Forbidden subgraphs for constant domination number Michitaka Furuya - - PowerPoint PPT Presentation
Forbidden subgraphs for constant domination number Michitaka Furuya - - PowerPoint PPT Presentation
Forbidden subgraphs for constant domination number Michitaka Furuya (Kitasato University) Domination Let be a graph. A set is a dominating set of if for , s.t.
Let π» be a graph. A set π β π π» is a dominating set of π» if for β π¦ β π π» β π, β π§ β π s.t. π¦π§ β πΉ π» . The minimum cardinality of a dominating set of π» is called the domination number of π», and is denoted by πΏ π» .
Domination
Let π» be a graph. A set π β π π» is a dominating set of π» if for β π¦ β π π» β π, β π§ β π s.t. π¦π§ β πΉ π» . The minimum cardinality of a dominating set of π» is called the domination number of π», and is denoted by πΏ π» .
Domination
Domination
Let π» be a graph. A set π β π π» is a dominating set of π» if for β π¦ β π π» β π, β π§ β π s.t. π¦π§ β πΉ π» . The minimum cardinality of a dominating set of π» is called the domination number of π», and is denoted by πΏ π» . πΏ π» = 5
Domination
Theorem 1 (Ore, 1962) Let π» be a conn. graph of order π β₯ 2. Then πΏ π» β€ π/2. Theorem 2 (Fink et al., 1985; Payan and Xuong, 1982) A conn. graph π» of order π satisfies πΏ π» = π/2 if and only if π» = π·4 or π» is the corona of a conn. graph.
β¦ β¦
πΌ corona of πΌ
Domination
Theorem 1 (Ore, 1962) Let π» be a conn. graph of order π β₯ 2. Then πΏ π» β€ π/2. Theorem 2 (Fink et al., 1985; Payan and Xuong, 1982) A conn. graph π» of order π satisfies πΏ π» = π/2 if and only if π» = π·4 or π» is the corona of a conn. graph.
β¦ β¦
πΌ corona of πΌ
Forbidden subgraph
Let β be a set of conn. graphs. A graph π» is β-free if π» has no graph in β as an induced subgraph. (If π» is πΌ -free, then π» is simply said to be πΌ-free.) In this context, graphs in β are called forbidden subgraphs. πΏ1,3-free graph (πΏ1,3 : )
Forbidden subgraph
Let β be a set of conn. graphs. A graph π» is β-free if π» has no graph in β as an induced subgraph. (If π» is πΌ -free, then π» is simply said to be πΌ-free.) In this context, graphs in β are called forbidden subgraphs. Let β1 and β2 be sets of conn. graphs. We write β1 β€ β2 if for βπΌ2 β β2, βπΌ1 β β1 s.t. πΌ1 is an induced subgraph of πΌ2. Remark If β1 β€ β2, then every β1-free graph is β2-free.
Domination and forbidden subgraph
Theorem 3 (Cockayne et al., 1985) Let π» be a conn. {πΏ1,3, }-free graph of order π. Then πΏ π» β€ βπ/3β. Let πΏpr π» be the minimum cardinality of a dominating set π of π» s.t. π» π has a perfect matching. Theorem 4 (Dorbec et al., 2006) Let π» be a conn. πΏ1,π-free graph of order π β₯ 2. Then πΏpr π» β€ 2 ππ + 1 / 2π + 1 . Theorem 5 (Dorbec and Gravier, 2008) Let π» be a conn. π5-free graph of order π β₯ 2. If π» β π·5, then πΏpr π» β€ π/2 + 1.
Domination and forbidden subgraph
Theorem 3 (Cockayne et al., 1985) Let π» be a conn. {πΏ1,3, }-free graph of order π. Then πΏ π» β€ βπ/3β. Let πΏpr π» be the minimum cardinality of a dominating set π of π» s.t. π» π has a perfect matching. Theorem 4 (Dorbec et al., 2006) Let π» be a conn. πΏ1,π-free graph of order π β₯ 2. Then πΏpr π» β€ 2 ππ + 1 / 2π + 1 . Theorem 5 (Dorbec and Gravier, 2008) Let π» be a conn. π5-free graph of order π β₯ 2. If π» β π·5, then πΏpr π» β€ π/2 + 1.
Domination and forbidden subgraph
We focus on the most effective case, that is, sets β of connected graphs satisfying the following: β const. π = π β s.t. for β conn. β-free graph π», πΏ π» β€ π. What graphs do belong to β?? Let πΏπ+1
β
be the corona of πΏπ+1. Since πΏ πΏπ+1
β
= π + 1, πΏπ+1
β
is not β-free. β‘ βπΌ β β s.t. πΌ is an induced subgraph of πΏπ+1
β
. β‘ β β€ πΏπ+1
β
. By similar argument, β β€ , π3π+1 .
β¦
πΏπ+1
β¦
π + 1 πΏπ+1
β
οΌ
Domination and forbidden subgraph
We focus on the most effective case, that is, sets β of connected graphs satisfying the following: β const. π = π β s.t. for β conn. β-free graph π», πΏ π» β€ π. What graphs do belong to β?? Let πΏπ+1
β
be the corona of πΏπ+1. Since πΏ πΏπ+1
β
= π + 1, πΏπ+1
β
is not β-free. β‘ βπΌ β β s.t. πΌ is an induced subgraph of πΏπ+1
β
. β‘ β β€ πΏπ+1
β
. By similar argument, β β€ , π3π+1 .
β¦
πΏπ+1
β¦
π + 1 πΏπ+1
β
οΌ
Domination and forbidden subgraph
We focus on the most effective case, that is, sets β of connected graphs satisfying the following: β const. π = π β s.t. for β conn. β-free graph π», πΏ π» β€ π. What graphs do belong to β?? Let πΏπ+1
β
be the corona of πΏπ+1. Since πΏ πΏπ+1
β
= π + 1, πΏπ+1
β
is not β-free. β‘ βπΌ β β s.t. πΌ is an induced subgraph of πΏπ+1
β
. β‘ β β€ πΏπ+1
β
. By similar argument, β β€ , π3π+1 .
β¦
πΏπ+1
β¦
π + 1 πΏπ+1
β
οΌ
Main result
Theorem Let β be a set of conn. graphs. Then β const. π = π β s.t. for β conn. β-free graph π», πΏ π» β€ π if and only if β β€ πΏπ
β, ππ β, π π
for some positive integers π, π and π where πΏπ
β =
and ππ
β =
.
β¦
πΏπ
β¦
π
Outline of proof of main result
We show that πΏ π» β€ 1 +
2β€πβ€πβ2
π
π,π π π π, π
for βconn. πΏπ
β, ππ β, π π -free graph π», where
π
π,π π : = 1
π = 1 π π, π β 1 π
π,π π β 1 + 1 β 1
π β₯ 2 . Let π¦ β π π» , and let ππ = π§ β π π» βΆ dist π¦, π§ = π . Then π π» = 0β€πβ€πβ2 ππ. Key Lemma For π β₯ 2, the set ππ is dominated by at most π
π,π π π π, π vertices.
Outline of proof of main result
We show that πΏ π» β€ 1 +
2β€πβ€πβ2
π
π,π π π π, π
for βconn. πΏπ
β, ππ β, π π -free graph π», where
π
π,π π : = 1
π = 1 π π, π β 1 π
π,π π β 1 + 1 β 1
π β₯ 2 . Let π¦ β π π» , and let ππ = π§ β π π» βΆ dist π¦, π§ = π . Then π π» = 0β€πβ€πβ2 ππ. Key Lemma For π β₯ 2, the set ππ is dominated by at most π
π,π π π π, π vertices.
Outline of proof of main result
We show that πΏ π» β€ 1 +
2β€πβ€πβ2
π
π,π π π π, π
for βconn. πΏπ
β, ππ β, π π -free graph π», where
π
π,π π : = 1
π = 1 π π, π β 1 π
π,π π β 1 + 1 β 1
π β₯ 2 . Let π¦ β π π» , and let ππ = π§ β π π» βΆ dist π¦, π§ = π . Then π π» = 0β€πβ€πβ2 ππ. Key Lemma For π β₯ 2, the set ππ is dominated by at most π
π,π π π π, π vertices.
Suppose that ππ is independent. Let π β ππβ1 be a smallest set dominating ππ. If π is βlargeββ¦ ο¬ If βlarge clique π1 β π β¦ ο¬ If βlarge indep. set π2 β π β¦
Outline of proof of main result
π ππ ππβ1
β¦
π1
βπΏπ
β
π ππ ππβ1
β¦
π2
ππβ2
βππ
β
Suppose that ππ is independent. Let π β ππβ1 be a smallest set dominating ππ. If π is βlargeββ¦ ο¬ If βlarge clique π1 β π β¦ ο¬ If βlarge indep. set π2 β π β¦
Outline of proof of main result
π ππ ππβ1
β¦
π1
βπΏπ
β
π ππ ππβ1
β¦
π2
ππβ2
βππ
β
Extension of main result
Corollary Let π be an invariant of graphs s.t. π1πΏ π» β€ π π» β€ π2πΏ π» for β conn. graph π» of suff. large order.
- ---- (οΌ)
Let β be a set of conn. graphs. Then β const. π = π β s.t. for β conn. β-free graph π», π π» β€ π if and only if β β€ πΏπ
β, ππ β, π π
for some positive integers π, π and π. Many domination-like invariants satisfy (οΌ). (total domination πΏπ’, paired domination πΏpr, etcβ¦)
Extension of main result
Corollary Let π be an invariant of graphs s.t. π1πΏ π» β€ π π» β€ π2πΏ π» for β conn. graph π» of suff. large order.
- ---- (οΌ)
Let β be a set of conn. graphs. Then β const. π = π β s.t. for β conn. β-free graph π», π π» β€ π if and only if β β€ πΏπ
β, ππ β, π π