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Borsuk-Ulam in real-cohesive homotopy type theory Daniel Cicala, - PowerPoint PPT Presentation

Borsuk-Ulam in real-cohesive homotopy type theory Daniel Cicala, University of New Haven Amelia Tebbe, Indiana University Kokomo Chandrika Sadanand, University of Illinois Urbana Champaign 1 Thanks to 2017 MRC in HoTT program Mike Shulman for


  1. Borsuk-Ulam in real-cohesive homotopy type theory Daniel Cicala, University of New Haven Amelia Tebbe, Indiana University Kokomo Chandrika Sadanand, University of Illinois Urbana Champaign 1

  2. Thanks to 2017 MRC in HoTT program Mike Shulman for his guidance and patience with three non -experts Univalence, which I’ll be recklessly using without mentioning I’m doing so 2

  3. What’s this talk about? Borsuk-Ulam is a result in classical algebraic topology . We want to import it into HoTT. 3

  4. Outline of this talk 1. real-cohesive homotopy type theory 2. Borsuk-Ulam: algebraic topology vs. HoTT 3. proof sketch 4

  5. real-cohesive homotopy type theory 5

  6. Algebraic topology has many proofs that involve discontinuous constructions For instance, Brouwer fixed-pt theorem � � � � � � � � � � f ( x ) = x � � � � � � � � � � � � f : D 2 → D 2 x : D 2 0 No continuous way to pick x 6

  7. 7

  8. However, we don’t merely have HoTT... we have real-cohesive HoTT 8

  9. 9

  10. For spaces X and Y , how can we make a discontinuous map X → Y into a continuous map? Retopologize! discrete ( X ) → Y or X → codiscrete ( Y ) There’s a ready-made theory for this... Lawvere’s cohesive topoi 10

  11. For spaces X and Y , how can we make a discontinuous map X → Y into a continuous map? Retopologize! discrete ( X ) → Y or X → codiscrete ( Y ) There’s a ready-made theory for this... Lawvere’s cohesive topoi 10

  12. For spaces X and Y , how can we make a discontinuous map X → Y into a continuous map? Retopologize! discrete ( X ) → Y or X → codiscrete ( Y ) There’s a ready-made theory for this... Lawvere’s cohesive topoi 10

  13. Discontinuity via cohesive topoi SPACES SPACES ♯ := codiscretize ♭ := discretize codiscrete discrete forget ⊣ ⊣ ⊣ POINTS SPACES ♭ X → X → ♯ X Interpret ♭ X → Y or X → ♯ Y as not necessarily continuous maps from X → Y . 11

  14. Discontinuity via cohesive topoi SPACES SPACES ♯ := codiscretize ♭ := discretize codiscrete discrete forget ⊣ ⊣ ⊣ POINTS SPACES ♭ X → X → ♯ X Interpret ♭ X → Y or X → ♯ Y as not necessarily continuous maps from X → Y . 11

  15. Two concerns importing this to HoTT: 1) Algebraic topology trades in spaces not higher inductive types . 2) How can we retopologize when HoTT doesn’t have topologies (open sets)? 12

  16. higher inductive types vs. spaces in HoTT 13

  17. 14

  18. Lawvere’s theory of cohesive topoi has more to offer! SPACES connected components codiscrete discrete forget ⊣ ⊣ ⊣ POINTS � gives modality : SPACES → SPACES 15

  19. � Cohesive topos: is connected components � HoTT: is fundamental ∞ -groupoid � ⊣ ♭ ⊣ ♯ 16

  20. � Cohesive topos: is connected components � HoTT: is fundamental ∞ -groupoid � ⊣ ♭ ⊣ ♯ 16

  21. HoTT � + ⊣ ♭ ⊣ ♯ (suitably defined) cohesive homotopy type theory Notation S 1 := { ( x , y ) : x 2 + y 2 = 1 } S 1 := higher inductive type S 1 = S 1 , but we’re not there yet. � We want 17

  22. HoTT � + ⊣ ♭ ⊣ ♯ (suitably defined) cohesive homotopy type theory Notation S 1 := { ( x , y ) : x 2 + y 2 = 1 } S 1 := higher inductive type S 1 = S 1 , but we’re not there yet. � We want 17

  23. HoTT � + ⊣ ♭ ⊣ ♯ (suitably defined) cohesive homotopy type theory Notation S 1 := { ( x , y ) : x 2 + y 2 = 1 } S 1 := higher inductive type S 1 = S 1 , but we’re not there yet. � We want 17

  24. incorporating topology into HoTT 18

  25. The topology of a type X is encoded in the type of “continuous paths” R → X . � Needed to define : � An axiom ensuring that is constructed from continuous paths indexed by intervals in R . Axiom R ♭ : A type X is discrete iff const : X → ( R → X ) is an equivalence. 19

  26. The topology of a type X is encoded in the type of “continuous paths” R → X . � Needed to define : � An axiom ensuring that is constructed from continuous paths indexed by intervals in R . Axiom R ♭ : A type X is discrete iff const : X → ( R → X ) is an equivalence. 19

  27. The topology of a type X is encoded in the type of “continuous paths” R → X . � Needed to define : � An axiom ensuring that is constructed from continuous paths indexed by intervals in R . Axiom R ♭ : A type X is discrete iff const : X → ( R → X ) is an equivalence. 19

  28. TYPES Axiom R ♭ : ∞ -groupoid codiscrete discrete forget X is discrete ⊣ ⊣ ⊣ + iff const : X = − → ( R → X ) TYPES —equals— S 1 = S 1 . � real-cohesive homotopy type theory , a place where 20

  29. Borsuk-Ulam 21

  30. Three related statements in classical algebraic topology: For any continuous map f : S n → R n , there exists BU-classic an x ∈ S n such that f ( x ) = f ( − x ). For any continuous map f : S n → R n with the property that f ( − x ) = − f ( x ), there is an x ∈ S n BU-odd such that f ( x ) = 0 There is no continuous map f : S n → S n − 1 with the property that there exists an x ∈ S n such that BU-retract f ( − x ) = − f ( x ). Proof of BU-classic involves proving that 1. show (BU-classic) ≃ (BU-odd) 2. show ¬ (BU-odd) ⇒ ¬ (BU-retract) 3. hence (BU-retract) ⇒ (BU-classic). 4. prove (BU-retract) 5. conclude (BU-classic) 22

  31. Three related statements in classical algebraic topology: For any continuous map f : S n → R n , there exists BU-classic an x ∈ S n such that f ( x ) = f ( − x ). For any continuous map f : S n → R n with the property that f ( − x ) = − f ( x ), there is an x ∈ S n BU-odd such that f ( x ) = 0 There is no continuous map f : S n → S n − 1 with the property that there exists an x ∈ S n such that BU-retract f ( − x ) = − f ( x ). Proof of BU-classic involves proving that 1. show (BU-classic) ≃ (BU-odd) 2. show ¬ (BU-odd) ⇒ ¬ (BU-retract) 3. hence (BU-retract) ⇒ (BU-classic). 4. prove (BU-retract) 5. conclude (BU-classic) 22

  32. Three related statements in classical algebraic topology: For any continuous map f : S n → R n , there exists BU-classic an x ∈ S n such that f ( x ) = f ( − x ). For any continuous map f : S n → R n with the property that f ( − x ) = − f ( x ), there is an x ∈ S n BU-odd such that f ( x ) = 0 There is no continuous map f : S n → S n − 1 with the property that there exists an x ∈ S n such that BU-retract f ( − x ) = − f ( x ). Proof of BU-classic involves proving that 1. show (BU-classic) ≃ (BU-odd) 2. show ¬ (BU-odd) ⇒ ¬ (BU-retract) 3. hence (BU-retract) ⇒ (BU-classic). 4. prove (BU-retract) 5. conclude (BU-classic) 22

  33. Three related statements in classical algebraic topology: For any continuous map f : S n → R n , there exists BU-classic an x ∈ S n such that f ( x ) = f ( − x ). For any continuous map f : S n → R n with the property that f ( − x ) = − f ( x ), there is an x ∈ S n BU-odd such that f ( x ) = 0 There is no continuous map f : S n → S n − 1 with the property that there exists an x ∈ S n such that BU-retract f ( − x ) = − f ( x ). Proof of BU-classic involves proving that 1. show (BU-classic) ≃ (BU-odd) 2. show ¬ (BU-odd) ⇒ ¬ (BU-retract) 3. hence (BU-retract) ⇒ (BU-classic). 4. prove (BU-retract) 5. conclude (BU-classic) 22

  34. Three related statements in classical algebraic topology: For any continuous map f : S n → R n , there exists BU-classic an x ∈ S n such that f ( x ) = f ( − x ). For any continuous map f : S n → R n with the property that f ( − x ) = − f ( x ), there is an x ∈ S n BU-odd such that f ( x ) = 0 There is no continuous map f : S n → S n − 1 with the property that there exists an x ∈ S n such that BU-retract f ( − x ) = − f ( x ). Proof of BU-classic involves proving that 1. show (BU-classic) ≃ (BU-odd) 2. show ¬ (BU-odd) ⇒ ¬ (BU-retract) 3. hence (BU-retract) ⇒ (BU-classic). 4. prove (BU-retract) 5. conclude (BU-classic) 22

  35. BU-* in real-cohesive homotopy type theory: � � � � � � � � BU-classic � x : S n f ( − x ) = f ( x ) � � � � � � � f : S n → R n � � � � � � � � � � � x : S n f ( − x ) = − f ( x ) → � � BU-odd x : S n f ( x ) = 0 � � � � � � f : S n → R n � � � � � � � � � � BU-retract � x : S n f ( − x ) = − f ( x ) → 0 � � � � � � � � � f : S n → S n − 1 � � � � 23

  36. Proof of BU-classic, strategy: 1. show (BU-classic) ≃ (BU-odd) 2. show ¬ (BU-odd) ⇒ ¬ (BU-retract) 3. hence (BU-retract) ⇒ ¬¬ (BU-odd) 4. prove (BU-retract) 5. conclude ¬¬ (BU-classic) ¬¬ (BU-classic) � = (BU-classic) continuously but ¬¬ (BU-classic) = (BU-classic) discontinuously Lemma: (Shulman) For P a proposition, ♯ P = ¬¬ P 24

  37. Proof of BU-classic, strategy: 1. show (BU-classic) ≃ (BU-odd) 2. show ¬ (BU-odd) ⇒ ¬ (BU-retract) 3. hence (BU-retract) ⇒ ¬¬ (BU-odd) 4. prove (BU-retract) 5. conclude ¬¬ (BU-classic) ¬¬ (BU-classic) � = (BU-classic) continuously but ¬¬ (BU-classic) = (BU-classic) discontinuously Lemma: (Shulman) For P a proposition, ♯ P = ¬¬ P 24

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