Class 20: Work and kinetic energy Test 2 1. Next Wednesday (March 4) - - PowerPoint PPT Presentation

class 20 work and kinetic energy test 2
SMART_READER_LITE
LIVE PREVIEW

Class 20: Work and kinetic energy Test 2 1. Next Wednesday (March 4) - - PowerPoint PPT Presentation

Class 20: Work and kinetic energy Test 2 1. Next Wednesday (March 4) 11:00 11:50 in this class room. 2. Newtons Law of gravitation, Hookes Law, Newtons Law of motion. 3. No formula or cheat sheet. 4. 8 multiple choice problems (5


slide-1
SLIDE 1

Class 20: Work and kinetic energy

slide-2
SLIDE 2

Test 2

  • 1. Next Wednesday (March 4) 11:00‐11:50 in this class

room.

  • 2. Newton’s Law of gravitation, Hooke’s Law, Newton’s Law
  • f motion.
  • 3. No formula or cheat sheet.
  • 4. 8 multiple choice problems (5 points each) and 2 long (30

points each) problems. Total 100 points.

  • 5. Calculators allowed, but not the program function (though

I don’t think it will help).

  • 6. Please bring photo ID.
  • 7. No reschedule of test even though you have more than

two tests that day.

  • 8. Classwork Monday will be 8 multiple choices on the test

materials.

slide-3
SLIDE 3

Problem solved? Problem is solve if we know F as a function of time. If we can solve the differential equations, we will know the position and velocity of the particle at any time.

z dt d m F y dt d m F x dt d m F

2 2 z 2 2 y 2 2 x

     

slide-4
SLIDE 4

The problem In most cases we live in a “force field” – there is always a force acting on us and this force depends on where we are.

x

z dt d m F y dt d m F x dt d m F

2 2 z 2 2 y 2 2 x

     

slide-5
SLIDE 5

Acceleration by chain rule (1D)

If we know the velocity as a function of time, we can differentiate it w.r.t. time and find out how the acceleration depends on time:

dt dv a

x 

However, very often we only know the velocity as a function of position (i.e. coordinate x). What to do in this case?

dx dv v a dx dv dt dx dt dv a

x x

   

slide-6
SLIDE 6

The answer

In most cases we live in a “force field” – there is always a force acting on us and this force depends on where we are.

x

dx F mv 2 1

  • mv

2 1 F v dx d v m v dx d m F x dt d m F

x x x 2 xi 2 xf x x x x x 2 2 x

f i

              

slide-7
SLIDE 7

3D

dz F mv 2 1

  • mv

2 1 dy F mv 2 1

  • mv

2 1 dx F mv 2 1

  • mv

2 1

z z z 2 iz 2 fz y y y 2 iy 2 fy x x x 2 ix 2 fx

f i f i f i

  

                    

+

                

  

dz F dy F dx F mv 2 1

  • mv

2 1

z z z y y y x x x 2 i 2 f

f i f i f i

slide-8
SLIDE 8

Work (abbreviation: W)

dz F dy F dx F F

z z z y y y x x x

f i f i f i

  

   

Work done W by a force

  • 1. Work is a scalar (sum of definite integrals) – it has no

direction.

  • 2. Unit of work: Joule (J). Joule is not a fundamental

unit, J  Nm  Kgm2s‐2.

  • 3. Work done by a force can be positive, negative, or 0.