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Joint use of SAXS and SANS Jill Trewhella, The University of Sydney - PowerPoint PPT Presentation

Joint use of SAXS and SANS Jill Trewhella, The University of Sydney Structural & biophysical methods for biological macromolecules in solution Sungkyunkwan University, Suwon Korea, June 19-26, 2016 Review: properties of neutrons and


  1. Joint use of SAXS and SANS Jill Trewhella, The University of Sydney Structural & biophysical methods for biological macromolecules in solution Sungkyunkwan University, Suwon Korea, June 19-26, 2016

  2.  Review: properties of neutrons and contrast  Contrast varation and deuterium labelling  Data models  Basic scattering functions  Stuhrmann analysis  Bead and rigid body modelling  Data collection strategies  Solvent matching  Contrast variation

  3. About neutrons  zero charge and negligible electric dipole  interact with matter via very short range nuclear forces (10 -15 m) and nuclei are ~100,000 smaller than their separation distances, thus neutrons can therefore travel long distances in material without being scattered or absorbed.  interact weakly with matter and are difficult to produce.  non-ionizing radiation  wavelength and energies available that are suitable for probing structures with dimensions 1- 1000s Å

  4. Scattering cross-section is the effective area presented by a scattering center – or atom; i.e. the cross-section is the probability of a scattering event defined as:  = 4 π A 2 where A is the effective radius of the cross section as seen by the X-ray or neutron and has coherent and incoherent components. For neutrons, this radius is called the scattering length, b and it depends on the nuclear isotope, spin relative to the neutron & nuclear eigenstate

  5. Coherent scattering lengths: vary linearly with atomic number for X-rays, o o show only a weak dependence on atomic number for neutrons compared to nuclear properties; e.g. nuclear isotope

  6. Among the nuclei commonly found in biomolecules, 1 H has the largest  incoherent , by a factor of ~40 and is therefore gives rise to a very large background signal  co  in Atom Nucleus coherent incoherent ( 10 -24 cm ) ( 10 -24 cm ) Hydrogen 1 H 1.8 .8 80.2 Deuteriu ium 2 H 5.6 .6 2.0 .0 Carbon 12 C 5.6 0.0 Nitrogen 14 N 9.4 2.0 Oxygen 16 O 4.2 0.0 Phosphorous 31 P 5.1 0.2 Sulfur Mostly 32 S 2.8 0.0

  7. Effect of incoherent background of 1 H on scattering from lysozyme Lysozyme in 100% 2 H 2 O Lysozyme in 100% 1 H 2 O

  8. Scattering lengths, b , for nuclei in bio-molecules or  = 0 Atom om Nucleus b (10 (10 -12 12 f x-ray for 0 in in ele electrons 12 cm) a cm) (an (and in in units of of 10 10 -12 Hydrogen 1 H -0. 0.3742 1. 1.000 (0 (0.2 .28) Deu euterium 2 H 0.6 0.6671 1. 1.000 (0 (0.2 .28) Carbon 12 C 0.6651 6.000 (1.69) Nitrogen 14 N 0.940 7.000 (1.97) Oxygen 16 O 0.5804 8.000 (2.25) Phosphorous 31 P 0.517 15.000 (4.23) Sulfur Mostly 32 S 0.2847 16.000 (4.5) At very short wavelengths and low q , the X-ray coherent scattering cross- section of an atom with Z electrons is 4π(Zr 0 ) 2 , where r 0 = e 2 /m e c 2 = 0.28 x 10 -12 cm.

  9. The scattering density of an object is simply the sum of the scattering amplitudes divided by the volume. For an assembly of atoms: 𝑂 𝑐 𝑗 𝜍 = 𝑊 𝑗=1 As 1 H has a negative coherent scattering length, and 2 H and all the common elements in biomolecules have positive coherent scattering lengths, substitution of 1 H with 2 H can dramatically change the scattering density of an object.

  10.  particle   solvent For a solution, pairs of volume elements between the solvent and solute give rise to a net scattering difference providing there is a difference in scattering density; i.e. co contr trast

  11. By adjusting the H/D ratio in a biomolecule and/or its 𝑐 𝑗 𝑂 solvent one can systematically vary 𝜍 = 𝑗=1 𝑊 and hence contrast , Δ ρ . 0% Increasing % 2 H 2 O in the solvent

  12. Mean scattering length density (10 10 cm 2 ) Contrast variation in biomolecules can take advantage of the fortuitous fact that the major bio-molecular constituents of have mean scattering length densities that are distinct and lie between the values for pure D 2 O and pure H 2 O

  13. Protein complexes require deuteration • Incorporation of deuterium up up to to 86% of the chemically Non-exchangeable protons can be obtained in minimal media using D 2 O as the deuterium source. P • Complete deuteration can only be obtained by addition of perdeuterated carbon source (g (glu lucose or r glycerol). • Use mass spec to determine deuteration levels. • Must use an E. coli B strain (e.g., BL21) – K12 strains (DH5a) do not grow. • Growth is VERY slow and requires cell adaption to the D 2 O. This can take several days to a week.

  14. More recently Duff AP, Wilde KL, Rekas A, Lake V, Holden PJ (2015) Robust High-Yield Methodologies for 2 H and 2 H/ 15 N/ 13 C Labelling of Proteins for Structural Investigations Using Neutron Scattering and NMR. Methods Enzymol . 565 , 3-25 .

  15. Solvent matching  For two scattering density component complexes; internal density fluctuations within each component <<< scattering density difference between them.  Best used when you are interested in the shape of one component in a complex, possibly how it changes upon ligand binding or complex formation.  Requires enough of the component to be solvent matched to complete a contrast variation series to determine required %D 2 O (~4 x 200-300  L, ~5 mg/ml) for precise solvent matching.  Requires 200-300  L of the labeled complex at 5-10mg/ml.

  16. Synaptic Connections & mutations implicated to Autism  -neurexin - presynaptic Neuroligin – post synaptic extracellular domains Intra-cellular domain Extra-cellular TMD domain LNS stop Stalk region TMD

  17. P ( r ) function of NL1-638 dimer shows subunit dispositions of the initial homology need refinement Vol (Å 3 ) Vol (Å 3 ) Sample Rg (Å) Experimental Calculated 21 NL1-638 41.44 ± 0.2 184,172 ± 7,778 199,261 18 15 NL1-638 (SSRL data) P(r) arbitrary units NL1-638 initial homology model 12 9 6 3 0 0 10 20 30 40 50 60 70 80 90 100 110 120 130 Distance (Angstroms)

  18. Front view Shape restoration results using X-ray scattering data from NL1 dimer complexed with  neurexin 90 ° Side view 50% of the reconstructions were similar to the shape shown here, while the other 50% gave shapes that were inconsistent with 90 ° biochemical data. To eliminate any uncertainty from the observed degeneracy in the set of shapes that fit the X-ray data, we turned to neutrons. Apical view

  19. Solvent match point determination for NL1-638 dimer complexed with D  neurexin ( NL1 2 - 2 D  n )

  20. Solvent matching experiment L1 2 -2 D  n in ~40% NL1 D 2 O to solvent match the NL1 in the neutron experiment.

  21. Co-refinement of the symmetric  ne neurex exin in positions and orientations with respect to NL1 NL1 2 give a model against the X-ray and neutron data gives us a model that we can map autism-linked mutations K378R G99S R451C V403M Comoletti, Grishaev, Whitten et al. Structure 15 , 693-705, 2007.

  22. Superposition of SANS scattering and crystal structure for NL1 2 -2 D  n Crystal Structure (3BIW) Arac et al. (2007) Neuron 56 , 992-1003

  23. Contrast variation  To determine the shapes and dispositions of labeled and unlabeled components in a complex  Requires  5 x 200-300  L (= 1 – 1.5mL) of your labeled complex at  5 mg/ml .  Deuteration level in labeled protein depends upon its size.  Smaller components require higher levels of deuteration to be distinguished.  Ideally would like to be able to take data at the solvent match points for the labeled and unlabeled components

  24. The total scattering from a two-phase scattering system is where the scattering density difference between the two phases is significantly greater than their contrast with the solvent can be approximated as: 2 𝐽 1 𝑟 + ∆ 2 𝐽 2 𝑟 + ∆ 𝐽 𝑟 = ∆ 𝜍 1 𝜍 2 𝜍 1 ∆ 𝜍 2 𝐽 12 (𝑟) where:  I 1 ( q ) and I 2 ( q ) are the form factors for the two phases (assumes S ( q ) = 1);  scattering phases 1 and 2 have a mean contrast ∆ 𝜍 1 and ∆ 𝜍 2 (uniform density approximation); and  I 12 ( q ) is the cross term. I 2 I 12 I 1

  25. D TnC-TnI (1994) 𝑸(𝒔) 𝑱(𝒓) 𝑱(𝒓) 𝒓 (Å -1 ) 𝒓 (Å -1 ) 𝒔 (Å) Two phase scattering particle in different %D 2 O solvents generates a set of linear equation of the form: 2 𝐽 1 𝑟 + ∆ 2 𝐽 2 𝑟 + ∆ 𝐽 𝑟 = ∆ 𝜍 1 𝜍 2 𝜍 1 ∆ 𝜍 2 𝐽 12 (𝑟) ∆ 𝜍 terms can be calculated from chemical and isotopic composition and one can solve for I 1 ( q ), I 2 ( q ) and I 1,2 ( q ). D TnC

  26. Stuhrmann showed that the observed R g for a scattering object with internal density fluctuations can be expressed as a quadratic function of the contrast ∆ 𝜍 : 2 + 𝛽 𝜍 − 𝛾 2 𝑆 𝑝𝑐𝑡 = 𝑆 𝑛 ∆ ∆ 𝜍 2 where R m is the R g at infinite contrast,  the second moment of the internal density fluctuations within the scattering object: 𝛽 = 𝑊 −1 𝜍 𝐺 ( 𝑠) 𝑠 2 𝑒 3 𝑠 𝑠 and  is the square of the first moment of the density fluctuations and is a measure of the displacement of the scattering length distribution with contrast: 𝛾 = (𝑊 −1 𝜍 𝐺 ( 𝑠) 𝑠 𝑒 3 𝑠) 2 𝑠

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