SLIDE 1 Interlacing Families I: Bipartite Ramanujan Graphs of all Degrees
Nikhil Srivastava (Microsoft Research) Adam Marcus (Yale), Daniel Spielman (Yale)
SLIDE 2 Expander Graphs
Sparse regular well-connected graphs with many properties of random graphs.
Every set of vertices has many neighbors. Random walks mix quickly. Pseudo-random generators. Error-correcting codes. Used throughout Computer Science.
SLIDE 3 Spectral Expanders
Let G be a graph and A be its adjacency matrix eigenvalues π1 β₯ π2 β₯ β― ππ
a c d e b
0 1 0 0 1 1 0 1 0 1 0 1 0 1 0 0 0 1 0 1 1 1 0 1 0
SLIDE 4 Spectral Expanders
Let G be a graph and A be its adjacency matrix eigenvalues π1 β₯ π2 β₯ β― ππ
If d-regular, then π΅π = ππ so π1 = π If bipartite then eigs are symmetric about zero so ππ = βπ
a c d e b
0 1 0 0 1 1 0 1 0 1 0 1 0 1 0 0 0 1 0 1 1 1 0 1 0
βtrivialβ
SLIDE 5 Spectral Expanders
Definition: G is a good expander if all non-trivial eigenvalues are small
[ ]
d
SLIDE 6 Spectral Expanders
Definition: G is a good expander if all non-trivial eigenvalues are small
[ ]
d e.g. πΏπ and πΏπ,π have all nontrivial eigs 0.
SLIDE 7 Spectral Expanders
Definition: G is a good expander if all non-trivial eigenvalues are small
[ ]
d e.g. πΏπ and πΏπ,π have all nontrivial eigs 0.
Alon-Boppanaβ86: For every π > 0, every sufficiently large d-regular graph has a nontrivial eigenvalue greater than2 π β 1 β π
Challenge: construct infinite families.
SLIDE 8 Ramanujan Graphs:
Definition: G is Ramanujan if all non-trivial eigs have absolute value at most 2 π β 1
[ ]
d
[
]
2 π β 1
SLIDE 9 Ramanujan Graphs:
Definition: G is Ramanujan if all non-trivial eigs have absolute value at most 2 π β 1
[ ]
d
[
]
2 π β 1
Margulis, Lubotzky-Phillips-Sarnakβ88: Infinite sequences of Ramanujan graphs exist for π = π + 1 Friedmanβ08: A random d-regular graph is almost Ramanujan : 2 π β 1 + π
SLIDE 10 Main Result
- Theorem. Infinite families of bipartite Ramanujan graphs
exist for every π β₯ 3.
SLIDE 11 Main Result
- Theorem. Infinite families of bipartite Ramanujan graphs
exist for every π β₯ 3. Proof is elementary, doesnβt use number theory. Not explicit. Based on a new existence argument: method of interlacing families of polynomials.
SLIDE 12 Bilu-Linialβ06 Approach
Find an operation which doubles the size of a graph without blowing up its eigenvalues.
[ ]
d
[
]
2 π β 1
SLIDE 13 Bilu-Linialβ06 Approach
Find an operation which doubles the size of a graph without blowing up its eigenvalues.
[ ]
d
[
]
2 π β 1
SLIDE 14 Bilu-Linialβ06 Approach
Find an operation which doubles the size of a graph without blowing up its eigenvalues.
[ ]
d
[
]
2 π β 1
β¦ β
SLIDE 15
2-lifts of graphs
a c d e b
SLIDE 16
2-lifts of graphs
a c d e b a c d e b
duplicate every vertex
SLIDE 17 2-lifts of graphs
duplicate every vertex
a0 c0
d0
e0
b0
a1 c1
d1
e1
b1
SLIDE 18 2-lifts of graphs
a0 c0
d0
e0
b0
a1
d1
e1
b1
c1
for every pair of edges: leave on either side (parallel),
SLIDE 19 2-lifts of graphs
for every pair of edges: leave on either side (parallel),
a0 c0
d0
e0
b0
a1
d1
e1
b1
c1
SLIDE 20 2-lifts of graphs
for every pair of edges: leave on either side (parallel),
a0 c0
d0
e0
b0
a1
d1
e1
b1
c1
2π possibilities
SLIDE 21 2-lifts of graphs
0 1 0 0 1 1 0 1 0 1 0 1 0 1 0 0 0 1 0 1 1 1 0 1 0
n eigenvalues {π1 β¦ ππ}
SLIDE 22 2-lifts of graphs
0 1 0 0 1 0 0 0 0 0 1 0 1 0 1 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 1 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 1 0 1 0 1 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 1 1 0 1 0
SLIDE 23 2-lifts of graphs
0 0 0 0 1 0 1 0 0 0 0 1 0 1 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 1 0 0 1 0 0 1 1 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 1 0 1 0 0 0 1 0 1 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 1 1 0 1
SLIDE 24 2-lifts of graphs
0 0 0 0 1 0 1 0 0 0 0 1 0 1 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 1 0 0 1 0 0 1 1 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 1 0 1 0 0 0 1 0 1 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 1 1 0 1
2n eigenvalues π1 β¦ ππ βͺ {π1
β² β¦ ππ β² }
SLIDE 25 Eigenvalues of 2-lifts (Bilu-Linial)
Given a 2-lift of G, create a signed adjacency matrix As with a -1 for crossing edges and a 1 for parallel edges
0 -1 0 0 1
0 1 0 -1 0 0 0 -1 0 1 1 1 0 1 0
a0 c0
d0
e0
b0
a1
d1
e1
b1
c1
SLIDE 26 Eigenvalues of 2-lifts (Bilu-Linial)
Theorem: The eigenvalues of the 2-lift are the union of the eigenvalues of A (old) and the eigenvalues of As (new)
π1
β² β¦ ππ β²
= ππππ‘(π΅π‘)
0 -1 0 0 1
0 1 0 -1 0 0 0 -1 0 1 1 1 0 1 0
π΅π‘ =
SLIDE 27
Eigenvalues of 2-lifts (Bilu-Linial)
Theorem: The eigenvalues of the 2-lift are the union of the eigenvalues of A (old) and the eigenvalues of As (new) Conjecture: Every d-regular graph has a 2-lift in which all the new eigenvalues have absolute value at most
SLIDE 28
Eigenvalues of 2-lifts (Bilu-Linial)
Theorem: The eigenvalues of the 2-lift are the union of the eigenvalues of A (old) and the eigenvalues of As (new) Conjecture: Every d-regular adjacency matrix A has a signing π΅π‘ with ||π΅π|| β€ 2 π β 1
SLIDE 29 Eigenvalues of 2-lifts (Bilu-Linial)
Conjecture: Every d-regular adjacency matrix A has a signing π΅π‘ with ||π΅π|| β€ 2 π β 1
We prove this in the bipartite case.
SLIDE 30
Eigenvalues of 2-lifts (Bilu-Linial)
Theorem: Every d-regular adjacency matrix A has a signing π΅π‘ with π1(π΅π) β€ 2 π β 1
SLIDE 31
Eigenvalues of 2-lifts (Bilu-Linial)
Theorem: Every d-regular bipartite adjacency matrix A has a signing π΅π‘ with ||π΅π|| β€ 2 π β 1 Trick: eigenvalues of bipartite graphs are symmetric about 0, so only need to bound largest
SLIDE 32
Random Signings
Idea 1: Choose π‘ β β1,1 π randomly.
SLIDE 33
Random Signings
Idea 1: Choose π‘ β β1,1 π randomly. Unfortunately, (Bilu-Linial showed when A is nearly Ramanujan )
SLIDE 34
Random Signings
Idea 2: Observe that where
SLIDE 35
Random Signings
Idea 2: Observe that where
Consider
SLIDE 36
Random Signings
Idea 2: Observe that where Usually useless, but not here! is an interlacing family. such that
Consider
SLIDE 37 3-Step Proof Strategy
- 1. Show that some poly does as well as the .
such that
SLIDE 38 3-Step Proof Strategy
- 1. Show that some poly does as well as the .
- 2. Calculate the expected polynomial.
such that
SLIDE 39 3-Step Proof Strategy
- 1. Show that some poly does as well as the .
- 2. Calculate the expected polynomial.
- 3. Bound the largest root of the expected poly.
such that
SLIDE 40 3-Step Proof Strategy
- 1. Show that some poly does as well as the .
- 2. Calculate the expected polynomial.
- 3. Bound the largest root of the expected poly.
such that
SLIDE 41 3-Step Proof Strategy
- 1. Show that some poly does as well as the .
- 2. Calculate the expected polynomial.
- 3. Bound the largest root of the expected poly.
such that
SLIDE 42
Step 2: The expected polynomial
Theorem [Godsil-Gutmanβ81] For any graph G, the matching polynomial of G
SLIDE 43 The matching polynomial (Heilmann-Lieb β72)
mi = the number of matchings with i edges
SLIDE 44
SLIDE 46 7 matchings with 1 edge
SLIDE 47
SLIDE 48
SLIDE 49 Proof that
x Β±1 0 0 Β±1 Β±1 Β±1 x Β±1 0 0 0 0 Β±1 x Β±1 0 0 0 Β±1 x Β±1 0 Β±1 0 0 Β±1 x Β±1 Β±1 0 0 0 Β±1 x
Expand using permutations
SLIDE 50 Proof that
x Β±1 0 0 Β±1 Β±1 Β±1 x Β±1 0 0 0 0 Β±1 x Β±1 0 0 0 Β±1 x Β±1 0 Β±1 0 0 Β±1 x Β±1 Β±1 0 0 0 Β±1 x
Expand using permutations
same edge: same value
SLIDE 51 Proof that
x Β±1 0 0 Β±1 Β±1 Β±1 x Β±1 0 0 0 0 Β±1 x Β±1 0 0 0 Β±1 x Β±1 0 Β±1 0 0 Β±1 x Β±1 Β±1 0 0 0 Β±1 x
Expand using permutations
same edge: same value
SLIDE 52 Proof that
x Β±1 0 0 Β±1 Β±1 Β±1 x Β±1 0 0 0 0 Β±1 x Β±1 0 0 0 Β±1 x Β±1 0 Β±1 0 0 Β±1 x Β±1 Β±1 0 0 0 Β±1 x
Expand using permutations Get 0 if hit any 0s
SLIDE 53 Proof that
x Β±1 0 0 Β±1 Β±1 Β±1 x Β±1 0 0 0 0 Β±1 x Β±1 0 0 0 Β±1 x Β±1 0 Β±1 0 0 Β±1 x Β±1 Β±1 0 0 0 Β±1 x
Expand using permutations Get 0 if take just one entry for any edge
SLIDE 54 Proof that
x Β±1 0 0 Β±1 Β±1 Β±1 x Β±1 0 0 0 0 Β±1 x Β±1 0 0 0 Β±1 x Β±1 0 Β±1 0 0 Β±1 x Β±1 Β±1 0 0 0 Β±1 x
Expand using permutations Only permutations that count are involutions
SLIDE 55 Proof that
x Β±1 0 0 Β±1 Β±1 Β±1 x Β±1 0 0 0 0 Β±1 x Β±1 0 0 0 Β±1 x Β±1 0 Β±1 0 0 Β±1 x Β±1 Β±1 0 0 0 Β±1 x
Expand using permutations Only permutations that count are involutions
SLIDE 56 Proof that
x Β±1 0 0 Β±1 Β±1 Β±1 x Β±1 0 0 0 0 Β±1 x Β±1 0 0 0 Β±1 x Β±1 0 Β±1 0 0 Β±1 x Β±1 Β±1 0 0 0 Β±1 x
Expand using permutations Only permutations that count are involutions Correspond to matchings
SLIDE 57 Proof that
x Β±1 0 0 Β±1 Β±1 Β±1 x Β±1 0 0 0 0 Β±1 x Β±1 0 0 0 Β±1 x Β±1 0 Β±1 0 0 Β±1 x Β±1 Β±1 0 0 0 Β±1 x
Expand using permutations Only permutations that count are involutions Correspond to matchings
SLIDE 58 3-Step Proof Strategy
- 1. Show that some poly does as well as the .
- 2. Calculate the expected polynomial.
[Godsil-Gutmanβ81]
- 3. Bound the largest root of the expected poly.
such that
ο
SLIDE 59 3-Step Proof Strategy
- 1. Show that some poly does as well as the .
- 2. Calculate the expected polynomial.
[Godsil-Gutmanβ81]
- 3. Bound the largest root of the expected poly.
such that
ο
SLIDE 60
The matching polynomial (Heilmann-Lieb β72)
Theorem (Heilmann-Lieb) all the roots are real
SLIDE 61
The matching polynomial (Heilmann-Lieb β72)
Theorem (Heilmann-Lieb) all the roots are real and have absolute value at most Proof: simple, based on recurrences.
SLIDE 62 3-Step Proof Strategy
- 1. Show that some poly does as well as the .
- 2. Calculate the expected polynomial.
[Godsil-Gutmanβ81]
- 3. Bound the largest root of the expected poly.
[Heilmann-Liebβ72] such that
ο ο
SLIDE 63 3-Step Proof Strategy
- 1. Show that some poly does as well as the .
- 2. Calculate the expected polynomial.
[Godsil-Gutmanβ81]
- 3. Bound the largest root of the expected poly.
[Heilmann-Liebβ72] such that
ο ο
SLIDE 64 3-Step Proof Strategy
- 1. Show that some poly does as well as the .
Implied by: β is an interlacing family.β such that
SLIDE 65 Averaging Polynomials
Basic Question: Given when are the roots
- f the related to roots of ?
SLIDE 66 Averaging Polynomials
Basic Question: Given when are the roots
- f the related to roots of ?
Answer: Certainly not always
SLIDE 67 Averaging Polynomials
Basic Question: Given when are the roots
- f the related to roots of ?
Answer: Certainly not alwaysβ¦
SLIDE 68 Averaging Polynomials
Basic Question: Given when are the roots
- f the related to roots of ?
But sometimes it works:
SLIDE 69 A Sufficient Condition
Basic Question: Given when are the roots
- f the related to roots of ?
Answer: When they have a common interlacing.
if
SLIDE 70
- Theorem. If have a common
interlacing,
SLIDE 71
- Theorem. If have a common
interlacing, Proof.
SLIDE 72
- Theorem. If have a common
interlacing, Proof.
SLIDE 73
- Theorem. If have a common
interlacing, Proof.
SLIDE 74
- Theorem. If have a common
interlacing, Proof.
SLIDE 75
- Theorem. If have a common
interlacing, Proof.
SLIDE 76
- Theorem. If have a common
interlacing, Proof.
SLIDE 77 Interlacing Family of Polynomials
Definition: is an interlacing family
if can be placed on the leaves of a tree so that when every node is the sum of leaves below, sets of siblings have common interlacings
SLIDE 78 Interlacing Family of Polynomials
Definition: is an interlacing family
if can be placed on the leaves of a tree so that when every node is the sum of leaves below, sets of siblings have common interlacings
SLIDE 79 Interlacing Family of Polynomials
Definition: is an interlacing family
if can be placed on the leaves of a tree so that when every node is the sum of leaves below, sets of siblings have common interlacings
SLIDE 80 Interlacing Family of Polynomials
Definition: is an interlacing family
if can be placed on the leaves of a tree so that when every node is the sum of leaves below, sets of siblings have common interlacings
SLIDE 81 Interlacing Family of Polynomials
Definition: is an interlacing family
if can be placed on the leaves of a tree so that when every node is the sum of leaves below, sets of siblings have common interlacings
SLIDE 82
Interlacing Family of Polynomials
Theorem: There is an s so that
SLIDE 83
Proof: By common interlacing, one of , has
Interlacing Family of Polynomials
Theorem: There is an s so that
SLIDE 84
Proof: By common interlacing, one of , has
Interlacing Family of Polynomials
Theorem: There is an s so that
SLIDE 85
Proof: By common interlacing, one of , has
Interlacing Family of Polynomials
Theorem: There is an s so that
SLIDE 86
Proof: By common interlacing, one of , has β¦.
Interlacing Family of Polynomials
Theorem: There is an s so that
SLIDE 87
Proof: By common interlacing, one of , has
Interlacing Family of Polynomials
Theorem: There is an s so that
SLIDE 88
An interlacing family
Theorem: Let is an interlacing family
SLIDE 89
An interlacing family
Theorem: Let is an interlacing family Lemma (easy): and have a common interlacing if and only if is real rooted for all
SLIDE 90
To prove interlacing family
Let Leaves of tree = signings π‘1, β¦ , π‘π Internal nodes = partial signings π‘1, β¦ , π‘π
SLIDE 91
To prove interlacing family
Let Need to prove that for all , is real rooted
SLIDE 92 To prove interlacing family
Need to prove that for all ,
are fixed is 1 with probability , -1 with are uniformly
is real rooted Let
SLIDE 93 Generalization of Heilmann-Lieb
Suffices to prove that is real rooted for every independent distribution
SLIDE 94 Generalization of Heilmann-Lieb
Suffices to prove that is real rooted for every independent distribution
SLIDE 95
Transformation to PSD Matrices
Suffices to show real rootedness of
SLIDE 96
Transformation to PSD Matrices
Suffices to show real rootedness of Why is this useful?
SLIDE 97
Transformation to PSD Matrices
Suffices to show real rootedness of Why is this useful?
SLIDE 98
Transformation to PSD Matrices
SLIDE 99 π€ππ = ππ β π
π with probability Ξ»ππ
ππ + π
π with probability (1βπππ)
Transformation to PSD Matrices
π½π‘ det π¦π½ β ππ½ β π΅π‘ = π½det π¦π½ β
ππβπΉ
π€πππ€ππ
π
where
SLIDE 100 Master Real-Rootedness Theorem
Given any independent random vectors π€1, β¦ , π€π β βπ, their expected characteristic polymomial has real roots.
π½det π¦π½ β
π
π€ππ€π
π
SLIDE 101 Master Real-Rootedness Theorem
Given any independent random vectors π€1, β¦ , π€π β βπ, their expected characteristic polymomial has real roots.
π½det π¦π½ β
π
π€ππ€π
π
How to prove this?
SLIDE 102 The Multivariate Method
ββ¦it is often useful to consider the multivariate polynomial β¦ even if one is ultimately interested in a particular one-variable specializationβ
Borcea-Branden 2007+: prove that univariate polynomials are real-rooted by showing that they are nice transformations of real-rooted multivariate polynomials.
SLIDE 103
Real Stable Polynomials
is real stable if for all i Implies . Definition:
SLIDE 104
Real Stable Polynomials
is real stable if no roots in the upper half-plane univariate real stable = real-rooted for all i Implies . Definition:
SLIDE 105 If is real stable, then so is
- 1. π(π½, π¨2, β¦ , π¨π) for any π½ β β
- 2. 1 β ππ¨π π(π¨1, β¦ π¨π)
Excellent Closure Properties
is real stable if for all i Implies . Definition:
SLIDE 106
A Useful Real Stable Poly
Borcea-BrΓ€ndΓ©n β08: For PSD matrices is real stable
SLIDE 107 A Useful Real Stable Poly
Borcea-BrΓ€ndΓ©n β08: For PSD matrices is real stable Plan: apply closure properties to this to show that π½det π¦π½ β π π€ππ€π
π is real stable.
SLIDE 108 Central Identity
Suppose π€1, β¦ , π€π are independent random vectors with π΅π β π½π€ππ€π
π. Then
π½det π¦π½ β
π
π€ππ€π
π
=
π=1 π
1 β π ππ¨π det π¦π½ +
π
π¨ππ΅π
π¨1=β―=π¨π=0
SLIDE 109 Central Identity
Suppose π€1, β¦ , π€π are independent random vectors with π΅π β π½π€ππ€π
π. Then
π½det π¦π½ β
π
π€ππ€π
π
=
π=1 π
1 β π ππ¨π det π¦π½ +
π
π¨ππ΅π
π¨1=β―=π¨π=0
Proof: easy, tomorrow.
SLIDE 110 Proof of Master Real- Rootedness Theorem
Suppose π€1, β¦ , π€π are independent random vectors with π΅π β π½π€ππ€π
π. Then
π½det π¦π½ β
π
π€ππ€π
π
=
π=1 π
1 β π ππ¨π det π¦π½ +
π
π¨ππ΅π
π¨1=β―=π¨π=0
SLIDE 111 Proof of Master Real- Rootedness Theorem
Suppose π€1, β¦ , π€π are independent random vectors with π΅π β π½π€ππ€π
π. Then
π½det π¦π½ β
π
π€ππ€π
π
=
π=1 π
1 β π ππ¨π det π¦π½ +
π
π¨ππ΅π
π¨1=β―=π¨π=0
SLIDE 112 Proof of Master Real- Rootedness Theorem
Suppose π€1, β¦ , π€π are independent random vectors with π΅π β π½π€ππ€π
π. Then
π½det π¦π½ β
π
π€ππ€π
π
=
π=1 π
1 β π ππ¨π det π¦π½ +
π
π¨ππ΅π
π¨1=β―=π¨π=0
SLIDE 113 Proof of Master Real- Rootedness Theorem
Suppose π€1, β¦ , π€π are independent random vectors with π΅π β π½π€ππ€π
π. Then
π½det π¦π½ β
π
π€ππ€π
π
=
π=1 π
1 β π ππ¨π det π¦π½ +
π
π¨ππ΅π
π¨1=β―=π¨π=0
SLIDE 114 Proof of Master Real- Rootedness Theorem
Suppose π€1, β¦ , π€π are independent random vectors with π΅π β π½π€ππ€π
π. Then
π½det π¦π½ β
π
π€ππ€π
π
=
π=1 π
1 β π ππ¨π det π¦π½ +
π
π¨ππ΅π
π¨1=β―=π¨π=0
SLIDE 115 The Whole Proof
π½det π¦π½ β π π€ππ€π
π is real-rooted for all indep. π€π.
SLIDE 116 The Whole Proof
π½det π¦π½ β π π€ππ€π
π is real-rooted for all indep. π€π.
π½ππ΅π‘(π β π¦) is real-rooted for all product distributions on signings.
SLIDE 117 The Whole Proof
π½det π¦π½ β π π€ππ€π
π is real-rooted for all indep. π€π.
π½ππ΅π‘(π¦) is real-rooted for all product distributions on signings.
SLIDE 118 The Whole Proof
π½det π¦π½ β π π€ππ€π
π is real-rooted for all indep. π€π.
π½ππ΅π‘(π¦) is real-rooted for all product distributions on signings. ππ΅π‘ π¦
π¦β Β±1 π is an interlacing family
SLIDE 119 The Whole Proof
π½det π¦π½ β π π€ππ€π
π is real-rooted for all indep. π€π.
such that π½ππ΅π‘(π¦) is real-rooted for all product distributions on signings. ππ΅π‘ π¦
π¦β Β±1 π is an interlacing family
SLIDE 120 3-Step Proof Strategy
- 1. Show that some poly does as well as the .
- 2. Calculate the expected polynomial.
- 3. Bound the largest root of the expected poly.
such that
ο ο ο
SLIDE 121 Infinite Sequences of Bipartite Ramanujan Graphs
Find an operation which doubles the size of a graph without blowing up its eigenvalues.
[ ]
d
[
]
2 π β 1
β¦ β
SLIDE 122 Main Theme
Reduced the existence of a good matrix to:
- 1. Proving real-rootedness of an
expected polynomial.
- 2. Bounding roots of the expected
polynomial.
SLIDE 123 Main Theme
Reduced the existence of a good matrix to:
- 1. Proving real-rootedness of an
expected polynomial. (general, using real stability)
- 2. Bounding roots of the expected
polynomial. (specific, using combinatorics)
SLIDE 124 Tomorrow
Reduced the existence of a good matrix to:
- 1. Proving real-rootedness of an
expected polynomial. (general, using real stability)
- 2. Bounding roots of the expected
polynomial. (general, using new method)
SLIDE 125 Tomorrow
Reduced the existence of a good matrix to:
- 1. Proving real-rootedness of an
expected polynomial. (general, using real stability)
- 2. Bounding roots of the expected
polynomial. (general, using new method)
major implications in combinatorics, linear algebra + 1959 Kadison-Singer Conjecture.
SLIDE 126 Tomorrow
Reduced the existence of a good matrix to:
- 1. Proving real-rootedness of an
expected polynomial. (general, using real stability)
- 2. Bounding roots of the expected
polynomial. (general, using new method)
major implications in combinatorics, linear algebra + 1959 Kadison-Singer Conjecture.