ψ4/3
2
T 0S0†Ψ4/3
2
J T 0S0†Ψ4/3
2
˜ ψ1 ⇤ = 1 4Π h ˜ ψ2, Ψ4/3
2
J þ4 ⇣ ¯ Ψ4/3
2
þ04 ⇣ Ψ4/3
2
˜ ψ1 ⌘⌘i⇤ = 1 4 DD ˜ ψ2, þ4 ⇣ ¯ Ψ4/3
2
þ04 ⇣ Ψ4/3
2
˜ ψ1 ⌘⌘EE⇤
s=+2
<latexit sha1_base64="yRnMs/r2tZetPu4G3Gv8gspZSco=">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</latexit>bilinear form on Hertz potentials
30
þ4 ⇣ ¯ Ψ4/3
2
þ04 ⇣ Ψ4/3
2
˜ ψ1 ⌘⌘ = ð4 ⇣ ¯ Ψ4/3
2
ð04 ⇣ Ψ4/3
2
˜ ψ1 ⌘⌘ − 9¯ ŁξŁξ ˜ ψ1
<latexit sha1_base64="8wbQgdbOp68FSt+4fm0O4z3JBCE=">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</latexit>algebraic on modes
n = 0 n = 1
accumulation point at horizon frequency
<(ω) =(ω)
surface gravity
κ = p 1 − a2/M 2
<latexit sha1_base64="/37GCVStuCEL0a8q4VOKyrZx2A8=">ACAHicbVBNS8NAEN3Ur1q/oh48eAkWwYs1qYJehKIXL0IF+wFNWibt0k6y7G6GEXPwrXjwo4tWf4c1/47bNQVsfDzem2Fmns8Zlcq2v43cwuLS8kp+tbC2vrG5ZW7v1GUC0xqOGKRaPogCaMhqSmqGlyQSDwGWn4w+ux3gkQtIovFcjTrwA+iHtUQxKSx1zx0C53DpygehEucY2uWT23Y57ZhFu2RPYM0TJyNFlKHaMb/cboTjgIQKM5Cy5dhceQkIRTEjacGNJeGAh9AnLU1DCIj0kskDqXWola7Vi4SuUFkT9fdEAoGUo8DXnQGogZz1xuJ/XitWvQsvoSGPFQnxdFEvZpaKrHEaVpcKghUbaQJYUH2rhQcgACudWUGH4My+PE/q5ZJzWrLvzoqVqyOPNpHB+gIOegcVdANqIawihFz+gVvRlPxovxbnxMW3NGNrOL/sD4/AGFypWy</latexit>31
.
radial solution to extreme Kerr
matching
¯ ωn = − i 2(h+ + n + im), h+ ∈ R+ ¯ ωn = − i 2(h− + n + im), h− = 1/2 + ir ∈ C
<latexit sha1_base64="q2pWNE3D/KYTdQsdbxnzmhxSJnA=">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</latexit>h± = 1 2 ± r 1 4 + K − 2m2
<latexit sha1_base64="h/zS4W+LyaSA9PFU4hiG1t9Z5jU=">ACQXicfZDLSsNAFIYn9VbrLerSzWARBGlJYkE3QtGN4KaCvUBTy2Q6aYfOJHFmIpSQp/Bp3Nqn8BHciVsRnLRd2Bb84cDPd86Bc34vYlQqy3o3ciura+sb+c3C1vbO7p65f9CQYSwqeOQhaLlIUkYDUhdUcVIKxIEcY+Rpje8yfrNZyIkDYMHNYpIh6N+QH2KkdKoa5YGXTfi8Aq6vkA4sdPESWFGXPkVDKhduXsruTwRyftmkWrbE0El409M0UwU61r/ri9EMecBAozJGXbtiLVSZBQFDOSFtxYkgjhIeqTtrYB4kR2kslbKTzRpAf9UOgKFJzQvxsJ4lKOuKcnOVIDudjL4L+9OZgRIX25cJTyLzsJDaJYkQBPb/JjBlUIszhjwqCFRtpg7Cg+i2IB0iHpnToBZ2XvZjOsmk4Zfu87NxXitXrWXJ5cASOwSmwQWogltQA3WAwQt4BW9gbIyND+PT+JqO5ozZziGYk/H9C/efsEI=</latexit>32
hhΥ1, Υ2iinear = 2M −2/3 " 2i lim
✏→0
Z c/√
✏
d¯ x ⇣ ¯ !1 + ¯ !2 + 2ˆ e ˆ A¯
t
⌘ (x(1 + x))−3 Rnear
1
Rnear
2
+Rnear
1
(✏)Rnear
2
(✏) ✏2(1 + ✏)2
33
34