Koushik Balasubramanian
YITP, Stony Brook University
New Frontiers in Dynamical Gravity, 2014
Numerical Techniques for Holography
based on KB, Christopher P. Herzog arXiv:1312.4953
Saturday, March 29, 14
Numerical Techniques for Holography based on KB, Christopher P. - - PowerPoint PPT Presentation
Numerical Techniques for Holography based on KB, Christopher P. Herzog arXiv:1312.4953 Koushik Balasubramanian YITP, Stony Brook University New Frontiers in Dynamical Gravity, 2014 Saturday, March 29, 14 Numerical Techniques for Holography
YITP, Stony Brook University
New Frontiers in Dynamical Gravity, 2014
based on KB, Christopher P. Herzog arXiv:1312.4953
Saturday, March 29, 14
YITP, Stony Brook University
New Frontiers in Dynamical Gravity, 2014
based on KB, Christopher P. Herzog arXiv:1312.4953
Saturday, March 29, 14
Saturday, March 29, 14
using gauge/gravity duality?
Saturday, March 29, 14
using gauge/gravity duality?
Saturday, March 29, 14
using gauge/gravity duality?
Saturday, March 29, 14
using gauge/gravity duality?
(Breakdown of gradient expansion)
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Saturday, March 29, 14
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humans.
Saturday, March 29, 14
humans.
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Vorticity Profile as a function of time
Saturday, March 29, 14
Vorticity Profile as a function of time
hydrodynamics (Israel-Stewart type equations)
Saturday, March 29, 14
Vorticity Profile as a function of time
hydrodynamics (Israel-Stewart type equations)
Saturday, March 29, 14
Vorticity Profile as a function of time
hydrodynamics (Israel-Stewart type equations)
Plasma
Saturday, March 29, 14
Vorticity Profile as a function of time
hydrodynamics (Israel-Stewart type equations)
Plasma
Saturday, March 29, 14
Vorticity Profile as a function of time
hydrodynamics (Israel-Stewart type equations)
Plasma
Saturday, March 29, 14
Vorticity Profile as a function of time
hydrodynamics (Israel-Stewart type equations)
Plasma
Carrasco, Lehner, Myers (2012); Adams, Chesler, Liu (2013)
Saturday, March 29, 14
Vorticity Profile as a function of time
hydrodynamics (Israel-Stewart type equations)
Plasma
Carrasco, Lehner, Myers (2012); Adams, Chesler, Liu (2013)
structure of horizon
Saturday, March 29, 14
Vorticity Profile as a function of time
hydrodynamics (Israel-Stewart type equations)
Plasma
Carrasco, Lehner, Myers (2012); Adams, Chesler, Liu (2013)
structure of horizon
Saturday, March 29, 14
Vorticity Profile as a function of time
hydrodynamics (Israel-Stewart type equations)
Plasma
Carrasco, Lehner, Myers (2012); Adams, Chesler, Liu (2013)
structure of horizon
driving happens on short length scales?
Saturday, March 29, 14
Temperature profile as a function of time
Saturday, March 29, 14
Temperature profile as a function of time
gtt
Saturday, March 29, 14
Temperature profile as a function of time
good (steepening of waves)
gtt
Saturday, March 29, 14
Temperature profile as a function of time
good (steepening of waves)
width and shock standoff distance?
gtt
Saturday, March 29, 14
Temperature profile as a function of time
good (steepening of waves)
width and shock standoff distance?
expansion?
gtt
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\nonumber
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Saturday, March 29, 14
based on KB, Christopher P. Herzog arXiv:1312.4953
Saturday, March 29, 14
is broken by the presence of impurities.
conductivity is infinite
conductivity.
σ(ω) ∼ C0δ(ω)
Saturday, March 29, 14
∆S = δL R dxO(x)eikx 1 ⌧ = 2
Lk2
✏ + p. lim
ω→0
=[GR(!, k)]
!
theory.
Saturday, March 29, 14
introducing scalar perturbations, spatially dependent chemical potential (ionic lattice) or metric perturbations
introducing metric perturbations.
following definition:
gtt = (1 + δe−m/t cos(kx)), O(x) ≡ T t
t
∂t ¯ Ttx + 1 τ ¯ Ttx = 0
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δ
theory : (Kovtun, 2012)
number)
GR
OO =
k2(✏ + p)2 k2(c2
s(✏ + p) + 4i⌘! − !2(✏ + p) + ✏
(m = 0) 1 ⌧ = 22⌘k2 3✏0T0
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steady state solution:
rate at late times using linear perturbation theory around this steady state solution
T = T0 √gtt , u = 0 1 ⌧ = 2(1 − √ 1 − 2)⌘k2 3✏0T0
Saturday, March 29, 14
to obtain relaxation time scale.
2 4 6 8 10
2.3k
− 8 − 7 − 6 − 5 − 4 − 3 − 2 − 1
log D
Im(G(ω)) 2ω
E
Text
equations for small .
wavenumber behavior (simple WKB approximation is not good enough).
are measured in units where δ
T =
3 4π
The markers show values obtained by solving the full nonlinear equations.
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derivatives.
solving Einstein’s equations.
equations, 2 bulk graviton evolution equations and one evolution equation at the apparent horizon.
same as hydro.
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horizon is fixed.
ds2 = − ✓ e2βV z − hABU AU B z2 ◆ dt2−2e2β z2 dt dz−2hABU B z2 dt dxA+hAB z2 dxA dxB .
Saturday, March 29, 14
✓ Dz + 4 z I ◆ βs = Sβ (z, αs, θs, χs) (1) (Dz) πA
s
= SπA (z, αs, θs, χs, βs) (2) ✓ Dz + 2 z I ◆ U A
s
= SU A
s
(Dz) dtχs = Sdtχ
s
β = β0 − z3 2 χ3 + z4βs, α = z2αs, θ = z2θs. U A = −z∂A(e2β0) + z2U A
s ,
πA = − 2 z2 ∂Aβ0 + πA
s ,
V = 1 z3 (V0e2β0 + z2Vs), dtα = ˙ α − z3 2 V α0, dtθ = ˙ θ − z3 2 V θ0
Saturday, March 29, 14
✓ Dz + 1 z I ◆ dtαs + Cααdtαs + Cαθdtθs = Sdtα (. . . , dtχs) ✓ Dz + 1 z I ◆ dtθs + Cθαdtαs + Cθθdtθs = Sdtθ (. . . , dtχs)
CH
xxD(2) x VH + CH x D(1) x VH + CH 0 VH = SVH
H, χH, dtχH, dtαH, dtθH
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∂tαs = 1 z (dtα)s + 1 2(zα0
s + 2αs)z3V
(1) ∂tθs = 1 z (dtθ)s + 1 2(zθ0
s + 2θs)z3V
(2) ∂tχ = Sχ
H, χH
∂tU A
3
= SU A
3
3 , β0
∂tV3 = SV3
3 , β0
∂zβs = 0 , πA
s
= 3e−2β0U A
3 ,
∂zU A
s
= U A
3 ,
dtαs = 0 , dtθs = 0 .
Saturday, March 29, 14
1 2 3 4 5 6 7 8
k2δ2t 8πTi
−8 −7 −6 −5 −4 −3 −2 −1
log D
Ttx(t) Ttx(0)
E
k = π
50k = 4π
50k = 5π
50k = 6π
50Ref.
1 2 3 4 5 6
k2δ2t 8πTi
−6 −5 −4 −3 −2 −1
log D
Ttx(t) Ttx(0)
E
k = π
50k = 4π
50k = 5π
50k = 6π
50Ref.
δ = 0.2, v = 0.2
become important at late times.
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−0.006 −0.004 −0.002 0.000 0.002
∆Ttx
−0.003 −0.002 −0.001 0.000 0.001
∆Ttt
0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0
k2δ2t 8πTi
−0.003 −0.002 −0.001 0.000
∆Txx
k = 4π/50 δ = 0.2, v = 0.2
Saturday, March 29, 14
1 2 3 4 5
k2δ2t 8πTi
−5 −4 −3 −2 −1
log D
Ttx(t) Ttx(0)
E
Gravity Hydro Ref GR Ref Hydro
k = 20π 50 , δ = 0.2, v = 0.2
Saturday, March 29, 14
0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4
k2f(δ)t 8πT0
−1.5 −1.0 −0.5 0.0
log D
Ttx(t) Ttx(t∗)
E
δ = 0.2 δ = 0.3 δ = 0.4 δ = 0.5 Ref.
k = π/50 1 ⌧ = 2(1 − √ 1 − 2)⌘k2 3✏0T0
f(δ) = 2(1 − √ 1 − δ2)
Saturday, March 29, 14
0.0 0.2 0.4 0.6 0.8 1.0
k2f(δ)t 8πT0
−1.0 −0.8 −0.6 −0.4 −0.2 0.0 0.2
log D
Ttx(t) Ttx(t∗)
E
δ = 0.2 δ = 0.3 δ = 0.4 Ref.
k = π/50
1 ⌧ = 2(1 − √ 1 − 2)⌘k2 3✏0T0
f(δ) = 2(1 − √ 1 − δ2)
Saturday, March 29, 14
−40 −20 20 40 −0.6 −0.4 −0.2 0.0 0.2 0.4 0.6 0.8
∆T
×10−3 t = 2000 −40 −20 20 40 −0.6 −0.4 −0.2 0.0 0.2 0.4 0.6 0.8
∆T
×10−3 t = 4000 −40 −20 20 40
x
−0.6 −0.4 −0.2 0.0 0.2 0.4 0.6 0.8
∆T
×10−3 t = 10000
T = T0 √gtt , u = 0
Late time solution agrees with the exact analytical solution.
k = 4π/50
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20 40 60 80 100
k2f(δ)t 8πT0
−10 −8 −6 −4 −2
log D
Ttx(t) Ttx(0)
E
δ = 0.2 δ = 0.3 δ = 0.4 Ref.
result!!!
for large lattice strength at large δ, k
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small values of lattice strength.
analytical results for small lattice wave numbers.
cases.
Saturday, March 29, 14
Saturday, March 29, 14