Measuring Angles and Angular Resolution 1 Angles Angle is the - - PDF document

measuring angles and angular resolution
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Measuring Angles and Angular Resolution 1 Angles Angle is the - - PDF document

Measuring Angles and Angular Resolution 1 Angles Angle is the ratio of two lengths: R: physical distance between observer and objects [km] S: physical distance along the arc between 2 objects Lengths are measured in same


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Measuring Angles and Angular Resolution

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2

Angles

Angle θ is the ratio of two lengths:

R: physical distance between observer and objects [km] S: physical distance along the arc between 2 objects Lengths are measured in same “units” (e.g., kilometers) θ is “dimensionless” (no units), and measured in

“radians” or “degrees” R S R

θ

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“Angular Size” and “Resolution”

Astronomers usually measure sizes in terms

  • f angles instead of lengths

because the distances are seldom well known

S R θ

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Trigonometry

R S R

θ

Y

2 2

R Y +

S = physical length of the arc, measured in m Y = physical length of the vertical side [m]

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Trigonometric Definitions

[ ] [ ]

2 2 2 2

  • pposite side

tan adjacent side

  • pposite side

1 sin hypotenuse 1 S R Y R Y R Y R Y θ θ θ ≡ ≡ = ≡ = = + +

R S R θ Y

2 2

R Y +

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Angles: units of measure

2π (≈ 6.28) radians in a circle

1 radian = 360˚ ÷ 2π ≈ 57 ˚ ⇒ ≈ 206,265 seconds of arc per radian

Angular degree (˚) is too large to be a useful

angular measure of astronomical objects

1º = 60 arc minutes 1 arc minute = 60 arc seconds [arcsec] 1º = 3600 arcsec 1 arcsec ≈ (206,265)-1 ≈ 5 × 10-6 radians = 5 µradians

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Number of Degrees per Radian

2 radians per circle 360 1 radian = 57.296 2 57 17'45" π π

° ° °

≈ ≈

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Trigonometry in Astronomy

S

θ

R Usually R >> S (particularly in astronomy), so Y ≈ S Y

2 2 2 2

1 1 S Y Y R R R Y R Y θ ≡ ≈ ≈ ≈ + +

[ ] [ ]

tan sin θ θ θ ≈ ≈

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Relationship of Trigonometric Functions for Small Angles

Check it! 18˚ = 18˚ × (2π radians per circle) ÷ (360˚ per circle) = 0.1π radians ≈ 0.314 radians Calculated Results tan(18˚) ≈ 0.32 sin (18˚) ≈ 0.31 0.314 ≈ 0.32 ≈ 0.31

θ ≈ tan[θ ] ≈ sin[θ ] for |θ |<0.1π

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  • 1
  • 0.5

0.5 1

  • 0.5
  • 0.25

0.25 0.5

sin(πx) tan(πx) πx x

Three curves nearly match for x ≤ 0.1⇒ π|x| < 0.1π ≈ 0.314 radians

sin[θ ] ≈ tan[θ ] ≈ θ

for θ ≈ 0

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Astronomical Angular “Yardsticks”

Easy yardstick: your hand held at arms’ length

fist subtends angle of ≈ 5˚ spread between extended index finger and thumb ≈ 15˚

Easy yardstick: the Moon

diameter of disk of Moon AND of Sun ≈ 0.5˚ = ½˚

½˚ ≈ ½ · 1/60 radian ≈ 1/100 radian ≈ 30 arcmin = 1800 arcsec In the DRAWING: Point A: The sky appears blue due to scattering. The scattered light from the

  • ther ray is linearly polarized.

Point B: When this person looks toward the sun the sky appears reddish because the most of the shorter wavelength light has already been scattered away.

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“Resolution” of Imaging System

Real systems cannot “resolve” objects that

are closer together than some limiting angle

“Resolution” = “Ability to Resolve”

Reason: “Heisenberg Uncertainty Relation”

Fundamental limitation due to physics

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Image of Point Source

  • 1. Source emits “spherical waves”
  • 2. Lens “collects” only part of the sphere

and “flips” its curvature

  • 3. “piece” of sphere converges to

form image

D λ

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With Smaller Lens

Lens “collects” a smaller part of sphere. Can’t locate the equivalent position (the “image”) as well Creates a “fuzzier” image

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Image of Two Point Sources

Fuzzy Images “Overlap” and are difficult to distinguish (this is called “DIFFRACTION”)

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Image of Two Point Sources

Apparent angular separation of the stars is ∆θ

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Resolution and Lens Diameter

Larger lens:

collects more of the spherical wave better able to “localize” the point source makes “smaller” images smaller ∆θ between distinguished sources means

BETTER resolution

D λ θ ∆ ≈

λ = wavelength of light D = diameter of lens

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Equation for Angular Resolution

Better resolution with:

larger lenses shorter wavelengths

Need HUGE “lenses” at radio wavelengths

to get same angular resolution

D λ θ ∆ ≈

λ = wavelength of light D = diameter of lens

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Resolution of Unaided Eye

Can distinguish shapes and shading of light

  • f objects with angular sizes of a few

arcminutes

Rule of Thumb: angular resolution of unaided

eye is 1 arcminute

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Telescopes and magnification

Telescopes magnify distant scenes Magnification = increase in angular size

(makes ∆θ appear larger)

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Simple Telescopes

Simple refractor telescope (as used by Galileo,

Kepler, and their contemporaries) has two lenses

  • bjective lens

collects light and forms intermediate image “positive power” Diameter D determines the resolution

eyepiece

acts as “magnifying glass” applied to image from

  • bjective lens

forms magnified image that appears to be infinitely far

away

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Galilean Telescope

Ray incident “above” the optical axis emerges “above” the axis image is “upright” fobjective

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Galilean Telescope

Ray entering at angle θ emerges at angle θ′ > θ Larger ray angle ⇒ angular magnification θ′ θ

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Keplerian Telescope

Ray incident “above” the optical axis emerges “below” the axis image is “inverted” fobjective feyelens

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Keplerian Telescope

Ray entering at angle θ emerges at angle θ′ where |θ′ | > θ Larger ray angle ⇒ angular magnification θ′ θ

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Telescopes and magnification

Ray trace for refractor telescope demonstrates

how the increase in magnification is achieved

Seeing the Light, pp. 169-170, p. 422

From similar triangles in ray trace, can show

that

fobjective = focal length of objective lens feyelens = focal length of eyelens

magnification is negative ⇒ image is inverted

  • bjective

eyelens

f magnification f = −

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Magnification: Requirements

To increase apparent angular size of Moon from

“actual” to angular size of “fist” requires magnification

  • f:

Typical Binocular Magnification with binoculars, can easily see shapes/shading on

Moon’s surface (angular sizes of 10's of arcseconds)

To see further detail you can use small telescope w/

magnification of 100-300

can distinguish large craters w/ small telescope angular sizes of a few arcseconds

5 10 0.5

° ° =

×

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Ways to Specify Astronomical Distances

light year = distance light travels in 1 year

1 light year = 60 sec/min × 60 min/hr × 24 hrs/day × 365.25 days/year × (3 × 105) km/sec ≈ 9.5 × 1012 km ≈ 5.9 × 1012 miles ≈ 6 trillion miles

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Aside: parallax and distance

The only direct measure of distance astronomers

have for objects beyond the solar system is parallax

Triangulation Parallax: apparent motion of nearby stars (against a

background of very distant stars) as Earth orbits the Sun

Requires taking images of the same star at two different

times of the year

Foreground star “Background” star

Caution: NOT to scale A B (6 months later)

Apparent Position of Foreground Star as seen from Location “B” Apparent Position of Foreground Star as seen from Location “A”

Earth’s Orbit

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Parallax as Measure of Distance

P is the “parallax” typically measured in arcseconds

Image from “A” Image from “B” 6 months later

Background star

P

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Parallax as Measure of Distance

Apparent motion of 1 arcsec in 6 months defines the

distance of 1 parsec (parallax of 1 second)

1 parsec = 3.26 light years ≈ 3 × 1013 km ≈ 20 × 1012 miles = 20 trillion

miles

D = P-1

D is the distance (measured in pc) and P is parallax (in arcsec)

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Limitations to Magnification

Can you use a telescope (even a large one) to

increase angular size of nearest star to match that of the Sun?

nearest star is α Cen (alpha Centauri)

Brightest star in constellation Centaurus

Diameter is similar to Sun’s

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α Centaurus

Near South Celestial

Pole

Not visible from

Rochester!

Southern Cross α Centaurus

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Limitations to Magnification

Distance to α Cen is 1.3 pc

1.3 pc ≈ 4.3 light years ≈ 1.5×1013 km from Earth

Sun is 1.5 × 108 km from Earth ⇒ would require angular magnification of

100,000 = 105

⇒ To obtain that magnification using telescope:

fobjective=105 × feyelens

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Can one magnify images by arbitrarily large factors? Increasing magnification involves “spreading light

  • ut” over a larger imaging (detector) surface

necessitates ever-larger light-gathering power, larger

telescopes

BUT: Remember diffraction

Wave nature of light, Heisenberg “uncertainty principle” Diffraction is the unavoidable propensity of light to change

direction of propagation, i.e., to “bend”

Cannot focus light from a point source to an arbitrarily small

“spot”

Diffraction Limit of telescope

Limitations to Magnification

D λ θ ∆ ≈

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Magnification: Limitations

However, atmospheric effects typically

dominate effects from diffraction

most telescopes are limited by “seeing”: image

“smearing” due to atmospheric turbulence

Rule of Thumb:

limiting resolution for visible light through the

atmosphere is equivalent to that obtained by a telescope with D ≈ 3.5" (≈ 90 mm)

9 6

at 500nm (Green light) 500 10 5.6 10 5.6 rad 0.09 1.2 arcsec 1/50 of eye's limit D m radians m λ θ λ µ

− −

∆ ≈ = × = ≈ × = ≈ ≈