Introduction to Mesoscale Modelling Kazuo Saito - - PowerPoint PPT Presentation

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Introduction to Mesoscale Modelling Kazuo Saito - - PowerPoint PPT Presentation

WSN16 Evening school, 29 July 2016, Chinese University of Hong Kong Introduction to Mesoscale Modelling Kazuo Saito ksaito@mri-jma.go.jp Meteorological Research Institute 1. Fundamental equations for atmosphere 2. Waves in mesoscale atmosphere


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SLIDE 1

Introduction to Mesoscale Modelling

WSN16 Evening school, 29 July 2016, Chinese University of Hong Kong

Kazuo Saito

ksaito@mri-jma.go.jp

  • 1. Fundamental equations for atmosphere
  • 2. Waves in mesoscale atmosphere
  • 3. Classification of nonhydrostatic models
  • 4. Numerics of JMA-NHM

Meteorological Research Institute

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SLIDE 2
  • 1. Fundamental equations for atmosphere

Diagnostic equation Prognostic equations

  • Momentum equation(three wind components: u, v and w )
  • Continuity equation(pressure: p)
  • Thermodynamic equation (temperature: T)

Six variables which describe the state of dry atmosphere: three velocity components, pressure, temperature and density

In the case of moist atmosphere, preservation of water substances and the phase change must be considered (cloud micro-physics).

  • State equation (density: ρ)
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SLIDE 3

Momentum equation

w dif g z p t d dw v dif y p t d dv u dif x p t d du . 1 . 1 . 1 = + + = + = + ∂ ∂ ρ ∂ ∂ ρ ∂ ∂ ρ

  • Momentum equation(three components)

・Newton’s law of motion: (Force)=(mass×acceleration) → Navier-Sokes’ equation for fluid: (acceleration)=(pressure gradient force per unit mass) (+diffusion+gravity force for vertical direction )

∂: partial derivative symbol

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SLIDE 4

Momentum equation

w dif g z p t d dw v dif y p t d dv u dif x p t d du . 1 . 1 . 1 = + + = + = + ∂ ∂ ρ ∂ ∂ ρ ∂ ∂ ρ

  • Momentum equation(three components)

・Nwton’s law of motion: (Force)=(mass×acceleration) → Navier-Sokes’ equation for fluid: (acceleration)=(pressure gradient force per unit mass) (+diffusion+gravity acceleration for vertical direction )

∂: partial derivative symbol

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SLIDE 5

地軸 Universal gravitation Centrifugal force Gravity force Rotating spheroid

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SLIDE 6

Hydrostatic equilibrium

w dif g z p t d dw . 1 = + + ∂ ∂ ρ In case the aspect ratio of the atmospheric motion is much smaller than unity, the equation for vertical motion 1 = + g z p ∂ ∂ ρ can be replaced by hydrostatic equilibrium This relation equilibrium (balance) of forces between vertical pressure gradient force and gravity force.

Pressure gradient force Gravity force Isobaric plain high pressure low pressure

Vertical pressure gradient force usually balances with the gravity force (hydrostatic equilibrium)

acceleration

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SLIDE 7

Coriolis’ force

Effect of Coriolis’ force is added on the earth , 1 ) 2 ( F g p V dt V d + + ∇ − × Ω − = ρ

Earth rotation Earth rotation North Pole Low latitude High latitude

In vector formulation, Coriolis’ force is given by vector product of angular velocity of the earth rotation vector Ω and wind vector V:

Northward motion shifts eastward in Northern hemisphere due to the difference

  • f speeds of earth rotation.
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SLIDE 8

Continuity equation(law of mass preservation)

= + + + z w y v x u t ∂ ∂ρ ∂ ∂ρ ∂ ∂ρ ∂ ∂ρ

‥local time tendency of density=differences of mass flux through surrounding boundaries

Continuity equation

Mass flux (density x wind speed)

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SLIDE 9

) ( = + + + + + + z w y v x u z w y v x u t ∂ ∂ ∂ ∂ ∂ ρ ρ ∂ ∂ρ ∂ ∂ρ ∂ ∂ρ ∂ ∂ρ

1 = + + ∂ + z w y v x u t d d ∂ ∂ ∂ ∂ ∂ ρ ρ

we obtain the continuity equation in advective form: From the following relationship, .. flow dependent time tendency of density is given by local convergence

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SLIDE 10

State equation for ideal gasses

i is index to represent gas component such as nitrogen, oxygen, and argon, and md the weigh-average molecular of dry air (28.966 g/mol) Boyle-Charles’s combined law for ideal gas with a molecular weight of m R*:universal gas constant (=8.314J/mol/K) In case of dry air (represented by subscript d), by Dalton’s law for partial pressure, R (=R*/md):gas constant for dry air (=287.05 J/Kg/K)

T V R m M m R T

p

* *

= = ρ

RT m M T V R m M T V R p p

d d i i i i i i i d

ρ = = = =

∑ ∑ ∑

* *

∑ ∑

=

i i i i i d

m M M m

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SLIDE 11

Diagnostic equation for density

( p0=1000hPa, Cp is the specific heat of dry air in constant pressure; 7R/2=1004.7J/Kg/K) State equation for dry air Using the specific volume α (inverse of density ρ)

π θ π T p p

p

C R

= = , ) (

/

RT p ρ =

p v

C C

p p R p

/

) ( θ ρ =

where Cv is the specific heat of dry air in constant volume; Cv = Cp –R=5R/2=717.6J/Kg/K If we define the non-dimensional pressure (Exner function) π and the potential temperature θ

RT p = α

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SLIDE 12

Pressure-height equation for hydrostatic atmosphere

Pressure gradient force Gravity force Isobaric plain high pressure low pressure

Veridical pressure gradient force usually balances with the gravity force (hydrostatic equilibrium)

acceleration

Applying the state equation to hydrostatic equilibrium

1 = + g z d dp ρ

RT g z d dp p − = 1

m

RT gz

e p p

=

RT g p z d d − = ) (log

We obtain well-known barometric height formula (pressure-height equation)

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SLIDE 13

Thermodynamic equation (Conservation of potential temperature)

α pd dI dQ + =

First law of thermodynamics

‥change in the internal energy of a closed system is equal to the amount of heat supplied to the system minus the amount of work done by the system on its surroundings Let non-adiabatic heating rate Q,

θ π α α d C dp dT R C pd dT C Qdt

P v v

= − + = + = ) (

π θ π θπ α α d C p d p R dp RT p

p R C p

= = = ) ( , 

Thus,

π θ

P

C Q t d d =

‥Conservation law (prognostic equation) of potential temperature

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SLIDE 14

ρa:density of moist air, Tv:virtual temperature, qv: Specific humidity Virtual potential temperature is defined by replacing temperature by virtual temperature in definition of potential temperature Partial pressure of moist air

v

RT RT q RT RT T V R M M T V R m m M M T V R m M m M p p p

a v a v a v d v d v d v d v v d d v d

ρ ρ ρ ρ ρ ρ = + + + + + = + = + =

= = = =

) 61 . 1 ( ) 61 . ( ) 61 . 1 ( ) 61 . 1 ( ) ( * ) (

θ π π θ ) 61 . 1 ( ) 61 . 1 (

v v v v

q T q T + = + = ≡

State equation for moist air

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SLIDE 15

Thermodynamic equation for moist air

dT q C dT r rC C dQ

v p pv p

) 85 . 1 ( 1 ) ( + ≅ + + = First law of thermodynamics for moist air is given by The difference between θ and θmoist is less than 0.1K, and can be ignored as

p v

C C

p p v R p a

/

) ( θ ρ =

) 24 . 1 ( ) 85 . 1 ( ) 61 . 1 ( /

) ( ) ( ) (

v q C R v q C v q R pm C m R

p p

p p T p p T p p T moist

− + +

≅ = = θ

where r is the mixing ratio. Likewise, specific heat of moist air in constant volume is ) 94 . 1 ( 1 ) (

v v vv v vv

q C r rC C C + ≅ + + = Specific heat of water vapor in constant pressure Cpv =1854J/Kg/K Specific heat of water vapor in constant volume Cvv =Cpv –R*/mv=1390J/Kg/K Potential temperature of moist air may be modified as

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SLIDE 16

Transport of water vapor

= + + + z w y v x u t ∂ ∂ρ ∂ ∂ρ ∂ ∂ρ ∂ ∂ρ

‥local tie tendency of q =advection + moisture source Combining with the continuity equation, M z q w y q v x q u t q = + + + ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ We obtain the following flux form equation,

Flux form equation

M z wq y vq x uq t q ρ ∂ ∂ρ ∂ ∂ρ ∂ ∂ρ ∂ ∂ρ = + + +

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SLIDE 17

where From state equation, perturbation of density can be divided into the following two terms:

Perturbation of the density

) 11 . ( ' ' ' ' ' ) ( ) ' ( ) ( ' } ) ( { ' ) ( '

2 1 2

A C p p p C C p p p p C C R p p p R p p p R p R p

S p v C C p v C C C C

p v p v p v

+ − = + − = + − = = =

θ θ ρ ρ θ θ ρ θ θ θ θ θπ ρ

) 12 . (A RT C C C

v p S =

Since potential temperature is invariant for total derivation,

dt d C dt dp

S

ρ

2

' =

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SLIDE 18
  • 2. Waves in mesoscale atmosphere

Starting from the following 2-dimensional basic equations, we derivate three wave solutions in mesoscale atmosphere.

) 4 ( ) 3 ( ) 2 ( 1 ) 1 ( 1 = = + + − − = − = dt d z w x u t g z p dt dw x p dt du θ ∂ ∂ρ ∂ ∂ρ ∂ ∂ρ ∂ ∂ ρ ∂ ∂ ρ

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SLIDE 19

If we linearize the equation (1)-(3) by

u=u’, w=w’, θ= θ + θ’, ρ=ρ0+ ρ‘

The system becomes Time tendency of the density is replaced by the pressure tendency as

) ' ' 3 . ( ) ' ' ( ' ) ' ' 2 . ( ' ' '

1 ' 1

) ' ' 1 . (

A z w x u t A z p t w t u

A

x p

= + + = + +

=

∂ ∂ ∂ ∂ ρ ∂ ∂ρ ∂ ∂ ∂ ∂ ∂ ∂

ρ ∂ ∂ ρ

) 13 . ( ) ' ' ( '

2

A z w x u C t p

S

= + + ∂ ∂ ∂ ∂ ρ ∂ ∂

1) Sound waves

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SLIDE 20

) 14 . (

) ' ' ( '

2 2 2 2 2 2

2

A

z p x p C t p

S

= + − ∂ ∂ ∂ ∂ ∂ ∂

Eliminating u’ and w’ from (A.1’’),(A.2’’),(A.13), we obtain Since phase speed normal to wave plain is

S

C

m k c = + =

2 2

ω

Cs means the sound wave speed Assuming the solution of p’ as

) 8 . ( )} ( exp{ ' A t mz kx i A p ω − + =

We obtain the following dispersion relation:

2 2

2 , , 2 , , 2 m k m c m k c k

z z x x

+ = = = = = π λ ω π λ ω π λ ) 15 . ( )

2 2 2

(

2

A m k

S

C

= + − ω

Relationships between the wave number and wave length and phase speed:

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SLIDE 21

If we linearize the equation (1)-(3) by

u=u’, w=w’, θ= θ + θ’, ρ=ρ0+ ρ‘

The system becomes

2) Gravity waves

) ' 4 . ( ' ' ) ' 3 . ( ' ' ) ' 2 . ( ' ' ' '

2

1 ' 1

) ' 1 . (

A N w t b A z w x u A b z p t w t u

A

x p

= + = + = + +

=

∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ σ ∂ ∂

ρ ∂ ∂ ρ

where

b’=gθ’/θ : buoyancy N2=g/θ×dθ/dz : Brunt-Visala’s frequency σ =0 for hydrostatic, σ =1 for a nonhydrostatic system

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SLIDE 22

Eliminating u’ from (A.1’) and (A.3’), and eliminating b’ from (A.2’) and (A.4’), we obtain the following equations for p’ and w’

) 6 . ( ' ' ' ) 5 . ( ' 1 '

2 2 2 2 2 2 2

1

A N w z t p t w A x p z t w = + + = − ∂ ∂ ∂ ∂ ∂ σ ∂ ∂ ρ ∂ ∂ ∂

ρ Further eliminating p’ we obtain the following elliptic equation for w’

) 7 . ( ' ) ' ' (

2 2 2 2 2 2 2 2 2

A x w N z w x w t = + + ∂ ∂ ∂ ∂ ∂ ∂ σ ∂ ∂

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SLIDE 23

If we assume solution of w’ as

) 8 . ( )} ( exp{ ' A t mz kx i A w ω − + =

) 9 . ( , 2 , 2 , , 2

2 2 2 2

A m k c m k m c m k c k

z z x x

+ = + = = = = = ω π λ ω π λ ω π λ

Relationships between the wave number and wave length and phase speed are: Dispersion relation for gravitiy waves is

) 10 . (

2 2 2 2 2

A m k N k + = σ ω

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SLIDE 24

In hydrostatic system (σ=0 or m>>k), ω=kN/m, Cx= N/m Phase speed for horizontal direction is independent from the wave number, thus hydrostatic gravity waves do not have dispersibility horizontally. In nonhydrostatic case (σ=1 and m~k), ω becomes smaller than N. In the limit of k=∞, ( in case of vertical motion only) magnitude of ω becomes N

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SLIDE 25

Steady state linear mountain wave is a special case where upward phase velocity of internal gravity wave is in equilibrium with the ambient wind U. If we linearize the equation (1)-(3) by

u=U+u’, w=w’, θ= θ + θ’, ρ=ρ0

and assuming the steady state (time tendency is zero), the system becomes

3) Mountain waves

) 4 ( ' ' ) 3 ( ' ' ) 2 ( ' ' ' '

2

1 ' 1

) 1 (

B N w x b U B z w x u B b z p t w U x u U

B

x p

= + = + = + +

=

∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ σ ∂ ∂

ρ ∂ ∂ ρ

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SLIDE 26

Eliminating u’ from (B1) and (B3), and b’ from (B2) and (B4), we

  • btain the following equations for p’ and w’

) 6 . ( ' ' ' ) 5 . ( ' 1 '

2 2 2 2

B N w z x p x w B x p z w U

U

= + + = − ∂ ∂ ∂ ∂ ∂ σ ∂ ∂ ρ ∂ ∂

ρ

Further eliminating p’ we obtain the following elliptic equation for w’

) 7 . ( ' ) ' ' (

2 2 2 2 2 2

B w N z w x w U = + + ∂ ∂ ∂ ∂ σ

If we assume solution of w’ as in (A.8), we obtain the following (famous) Long’s (1952) equation:

) 8 . ( ' ) ( '

2 2 2 2

B w k l z w = − + σ ∂ ∂

where l=N/U is the scorer parameter.

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SLIDE 27

In hydrostatic system (σ=0 or m>>k), the solution is periodic waves with the vertical wave length 2π/l without the dispersibility horizontally. In nonhydrostatic case (σ=1 and m~k), characteristic of the solution depends on the magnitude relation of l and k. In case k2 > l2, the wave amplitude decreases exponentially in vertical (external wave). In case k2 < l2, the waves become periodic ones with the following vertical wave length (internal wave).

) 8 . ( 2

2 2

B k l z = − = π λ

The real solution of mountain waves can be obtained by superposition of several waves with the corresponding wave numbers.

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SLIDE 28

In case of 3-dimensional mountain waves, the set of equation becomes

3’) Three dimensional mountain waves

) 4 ( ' ' ) ' 3 ( ' ' ' ) 2 ( ' ' ' ' '

2

1 ' 1 ' 1

) ' 1 ( ) 1 (

B N w x b U B z w y v x u B b z p t w U x v U x u U

B B

y p x p

= + = + + = + + +

= =

∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ σ ∂ ∂ ∂ ∂

ρ ∂ ∂ ρ ∂ ∂ ρ

) ' 7 . ( ) ' ' ( }] ' ) ' ' ( { [

2 2 2 2 2 2 2 2 2 2 2 2 2 2

B y w x w N z w y w x w x U = + + + + ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ σ ∂ ∂

and the resultant equation for w’ becomes

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SLIDE 29

Example of linear mountain waves over a 3-dimensional ax-symmetric bell-shaped mountain (h=100 m) in the stable atmosphere (dθ/dz=3 K/km) of U=8m/s. Upper) hydrostatic case (half width a = 6 km), Lower) nonhydrostatic case a = 1.2 km Left) Vertical cross-section through mountain top, Right) Horizontal plain at 2.44 km AGL.

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SLIDE 30
  • 3. Classification of nonhydrostatic models

1) classification by the continuity equation

Basic equations

) 4 . 1 ( , ) 3 . 1 ( , ) 2 . 1 ( , ) 1 . 1 ( , 1 RT p C Q t d d t d d g p t d d

P

ρ π θ ρ ρ ρ = = ⋅ ∇ − = − ∇ − = v k v

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SLIDE 31
  • a. Anelastic model

) 14 . 1 ( , ) ( ) 13 . 1 ( , ' ' = ⋅ ∇ − = ∇ + + ∂ ∂ v k Adv v ρ ρ ρ g p t

Substituting the reference density in the momentum and continuity equations, we obtain governing equations of the anelastic model

) 12 . 1 ( ' , ' , ' θ θ θ ρ ρ ρ + = + = + = p p p

The anelastc (AE) model removes sound waves from solutions by a scale analysis. Field variables are divided into the time independent horizontal uniform reference state f (z) and its perturbation f' (x, y, z, t) as

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SLIDE 32

) 16 . 1 ( . ' ' '

2

k k Adv v g g C p p t

s

θ θ ρ ρ = + ∇ + + ∂ ∂

Because the density perturbation can be divided into the perturbation

  • f potential temperature and pressure as

) 15 . 1 ( ' ' ' ' ' ) ( ) ' ( ) ( ' } ) ( { ' ) ( '

2 1 2 S p v C C p v C C C C

C p p p C C p p p p C C R p p p R p p p R p R p

p v p v p v

+ − = + − = + − = = =

θ θ ρ ρ θ θ ρ θ θ θ θ θπ ρ Momentum equation may be rewritten as

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SLIDE 33
  • b. Quasi compressible model

) 20 . 1 ( . ) ( = ⋅ ∇ + ∂ ∂ v ρ ρ t

The quasi-compressible model considers the compressibility of air and predicts the pressure from divergence, while the reference density is used for momentum equations. Using the relation of

, ' ' '

2 S

C p + − = θ θ ρ ρ

following pressure equation is obtained

) 21 . 1 ( }, ) ( {

2

t C t p

S

∂ ∂ − ⋅ ∇ − = ∂ ∂ θ θ ρ ρv

if the Exner function is used to represent the pressure, the pressure equation is given by ) ' 21 . 1 ( . ) (

2 2

dt d C C C R t d d

p S v

θ θ π π + ⋅ ∇ − = v Momentum equation is same as in the anelastic equation; (1.16).

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SLIDE 34
  • c. Fully compressible model

) 4 . 1 ( , ) 2 . 1 ( , ) 1 . 1 ( , 1 RT p t d d g p t d d ρ ρ ρ ρ = ⋅ ∇ − = − ∇ − = v k v

The fully compressible model uses basic equations without the linearization by the reference atmosphere Since the fully compressible model includes sound waves in its solutions and allows the time change of the density, careful attention must be paid on computation of sound waves and computational accuracy in the finite discretization.

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SLIDE 35

Table 1. Classification of nonhydrostatic models and their behaviors.

Adiabatic expansion Constant volume heating Constant pressure heating Classification Pressure Density Volume Pressure Density Volume Density Anelastic (AE) impossible invariant invariant invariant invariant Quasi-compressible without the thermal expansion term decrease invariant increase invariant invariant invariant invariant Quasi-compressible with the thermal expansion term decrease invariant increase increase invariant increase invariant Fully-compressible without the thermal expansion term decrease decrease increase invariant decrease invariant decrease Fully-compressible with the thermal expansion term decrease decrease increase increase invariant increase decrease

) 21 . 1 ( }, ) ( {

2

t C t p

S

∂ ∂ − ⋅ ∇ − = ∂ ∂ θ θ ρ ρv

thermal expansion term

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SLIDE 36

2) treatment of sound waves

  • a. AE scheme

) 25 . 1 ( , . ) (

2

AE FP hP z P = ∂ ∂ + ∇ Nonhydrostatic models can be classified further by the treatment of sound waves. Taking total divergence of momentum equations, the following 3- dimensional Poisson-type pressure diagnostic equation is obtained. where P=p’, and h=g/Cs

2 , and r.h.s. is the forcing term by

divergence of advection and buoyancy terms. ) 25 . 1 ( 2 1 ) . . ' ( ) . . ( ) . . ( .

t t

DIV t w Adv w Dif g z v Adv v Dif y u Adv u Dif x AE FP

∆ −

∆ + − + + − + − = ρ ρ θ θ ρ ∂ ∂ ρ ρ ∂ ∂ ρ ρ ∂ ∂ Here, the last term of r.h.s. (DIV) is the divergence at the time step t-∆t, which is required for computational stability to adjust the divergence zero at next time step (Clark, 1977).

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SLIDE 37
  • b. HE-VI scheme

) 44 . 1 ( , . ' ) (

2 2

HE FP P e P h z z P = + ∂ ∂ + ∂ ∂

τ τ τ

The HE-VI (horizontally explicit vertically implicit) scheme treats sound waves implicitly only for the vertical direction. This scheme is often referred as the split-explicit method because sound waves are treated in a short time step ∆τ while low frequency modes and physical processes are treated in a long time step ∆t. Following 1-dimensional Helmholtz pressure equation is obtained The pressure equation (1.44) is formally similar to the pressure equation of the HI-VI scheme (1.36) except the Laplacian in the pressure equation is vertically 1-dimensional.

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SLIDE 38

) ' 29 . 1 ( . ) ( ) ' 28 . 1 ( ) ( ) ' 27 . 1 ( ) ' 26 . 1 (

2 2

E FP z W y V x U C P FW P C g z W FV y P V FU x P U

S S

= + + + = + + = + = +

∆ + ∆ + τ τ τ τ τ τ τ τ

∂ ∂ ∂ ∂ ∂ ∂ δ ∂ ∂ δ ∂ ∂ δ ∂ ∂ δ

) 34 . 1 ( τ δ

τ τ τ τ

∆ − ≡

∆ +

A A A

For example, if we define time tendency term of A as Momentum equations and the pressure equations may be written as

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SLIDE 39

) 38 . 1 ( } ) ( . { ) 37 . 1 ( } ) ( { ) 36 . 1 ( ) ( ) 35 . 1 ( ) (

2 2 τ τ τ τ τ τ τ τ τ τ τ τ τ τ τ τ

∂ ∂ ∂ ∂ ∂ ∂ τ ∂ ∂ τ ∂ ∂ τ ∂ ∂ τ

∆ + ∆ + ∆ + ∆ + ∆ + ∆ +

+ + − ∆ + = + − ∆ + = − ∆ + = − ∆ + = z W y V x U C E FP P P P C g z FW W W y P FV V V x P FU U U

S S

Solving for Pτ+∆t ) 39 . 1 ( . ) ( 1 ) (

2 2 2 2

HE FP P C P C g z P z

S S

= ∆ − +

∆ + ∆ + ∆ + τ τ τ τ τ τ

τ ∂ ∂ ∂ ∂

) 40 . 1 ( ) ( 1 } ) {( 1 . 1 .

2 2 τ τ τ τ

τ ∂ ∂ ∂ ∂ ∂ ∂ τ ∂ ∂ τ P C z W y V x U FW z C E FP HE FP

S S

∆ − + + ∆ + + ∆ − =

∆ +

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SLIDE 40
  • c. HI-VI scheme

) 36 . 1 ( , . ' ) ' ( '

2

HI FP eP hP z P = + ∂ ∂ + ∇

The HI-VI (horizontally implicit vertically implicit) scheme treats sound waves implicitly for both vertical and horizontal directions. This scheme,

  • ften referred as the semi-implicit method.

The following 3-dimensional Helmholtz-type pressure equation is used

) 31 . 1 ( . '

t t

P P P − =

where P’ is defined by Above pressure equation (1.36) is formally similar to the anelastic pressure equation (1.25).

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SLIDE 41

) ' ' 29 . 1 ( . ) ( ) ' ' 28 . 1 ( ) ( ) ' ' 27 . 1 ( ) ' ' 26 . 1 (

2 2

E FP z W y V x U C P FW P C g z W FV y P U FU x P U

t t t S t t S t t t t t

= + + + = + + = + = + ∂ ∂ ∂ ∂ ∂ ∂ δ ∂ ∂ δ ∂ ∂ δ ∂ ∂ δ where the term –t is weight average of A at t-∆t and t+∆t

) ' 41 . 1 ( 2 1 2 1

t t t t t

A A A

∆ − ∆ +

− + + = α α

) ' 34 . 1 ( ) 1 ( ) ( ) 1 ( 2

2

t A A t A t A A A

t t t t t t t t

∆ + − + ∆ + ∆ = ∆ − ≡

∆ − ∆ − ∆ +

α α δ For example, if we define time tendency term of A as Momentum equations and the pressure equations may be written as

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SLIDE 42

) 42 . 1 (

2 t t

A A A − ≡ ∆

If we define ∆2 as an operator Momentum equations and the pressure equations (1.26’’) ~(1.29’’)may be written as

) 46 . 1 ( ) ( ) 1 ( . ) ( ) 1 ( ) 45 . 1 ( ) ( ) 1 ( ) ( ) 1 ( ) 44 . 1 ( ) 1 ( ) 1 ( ) 43 . 1 ( ) 1 ( ) 1 (

2 2 2 2 2 2 2 2 2 2 2 2 2 2

z W y V x U C t P P E FP z W y V x U C t P P C g z t W W FW P C g z t W y P t V V FV y P t V x P t U U FU x P t U

t t t S t t t S t S t t t S t t t t t t t t

∂ ∂ ∂ ∂ ∂ ∂ ∆ α ∂ ∂∆ ∂ ∂∆ ∂ ∂∆ ∆ α ∆ ∂ ∂ ∆ α ∆ ∂ ∂ ∆ α ∆ ∂ ∂ ∆ α ∂ ∂∆ ∆ α ∆ ∂ ∂ ∆ α ∂ ∂∆ ∆ α ∆ + + + + − + = + + + + + − + − − = + + + − + − − = + + − + − − = + +

∆ − ∆ − ∆ − ∆ −

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SLIDE 43

We obtain the following elliptic tendency equation for ∆2P

) 47 . 1 ( .

2 2 2 2 2 2 2 2 2 2

) 1 ( ) ( 1 ) ( ) (

2 2

HI FP P P z y x

t C C g z P

S S

=

+ − + + +

∆ ∆ ∂ ∂ ∂ ∂ ∂ ∂

α ∆ ∂ ∂ ∆

) 48 . 1 ( ) 1 ( '

2

) ' ' ' ( .

t C FP

S

z FW y FV x FU HI FP

∆ α

∂ ∂ ∂ ∂ ∂ ∂

+

− + + =

and FU’,FV’,FW’,FP’ are r.h.s. of (1.43)~(1.46), respectively. where

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SLIDE 44

2.4. Characteristics in three methods

Method Accuracy Comput ational robust- ness Pressure equation Scalability in parallel computati

  • n

Efficiency in large scale computati

  • n

Compatibi lity with semi- Lagrangia n scheme Compatibi lity with spectral method AE Anelastic approxi- mation Good 3D Poisson Depends

  • n elliptic

solver Depends

  • n elliptic

solver Good Good HI-VI Good Fair 3D Helmholtz Depends

  • n elliptic

solver Depends

  • n elliptic

solver Good Good HE-VI Good Fair 1D Helmholtz Good Good Sound waves exist Fair

slide-45
SLIDE 45
  • 4. Numerics of JMA-NHM

Basic Equations

, , ,

3 2 2 1 1

dz ds m d ds m d ds = = = η ξ

The governing basic equations of the model consist of the flux form equations on the spherical curvilinear orthogonal coordinate. Let m1 and m2 be the map factors in the ξ (x) and η (y) directions,

dt dz dt ds w dt d m dt ds v dt d m dt ds u w k v j u i V = = = = = = + + =

3 2 2 1 1

, 1 , 1 , η ξ

slide-46
SLIDE 46

Momentum equation is , 1 2 F g p V dt V d + + ∇ − × Ω − = ρ ) ( ) ( ) ( , , η ξ η ξ η ξ η ξ η η ξ ξ η ξ ∂ ∂ + ∂ ∂ + ∂ ∂ + ∂ ∂ + ∂ ∂ + ∂ ∂ + + + = + + + + + = ∂ ∂ + ∂ ∂ + ∂ ∂ + ∂ ∂ = ∂ ∂ + ∂ ∂ + ∂ ∂ + ∂ ∂ = ∂ ∂ + ∂ ∂ + ∂ ∂ = ∇ k nv k mu w j nv j mu v i nv i mu u dt dw k dt dv j dt du i dt k d w dt j d v dt i d u dt dw k dt dv j dt du i dt V d z w nv mu t z dt dz dt d dt d t dt d z k n j m i where

slide-47
SLIDE 47

Change of unit vectors along each coordinates are an j k am i k an k n m i j m n i j n m j i am k m n j i 1 , 1 , 1 ) 1 ( ), 1 ( ), 1 ( , 1 ) 1 ( − = ∂ ∂ − = ∂ ∂ − ∂ ∂ − = ∂ ∂ ∂ ∂ = ∂ ∂ ∂ ∂ = ∂ ∂ − ∂ ∂ − = ∂ ∂ η ξ ξ η η ξ ξ η η ξ where a is radius of earth. Curvature term is

a v u k a wv j n v m u mnu j a wu i n v m u mnv i k nv k mu w j nv j mu v i nv i mu u M

2 2

)} 1 ( ) 1 ( { )} 1 ( ) 1 ( { ) ( ) ( ) ( + − + ∂ ∂ + ∂ ∂ − + + ∂ ∂ − ∂ ∂ = ∂ ∂ + ∂ ∂ + ∂ ∂ + ∂ ∂ + ∂ ∂ + ∂ ∂ = ξ η ξ η η ξ η ξ η ξ

slide-48
SLIDE 48

a w z w m v n u mn z w a w n mnu v n a w m mnv u m z w k w i u n j v n k w j v m i u m w k v j u i z k n j m i V V dt d 2 )} ( ) ( { ) 1 ( ) 1 ( ) ( ) ( ) )( ( + ∂ ∂ + ∂ ∂ + ∂ ∂ = ∂ ∂ + + ∂ ∂ + ∂ ∂ + + ∂ ∂ + ∂ ∂ = ∂ ∂ + ∂ ∂ + ∂ ∂ + ∂ ∂ + ∂ ∂ + ∂ ∂ + ∂ ∂ = + + ∂ ∂ + ∂ ∂ + ∂ ∂ = ∇ = ∇ + η ξ ξ η η ξ η η η ξ ξ ξ η ξ ρ ρ Continuity equation is

slide-49
SLIDE 49

Conformal projections

, 1 , 1 , 1

3 3 3 2 2 2 1 1 1

Dif g z p Crv Cor dt dw Dif y p m Crv Cor dt dv Dif x p m Crv Cor dt du + − − + = + − + = + − + = ∂ ∂ ρ ∂ ∂ ρ ∂ ∂ ρ

where Set n=m in the curvilinear orthogonal coordinates equations , and notate ξ, η by x, y,

v c u c Cor u w c Cor w c v Cor λ ϕ λ ϕ ϕ λ ϕ λ ϕ ϕ ∆ Ω + ∆ Ω = Ω − ∆ Ω − = ∆ Ω − Ω = sin cos 2 cos cos 2 3 sin 2 sin cos 2 2 cos cos 2 sin 2 1

a w u Crv a vw m x v m y u u m Crv a uw m y u m x v v m Crv

2 2 3 2 2 2 1

)} 1 ( ) 1 ( { )} 1 ( ) 1 ( { + = − − = − − = ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂

slide-50
SLIDE 50

, cos cos sin cos

, 1

          ∆ − ∆ + =        

=

λ ϕ λ ϕ ma y ma x y x

p p

c

1) Polar stereo projection , sin 1 sin 1 ϕ ϕ + + = m

slide-51
SLIDE 51

2) Lambert-conformal projection . ) 2 4 tan( ) 2 4 tan( ln{ / ) cos cos ln(

2 1 2 1

ϕ π ϕ π ϕ ϕ − − = c

, cos cos sin cos             ∆ − ∆ + =         λ ϕ λ ϕ c a c m y c a c m x y x

p p

, ) sin 1 sin 1 ( ) cos cos (

1 1 1 c c

m ϕ ϕ ϕ ϕ + + =

Normally, ϕ1=π/6, ϕ2=π/3

slide-52
SLIDE 52

3)Mercator projection

, ) cos sin 1 ( cos cos ,

ln

          + + ∆ + =         =

ϕ ϕ ϕ ϕ

λ a y a x y x c

  • .

cos cos ϕ ϕ = m

slide-53
SLIDE 53

Flux form equation

Continuity equation was ) 40 . 2 ( 2 )} ( ) ( {

2

prc a w z w m v y m u x m dt d = + + + + ρ ∂ ∂ ρ ∂ ∂ ∂ ∂ ρ ρ

) 41 . 2 (

) ( z w y v x u m t dt d ∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ + + + =

If we neglect the last term of l.h.s. of (2.40)by shallow assumption, we

  • btain

) 42 . 2 ( ) ( )} ( ) ( { )} ( ) ( {

2 2

) (

prc w z m v y m u x m z w m v y m u x m

t z w y v x u m t

= + + = + + +

+ + + +

ρ ∂ ∂ ρ ∂ ∂ ρ ∂ ∂ ∂ ∂ ρ ∂ ∂ ∂ ∂ ρ

∂ ∂ρ ∂ ∂ρ ∂ ∂ρ ∂ ∂ρ ∂ ∂ρ

where

slide-54
SLIDE 54

From (2.42)

) 45 . 2 ( ) ( )} ( ) ( {

2 2

= − + +

+

Prc m m w z m m v y m u x m

t

φ ρ ∂ ∂ φ ρ ∂ ∂ ρ ∂ ∂ φ φ

∂ ∂ρ

) 46 . 2 ( ) 1 ) ) ) 1

2 2 2 2

( ( ( (

Prc m w m m v m u m m

z y x t dt d

φ φ ρ φ ρ φ ρ ρφ ρ

∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ φ

+ + + = ) 47 . 2 ( ) )} ) )

( ( ( { (

Prc m m w m v m u m m

z y x m t dt d

φ φ ρ φ ρ φ ρ ρφ ρ

∂ ∂ ∂ ∂ ∂ ∂ ∂ ∂ φ

+ + + =

thus

) 44 . 2 (

2 2 2

z y x t dt d

m w m v m u m m

∂ ∂φ ∂ ∂φ ∂ ∂φ ∂ ∂φ φ

ρ ρ ρ ρ ρ

+ + + =

For arbitrary variable φ, from (2.41)

  • r
slide-55
SLIDE 55

Terms Adv.U, Adv.V, Adv.W:replace φ by u, v, w in Terms Crv.U, Crv.V, Crv.W , Cor.U, Cor.V, Cor.W:multiply ρ/m to the terms of the equations in conformal projection

) 50 . 2 ( ) 49 . 2 ( ) 48 . 2 (

. . . ) ( 1 . ) ( . . . . ) ( . . . . ) ( W Dif W Cor W Crv g z p m W Adv m w t V Dif V Cor V Crv y p V Adv m v t U Dif U Cor U Crv x p U Adv m u t + + = + + + + + = + + + + = + + ρ ∂ ∂ ρ ∂ ∂ ∂ ∂ ρ ∂ ∂ ∂ ∂ ρ ∂ ∂

(2.31)~(2.33) become

slide-56
SLIDE 56

Prognostic equation for potential temperature is where

) 51 . 2 (

. . θ π θ ∂ ∂θ

θ

Dif C Q ADV t

p

dt d

+ = + =

) 52 . 2 ( ) )} ) [ .

)] ( ( ( ( {

ρ ∂ ∂ρ θ θ ρ θ ρ θ ρ θ

∂ ∂ ∂ ∂ ∂ ∂

m t Prc m m w m v m u ADV

z y x m

− − =

+ +

underlined term is divergence.

slide-57
SLIDE 57

Pressure equation

From state equation

Here、Cm is the sound wave speed in case no liquid water Combining continuity equation Pressure equation is

p v C

C m

p p R p

/

) ( θ ρ=

t p C t t

m m m

∂ ∂ + ∂ ∂ − = ∂ ∂

2

1 θ θ ρ ρ

prc w z m v y m u x m t = + + + ) ( )} ( ) ( {

2

ρ ∂ ∂ ρ ∂ ∂ ρ ∂ ∂ ∂ ∂ρ

] ) ( )} ( ) ( { [

2 2

t prc w z m v y m u x m C t p

m m m

∂ ∂θ θ ρ ρ ∂ ∂ ρ ∂ ∂ ρ ∂ ∂ ∂ ∂ + − + + − =

slide-58
SLIDE 58

c) Time-splitting of advection term

In order to enhance the computational robustness, advection terms of momentum and potential temperature are split at small time step At the center of the Leapfrog time step, high-order advection terms are fully evaluated with the flux correction, and then second-order components are adjusted at each short time steps in the later half of the Leapfrog time integration

τ

ADVL kt ADVL kt ADV ADV + − = ) ( ) (

small time step ∆τ large time step 2∆t ADV(kt) kt-1 (ns-1)/2+1 ns-1 Advection terms are fully evaluated by higher order difference with flux correction ∆t = 40sec for 10km model; corresponds to ∆t = 80 sec in RK2 Modified by lower order advection components

slide-59
SLIDE 59

) 20 ( . ) 1 ( ) ( 1 1 ) 19 ( , . ) (

2 2 * 2 1 τ τ τ τ β β τ τ τ τ τ τ τ τ

σ ∂ ∂ τ θ θ θ θ π θ θ θ τ θ θ P mC g RW ADVLW ADVLW ADVW BUOY m P mC g z P mG W W t ADVL ADVL dif c Q ADVL ADVL ADV

m m p

− + − + − − = + + ∆ −       ∂ ∂ + − = + + + − − = ∆ −

∆ + ∆ + ∆ +

Time splitting of gravity waves

The tendency term in (19) is given by a tentative time integration in the cloud microphysical process.

slide-60
SLIDE 60

Test of 3-D Linear Mountain waves

Uniform atmosphere with U=10m/s, N=0.02/s Bell-shaped mountain h=100m、a=30km with horizontal resolution 10km

Cross-section of vertical velocity without time-splitting of advection. Left)∆t=30sec, t=10 hrs. Contour interval is 0.5 cm/s. Center) ∆t=40sec、t=2 hrs. Contour interval is1cm/s Right)∆t=50sec, t=10 hrs. Contour interval is 0.5 cm/s. With time-splitting of advection.

, } ) ( ) ( 1 { ) , (

2 3 2 2

a y a x h y x Z

m s

+ + =

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SLIDE 61

Case of 9 April 2001, 06UTC initial

Gravity waves sometimes become unstable when an inversion layer exists in strong wind environment. Vertical cross-section of 3 hrs forecast of NHM with ∆x=10km. 9 April 2001, 06UTC initial , ∆t=40 sec. Potential temperature and vertical wind.

Without time-splitting of advection With time-splitting of advection

slide-62
SLIDE 62

d) Divergence damping

, ) ( * , ) ( *

2 1 2 1 2 1 2 1

23 13

DIVT y RV ADVV z G P G G y P V V DIVT x RU ADVU z G P G G x P U U

H H

α ∂ ∂ ∂ ∂ τ α ∂ ∂ ∂ ∂ τ

τ τ τ τ τ τ τ τ τ τ

∂ ∂ + + − = + + ∆ − ∂ ∂ + + − = + + ∆ −

∆ + ∆ +

T DIV z RW ADVW BUOY m P mC g z P mG W W

Z m

α ∂ ∂ τ

β β τ τ τ

∂ ∂ + − − = + + ∆ −

∆ +

) ( 1 1

2 * 2 1

Based on the idea of Wicker and Skamarock (1992), while acts on the flux form total divergence where αH=0.06* (∆x)2/∆τ αZ((kz)=0.05* (∆z(kz))2/∆τ

slide-63
SLIDE 63

e) Direct evaluation of buoyancy

) 24 ( ) ( ) 1 ( '

2 1

2 1

gG g G BUOY

m m

ρ ρ σ θ θ ρ σ − − + ≡

. 1 * 1

2

2 1

RW ADVW BUOY m mC P z P mG t W

m

+ − = + + σ ∂ ∂ ∂ ∂

σ=0: density perturbation, σ=1: potential temperature perturbation vertical momentum equation In case of σ = 0 , BUOY includes pressure perturbation, which has to be treated implicitly. The buoyancy term BUOY is defined by

slide-64
SLIDE 64

Implicit treatment

Independent of σ, pressure perturbation term is treated implicitly as

) 29 . 2 . 2 ( . ) 1 ( ) ( 1 1

2 2 * 2 1

P mC g RW ADVW BUOY m P mC g z P mG W

m m

σ ∂ ∂ δ

β β τ

− + − − = + +

To split gravity waves, diagnosis of density is required in each short time step. ) 39 . 2 . 2 ( . } ) 1 ( { 1 ) ( ) 1 (

2 2 * 2 1

P C g BUOY m RW ADVW P mC g z mG

m m

σ ∂ ∂

β

− + + − − = + The last term in r.h.s. is evaluated in short time step. Upper and lower boundary condition of pressure equation is

slide-65
SLIDE 65

Cloud Microphysics

  • Typical prognostic variables

– water vapor, cloud water, rain, cloud ice, and graupel (Qv, Qc, Qr, Qi, Qs, Qg) – number density of cloud ice, snow and graupel (Ni, Ns, Ng)

graupel rain snow cloud ice cloud water water vapor

Tetens’ formula for saturated vapor pressure [hPa]

t t

s

e

+ ×

× =

7 . 237 5 . 7

10 11 . 6

slide-66
SLIDE 66

In bulk method, the size distribution function of water substance is expressed by the inverse exponential function of the particle diameter D.

Bulk cloud microphysics

D

e N D N

λ −

= ) (

Fall-out terminal velocity of particle is given as a power function of D by the Stokes’ law in the form of

b

aD D V = ) (

slide-67
SLIDE 67

Bulk cloud microphysics

The mass-weighted mean velocity is obtained by Here Γ(z) is the Gamma function

b D D b w w

b a dD e D dD e aD D dD D N D dD D N D V D V λ ρ π ρ π

λ λ

6 ) 4 ( ) ( 6 ) ( ) ( 6

3 3 3 3

+ Γ = = =

∫ ∫ ∫ ∫

− −

[ ]

) 1 ( ) 1 ( ) 1 ( ) )' ( ) (

2 1 1

− Γ − = − + − = − = Γ

∫ ∫

∞ − − ∞ − − ∞ − −

z z dt e t z e t dt e t z

t z t z t z

By Euler’s partial integration, the Gamma function has the following characteristic

dt e t z

t z

∞ − −

= Γ

1

) (