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CS 310 - Advanced Data Structures and Algorithms Basic Data Structures June 5, 2017 Tong Wang UMass Boston CS 310 June 5, 2017 1 / 22 Basic Data Structures Array Dynamic Array (amortized analysis) LinkedList Stack Queue Set Map Tong


  1. CS 310 - Advanced Data Structures and Algorithms Basic Data Structures June 5, 2017 Tong Wang UMass Boston CS 310 June 5, 2017 1 / 22

  2. Basic Data Structures Array Dynamic Array (amortized analysis) LinkedList Stack Queue Set Map Tong Wang UMass Boston CS 310 June 5, 2017 2 / 22

  3. Array Many advantages over linked list Constant-time access for any index Space efficiency: all space is used for data Restriction: Inserting a new element in an array of elements is expensive Once allocated, an array has a fixed length Solution: dynamic array Tong Wang UMass Boston CS 310 June 5, 2017 3 / 22

  4. Dynamic Array Initialize an array with one element Before inserting a new element (at the end), if the array is full Allocate a new array of twice the length Copy the existing elements to the new array Then proceed with insertion Tong Wang UMass Boston CS 310 June 5, 2017 4 / 22

  5. Amortized analysis What is the time complexity of insertion for a dynamic array? Amortized analysis is a strategy for analyzing a sequence of operations to show that the average cost per operation is small, even though a single operation within the sequence might be expensive. It gives us a worst-case bound on the cost of an algorithm. Aggregate method Accounting method Tong Wang UMass Boston CS 310 June 5, 2017 5 / 22

  6. Aggregate method The cost of the i-th insertion is � i if i − 1 is a power of 2 c i = 1 otherwise i 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 c i 1 2 3 1 5 1 1 1 9 1 1 1 1 1 1 1 17 The total cost of n insertions is ⌊ log n ⌋ n � � 2 j c i ≤ n + i =1 j =0 < n + 2 n = 3 n The average cost of one insertion is 3 Tong Wang UMass Boston CS 310 June 5, 2017 6 / 22

  7. Accounting Method We will say that the amortized cost for the ith insertion is 3 dollars, and this works as follows: One dollar pays for inserting the element itself. One dollar is stored to move the element later when the array is doubled One dollar is stored to move an element in the array that was already moved from previous array For instance, the size of the array is m immediately after expansion. So the number of elements in the array is m / 2. If we charge 3 dollars for each insertion, then by the time the array is filled up again, we will have 2( m / 2) extra dollars, which pays for moving all the elements to the new array. Tong Wang UMass Boston CS 310 June 5, 2017 7 / 22

  8. Time Complexities of Array Operations Let n be the length of the array Access element of index i , O (1) Insert at the end Amortized O (1) by using dynamic array Insert anywhere (to maintain the array as sorted) Best case O (1) Worst case O ( n ) Average case O ( n ) Delete at the end O (1) Delete anywhere Best case O (1) Worst case O ( n ) Average case O ( n ) Tong Wang UMass Boston CS 310 June 5, 2017 8 / 22

  9. Linked List A linked list is an ordered sequence of elements: A 0 , A 1 , A 2 , . . . , A n − 1 Simplest form: singly linked, with a pointer to the head of the list, not sorted Rarely maintained as sorted Variations: doubly linked, two pointers (head and tail), circular If the size of an element is large, a linked list may be a better choice than an array Tong Wang UMass Boston CS 310 June 5, 2017 9 / 22

  10. Definition for singly-linked list /* Java version */ public class ListNode { int val; ListNode next; ListNode(int x) val = x; } /* Python version */ class ListNode(object): { def init (self, x): self.val = x self.next = None } Tong Wang UMass Boston CS 310 June 5, 2017 10 / 22

  11. Basic Operations Insertion Inserting B between A and C: B.next = C A.next = B Deletion Deleting B: A.next = B.next Find while(head != null) { if(head.val == val) return head; head = head.next; } Reverse while(currNode != null) { nextNode = curNode.next curNode.next = prevNode prevNode = curNode curNode = nextNode } Tong Wang UMass Boston CS 310 June 5, 2017 11 / 22

  12. Time Complexities of Linked List Operations Insert (at the front): O (1) Find Best case O (1) Worst case O ( n ) Average case O ( n ) Delete Best case O (1) Worst case O ( n ) Average case O ( n ) Tong Wang UMass Boston CS 310 June 5, 2017 12 / 22

  13. Remove the Nth node from end of list //two pointers def removeNthFromEnd(head, n): fast = slow = head for in range(n): fast = fast.next if not fast: return head.next while fast.next: fast = fast.next slow = slow.next slow.next = slow.next.next return head Tong Wang UMass Boston CS 310 June 5, 2017 13 / 22

  14. Stacks Stacks support two operations Push Pop Retrieval from stacks is last-in, first-out (LIFO) Stacks can be easily implemented by either arrays or linked lists Applications: reversing a word, ”undo” mechanism in text editors, matching braces, etc. Tong Wang UMass Boston CS 310 June 5, 2017 14 / 22

  15. Example: Valid Parentheses Given a string containing just the characters ’(’, ’)’, ’ { ’, ’ } ’, ’[’ and ’]’, determine if the input string is valid. Valid: ’ { [()] } ()’ Invalid: ’[(])’ Tong Wang UMass Boston CS 310 June 5, 2017 15 / 22

  16. Valid Parentheses def isValid(s): stack = [] for x in s: if x == ’(’ or x == ’ { ’ or x == ’[’: stack.append(x) # )] } else: if not stack: return False else: top = stack.pop() if not (top == ’(’ and x == ’)’ or top == ’[’ and x == ’]’ or top == ’ { ’ and x == ’ } ’): return False return stack = [] Tong Wang UMass Boston CS 310 June 5, 2017 16 / 22

  17. Queues Queues support two operations Enqueue Dequeue Retrieval from queues is first-in, first-out (FIFO) Queues can be easily implemented by either arrays or linked lists Applications: Breadth first search, CPU scheduling, resource is shared among multiple consumers Tong Wang UMass Boston CS 310 June 5, 2017 17 / 22

  18. Sets A set contains a number of elements, with no duplicates and no order Examples A = { 1, 5, 3, 96 } B = { 17, 5, 1, 96 } C= { “Mary”, “contrary”, “quite” } Incorrect: { “Mary”, “contrary”, “quite”, “Mary” } Tong Wang UMass Boston CS 310 June 5, 2017 18 / 22

  19. Map Also known as dictionary , associative array Range Domain Given two sets, Domain and Range, like a math function, each domain element has exactly one range element associated with it Two arrows can land on the same range element, but one domain element cannot have two arrows out of it Tong Wang UMass Boston CS 310 June 5, 2017 19 / 22

  20. Basic operations Mapping creates pairs of < DomainType, RangeType > < key, value > pairs Basic operations put: add a key-value pair to a Map get: look up the value of a key Tong Wang UMass Boston CS 310 June 5, 2017 20 / 22

  21. Map Example ’A’ → “excellent” Descriptions of grades: ’B’ → “good” ’C’ → “ok” DomainType is char, and RangeType is string Each of these is a key-value pair, or just pair (’A’, “excellent”) is a pair of the grade ’A’ (key) and the phrase “excellent” (value) The whole mapping is the set of these 3 pairs M = { (’A’, “excellent”), (’B’, “good”), (’C’, “ok”) } – a map is a set of pairs, or “associations” Note that not every collection of pairs makes a proper map: M qualifies as a map only if the collection of keys has no duplicates Tong Wang UMass Boston CS 310 June 5, 2017 21 / 22

  22. Map Example In almost all natural langue processing (NLP) tasks, it is common to have these maps: id2word: map id to a word word2id: map a word to its id word2count: map a word to its count in the corpus Example: Words: “NLP is a field of CS ” Ids: [1098, 17, 1, 922, 390, 2001] Words: “NLP is also a field of AI” Ids: [1098, 17, 9, 1, 922, 390, 1922] Tong Wang UMass Boston CS 310 June 5, 2017 22 / 22

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