Covering Graphs and Linear Extensions of Signed Posets Eric - - PowerPoint PPT Presentation

covering graphs and linear extensions of signed posets
SMART_READER_LITE
LIVE PREVIEW

Covering Graphs and Linear Extensions of Signed Posets Eric - - PowerPoint PPT Presentation

Covering Graphs and Linear Extensions of Signed Posets Eric Fawcett, Torey Hilbert, Mikey Reilly Joint work with Jake Huryn, Kat Husar and Hannah Johnson under Dr. Sergei Chmutov The Ohio State University August 14th, 2020 The Big Picture


slide-1
SLIDE 1

Covering Graphs and Linear Extensions of Signed Posets

Eric Fawcett, Torey Hilbert, Mikey Reilly

Joint work with Jake Huryn, Kat Husar and Hannah Johnson under Dr. Sergei Chmutov

The Ohio State University

August 14th, 2020

slide-2
SLIDE 2

The Big Picture

Stanley’s work in [1]: This presentation:

slide-3
SLIDE 3

(Unsigned) Graphs and Orientations

A graph G is a set of vertices V with edges E connecting vertices. An orientation τ on the edges assigns each edge a direction. An

  • rientation is acyclic if every cycle has a sink or a source.
slide-4
SLIDE 4

(Unsigned) Posets Associated to Acyclic Orientations

A poset P is a set with a partial order <P (written < when there’s no ambiguity). Partial orders are transitive and antisymmetric. We can define a poset from an acyclic orientation τ by letting u <τ v when an edge points from u to v.

slide-5
SLIDE 5

(Unsigned) Linear Extension

Given a poset P, a linear extension P∗ is a total order which preserves P. Namely for any u = v ∈ P∗:

  • 1. Either u <P∗ v or v <P∗ u
  • 2. If u <P v, then u <P∗ v
slide-6
SLIDE 6

Signed Graphs and Orientations [Zaslavsky [2]]

A signed graph Σ is a graph where every edge is given a sign ±1. An orientation τ now assigns to each half edge (i.e. the part of the edge next to a vertex) an arrow such that:

  • 1. For positive edges the arrows face the same direction
  • 2. For negative edges they face opposite directions

An orientation is acyclic if every cycle has a source or a sink.

slide-7
SLIDE 7

Do Signed Acyclic Orientations define a Poset?

For positive edges, we have no issues. However, for negative edges, it’s unclear which edge is bigger in the poset. For example, if the arrows on edge (u, v) point both into u and into v, then neither u <τ v nor v <τ u. But then we’re ignoring all of the negative edges from our poset!

slide-8
SLIDE 8

The Root System Approach [Reiner [3]]

Instead of writing vi <P vj, we use the vector ej − ei. If we have n elements in our poset, then these vectors live in Rn. For negative edges where both arrows point into the vertices, we then have no problem writing ej + ei ∈ Rn.

slide-9
SLIDE 9

The An Root System

For (unsigned) posets, we use the An root system, Φ = Φ+ ∪ −Φ+, where Φ+ = {ei − ej | 1 ≤ i < j ≤ n} For the orientation shown below, the arrow pointing from v2 to v1 tells us e1 − e2 ∈ P. Furthermore, P = { e1 − e2, e2 − e3, e1 − e3 }

slide-10
SLIDE 10

The Bn Root System

For signed posets, the vectors live in the Bn root system, Φ = Φ+ ∪ −Φ+, where Φ+ = {e1, e2, ..., en} ∪ {ei − ej | 1 ≤ i < j ≤ n} ∪ {ei + ej | 1 ≤ i < j ≤ n} Some examples of elements in Φ: ◮ e7, e2 − e4, e3 + e17 ∈ Φ+ ◮ −e7, e4 − e2, −e3 − e17 ∈ −Φ+.

slide-11
SLIDE 11

Signed Posets

A subset P± ⊆ Φ is a (signed) poset if it satisfies:

  • 1. If v ∈ P± then −v /

∈ P±

  • 2. For v, u ∈ P± and a, b ≥ 0, if w = av + bu ∈ Φ, then w ∈ P±
slide-12
SLIDE 12

Signed Poset Example

In the orientation of graph below, the visible edges give us: P± = { e1 − e4, e1 + e3, e4 − e2, −e3 − e4 } Additionally, we have a implied edges e1 − e2 and −e3 − e2.

slide-13
SLIDE 13

B-Symmetric Signed Permutations

A B-Symmetric signed permutation is a bijective function π : {−n, ..., n} \ {0} → {−n, ..., n} \ {0} such that π(i) = −π(−i). Notice that this condition means it suffices to specify where the first n positive integers map to define the function. Example: π =

  • −2

−1 1 2 1 −2 2 −1

  • 1

2 2 −1

slide-14
SLIDE 14

The Jordan-H¨

  • lder Set

Given a signed poset P± on n elements, the Jordan-H¨

  • lder set is

denoted L (P±) where L (P±) = {π ∈ Bn : P± ⊆ πΦ+} where π(ei) = sign(π(i))e|π(i)|.

slide-15
SLIDE 15

Jordan-H¨

  • lder Set Example
slide-16
SLIDE 16

Covering Graphs

Given an oriented signed graph Σ(V , E, τ), the covering graph Σ(V ′, E ′, τ ′) is created as follows:

  • 1. For each v ∈ V , +v, −v ∈ V ′
  • 2. If vivj ∈ E is a positive edge, then +vi + vj, −vi − vj ∈ E ′.
  • 3. If vivj ∈ E is a negative edge, then +vi − vj, −vi + vj ∈ E ′.
  • 4. The orientation at +vi is ”the same” as vi.
  • 5. The orientation at −vi is ”the opposite” as vi
slide-17
SLIDE 17

Covering Graph Example

slide-18
SLIDE 18

Covering Relation to Root System

We can lift a signed poset on n vertices P± to an unsigned poset P on 2n vertices by the following:

  • 1. If i = j, (ǫiei − ǫjej) ∈ P± iff

(eǫii − eǫjj) ∈ P and (e−ǫjj − e−ǫii) ∈ P

  • 2. if ei ∈ P± then ei − e−i ∈ P
  • 3. if−ei ∈ P± then e−i − ei ∈ P

where e±1, ..., e±n form an orthonormal basis of R2n.

slide-19
SLIDE 19

Example of Lifting Signed Poset

slide-20
SLIDE 20

Motivating Example

slide-21
SLIDE 21

Theorem

Theorem

For a signed poset P±, which is associated with a signed graph Σ, every B-Sym linear extension of the covering graph of Σ can be associated with exactly one signed permutation in L (P±) and vice versa. Specifically, for a linear extension, β, of the covering graph of Σ we can associate β with a signed permutation πβ which has the property that if β(ǫvk) = n-i+1, where ǫ ∈ {+, −} and n is the number of vertices, then πβ(i) = ǫk. The theorem states that every πβ is an element of L (P±) and every π ∈ L (P±) has π = πβ for some β which is a B-Sym linear extension of Σ.

slide-22
SLIDE 22

Motivating Example

slide-23
SLIDE 23

Intuition

It is often more useful to think about the equivalent condition π−1P± ⊂ Φ+ π−1(k) = ǫi where β(ǫvk) = n − i + 1, i.e. ǫvk is the ith greatest element under β. Φ+ = {ei} ∪ {e1 − e2, e1 − e3, . . . , e1 − en, e2 − e3, e2 − e4, . . . , } ∪ {e1 + e2, e1 + e3, . . . , e1 + en, e2 + e3, e2 + e4, . . . , } If we consider Φ+ as a poset, then the element represented by e1 would be maximal, the element represented by e2 would be next maximal and so on. Therefore it makes sense to consider π such that π−1 sends the maximal element of P to 1 and so on.

slide-24
SLIDE 24

Acknowledgements

Thank you to: ◮ The YMC ◮ Dr. Sergei Chumtov ◮ Jake Huryn ◮ Kat Husar ◮ Hannah Johnson ◮ The audience

slide-25
SLIDE 25

References

R.P. Stanley. A symmetric function generalization of the chromatic polynomial of a graph. Advances in Mathematics, 111(1):166 – 194, 1995. Thomas Zaslavsky. Signed graph coloring. Discrete Mathematics, 39(2):215 – 228, 1982. Victor Reiner. Signed posets. Journal of Combinatorial Theory, Series A, 62(2):324 – 360, 1993.