Lecture 3: Euler-Equation Estimation Simon Gilchrist Boston - - PowerPoint PPT Presentation

lecture 3 euler equation estimation
SMART_READER_LITE
LIVE PREVIEW

Lecture 3: Euler-Equation Estimation Simon Gilchrist Boston - - PowerPoint PPT Presentation

Lecture 3: Euler-Equation Estimation Simon Gilchrist Boston Univerity and NBER EC 745 Fall, 2013 Euler equation tests This lecture considers some further implications and tests of the standard asset pricing model: for any gross return R


slide-1
SLIDE 1

Lecture 3: Euler-Equation Estimation

Simon Gilchrist Boston Univerity and NBER

EC 745

Fall, 2013

slide-2
SLIDE 2

Euler equation tests

This lecture considers some further implications and tests of the “standard” asset pricing model: for any gross return Rt+1, we have the equation: Et βu′(Ct+1) u′(Ct) Rt+1

  • = 1,

Hence for any gross return Rt+1, we have Et βu′(Ct+1) u′(Ct)

  • Rt+1 − Rf

t+1

  • = 0.

These equations hold for any asset which you can buy or sell (at the margin): stocks, bonds, options, commodities, etc. Key intuition: assets are priced according to their covariance with consumption growth. Assets which pay off when consumption growth is high (in good times) are risky, hence they will need to have high expected returns for investors to want to hold them.

slide-3
SLIDE 3

Euler equation methods

Earlier lecture studies the implication of the Euler equation, plus an assumption that consumption growth is iid and dividends = consumption. Euler equation methods requires very few assumptions - no need to specify the shocks, the technology (as you would in a GE model), or the endowment process. The logic of Euler equation methods applies to models others than the CRRA representative agent model.

Example: Suppose utility depends on ct and other observable xt, say U(ct, xt), then we have Mt+1 = βU1 (ct+1, xt+1) U1(ct, xt) , and Et (Mt+1Rt+1) = 1 can similarly be tested.

slide-4
SLIDE 4

Euler equation tests

Specify u(C) = C1−γ

1−γ . For any variable Zt known at time t, we

have: ZtEt

  • β

Ct+1 Ct −γ Rt+1 − 1

  • = 0,

Since Zt known at t: Et

  • Zt
  • β

Ct+1 Ct −γ Rt+1 − 1

  • = 0

Take unconditional expectations: E

  • Zt
  • β

Ct+1 Ct −γ Rt+1 − 1

  • = 0.

This is a set of restrictions that the theory imposes on the joint distribution of consumption growth, returns and Zt.

slide-5
SLIDE 5

Alternative interpretation

Express the Euler equation as: βu′(Ct+1) u′(Ct) Rt+1 − 1

  • = εt+1,

where εt+1 = βu′(Ct+1) u′(Ct) Rt+1 − 1

  • − Et

βu′(Ct+1) u′(Ct) Rt+1 − 1

  • By construction εt+1 is a forecast error – the difference between

realized and expected values. Therefore it is uncorrelated with any variable known at time t: E (Ztεt+1) = 0 No need for distributional assumption, except that returns and consumption growth must be stationary.

slide-6
SLIDE 6

Instrument Relevance

Any stationary variable Zt realized at time t is a valid instrument. if Zt is uncorrelated with future returns and consumption, then it does not add any restriction since = E

  • Zt
  • β

Ct+1 Ct −γ Rt+1 − 1

  • =

E(Zt)E

  • β

Ct+1 Ct −γ Rt+1 − 1

  • .

Instrument relevance: Zt must forecast future returns or future consumption growth.

slide-7
SLIDE 7

Empirical Implementation

This equation holds for any returns Rt+1, Zt, so we have NK equations, where N = # of returns and K = # of “instruments” Zt, and we have 2 parameters (β, γ). Intuitively, we simply pick β and γ to set the sample version of these equations equal to zero, i.e. 1 T

T

  • t=1

Zt

  • β

Ct+1 Ct −γ Rt+1 − 1

  • = 0.
slide-8
SLIDE 8

Exact identification:

Let Zt = 1 and apply to excess aggregate stock returns: choose γ such that 1 T

T

  • t=1

Ct+1 Ct −γ Re

t+1 − Rf t+1

  • = 0.

Note: this may not be possible! i.e. with the data there may not be a γ s.t. this holds. Let Zt = 1 find β and γ to match both stock returns and the risk-free rate: 1 T

T

  • t=1
  • β

Ct+1 Ct −γ Re

t+1 − 1

  • = 0,

1 T

T

  • t=1
  • β

Ct+1 Ct −γ Rf

t+1 − 1

  • = 0.

Two eqns in two unknowns. Again, this may not be possible to find both β and γ in sample.

slide-9
SLIDE 9

Over-identification

If more than equations, then of course (generically) cannot set all the equations equal to zero. In practice minimize the weighted errors: min

β,γ g′ T WT gT ,

where gT = 1

T

T

t=1 Zt

  • β
  • Ct+1

Ct

−γ Rt+1 − 1

  • and WT is a

weighting matrix. Can pick WT = I, or WT so that moments have the same scale,

  • r choose W in a statistically optimal way. Formula for WT is

the inverse of the asymptotic variance of the moment vector: W =

  • V ar
  • 1

T

T

  • t=1
  • β

Ct+1 Ct −γ Rt+1 − 1 −1

slide-10
SLIDE 10

Over-identifying tests

Overidentification: if NK > # of parameters the system is

  • ver-identified.

Test that 1

T

T

t=1 Zt

  • β
  • Ct+1

Ct

−γ Rt+1 − 1

  • is close to zero0.
slide-11
SLIDE 11

GMM general formulas

Express a model as E[f(xt, b)] = 0 The general GMM estimate ˆ b is given by: aT gT (ˆ b) = 0, where gT (b) ≡ 1 T

T

  • t=1

f(xt, b), and aT is a matrix that defines which linear combination of gT (b) will be set to zero.

slide-12
SLIDE 12

Asymptotics

The asymptotic distribution of the GMM estimate is: √ T(ˆ b − b) → N[0, (ad)−1aSa′(ad)−1′], where d ≡ E ∂f ∂b′ (xt, b)

  • = ∂gT (b)

∂b′ , a ≡ aT , S ≡

  • j=−∞

E[f(xt, b)f(xt−j, b)′]. Hansen (1982) gives the sampling distribution of the moments gT (b): √ TgT (ˆ b) → N[0, (I − d(ad)−1a)S(I − d(ad)−1a)′].

slide-13
SLIDE 13

Efficieny

The efficient estimate is obtained by setting: a = d′S−1 In this case, √ T(ˆ b − b) → N[0, (d′S−1d)−1] The quadratic objective function provides a test of

  • ver-identifying restrictions:

TJT = TgT (ˆ b)′S−1gT (ˆ b) = χ2(NK − x)

slide-14
SLIDE 14

Testing parameter restrictions

Suppose we estimate a model that imposes R restrictions on b. We can test these restrictions using: T (JT,R − JT ) = χ2(R). where JT,R is the value of objective estimated under the restriction. Comment: when imposing the restrictions we should use the unrestricted weighting matrix. Otherwise the test statistic has a non-central χ2 distribution.

The test statistic is constructed as a quadratic function of the difference between the two moment vectors: (gT,R − gT )′WT (gT,R − gT ) If we used alternative weighting matrices the difference in the J statistics is not guaranteed to be positive.

slide-15
SLIDE 15

Ordinary Least Squares

β solves: Minβ ET [(yt − β′xt)2] In this case: f(xt, β) = xt(yt − β′xt) = xtεt, gT (β) = ET [xt(yt − β′xt)], aT = I, d = −ET (xtx′

t),

ˆ β = ET [xtx′−1

t

ET (xtyt) var(ˆ β) = 1 T ET [xtx′−1

t

[

  • j=−∞

E(εtxtx′

t−jε′ t−j)]ET [xtx′−1 t

slide-16
SLIDE 16

An implication of Euler equations

With Euler equations we have gT (b) = 1 T

T

  • t=1

Ztεt+1(b) We then choose b to minimize the quadratic gT (b)WT gT This is equivalent to choosing b so that d(gT (b))′ db WT gT = 0 In this case, the optimal weighting matrix is WT =V−1

gT where

VgT = E

  • gT (b)gT (b)′
slide-17
SLIDE 17

Variance-covariance matrix

Note that in Euler equation case: E (f(xt, b)f(xt−s, b)) = E

  • Ztεt+1ε′

t−s+1Z′ t−s

  • If we confine attention to one period returns then εt is serially

uncorrelated and this exprssion is zero for s = 0. In this case, the variance-covariance matrix can be constructed as E

  • gT (b)gT (b)′

= 1 T

T

  • t=1

Ztεt+1ε′

t+1Z′ t

If we use multi-period returns then we induce serial correlation and we need a Newey-West style estimator of the variance of the moment matrix.