Flat solutions to the Cauchy-Riemann Equations Yuan Zhang Joint - - PowerPoint PPT Presentation

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Flat solutions to the Cauchy-Riemann Equations Yuan Zhang Joint - - PowerPoint PPT Presentation

Flat solutions to the Cauchy-Riemann Equations Yuan Zhang Joint with Y. Liu, Z. Chen and Y. Pan Indiana University - Purdue University Fort Wayne, USA Midwestern Workshop on Asymptotic Analysis Indiana University, Bloomington, IN October


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Flat solutions to the Cauchy-Riemann Equations

Yuan Zhang Joint with Y. Liu, Z. Chen and Y. Pan

Indiana University - Purdue University Fort Wayne, USA

Midwestern Workshop on Asymptotic Analysis Indiana University, Bloomington, IN

October 9-11th, 2015

Yuan Zhang (IPFW) Flat solutions 1 / 16

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Motivation - two Unique continuation Property (UCP) problems

Definition: A smooth function (or map) f is said to be flat (at 0) if Dαf (0) = 0 for all multi-indices α.

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Motivation - two Unique continuation Property (UCP) problems

Definition: A smooth function (or map) f is said to be flat (at 0) if Dαf (0) = 0 for all multi-indices α. DR:= {z ∈ C : |z| = R}. BR:= {z ∈ Cn : |z| = R}.

Theorem (Chanillo-Sawyer)

Let V ∈ L2(DR) and u : DR ⊂ R2 → RN be smooth. If |∆u| ≤ V |▽u|, then UCP holds, i.e., u ≡ 0 on DR whenever u is flat.

Theorem (Pan)

Let V ∈ L2(DR) and v : DR ⊂ C → CM be smooth. If |¯ ∂v| ≤ V |v|, then UCP holds, i.e., v ≡ 0 on DR whenever v is flat.

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Question

Question: Given a ¯ ∂-closed (0,1) form f near 0 ∈ Cn and flat at 0, does there always exist a flat function u such that ¯ ∂u = f locally?

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Question

Question: Given a ¯ ∂-closed (0,1) form f near 0 ∈ Cn and flat at 0, does there always exist a flat function u such that ¯ ∂u = f locally? The global version of the question (on BR): No!

Yuan Zhang (IPFW) Flat solutions 3 / 16

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Question

Question: Given a ¯ ∂-closed (0,1) form f near 0 ∈ Cn and flat at 0, does there always exist a flat function u such that ¯ ∂u = f locally? The global version of the question (on BR): No! Examples suggested by Bo-Yong Chen.

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Question

Question: Given a ¯ ∂-closed (0,1) form f near 0 ∈ Cn and flat at 0, does there always exist a flat function u such that ¯ ∂u = f locally? The global version of the question (on BR): No! Examples suggested by Bo-Yong Chen. What happens in the sense of germs (where f cannot be trivially 0 near 0)?

Yuan Zhang (IPFW) Flat solutions 3 / 16

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Criterion in C

Lemma

Let f be flat at 0 ∈ C. The following two statements are equivalent: 1) ¯ ∂u = fd¯ z has a flat solution locally. 2) There exists some neighborhood U of 0 such that the following series

  • n=0
  • U

f (ξ) ξn+1 d ¯ ξ ∧ dξ

  • zn

is holomorphic near 0.

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Sketch of the proof

Denote the Cauchy-Green operator by Tf (z) := −1

2πi

  • DR

f (ζ) ζ−z d ¯

ζ ∧ dζ. Then ¯ ∂Tf = fd¯ z on DR. Higher order derivative formulas of T on DR:

Theorem (Pan, preprint)

Let f ∈ C k+α(DR) with 0 < α < 1 and k ∈ Z+ ∪ {0}. Then ∂k+1T(f )(z) = −k! 2πi

  • DR

f (ζ) − Pk(ζ, z) (ξ − z)k+2 d ¯ ζ ∧ dζ

  • n DR, where Pk(ζ, z) is the Taylor expansion of f at z of degree k.

See [Liu-Pan-Z., 2015, preprint] for the higher order derivative formulas of T on general domains.

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Positive examples in C

Example

Let ϕ ∈ C ∞(R, C) be flat at 0 and g be harmonic on D. Then ¯ ∂u(z) = ϕ(|z|)g(z)d¯ z always has a flat solution locally.

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Counter-examples in C

The construction is essentially motivated by Rosay and Coffman-Pan. s: a nondecreasing function on R+, s = 0 in [0, 1

4], 0 < s < 1 on ( 1 4, 3 4)

and s = 1 on [ 3

4, ∞);

{rn}∞

n=1: a decreasing positive sequence, limn→∞ rn = 0. ∆rn := rn − rn+1,

annuli An := {z ∈ C : rn+1 ≤ |z| ≤ rn}; {p(n)}∞

n=0: an increasing positive integer sequence with p(0) = 0;

{F(n)}∞

n=0: a positive sequence with F(0) = 1.

Let gn(z) = F(n)zp(n), Xn = s( |·|−rn+1

∆rn

) : An → R, and f (z) =      gn(z), z ∈ An for odd n, Xn(z)gn−1(z) + (1 − Xn(z))gn+1(z), z ∈ An for even n, 0, z = 0.

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Lemma of Coffman-Pan

Lemma (Coffman-Pan)

If

(∆rn/rn) (∆rn+2)/(rn+2) is a bounded sequence and for each integer k ≥ 0,

lim

n→∞

F(n + 1)(p(n + 1))krp(n+1)−4k

n

(∆rn/rn)k = 0, then f is smooth and flat at the origin.

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The Family S

Denote by S the set of functions f such that

(∆rn/rn) (∆rn+2)/(rn+2) is bounded,

lim

n→∞

F(n + 1)(p(n + 1))krp(n+1)−4k

n

(∆rn/rn)k = 0, as well as either one of the following conditions: lim

n→∞

p(n)

  • F(n)∆rnrn+1 = ∞,

lim

n→∞

p(n)

  • F(n)(∆rn−1)2 = ∞,

lim

n→∞

p(n)

  • F(n)∆rn−1rn = ∞,

lim

n→∞

p(n)

  • F(n)(∆rn+1)2 = ∞,

lim

n→∞

p(n)

  • F(n)∆rn+1rn+2 = ∞.

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Examples in S

Example (Rosay)

R = 1, p(n) = n, rn = 2−n+1, F(n) = 2n2/2.

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Examples in S

Example (Rosay)

R = 1, p(n) = n, rn = 2−n+1, F(n) = 2n2/2.

Example

R = 1. p(n), t(n) and q(n) are polynomials of degree dp, dt and dq with positive leading coefficients, t(1) = 0, dq > dp, dq > dt and dq < dp + dt. Let rn := 2−t(n), F(n) := 2q(n).

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The main theorems

Theorem

For every f ∈ S, there does not exist a flat smooth u such that ¯ ∂u = fd¯ z near the origin.

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The main theorems

Theorem

For every f ∈ S, there does not exist a flat smooth u such that ¯ ∂u = fd¯ z near the origin.

Theorem

There exists a family of germs of ¯ ∂-closed (0,1) forms, flat at 0 ∈ Cn, such that for every f in this family, the Cauchy-Riemann equation ¯ ∂u = f has no flat solution in the sense of germs.

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  • rmander’s L2 theory

Theorem (H¨

  • rmander, Acta. Math., 1965)

Let Ω be a bounded pseudoconvex open set in Cn, Let δ be the diameter

  • f Ω, and let φ be a plurisubharmonic function in Ω. For every ¯

∂-closed f ∈ L2

(0,q)(Ω, φ), q > 0, one can find u ∈ L2 (0,q−1)(Ω, φ) satisfying ¯

∂u = f in Ω and q

|u|2e−φdV ≤ eδ2

|f |2e−φdV .

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  • rmander’s L2 theory

Theorem (H¨

  • rmander, Acta. Math., 1965)

Let Ω be a bounded pseudoconvex open set in Cn, Let δ be the diameter

  • f Ω, and let φ be a plurisubharmonic function in Ω. For every ¯

∂-closed f ∈ L2

(0,q)(Ω, φ), q > 0, one can find u ∈ L2 (0,q−1)(Ω, φ) satisfying ¯

∂u = f in Ω and q

|u|2e−φdV ≤ eδ2

|f |2e−φdV . When q = 1, a minimal solution to ¯ ∂u = f on Ω is the solution that is

  • rthogonal to the space of holomorphic functions with respect to L2(Ω, φ)

norm.

Yuan Zhang (IPFW) Flat solutions 12 / 16

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Is the restriction of a minimal solution minimal?

Ω1, Ω2: smooth bounded pseudoconvex domains, Ω2 ⊂ Ω1; φ: a bounded plurisubharmonic function in Ω1; f : a ¯ ∂-closed (0,1) form in Ω1. Consider the minimal solution u1 to ¯ ∂u = f , Ω1 with respect to L2(Ω1, φ) norm and the minimal solution u2 to ¯ ∂u = f |Ω2, Ω2 with respect to L2(Ω2, φ|Ω2) norm. Question: Is u2 = u1|Ω2?

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Is the restriction of a minimal solution minimal?

Ω1, Ω2: smooth bounded pseudoconvex domains, Ω2 ⊂ Ω1; φ: a bounded plurisubharmonic function in Ω1; f : a ¯ ∂-closed (0,1) form in Ω1. Consider the minimal solution u1 to ¯ ∂u = f , Ω1 with respect to L2(Ω1, φ) norm and the minimal solution u2 to ¯ ∂u = f |Ω2, Ω2 with respect to L2(Ω2, φ|Ω2) norm. Question: Is u2 = u1|Ω2? In general, No!

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Is the restriction of a minimal solution minimal?

Ω1, Ω2: smooth bounded pseudoconvex domains, Ω2 ⊂ Ω1; φ: a bounded plurisubharmonic function in Ω1; f : a ¯ ∂-closed (0,1) form in Ω1. Consider the minimal solution u1 to ¯ ∂u = f , Ω1 with respect to L2(Ω1, φ) norm and the minimal solution u2 to ¯ ∂u = f |Ω2, Ω2 with respect to L2(Ω2, φ|Ω2) norm. Question: Is u2 = u1|Ω2? In general, No! Examples?

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Examples

Examples: Let ˜ f ∈ S and consider f (z) := ˜ f (z1)d¯ z1. Conclusion: For every f above, any given bounded plurisubharmonic weight function φ on B1 and positive decreasing sequence rn(< 1) → 0, the minimal solution un to ¯ ∂u = f |Brn on Brn with respect to L2(Brn, φ|Brn) norm is not the restriction of u1 onto Brn.

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Examples

Examples: Let ˜ f ∈ S and consider f (z) := ˜ f (z1)d¯ z1. Conclusion: For every f above, any given bounded plurisubharmonic weight function φ on B1 and positive decreasing sequence rn(< 1) → 0, the minimal solution un to ¯ ∂u = f |Brn on Brn with respect to L2(Brn, φ|Brn) norm is not the restriction of u1 onto Brn. Sketch of the proof: If not, then for each N, when n is large enough,

  • Brn

|u1|2dV ≤ C

  • Brn

|un|2e−φdV ≤ Cr2

n

  • Brn

|f (z1)|2e−φdV ≤ Cr2

n

  • Brn

|f (z1)|2dV ≤ CrN

n .

⇒ u1 is flat. Contradiction!

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Positive examples

Inspired by an example of Z. B locki, we have Example: Let fj and g be holomorphic in BR such that g(0) = 0 and

∂g ∂zj = fj in BR. Then given any bounded and radially symmetric

plurisubharmonic weight φ on BR, u(z) = g(z)|Br is the minimal solution to ¯ ∂u(z) = fj(z)d¯ zj|Br in Br in L2(Br, φ|Br ) norm for every r ≤ R.

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Thank you!

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