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MAT 137 LEC 0601 Instructor: Alessandro Malus TA: Muhammad Mohid - - PowerPoint PPT Presentation
MAT 137 LEC 0601 Instructor: Alessandro Malus TA: Muhammad Mohid - - PowerPoint PPT Presentation
MAT 137 LEC 0601 Instructor: Alessandro Malus TA: Muhammad Mohid September 18th, 2020 Warm-up question : Is this a good definition? Definition We say that x is brutal if a < x 2 , a is even. Why all this fuss about quantifiers
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Why all this fuss about quantifiers anyways?
The cake was delicious. The cake I baked was delicious.
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Why all this fuss about quantifiers anyways?
The cake was delicious. The cake I baked was delicious. I baked a cake. The cake was delicious.
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What is wrong with this proof?
Theorem
The sum of two odd numbers is even.
Proof
5 is odd. 3 is odd. 5 + 3 = 8 is even.
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What is wrong with this proof? (2)
Theorem
The sum of two odd numbers is even.
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What is wrong with this proof? (2)
Theorem
The sum of two odd numbers is even.
Proof.
The sum of two odd numbers is always even. even + even = even even + odd = odd
- dd + even = odd
- dd + odd = even.
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Definition of odd and even
Write a definition of “odd integer" and “even integer".
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Definition of odd and even
Write a definition of “odd integer" and “even integer".
Definition
Let x ∈ Z. We say that x is odd when ...
1 x = 2a + 1 ? 2 ∀a ∈ Z, x = 2a + 1? 3 ∃a ∈ Z s.t. x = 2a + 1?
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What is wrong with this proof? (3)
Theorem
The sum of two odd numbers is always even.
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What is wrong with this proof? (3)
Theorem
The sum of two odd numbers is always even.
Proof.
x = 2a + 1 odd y = 2b + 1 odd x + y = 2n even 2a + 1 + 2b + 1 = 2n 2a + 2b + 2 = 2n a + b + 1 = n
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Write a correct proof!
Theorem
The sum of two odd numbers is always even.
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One-to-one functions
Let f be a function with domain D. f is one-to-one means that ...
- ... different inputs (x) ...
- ... must produce different outputs (f (x)).
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One-to-one functions
Let f be a function with domain D. f is one-to-one means that ...
- ... different inputs (x) ...
- ... must produce different outputs (f (x)).
Write a formal definition of “one-to-one".
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One-to-one functions
Definition: Let f be a function with domain D. f is one-to-one means ...
1 f (x1) = f (x2) 2 ∃x1, x2 ∈ D, f (x1) = f (x2) 3 ∀x1, x2 ∈ D, f (x1) = f (x2) 4 ∀x1, x2 ∈ D, x1 = x2, f (x1) = f (x2) 5 ∀x1, x2 ∈ D, x1 = x2 =
⇒ f (x1) = f (x2)
6 ∀x1, x2 ∈ D, f (x1) = f (x2) =
⇒ x1 = x2
7 ∀x1, x2 ∈ D, f (x1) = f (x2) =
⇒ x1 = x2
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One-to-one functions
Let f be a function with domain D. What does each of the following mean?
1 f (x1) = f (x2) 2 ∃x1, x2 ∈ D, f (x1) = f (x2) 3 ∀x1, x2 ∈ D, f (x1) = f (x2) 4 ∀x1, x2 ∈ D, x1 = x2, f (x1) = f (x2) 5 ∀x1, x2 ∈ D, x1 = x2 =
⇒ f (x1) = f (x2)
6 ∀x1, x2 ∈ D, f (x1) = f (x2) =
⇒ x1 = x2
7 ∀x1, x2 ∈ D, f (x1) = f (x2) =
⇒ x1 = x2
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Proving a function is one-to-one
Definition
Let f be a function with domain D. We say f is one-to-one when
- ∀x1, x2 ∈ D, x1 = x2 =
⇒ f (x1) = f (x2)
- OR, equivalently,
∀x1, x2 ∈ D, f (x1) = f (x2) = ⇒ x1 = x2
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Proving a function is one-to-one
Definition
Let f be a function with domain D. We say f is one-to-one when
- ∀x1, x2 ∈ D, x1 = x2 =
⇒ f (x1) = f (x2)
- OR, equivalently,
∀x1, x2 ∈ D, f (x1) = f (x2) = ⇒ x1 = x2 Suppose I give you a specific function f and I ask you to prove it is one-to-one.
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Proving a function is one-to-one
Definition
Let f be a function with domain D. We say f is one-to-one when
- ∀x1, x2 ∈ D, x1 = x2 =
⇒ f (x1) = f (x2)
- OR, equivalently,
∀x1, x2 ∈ D, f (x1) = f (x2) = ⇒ x1 = x2 Suppose I give you a specific function f and I ask you to prove it is one-to-one.
- Write the structure of your proof (how do you begin? what
do you assume? what do you conclude?) if you use the first definition.
- Write the structure of your proof if you use the second
definition.
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Proving a function is NOT one-to-one
Definition
Let f be a function with domain D. We say f is one-to-one when
- ∀x1, x2 ∈ D, x1 = x2 =
⇒ f (x1) = f (x2)
- OR, equivalently,
∀x1, x2 ∈ D, f (x1) = f (x2) = ⇒ x1 = x2
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Proving a function is NOT one-to-one
Definition
Let f be a function with domain D. We say f is one-to-one when
- ∀x1, x2 ∈ D, x1 = x2 =
⇒ f (x1) = f (x2)
- OR, equivalently,
∀x1, x2 ∈ D, f (x1) = f (x2) = ⇒ x1 = x2 Suppose I give you a specific function f and I ask you to prove it is not one-to-one.
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Proving a function is NOT one-to-one
Definition
Let f be a function with domain D. We say f is one-to-one when
- ∀x1, x2 ∈ D, x1 = x2 =
⇒ f (x1) = f (x2)
- OR, equivalently,
∀x1, x2 ∈ D, f (x1) = f (x2) = ⇒ x1 = x2 Suppose I give you a specific function f and I ask you to prove it is not one-to-one. You need to prove f satisfies the negation of the definition.
- Write the negation of the first definition.
- Write the negation of the second definition.
- Write the structure of your proof.
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Proving a theorem
Theorem
Let f be a function with domain D.
- IF f is increasing on D
- THEN f is one-to-one on D
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Proving a theorem
Theorem
Let f be a function with domain D.
- IF f is increasing on D
- THEN f is one-to-one on D
1 Remind yourself of the precise definition of “increasing" and
“one-to-one".
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Proving a theorem
Theorem
Let f be a function with domain D.
- IF f is increasing on D
- THEN f is one-to-one on D
1 Remind yourself of the precise definition of “increasing" and
“one-to-one".
2 To prove the theorem, what will you assume? what do you want to
show?
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Proving a theorem
Theorem
Let f be a function with domain D.
- IF f is increasing on D
- THEN f is one-to-one on D
1 Remind yourself of the precise definition of “increasing" and
“one-to-one".
2 To prove the theorem, what will you assume? what do you want to
show?
3 Look at the part you want to show. Based on the definition, what is
the structure of the proof?
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Proving a theorem
Theorem
Let f be a function with domain D.
- IF f is increasing on D
- THEN f is one-to-one on D
1 Remind yourself of the precise definition of “increasing" and
“one-to-one".
2 To prove the theorem, what will you assume? what do you want to
show?
3 Look at the part you want to show. Based on the definition, what is
the structure of the proof?
4 Complete the proof.
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DISproving a theorem
FALSE Theorem
Let f be a function with domain D.
- IF f is one-to-one on D
- THEN f is increasing on D
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DISproving a theorem
FALSE Theorem
Let f be a function with domain D.
- IF f is one-to-one on D
- THEN f is increasing on D
1 This theorem is false. What do you need to do to prove it is false?
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DISproving a theorem
FALSE Theorem
Let f be a function with domain D.
- IF f is one-to-one on D
- THEN f is increasing on D
1 This theorem is false. What do you need to do to prove it is false? 2 Prove the theorem is false.
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Before next class...
- Watch videos 1.14, 1.15.
- Download the next class’s slides (no need to look at them!)