Basic Elec. Engr Basic Elec. Engr. Lab . Lab ECS 204 ECS 204 - - PowerPoint PPT Presentation

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Basic Elec. Engr Basic Elec. Engr. Lab . Lab ECS 204 ECS 204 - - PowerPoint PPT Presentation

Basic Elec. Engr Basic Elec. Engr. Lab . Lab ECS 204 ECS 204 Asst. Prof. Dr. Prapun Suksompong prapun@siit.tu.ac.th Operational amplifier Lab 8 V2I and I2V Converters Inverting Integrator 1 V2I and I2V Converters in out


slide-1
SLIDE 1
  • Asst. Prof. Dr. Prapun Suksompong

prapun@siit.tu.ac.th

1

Basic Elec. Engr Basic Elec. Engr. Lab . Lab

ECS 204 ECS 204

Lab 8

  • Operational amplifier
  • V2I and I2V Converters
  • Inverting Integrator
slide-2
SLIDE 2

V2I and I2V Converters

2

L in

  • ut

L in

  • ut

V2I Converter I2V Converter

slide-3
SLIDE 3

V2I and I2V Converters

3

R F in

  • ut
  • ut

L F in

  • ut

R in

  • ut

in

V 1 V

F R

R R        

  • ut

in

V V

F R

R R   Non-inverting Amplifier Inverting Amplifier

slide-4
SLIDE 4

V2I and I2V Converters

4

L in

  • ut

L in

  • ut

Iout = Vin/R V

  • ut = -IinR

These relations hold regardless of the value of RL.

slide-5
SLIDE 5

A: Voltage-to-current converter

5

Vin, V Iout, mA 1 3 6 10

Iout = Vin/R

slide-6
SLIDE 6

B: Current-to-voltage converter

6

Iin, mA Vout, V 1 3 6 10

V

  • ut = -IinR

Current Source

slide-7
SLIDE 7

Part C: Inverting Int Integrat grator

  • r

7

Zero-average input (DC offset = 0)

             

1

i C i

  • t
  • i

i t i t v t d C v t R dt v t v v t dt RC     

h 2 h h   1 2 T h RC

Area = hT/2

T

 

i

v t

 

  • v

t

As a Ramp Generator… Sawtooth waveform

slide-8
SLIDE 8

Inverting Integrator (2)

8

 An input with nonzero mean

(DC offset) can saturate the

  • p amp.

             

1

i C i

  • t
  • i

i t i t v t d C v t R dt v t v v t dt RC     

T

 

i

v t

 

  • v

t

slide-9
SLIDE 9

Inverting Integrator: AC SS Analysis

9

 The gain at f = 0 is unbounded.  Act like an active low pass filter, passing low

frequency signals while attenuating the high frequencies.

1

C

  • i

i

Z V V R V R j C                 

slide-10
SLIDE 10

Inverting Integrator w/ Shunt Resistor

10

 In practical circuit, a large resistor Rp is usually shunted

across the capacitor

 Observe that at f = 0, the gain is finite.

R + C + v

  • i

v V+ V- X R

/ / 1

C p

  • i

p i p

Z R V V R R V R j R C                  

(w/ DC Gain Control)

slide-11
SLIDE 11

Inverting Integrator w/ Shunt Resistor

11

 Output is not triangular.  “Virtually triangular” if

R + C + vo

  • iin

vi V+ V- X Rp

h  1 1 Rp R r h r   

1 2 exp

p

r fR C          

 

i

v t

 

  • v

t 1 2

p

R fC  2

p

T R C  1 2

p

C fR 

p

R C  