MATH 20: PROBABILITY Fundamental Theorems of Probability Theory Xingru Chen xingru.chen.gr@dartmouth.edu XC 2020
Fundamental Theorems of Probability Theory 4 5 Central Li Ce Limit 8 Th Theo eorem em 3 2 6 7 1 Law of La La Large ge Numbers Nu XC 2020
La Law of La Large ge Number bers frequency as interpretation of probability Β§ convergence of the sa sample m mea ean Β§ XC 2020
LAW W OF OF LARGE GE NU NUMBE MBERS FOR OR DISCRETE RAND NDOM OM VARIABL BLES discrete random variables XC 2020
Let π be a nonnegative discrete random variable with expected value πΉ(π) , and let This is a sample text. π > 0 be any positive number. Then Insert your desired text here. This is a sample text. Insert your desired text here. π : : nonnegative π(π β₯ π) πΉ(π) π Markov Ma πΈ(π β₯ π») β€ π(π) inequ in quality ity π» XC 2020
Proof Let π be a po posi sitive discrete random variable with expected value πΉ(π) , and let π > 0 be any positive number. πΈ(π β₯ π») β€ π(π) π» + π(π) = π π π β₯ π = + π(π¦) π !"# π π = + ππ(π) β₯ + ππ π β₯ π» + π π = π»π π β₯ π & ππ(π) = π(π) π π"π» π"π» π XC 2020
Let π be a discrete random variable with expected π ' = π(π) , value π = πΉ(π) and variance and let π > 0 be any positive number. Then This is a sample text. Insert your desired text here. This is a sample text. Insert your desired text here. π : : not t necessarily πΈ(|π β π| nonne no nnegative ve β₯ π») π π π» π Chebyshev Ch πΈ(|π β π| β₯ π») β€ π π inequalit in ity π» π XC 2020
Proof Let X be a discrete random variable with expected value π = πΉ(π) π ' = π(π) , and variance and let π > 0 be any positive number. πΈ(|π β π| β₯ π») β€ π π π» π + π(π) = π π(|π β π| β₯ π») = + π(π¦) π |π)π|"π» π ' = π π = + (π¦ β π) ' π(π¦) β₯ π¦ β π ' π π¦ + ! !)+ "# (π β π) π π(π) = πΎ(π) & β₯ π ' π π¦ = π ' π(|π β π| β₯ π) + π !)+ "# XC 2020
Ma Markov πΈ(π β₯ π») β€ π(π) in inequ quality ity π» π : : nonnegative π(π) : kn known Chebyshev Ch πΈ(|π β π| β₯ π») β€ π π inequalit in ity π» π π : : not t necessarily π(π) : kn known πΎ(π) : kn known no nonne nnegative ve XC 2020
Example 1 Β§ Let π be any random variable which takes on values 0, 1, 2, β― , π and has πΉ(π) = π (π) = 1 . Show that for any positive integer π , π(π β₯ π + 1) β€ " # # . Ma Markov kov Inequality Ch Chebys byshev Inequality π(|π β π| β₯ π) β€ π $ π(π β₯ π) β€ πΉ(π) π π $ XC 2020
Example 1 Β§ Let π be any random variable which takes on values 0, 1, 2, β― , π and has πΉ(π) = π (π) = 1 . Show that for any positive integer π , π(π β₯ π + 1) β€ " # # . Ch Chebyshev Inequ quality π(|π β π| β₯ π) β€ π ' π ' π = π ' = 1 , π = π π π β 1 β₯ π = π(π β₯ π + 1) β€ 1 π ' XC 2020
Example 2 Β§ Choose π with distribution βπ π . π π¦ = " " $ $ Ch Chebyshev Inequ quality π(|π β π| β₯ π) β€ π ' π π β₯ π = 1 π ' π = 0 , π ' = π ' π π β₯ π β€ π ' π ' = 1 XC 2020
Law of Large Numbers Β§ Let π " , π $ , β― , π % be an independent trials process, with same fi nite expected value π $ = π(π & ) and fi nite variance & ) . π = πΉ(π Β§ Let π % = π " + π $ + β― + π % . Then for any π > 0 , Large π(| ' $ % β π| β₯ π) β 0 , as π β +β . Numbers Β§ Equivalently, %β) π( ' $ % β π < π) = 1 . lim , ! As - is an average of the individual outcomes, the LLN is ! often referred to as the la law of averages . XC 2020
Law of Large Numbers Β§ Let π " , π $ , β― , π % be an independent trials process with πΉ π & = π and π π & = π $ . Β§ Let π % = π " + π $ + β― + π % be the sum, π β +β π΅ % = ' $ and % be the average. Then πΉ π΅ % = π = π π΅ % β 0 πΈ π΅ % β 0 π π΅ % = * # πΈ π΅ % = * % , = % XC 2020
Proof Let π . , π ' , β― , π - be an independent trials process, with same π ' = π(π fi nite expected value π = πΉ(π / ) and fi nite variance / ) . π(| π % π β π| β₯ π) β 0 , as π β +β . π π» π = π β€ π ' π - π π π β π β₯ π ππ ' = π π πΎ π» π π β +β π π π ' πΈ(|π β π| β₯ π») β€ π π ππ ' β 0 π» π XC 2020
Law of Large Numbers con convergence ce of of the the sa sample me mean (Strong) Law of Large π % Numbers π lim π = π = 1 %β) (Weak) %β) π( π % Law of Large lim π β π < π) = 1 Numbers XC 2020
Example 3 Consider the general Bernoulli trial process. Β§ As usual, we let π = 1 if the outcome is a success and 0 if it is a failure. Β§ Expect cted value π(π) I π¦π(π¦) = 1Γπ + 0Γ 1 β π = π Bernoulli Ber tria t ial +β- π, π = 1 π π¦ = L 1 β π, π = 0 Variance ce π π πΉ π $ β π $ = π β π $ = π(1 β π) XC 2020
Example 3 Now consider π Bernoulli trials. Β§ ' $ Then π % = β ./" % π . is the number of successes in π trials and π = πΉ = πΉ π . = π . Β§ % La Law o of La Large N Numbers -β2 π( π - lim π β π < π) = 1 π = π -β2 π( π - lim π β π < π) = 1 XC 2020
Coin Tossing π β +β π = 1 2 π " + π $ + β― + π % π XC 2020
Dice Rolling π β +β π = 7 2 π " + π $ + β― + π % π XC 2020
Bernoulli Trials We can start with a random experiment about which little can be predicted and, by taking averages, obtain an experiment in which the outcome can be predicted with a high degree of certainty. XC 2020
π΅ % = ' $ π % = π " + π $ + β― + π % , % Law of La La Large ge Number bers π π΅ % = * # πΉ π΅ % = π , % frequency as interpretation of probability Β§ convergence of the sa sample mea m ean Β§ β€ π $ π % π π β π β₯ π ππ $ XC 2020
LAW W OF OF LARGE GE NU NUMBE MBERS FOR OR CONT ONTINU NUOU OUS RAND NDOM OM VARIABL BLES continuous random variables XC 2020
Let π be a continuous random variable with density function finite fi te exp xpecte ted π(π¦) . This is a sample text. va value Suppose π has a finite Insert your desired text expected value π = πΉ(π) and here. This is a sample text. π ' = π(π) . fintite variance Insert your desired text Then for any positive π > 0 we here. fi finite te vari riance have πΈ(|π β π| β₯ π») π π π» π Chebyshev Ch πΈ(|π β π| β₯ π») β€ π π inequalit in ity π» π XC 2020
Law of Large Numbers Β§ Let π " , π $ , β― , π % be an independent trials process with a continuous density function π , fi ni nite te expected value π and fi ni nite te variance π $ . Β§ Let π % = π " + π $ + β― + π % . Then for any π > 0 , π(| ' $ % β π| β₯ π) β 0 , as π β +β . Β§ Equivalently, %β) π( ' $ % β π < π) = 1 . lim , ! As - is an average of the individual outcomes, the LLN is ! often referred to as the la law of averages . XC 2020
Example 4 Suppose we choose at random π numbers from the interval [0, 1] with uniform Β§ distribution. Let π . describes the π th choice. Β§ Expect cted value π(π) πΉ π = 1 2 π + π = 1 2 0 + 1 = 1 2 Un Unifor orm distribu bution on 1 π π¦ = π β π , π β€ π¦ β€ π Variance ce π π π π = πΉ π $ β π $ π π¦ = 1, 0 β€ π¦ β€ 1 = 1 12 (π β π) $ = 1 12 (1 β 0) $ = 1 12 XC 2020
Example 4 Suppose we choose at random π numbers from the interval [0, 1] with uniform Β§ distribution. Let π . describes the π th choice and π % = β ./" % π . . Β§ Expect cted value Ch Chebyshev Inequ quality π(π % π ) = 1 π(|π β π| β₯ π) β€ π $ 2 π $ π = " $ , π $ = " "$ Variance ce π % π β 1 1 π 2 β₯ π β€ 12ππ $ π π % 1 = π 12π XC 2020
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