Introduction To Genetic Algorithms Dr. Rajib Kumar Bhattacharjya - - PowerPoint PPT Presentation

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Introduction To Genetic Algorithms Dr. Rajib Kumar Bhattacharjya - - PowerPoint PPT Presentation

R.K. Bhattacharjya/CE/IITG 1 Introduction To Genetic Algorithms Dr. Rajib Kumar Bhattacharjya Professor Department of Civil Engineering IIT Guwahati Email: rkbc@iitg.ernet.in 24 April 2015 References R.K. Bhattacharjya/CE/IITG 2 D. E.


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R.K. Bhattacharjya/CE/IITG

Introduction To Genetic Algorithms

  • Dr. Rajib Kumar Bhattacharjya

Professor

Department of Civil Engineering IIT Guwahati Email: rkbc@iitg.ernet.in

24 April 2015

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R.K. Bhattacharjya/CE/IITG

References

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 D. E. Goldberg, ‘Genetic Algorithm In Search, Optimization And

Machine Learning’, New York: Addison – Wesley (1989)

 John H. Holland ‘Genetic Algorithms’, Scientific American Journal, July

1992.

 Kalyanmoy Deb, ‘An Introduction To Genetic Algorithms’, Sadhana,

  • Vol. 24 Parts 4 And 5.
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Introduction to optimization

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Local optima Local optima Local optima Local optima

f X

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Introduction to optimization

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Multiple optimal solutions

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Genetic Algorithms

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Genetic Algorithms are the heuristic search and optimization techniques that mimic the process of natural evolution.

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Principle Of Natural Selection

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“Select The Best, Discard The Rest”

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An Example….

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Giraffes have long necks

 Giraffes with slightly longer necks could feed on leaves of higher branches

when all lower ones had been eaten off.

 They had a better chance of survival.  Favorable characteristic

propagated through generations

  • f giraffes.

 Now, evolved species has long necks.

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This longer necks may have due to the effect of mutation initially. However as it was favorable, this was propagated over the generations.

An Example….

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Evolution of species

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Initial population of animals Struggle for existence Survival of the fittest Surviving individuals reproduce, propagate favorable characteristics Evolved species

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Thus genetic algorithms implement the optimization strategies by simulating evolution of species through natural selection

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Simple Genetic Algorithms

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Initialize population Evaluate Solutions YES T = 0 T=T+1 Selection Crossover Mutation

NO

Is optimum Solution ? Start Stop

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Simple Genetic Algorithm

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function sga () {

Initialize population; Calculate fitness function; While(fitness value != termination criteria) { Selection; Crossover; Mutation; Calculate fitness function;

} }

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GA Operators and Parameters

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 Selection  Crossover  Mutation  Now we will discuss about genetic operators

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Selection

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The process that determines which solutions are to be preserved and allowed to reproduce and which ones deserve to die out. The primary objective of the selection operator is to emphasize the good solutions and eliminate the bad solutions in a population while keeping the population size constant. “Selects the best, discards the rest”

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Functions of Selection operator

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Identify the good solutions in a population Make multiple copies of the good solutions Eliminate bad solutions from the population so that multiple copies of good solutions can be placed in the population Now how to identify the good solutions?

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Fitness function

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A fitness function value quantifies the optimality of a solution. The value is used to rank a particular solution against all the other solutions A fitness value is assigned to each solution depending on how close it is actually to the optimal solution of the problem A fitness value can be assigned to evaluate the solutions

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Assigning a fitness value

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Considering c = 0.0654

23

d h

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Selection operator

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 There are different techniques to implement selection in Genetic

Algorithms.

 They are:

 Tournament selection  Roulette wheel selection  Proportionate selection  Rank selection  Steady state selection, etc

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Tournament selection

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 In tournament selection several tournaments are played among a

few individuals. The individuals are chosen at random from the population.

 The winner of each tournament is selected for next generation.  Selection pressure can be adjusted by changing the tournament

size.

 Weak individuals have a smaller chance to be selected if

tournament size is large.

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Tournament selection

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22 13 +30 22 40 32 32 25 7 +45 25 25 32 25 22 40 22 13 +30 7 +45 13 +30 22 32 25 13 +30 22 25

Selected

Best solution will have two copies Worse solution will have no copies Other solutions will have two, one

  • r zero copies
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Roulette wheel and proportionate selection

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Chrom # Fitness 1 50 2 6 3 36 4 30 5 36 6 28 186 % of RW 26.88 3.47 20.81 17.34 20.81 16.18 100.00 EC 1.61 0.19 1.16 0.97 1.16 0.90 6 AC 2 1 1 1 1 6

1 21% 2 3% 3 21% 4 18% 5 21% 6 16%

Roulet wheel

Parents are selected according to their fitness values The better chromosomes have more chances to be selected

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Rank selection

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Chrom # Fitness 1 37 2 6 3 36 4 30 5 36 6 28 Chrom # Fitness 1 37 3 36 5 36 4 30 6 28 2 6

Sort according to fitness Assign raking

Rank 6 5 4 3 2 1 Chrom # 1 3 5 4 6 2 % of RW 29 24 19 14 10 5 Chrom # 1 3 5 4 6 2

Roulette wheel

6 5 4 3 2 1

EC AC 1.714 2 1.429 1 1.143 1 0.857 1 0.571 1 0.286 Chrom # 1 3 5 4 6 2

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Steady state selection

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In this method, a few good chromosomes are used for creating new offspring in every iteration. The rest of population migrates to the next generation without going through the selection process. Then some bad chromosomes are removed and the new offspring is placed in their places Good Bad New

  • ffspring

Good New

  • ffspring
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How to implement crossover

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Source: http://www.biologycorner.com/bio1/celldivision-chromosomes.html The crossover operator is used to create new solutions from the existing solutions available in the mating pool after applying selection operator. This operator exchanges the gene information between the solutions in the mating pool. 1 1 1 1 1 Encoding of solution is necessary so that our solutions look like a chromosome

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Encoding

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The process of representing a solution in the form of a string that conveys the necessary information. Just as in a chromosome, each gene controls a particular characteristic of the individual, similarly, each bit in the string represents a characteristic of the solution.

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Encoding Methods

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Most common method of encoding is binary coded. Chromosomes are strings of 1 and 0 and each position in the chromosome represents a particular characteristic of the problem

Decoded value 52 26 Mapping between decimal and binary value

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Encoding Methods

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d h

(d,h) = (8,10) cm Chromosome = [0100001010] Defining a string [0100001010] d h

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Crossover operator

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The most popular crossover selects any two solutions strings randomly from the mating pool and some portion of the strings is exchanged between the strings. The selection point is selected randomly. A probability of crossover is also introduced in order to give freedom to an individual solution string to determine whether the solution would go for crossover or not.

Solution 1 Solution 2 Child 1 Child 2

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Binary Crossover

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Source: Deb 1999

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Mutation operator

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Though crossover has the main responsibility to search for the

  • ptimal solution, mutation is also used for this purpose.

Mutation is the occasional introduction of new features in to the solution strings of the population pool to maintain diversity in the population. Before mutation After mutation

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Binary Mutation

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 Mutation operator changes a 1 to 0 or vise versa, with a mutation probability of .  The mutation probability is generally kept low for steady convergence.  A high value of mutation probability would search here and there like a random search

technique.

Source: Deb 1999

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Elitism

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 Crossover and mutation may destroy the best solution of the

population pool

 Elitism is the preservation of few best solutions of the

population pool

 Elitism is defined in percentage or in number

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Nature to Computer Mapping

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Nature Computer

Population Individual Fitness Chromosome Gene Reproduction Set of solutions Solution to a problem Quality of a solution Encoding for a solution Part of the encoding solution Crossover

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An example problem

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Consider 6 bit string to represent the solution, then 00000 = 0 and 11111 =

Assume population size of 4 Let us solve this problem by hand calculation

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Actual count 2 1 1 Sol No Binary String 1 100101 2 001100 3 111010 4 101110 DV 37 12 58 46 x value 0.587 0.19 0.921 0.73 f 0.96 0.56 0.25 0.75 Avg Max F 0.96 0.56 0.25 0.75 2.25 0.96 Relative Fitness 0.38 0.22 0.10 0.30 Expected count 1.53 0.89 0.39 1.19

Initialize population Calculate decoded value Calculate real value Calculate objective function value Calculate fitness value Calculate relative fitness value Calculate expected count Calculate actual count Selection: Proportionate selection Initial population Fitness calculation Decoding

An example problem

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Sol No Matting pool 1 100101 2 001100 3 100101 4 101110 f F 0.97 0.97 0.60 0.60 0.75 0.75 0.96 0.96 Avg 3.29 Max 0.97 CS 3 3 2 2 New Binary String 100100 001101 101110 100101 DV 36 13 46 37 x value 0.57 0.21 0.73 0.59

Matting pool Random generation of crossover site New population

Crossover: Single point

An example problem

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Sol No 1 2 3 4 Population after crossover 100100 001101 101110 100101 Population after mutation 100000 101101 100110 101101 f F 1.00 1.00 0.78 0.78 0.95 0.95 0.78 0.78 Avg 3.51 Max 1.00 DV 32 45 38 45 x value 0.51 0.71 0.60 0.71 Mutation

An example problem

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Real coded Genetic Algorithms

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 Disadvantage of binary coded GA

 more computation  lower accuracy  longer computing time  solution space discontinuity  hamming cliff

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Real coded Genetic Algorithms

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 The standard genetic algorithms has the following steps

1.

Choose initial population

2.

Assign a fitness function

3.

Perform elitism

4.

Perform selection

5.

Perform crossover

6.

Perform mutation

In case of standard Genetic Algorithms, steps 5 and 6 require bitwise manipulation.

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Real coded Genetic Algorithms

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 Simple crossover: similar to binary crossover

P1=[8 6 3 7 6] P2=[2 9 4 8 9] C1=[8 6 4 8 9] C2=[2 9 3 7 6]

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Real coded Genetic Algorithms

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Linear Crossover

  • Parents: (x1,…,xn ) and (y1,…,yn )
  • Select a single gene (k) at random
  • Three children are created as,

) ..., , 5 . 5 . , ..., , ( 1

n k k k

x x y x x    ) ..., , 5 . 5 . 1 , ..., , ( 1

n k k k

x x y x x    ) ..., , 5 . 1 5 .

  • ,

..., , ( 1

n k k k

x x y x x   

  • From the three children, best two are selected for the

next generation

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Real coded Genetic Algorithms

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Single arithmetic crossover

  • Parents: (x1,…,xn ) and (y1,…,yn )
  • Select a single gene (k) at random
  • child1 is created as,
  • reverse for other child. e.g. with  = 0.5

) ..., , ) 1 ( , ..., , ( 1

n k k k

x x y x x      

0.1 0.3 0.1 0.3 0.7 0.2 0.5 0.1 0.2 0.5 0.7 0.7 0.5 0.2 0.8 0.3 0.9 0.4 0.1 0.3 0.1 0.3 0.7 0.5 0.5 0.1 0.2 0.5 0.7 0.7 0.5 0.2 0.5 0.3 0.9 0.4

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Real coded Genetic Algorithms

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Simple arithmetic crossover

  • Parents: (x1,…,xn ) and (y1,…,yn )
  • Pick random gene (k) after this point mix values
  • child1 is created as:
  • reverse for other child. e.g. with  = 0.5

) ) 1 ( n y ..., , 1 ) 1 ( 1 , ..., , 1 ( n x k x k y k x x              

0.1 0.3 0.1 0.3 0.7 0.2 0.5 0.1 0.2 0.5 0.7 0.7 0.5 0.2 0.8 0.3 0.9 0.4 0.1 0.3 0.1 0.3 0.7 0.5 0.4 0.5 0.3 0.5 0.7 0.7 0.5 0.2 0.5 0.4 0.5 0.3

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Real coded Genetic Algorithms

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Whole arithmetic crossover

  • Most commonly used
  • Parents: (x1,…,xn ) and (y1,…,yn )
  • child1 is:
  • reverse for other child. e.g. with  = 0.5

y x     ) 1 (  

0.1 0.3 0.1 0.3 0.6 0.2 0.5 0.1 0.2 0.5 0.7 0.7 0.5 0.2 0.8 0.3 0.9 0.4 0.3 0.5 0.4 0.4 0.4 0.5 0.4 0.5 0.3 0.3 0.5 0.4 0.4 0.4 0.5 0.4 0.5 0.3

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Simulated binary crossover

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 Developed by Deb and Agrawal, 1995)

Where, a random number is a parameter that controls the crossover process. A high value of the parameter will create near-parent solution

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Random mutation

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Where is a random number between [0,1] Where, is the user defined maximum perturbation

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Normally distributed mutation

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A simple and popular method Where is the Gaussian probability distribution with zero mean

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Polynomial mutation

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Multi-modal optimization

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After Generation 200

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Multi-modal optimization

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Niche count Modified fitness Sharing function

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Hand calculation

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Maximize

Sol String Decoded value x f 1 110100 52 1.651 0.890 2 101100 44 1.397 0.942 3 011101 29 0.921 0.246 4 001011 11 0.349 0.890 5 110000 48 1.524 0.997 6 101110 46 1.460 0.992

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Distance table

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dij 1 2 3 4 5 6 1 0.254 0.73 1.302 0.127 0.191 2 0.254 0.476 1.048 0.127 0.063 3 0.73 0.476 0.572 0.603 0.539 4 1.302 1.048 0.572 1.175 1.111 5 0.127 0.127 0.603 1.175 0.064 6 0.191 0.063 0.539 1.111 0.064

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Sharing function values

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sh(dij) 1 2 3 4 5 6 nc 1 1 0.492 0.746 0.618 2.856 2 0.492 1 0.048 0.746 0.874 3.16 3 0.048 1 1.048 4 1 1 5 0.746 0.746 1 0.872 3.364 6 0.618 0.874 0.872 1 3.364

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Sharing fitness value

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Sol String Decoded value x f nc f’ 1 110100 52 1.651 0.890 2.856 0.312 2 101100 44 1.397 0.942 3.160 0.300 3 011101 29 0.921 0.246 1.048 0.235 4 001011 11 0.349 0.890 1.000 0.890 5 110000 48 1.524 0.997 3.364 0.296 6 101110 46 1.460 0.992 3.364 0.295

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Solutions obtained using modified fitness value

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Evolutionary Strategies

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 ES use real parameter value  ES does not use crossover operator  It is just like a real coded genetic algorithms with selection and

mutation operators only

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Two members ES: (1+1) ES

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 In each iteration one parent is used to create one offspring by

using Gaussian mutation operator

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Two members ES: (1+1) ES

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 Step1: Choose a initial solution and a mutation strength  Step2: Create a mutate solution  Step 3: If , replace with  Step4: If termination criteria is satisfied, stop, else go to step 2

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Two members ES: (1+1) ES

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 Strength of the algorithm is the proper value of  Rechenberg postulate

 The ratio of successful mutations to all the mutations should be 1/5. If this

ratio is greater than 1/5, increase mutation strength. If it is less than 1/5, decrease the mutation strength.

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Two members ES: (1+1) ES

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 A mutation is defined as successful if the mutated offspring is better

than the parent solution.

 If is the ratio of successful mutation over n trial, Schwefel (1981)

suggested a factor in the following update rule

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Matlab code

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Some results of 1+1 ES

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Optimal Solution is X*= [3.00 1.99] Objective function value f = 0.0031007

1 2 2 5 5 10 1 10 20 20 20 20 2 50 50 50 50 5 100 100 1 100 1 100 2 200 200 200 200 X Y 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5

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Multimember ES

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ES Step1: Choose an initial population of solutions and mutation strength Step2: Create mutated solution Step3: Combine and , and choose the best solutions Step4: Terminate? Else go to step 2

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Multimember ES

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ES

Through mutation Through selection

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Multimember ES

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ES

Offspring

Through mutation Through selection

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Multi-objective optimization

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Price Comfort

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Multi-objective optimization

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Two objectives are

  • Minimize weight
  • Minimize deflection
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Multi-objective optimization

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 More than one objectives  Objectives are conflicting in nature  Dealing with two search space

 Decision variable space  Objective space

 Unique mapping between the objectives and often the mapping is non-

linear

 Properties of the two search space are not similar  Proximity of two solutions in one search space does not mean a proximity in

  • ther search space
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Multi-objective optimization

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Vector Evaluated Genetic Algorithm (VEGA)

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f1 f2 f3 f4 … fn P1 P2 P3 P4 Pn … Crossover and mutation Old population Mating pool New population Propose by Schaffer (1984)

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Non-dominated selection heuristic

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 Give more emphasize on the non-dominated solutions in the population  This can be implemented by subtracting € from the dominated solution

fitness value

 Suppose N' is the number of sub-population and n' is the non-

dominated solution. Then total reduction is (N' - n')€.

 The total reduction is then redistributed among the non-dominated

solution by adding an amount (N' - n')€ /n.

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Non-dominated selection heuristic

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 This method has two main implications

Non-dominated solutions are given more importance Additional equal emphasis has been given to all the non-

dominated solution

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Weighted based genetic algorithm (WBGA)

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 The fitness is calculated  The spread is maintained using the sharing function approach

Niche count Modified fitness Sharing function

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Multiple objective genetic algorithm (MOGA)

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0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 x1 x2 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 10 20 30 40 50 60 f1 f2

Solution space Objective space

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Minimize f1 Minimize f2

Multiple objective genetic algorithm (MOGA)

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Multiple objective genetic algorithm (MOGA)

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 Fonseca and Fleming (1993) first introduced multiple objective genetic

algorithm (MOGA)

 The assigned fitness value based on the non-dominated ranking.  The rank is assigned as where is the ranking of the ith

solution and is the number of solutions that dominate the solution.

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1 1 1 1 2 2 3

Multiple objective genetic algorithm (MOGA)

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 Fonseca and Fleming (1993) maintain the diversity among the non-

dominated solution using niching among the solution of same rank.

 The normalize distance was calculated as,  The niche count was calculated as,

Multiple objective genetic algorithm (MOGA)

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NSGA

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 Srinivas and Deb (1994) proposed NSGA  The algorithm is based on the non-dominated sorting.  The spread on the Pareto optimal front is maintained using sharing

function

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NSGA II

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 Non-dominated Sorting Genetic Algorithms

 NSGA II is an elitist non-dominated sorting Genetic Algorithm to solve multi-

  • bjective optimization problem developed by Prof. K. Deb and his student

at IIT Kanpur.

 It has been reported that NSGA II can converge to the global Pareto-

  • ptimal front and can maintain the diversity of population on the Pareto-
  • ptimal front
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R.K. Bhattacharjya/CE/IITG

Non-dominated sorting

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Objective 1 (Minimize) Objective 2 (Minimize) 1 2 3 4 5 6

Objective 1 (Minimize) Objective 2 (Minimize) 1 2 3 4 5 Infeasible Region Feasible Region

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Calculation crowding distance

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R.K. Bhattacharjya/CE/IITG

Crowded tournament operator

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 A solution I wins a tournament with another solution j,

 If the solution i has better rank than j, i.e. ri<rj  If they have the sa,e rank, but i has a better crowding distance than j, i.e.

ri=rj and di>dj.

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Replacement scheme of NSGA II

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Non-dominating sorting Crowding distance sorting Rejected

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Initialize population of size N Calculate all the objective functions Rank the population according to non- dominating criteria Selection Crossover Mutation Calculate objective function of the new population Combine old and new population Non-dominating ranking on the combined population Replace parent population by the better members of the combined population Calculate crowding distance of all the solutions Get the N member from the combined population on the basis

  • f rank and crowding distance

Termination Criteria?

Pareto-optimal solution

Yes No

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THANKS

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