Discrete mathematics
Bernadett Aradi 2019 Fall
Information on the course, teaching materials:
https://arato.inf.unideb.hu/aradi.bernadett/discretemath.html
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Discrete mathematics Bernadett Aradi 2019 Fall Information on the course, teaching materials: https://arato.inf.unideb.hu/aradi.bernadett/discretemath.html Bernadett Aradi Discrete mathematics 2019 Fall 1 / 85 Table of contents
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◮ it contains the natural number 1, ◮ for every element of A its successor is also in A,
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1 The sum of the first n natural numbers is n(n+1)
2 x + 1
3 Prove that
4 Prove that
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1 ∀a = 0, a ∈ Z : a|0, 1|a, a|a 2 If a|b and c ∈ Z, then a|bc. (a|b ∧ c ∈ Z ⇒ a|bc) 3 If a|b1 and a|b2, then a|(b1 + b2). 4 If a|b and b|c, then a|c. 5 If a|b and b|a, then a = ±b. 2 ´
3 ⇒ If a|bi, i = 1, 2, . . . , n and c1, c2, . . . , cn ∈ Z, then
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1 If a ≡ b and c ≡ d (mod m), then
2 If a · c ≡ b · c (mod m) and gcd(c, m) = 1, then a ≡ b.
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1 What is the algebraic form of the complex number which has absolute
2 What is the trigonometric form of z =
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n
n
n
3
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n
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1 R2: the vectors of the plane. Elements: ordered pairs (x, y), x, y ∈ R. 2 Rn, its elements: ordered n-tuples: (x1, x2, . . . , xn), xi ∈ R.
1 {0} and V are linear subspaces of V , called trivial subspaces. 2 In R2 the elements of the form (x, 0) constitute a subspace (x ∈ R). 3 If v is a fixed vector is R2, then W = {λv ∈ V | λ ∈ R} is a subspace. Bernadett Aradi Discrete mathematics 2019 Fall 51 / 85
1 V = R2, v = (2, 1), w = (0, 3).
2 Let us fix a vector v = 0, linear combinations: vectors of the form λv.
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1 If two (or more) of the vectors are the same, then the vectors are
2 If one of the vectors is a scalar multiple of another vector, then the
3 If the zero vector is among the vectors, then the vectors are linearly
4 If a subset of the vectors is linearly dependent, then the entire set is
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1 Rn: vector space of n-tuples. (Vector addition, scalar multiplication
2 R2: special case of previous example (n = 2). Natural basis: {e1, e2},
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1 n = 2: det(A) = |A| = a11a22 − a12a21. 2 n = 3: det(A) = . . . .
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1 The rule of Sarrus: only for 2 × 2 and 3 × 3 determinants 2 Gaussian elimination (or row reduction): The modifications below
◮ If we multiply the determinant by a non-zero scalar, instead of
◮ If we add a scalar multiple of a a row to another row. ◮ If we interchange two rows, the determinant changes sign. 3 Laplace expansion: We choose an arbitrary row or column of the
◮ Cij is the cofactor of A corresponding to the element aij, that is,
◮ Aij is the (n − 1) × (n − 1) determinant obtained from A by deleting
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◮ determined if there is exactly 1 solution; ◮ undetermined if there are more than 1 solutions;
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