Colouring the Plane G. Eric Moorhouse Department of Mathematics - - PowerPoint PPT Presentation

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Colouring the Plane G. Eric Moorhouse Department of Mathematics - - PowerPoint PPT Presentation

Colouring the Plane G. Eric Moorhouse Department of Mathematics University of Wyoming Designs, Codes & Geometries 2010 G. Eric Moorhouse Colouring the Plane Chromatic Number of the Euclidean Plane Consider the Euclidean plane R 2 to be a


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SLIDE 1

Colouring the Plane

  • G. Eric Moorhouse

Department of Mathematics University of Wyoming

Designs, Codes & Geometries 2010

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 2

Chromatic Number of the Euclidean Plane

Consider the Euclidean plane R2 to be a graph with adjacency defined by the distance-one relation (x, y) ∼ (x′, y ′) iff (x′ − x)2 + (y ′ − y)2 = 1. The chromatic number χ(R2) is the minimum number of colours needed to colour the points of R2 such that no two points at distance one bear the same colour. Known: χ(R2) ∈ {4, 5, 6, 7} χ(R2) 4 as seen from the Moser spindle:

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 3

Chromatic Number of the Euclidean Plane

Consider the Euclidean plane R2 to be a graph with adjacency defined by the distance-one relation (x, y) ∼ (x′, y ′) iff (x′ − x)2 + (y ′ − y)2 = 1. The chromatic number χ(R2) is the minimum number of colours needed to colour the points of R2 such that no two points at distance one bear the same colour. Known: χ(R2) ∈ {4, 5, 6, 7} χ(R2) 4 as seen from the Moser spindle:

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 4

Chromatic Number of the Euclidean Plane

Consider the Euclidean plane R2 to be a graph with adjacency defined by the distance-one relation (x, y) ∼ (x′, y ′) iff (x′ − x)2 + (y ′ − y)2 = 1. The chromatic number χ(R2) is the minimum number of colours needed to colour the points of R2 such that no two points at distance one bear the same colour. Known: χ(R2) ∈ {4, 5, 6, 7} χ(R2) 4 as seen from the Moser spindle:

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 5

Chromatic Number of the Euclidean Plane

Consider the Euclidean plane R2 to be a graph with adjacency defined by the distance-one relation (x, y) ∼ (x′, y ′) iff (x′ − x)2 + (y ′ − y)2 = 1. The chromatic number χ(R2) is the minimum number of colours needed to colour the points of R2 such that no two points at distance one bear the same colour. Known: χ(R2) ∈ {4, 5, 6, 7} χ(R2) 4 as seen from the Moser spindle:

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 6
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SLIDE 7

Chromatic Number of the Affine Plane K 2

Let K be an arbitrary field (or any commutative ring with 1). Adjacency in K 2: (x, y) ∼ (x′, y ′) iff (x′ − x)2 + (y ′ − y)2 = 1. χ(F2

2 ) = 2

χ(F2

3 ) = 3

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 8

Chromatic Number of the Affine Plane K 2

Let K be an arbitrary field (or any commutative ring with 1). Adjacency in K 2: (x, y) ∼ (x′, y ′) iff (x′ − x)2 + (y ′ − y)2 = 1. χ(F2

2 ) = 2

χ(F2

3 ) = 3

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 9

Chromatic Number of the Affine Plane Q2

Consider the subring R = a

b : a, b ∈ Z, b is a product of primes ≡ 3 mod 4

  • ⊂ Q.

The connected component of (0, 0) in Q2 is R2. Note that R/2R ∼ = F

2 . There is a graph homomorphism R2 → F2 2 :

χ(R2) = 2 − → χ(F2

2 ) = 2

Since Q2 is a disjoint union of copies of R2, each of which is 2-colourable, so is Q2.

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 10

Chromatic Number of the Affine Plane Q2

Consider the subring R = a

b : a, b ∈ Z, b is a product of primes ≡ 3 mod 4

  • ⊂ Q.

The connected component of (0, 0) in Q2 is R2. Note that R/2R ∼ = F

2 . There is a graph homomorphism R2 → F2 2 :

χ(R2) = 2 − → χ(F2

2 ) = 2

Since Q2 is a disjoint union of copies of R2, each of which is 2-colourable, so is Q2.

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 11

Chromatic Number of the Affine Plane Q2

Consider the subring R = a

b : a, b ∈ Z, b is a product of primes ≡ 3 mod 4

  • ⊂ Q.

The connected component of (0, 0) in Q2 is R2. Note that R/2R ∼ = F

2 . There is a graph homomorphism R2 → F2 2 :

χ(R2) = 2 − → χ(F2

2 ) = 2

Since Q2 is a disjoint union of copies of R2, each of which is 2-colourable, so is Q2.

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 12

Chromatic Number of the Affine Plane Q2

Consider the subring R = a

b : a, b ∈ Z, b is a product of primes ≡ 3 mod 4

  • ⊂ Q.

The connected component of (0, 0) in Q2 is R2. Note that R/2R ∼ = F

2 . There is a graph homomorphism R2 → F2 2 :

χ(R2) = 2 − → χ(F2

2 ) = 2

Since Q2 is a disjoint union of copies of R2, each of which is 2-colourable, so is Q2.

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 13

χ(R2) = χ(K 2) for a small subfield K ⊆ R

By a theorem of de Bruijn and Erdös, χ(R2) = χ(Γ) for some finite subgraph Γ ⊂ R2. Let K ⊂ R be the subfield generated by the coordinates of all vertices in K. So χ(R2) = χ(K 2) where the subfield K ⊂ R is finitely generated over Q. In particular K is countable. In fact we may reduce further to the case K is a number field:

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 14

χ(R2) = χ(K 2) for a small subfield K ⊆ R

By a theorem of de Bruijn and Erdös, χ(R2) = χ(Γ) for some finite subgraph Γ ⊂ R2. Let K ⊂ R be the subfield generated by the coordinates of all vertices in K. So χ(R2) = χ(K 2) where the subfield K ⊂ R is finitely generated over Q. In particular K is countable. In fact we may reduce further to the case K is a number field:

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 15

χ(R2) = χ(K 2) for a small subfield K ⊆ R

By a theorem of de Bruijn and Erdös, χ(R2) = χ(Γ) for some finite subgraph Γ ⊂ R2. Let K ⊂ R be the subfield generated by the coordinates of all vertices in K. So χ(R2) = χ(K 2) where the subfield K ⊂ R is finitely generated over Q. In particular K is countable. In fact we may reduce further to the case K is a number field:

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 16

χ(R2) = χ(K 2) for a finite extension K ⊃ Q

Theorem (M.) There exists a number field K embeddable in R and subfields K = Kn ⊃ Kn−1 ⊃ · · · ⊃ K1 ⊃ K0 ⊇ Q such that (a) χ(R2) = χ(K 2) (b) [Ki : Ki−1] = 2 for i = 1, 2, . . ., n (c) the extension K0 ⊇ Q is finite of odd degree [K0 : Q] (d) χ(K 2

0 ) = χ(Q2) = 2

Note that points of K 2 are straightedge-and-compass constructible from points of K 2

0 .

Does it make sense to colour by induction on n? Each ‘new’ point in K 2

i (i.e. not in K 2 i−1) has at most two neighbours in K 2 i−1.

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 17

χ(R2) = χ(K 2) for a finite extension K ⊃ Q

Theorem (M.) There exists a number field K embeddable in R and subfields K = Kn ⊃ Kn−1 ⊃ · · · ⊃ K1 ⊃ K0 ⊇ Q such that (a) χ(R2) = χ(K 2) (b) [Ki : Ki−1] = 2 for i = 1, 2, . . ., n (c) the extension K0 ⊇ Q is finite of odd degree [K0 : Q] (d) χ(K 2

0 ) = χ(Q2) = 2

Note that points of K 2 are straightedge-and-compass constructible from points of K 2

0 .

Does it make sense to colour by induction on n? Each ‘new’ point in K 2

i (i.e. not in K 2 i−1) has at most two neighbours in K 2 i−1.

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 18

χ(R2) = χ(K 2) for a finite extension K ⊃ Q

Theorem (M.) There exists a number field K embeddable in R and subfields K = Kn ⊃ Kn−1 ⊃ · · · ⊃ K1 ⊃ K0 ⊇ Q such that (a) χ(R2) = χ(K 2) (b) [Ki : Ki−1] = 2 for i = 1, 2, . . ., n (c) the extension K0 ⊇ Q is finite of odd degree [K0 : Q] (d) χ(K 2

0 ) = χ(Q2) = 2

Note that points of K 2 are straightedge-and-compass constructible from points of K 2

0 .

Does it make sense to colour by induction on n? Each ‘new’ point in K 2

i (i.e. not in K 2 i−1) has at most two neighbours in K 2 i−1.

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 19

Quadratic extensions

We are especially interested in how much the chromatic number can grow for quadratic extensions. Note: K 2 contains a 3-cycle iff K ⊇ Q( √ 3 ). χ(Q( √ 3 )2) = 3. K 2 contains a Moser spindle iff K ⊇ Q( √ 3, √ 11 ). χ(Q( √ 3, √ 11 )2) ∈ {4, 5, 6, 7}. What can we say about χ(K 2) when K = Q( √ d ), d 2 a squarefree integer?

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 20

Quadratic extensions

We are especially interested in how much the chromatic number can grow for quadratic extensions. Note: K 2 contains a 3-cycle iff K ⊇ Q( √ 3 ). χ(Q( √ 3 )2) = 3. K 2 contains a Moser spindle iff K ⊇ Q( √ 3, √ 11 ). χ(Q( √ 3, √ 11 )2) ∈ {4, 5, 6, 7}. What can we say about χ(K 2) when K = Q( √ d ), d 2 a squarefree integer?

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 21

Quadratic extensions

We are especially interested in how much the chromatic number can grow for quadratic extensions. Note: K 2 contains a 3-cycle iff K ⊇ Q( √ 3 ). χ(Q( √ 3 )2) = 3. K 2 contains a Moser spindle iff K ⊇ Q( √ 3, √ 11 ). χ(Q( √ 3, √ 11 )2) ∈ {4, 5, 6, 7}. What can we say about χ(K 2) when K = Q( √ d ), d 2 a squarefree integer?

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 22

Quadratic extensions

We are especially interested in how much the chromatic number can grow for quadratic extensions. Note: K 2 contains a 3-cycle iff K ⊇ Q( √ 3 ). χ(Q( √ 3 )2) = 3. K 2 contains a Moser spindle iff K ⊇ Q( √ 3, √ 11 ). χ(Q( √ 3, √ 11 )2) ∈ {4, 5, 6, 7}. What can we say about χ(K 2) when K = Q( √ d ), d 2 a squarefree integer?

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 23

Quadratic extensions

We are especially interested in how much the chromatic number can grow for quadratic extensions. Note: K 2 contains a 3-cycle iff K ⊇ Q( √ 3 ). χ(Q( √ 3 )2) = 3. K 2 contains a Moser spindle iff K ⊇ Q( √ 3, √ 11 ). χ(Q( √ 3, √ 11 )2) ∈ {4, 5, 6, 7}. What can we say about χ(K 2) when K = Q( √ d ), d 2 a squarefree integer?

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 24
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SLIDE 25

Quadratic extensions

We are especially interested in how much the chromatic number can grow for quadratic extensions. Note: K 2 contains a 3-cycle iff K ⊇ Q( √ 3 ). χ(Q( √ 3 )2) = 3. K 2 contains a Moser spindle iff K ⊇ Q( √ 3, √ 11 ). χ(Q( √ 3, √ 11 )2) ∈ {4, 5, 6, 7}. What can we say about χ(K 2) when K = Q( √ d ), d 2 a squarefree integer?

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 26

χ(F2

q) for finite fields Fq

Let O be the ring of algebraic integers in K. Let P ⊂ O be a prime ideal such that q = |O/P| ≡ 3 mod 4. (This exists since i / ∈ K.) Consider the subring R = a

b : a, b ∈ O, b /

∈ P

  • ⊂ O.

The connected component of (0, 0) in K 2 lies in R2. There is a graph homomorphism R2 → F2

q, so χ(R2) χ(F2 q).

Since K 2 is a disjoint union of copies of R2, we have χ(K 2) F2

q as well.

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 27

χ(F2

q) for finite fields Fq

Let O be the ring of algebraic integers in K. Let P ⊂ O be a prime ideal such that q = |O/P| ≡ 3 mod 4. (This exists since i / ∈ K.) Consider the subring R = a

b : a, b ∈ O, b /

∈ P

  • ⊂ O.

The connected component of (0, 0) in K 2 lies in R2. There is a graph homomorphism R2 → F2

q, so χ(R2) χ(F2 q).

Since K 2 is a disjoint union of copies of R2, we have χ(K 2) F2

q as well.

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 28

χ(F2

q) for finite fields Fq

Let O be the ring of algebraic integers in K. Let P ⊂ O be a prime ideal such that q = |O/P| ≡ 3 mod 4. (This exists since i / ∈ K.) Consider the subring R = a

b : a, b ∈ O, b /

∈ P

  • ⊂ O.

The connected component of (0, 0) in K 2 lies in R2. There is a graph homomorphism R2 → F2

q, so χ(R2) χ(F2 q).

Since K 2 is a disjoint union of copies of R2, we have χ(K 2) F2

q as well.

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 29

χ(F2

q) for finite fields Fq

Let O be the ring of algebraic integers in K. Let P ⊂ O be a prime ideal such that q = |O/P| ≡ 3 mod 4. (This exists since i / ∈ K.) Consider the subring R = a

b : a, b ∈ O, b /

∈ P

  • ⊂ O.

The connected component of (0, 0) in K 2 lies in R2. There is a graph homomorphism R2 → F2

q, so χ(R2) χ(F2 q).

Since K 2 is a disjoint union of copies of R2, we have χ(K 2) F2

q as well.

  • G. Eric Moorhouse

Colouring the Plane

slide-30
SLIDE 30

χ(F2

q) for finite fields Fq

F2

q is regular of degree

   q, for q even; q − 1, if q ≡ 1 mod 4; q + 1, if q ≡ 3 mod 4. If q is even, then F2

q is a disjoint union of q/2 complete bipartite

graphs Kq,q, and χ(F2

q) = 2.

If q is odd, then χ(F2

q) 3.

If q ≡ ±1 mod 12, then χ(F2

q) 4.

q 3 5 7 9 11 13 17 χ(F2

q)

3 3 4 3 5 5 or 6 5, 6 or 7 Similar computations have been done by Sebastian Cioab˘ a and Jason Williford.

  • G. Eric Moorhouse

Colouring the Plane

slide-31
SLIDE 31

χ(F2

q) for finite fields Fq

F2

q is regular of degree

   q, for q even; q − 1, if q ≡ 1 mod 4; q + 1, if q ≡ 3 mod 4. If q is even, then F2

q is a disjoint union of q/2 complete bipartite

graphs Kq,q, and χ(F2

q) = 2.

If q is odd, then χ(F2

q) 3.

If q ≡ ±1 mod 12, then χ(F2

q) 4.

q 3 5 7 9 11 13 17 χ(F2

q)

3 3 4 3 5 5 or 6 5, 6 or 7 Similar computations have been done by Sebastian Cioab˘ a and Jason Williford.

  • G. Eric Moorhouse

Colouring the Plane

slide-32
SLIDE 32

χ(F2

q) for finite fields Fq

F2

q is regular of degree

   q, for q even; q − 1, if q ≡ 1 mod 4; q + 1, if q ≡ 3 mod 4. If q is even, then F2

q is a disjoint union of q/2 complete bipartite

graphs Kq,q, and χ(F2

q) = 2.

If q is odd, then χ(F2

q) 3.

If q ≡ ±1 mod 12, then χ(F2

q) 4.

q 3 5 7 9 11 13 17 χ(F2

q)

3 3 4 3 5 5 or 6 5, 6 or 7 Similar computations have been done by Sebastian Cioab˘ a and Jason Williford.

  • G. Eric Moorhouse

Colouring the Plane

slide-33
SLIDE 33

χ(F2

q) for finite fields Fq

F2

q is regular of degree

   q, for q even; q − 1, if q ≡ 1 mod 4; q + 1, if q ≡ 3 mod 4. If q is even, then F2

q is a disjoint union of q/2 complete bipartite

graphs Kq,q, and χ(F2

q) = 2.

If q is odd, then χ(F2

q) 3.

If q ≡ ±1 mod 12, then χ(F2

q) 4.

q 3 5 7 9 11 13 17 χ(F2

q)

3 3 4 3 5 5 or 6 5, 6 or 7 Similar computations have been done by Sebastian Cioab˘ a and Jason Williford.

  • G. Eric Moorhouse

Colouring the Plane

slide-34
SLIDE 34

χ(F2

q) for finite fields Fq

F2

q is regular of degree

   q, for q even; q − 1, if q ≡ 1 mod 4; q + 1, if q ≡ 3 mod 4. If q is even, then F2

q is a disjoint union of q/2 complete bipartite

graphs Kq,q, and χ(F2

q) = 2.

If q is odd, then χ(F2

q) 3.

If q ≡ ±1 mod 12, then χ(F2

q) 4.

q 3 5 7 9 11 13 17 χ(F2

q)

3 3 4 3 5 5 or 6 5, 6 or 7 Similar computations have been done by Sebastian Cioab˘ a and Jason Williford.

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 35

χ(K 2) for quadratic extensions K ⊃ Q

Theorem (M.) Let K = Q( √ d ), d 2 a squarefree integer. If d ≡ 47, 59 or 83 mod 84, then χ(K 2) 4. What about χ(Q( √ 47 )2)?

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 36

χ(K 2) for quadratic extensions K ⊃ Q

Theorem (M.) Let K = Q( √ d ), d 2 a squarefree integer. If d ≡ 47, 59 or 83 mod 84, then χ(K 2) 4. What about χ(Q( √ 47 )2)?

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 37

Other subfields K ⊆ C

Apparently open question: Is χ(C2) < ∞? Theorem (M.) Let K be a number field. Then (a) K 2 is disconnected iff i ∈ K where i = √ −1. (b) If i / ∈ K then χ(K 2) < ∞. Is χ(K 2) < ∞ where K = Q(i), i = √ −1?

  • G. Eric Moorhouse

Colouring the Plane

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SLIDE 38

Other subfields K ⊆ C

Apparently open question: Is χ(C2) < ∞? Theorem (M.) Let K be a number field. Then (a) K 2 is disconnected iff i ∈ K where i = √ −1. (b) If i / ∈ K then χ(K 2) < ∞. Is χ(K 2) < ∞ where K = Q(i), i = √ −1?

  • G. Eric Moorhouse

Colouring the Plane

slide-39
SLIDE 39

Other subfields K ⊆ C

Apparently open question: Is χ(C2) < ∞? Theorem (M.) Let K be a number field. Then (a) K 2 is disconnected iff i ∈ K where i = √ −1. (b) If i / ∈ K then χ(K 2) < ∞. Is χ(K 2) < ∞ where K = Q(i), i = √ −1?

  • G. Eric Moorhouse

Colouring the Plane