SLIDE 17
- defined. To do so, we first define the compactification of moduli space for more
general cases: M
x,y :=
Mx,z1 × Mz1,z2 × ... × Mzi,y (49) where i ≥ 0 is arbitrary, and ind(x) > ind(z1) > ... > ind(zi) > ind(y). The elements of M
x,y are called ‘broken trajectories’ connecting x and y, for we
can view it as flows consecutively visting x, z1, z2, ..., zi, y. We equip it with the following topology. To clarify the notions, we have the following definition: Definition 3.5. For a Morse function f on M, we fix Morse charts U(x) for each critical point x and choose ǫ(x) > 0 sufficiently small. Then we have Ω±(x) := U(x) ∩ f −1(f(x) ± ǫ(x)). When a trajectory (or a broken trajectory) meets Ω(x)±, we say that it enters (leaves) the corresponding Morse chart. Let γ = (γ1, γ2, ..., γi) ∈ Mx,z1 × Mz1,z2 × ... × Mzi−1,y, a neighbourhood U ǫ of γ in M
x,y contains τ such that:
- There exist 1 ≤ i1 < ... < ij−1 ≤ i − 1 such that τ = (τ1, ..., τj) ∈
Mx,zi1 × ...Mzij−1,y.
- For each x, z1, z2, ..., y, and its corresponding Morse chart, we require that
τ enters (exits) the chart ǫ-close to γ. Remark 3.4. The topology defined above is obviously Hausdorff and second
- countable. The inclusion i : Mx,y → M
x,y is an embedding.
Theorem 3.2. The space M
x,y is compact.
- Proof. It suffices to show sequential compactness since the space is second count-
- able. As the definition above, we fix Morse charts U(x) for each critical point
x, and fix Ω±(x) to determine when a trajectory leaves or enter a Morse chart. Let ln be a sequence of trajectories in M
x,y. First assume that all ln lies in
Mx,y, let l∓
n be the points where ln leaves U(x) and enters U(y). Note that
Ω−(x) ∩ M u
X(x) is diffeomorphic to Sind(x)−1 which is compact. So we may
assume l−
n converges to x− and likewise, l+ n converges to y+. Let τ1 ∈ Mx,z be
the trajectory through x− and τ +
1 be the point where τ1 enters U(z). By the
dependence of solution on initial data, ln will enter U(z) for n >> 0. Let mn be the points where ln enters U(z), we claim that m+
n would converge to τ + 1 .
This will follow from the lemma 3.1 below. If z = y, then by above claim, we have ln → τ1. If this were not the case, then m+
n is not contained in M s X(z) for n large. So ln will leave U(z) through
m−
n . Again, we assume m− n converges to z− and claim that z− lies on M u X(z).
If this were not the case, then z− would be on the flow line of some point z+ with f(z+) = f(m+
n ) such that z+ is not in M s X(z). But by lemma 3.1 again,
m+
n converges to z+ and τ + 1 at the same time. So z+ = τ + 1 ∈ M s X(z) which is
absurd. 17