BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
Automorphisms and Characters of Finite Groups Brittany Bianco, - - PowerPoint PPT Presentation
Automorphisms and Characters of Finite Groups Brittany Bianco, - - PowerPoint PPT Presentation
B ACKGROUND : N OTATION P RE -T HEOREM B ACKGROUND : T HEOREM R ESULTS R EFERENCES Automorphisms and Characters of Finite Groups Brittany Bianco, Leigh Foster Mentor: Mandi A. Schaeffer Fry Metropolitan State University of Denver Nebraska
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
BIG IDEA
Fixed Notation
◮ G = Sp4(q) where q is a power of an odd prime, p ◮ H = {diag(a, a−1, b, b−1) | a, b ∈ F∗ q} a subgroup of G ◮ ϕm p is a “field automorphism” of G ◮ σ is an automorphism of Q(e2πi/|G|)
Theorem
Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′(G) is also fixed by σ.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
Sp4(q) = {g is an invertible 4 × 4 matrix over Fq | gTJg = J} where J = 1 −1 1 −1
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
By definition, a group (G, ⋆) has:
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
By definition, a group (G, ⋆) has:
◮ Associativity
∀ a, b, c ∈ G, (a ⋆ b) ⋆ c = a ⋆ (b ⋆ c)
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
By definition, a group (G, ⋆) has:
◮ Associativity
∀ a, b, c ∈ G, (a ⋆ b) ⋆ c = a ⋆ (b ⋆ c)
◮ An identity element, e
∃ e ∈ G s.t. ∀ a ∈ G, a ⋆ e = e ⋆ a = a.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
By definition, a group (G, ⋆) has:
◮ Associativity
∀ a, b, c ∈ G, (a ⋆ b) ⋆ c = a ⋆ (b ⋆ c)
◮ An identity element, e
∃ e ∈ G s.t. ∀ a ∈ G, a ⋆ e = e ⋆ a = a.
◮ An inverse for every group element
∀ a ∈ G, ∃ b ∈ G (or a−1) s.t. a ⋆ b = b ⋆ a = e
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
By definition, a group (G, ⋆) has:
◮ Associativity
∀ a, b, c ∈ G, (a ⋆ b) ⋆ c = a ⋆ (b ⋆ c)
◮ An identity element, e
∃ e ∈ G s.t. ∀ a ∈ G, a ⋆ e = e ⋆ a = a.
◮ An inverse for every group element
∀ a ∈ G, ∃ b ∈ G (or a−1) s.t. a ⋆ b = b ⋆ a = e
under the binary operation ⋆
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
By definition, a group (G, ⋆) has:
◮ Associativity
∀ a, b, c ∈ G, (a ⋆ b) ⋆ c = a ⋆ (b ⋆ c)
◮ An identity element, e
∃ e ∈ G s.t. ∀ a ∈ G, a ⋆ e = e ⋆ a = a.
◮ An inverse for every group element
∀ a ∈ G, ∃ b ∈ G (or a−1) s.t. a ⋆ b = b ⋆ a = e
under the binary operation ⋆ Example: Z12 under addition
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
By definition, a group (G, ⋆) has:
◮ Associativity
∀ a, b, c ∈ G, (a ⋆ b) ⋆ c = a ⋆ (b ⋆ c)
◮ An identity element, e
∃ e ∈ G s.t. ∀ a ∈ G, a ⋆ e = e ⋆ a = a.
◮ An inverse for every group element
∀ a ∈ G, ∃ b ∈ G (or a−1) s.t. a ⋆ b = b ⋆ a = e
under the binary operation ⋆ Example: Z12 under addition Non-Example: Z12 under multiplication
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
So Sp4(q) is a group?
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
So Sp4(q) is a group? Recall Sp4(q) = {g is an invertible 4 × 4 matrix over Fq | gTJg = J}.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
So Sp4(q) is a group? Recall Sp4(q) = {g is an invertible 4 × 4 matrix over Fq | gTJg = J}.
◮ Associativity
Matrix multiplication is associative
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
So Sp4(q) is a group? Recall Sp4(q) = {g is an invertible 4 × 4 matrix over Fq | gTJg = J}.
◮ Associativity
Matrix multiplication is associative
◮ An identity element, e
e = I, the identity matrix since ITJI = J
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
So Sp4(q) is a group? Recall Sp4(q) = {g is an invertible 4 × 4 matrix over Fq | gTJg = J}.
◮ Associativity
Matrix multiplication is associative
◮ An identity element, e
e = I, the identity matrix since ITJI = J
◮ An inverse for every group element
Since g−1 also satisfies the group definition: (g−1)TJ(g−1) = J then every element has an inverse.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
A subgroup H is a subset of group elements of a group G that is itself a group under the group operation.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
A subgroup H is a subset of group elements of a group G that is itself a group under the group operation. Example: The evens mod 12 forms a subgroup of Z12 under addition.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
A subgroup H is a subset of group elements of a group G that is itself a group under the group operation. Example: The evens mod 12 forms a subgroup of Z12 under addition. Non-Example: The odds mod 12 do not form a subgroup of Z12 under addition.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H ={diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
A diagonal matrix has zeros everywhere except the main diagonal.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H ={diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
A diagonal matrix has zeros everywhere except the main diagonal. So diag(a, a−1, b, b−1) is the diagonal matrix a a−1 b b−1 With entries a, b ∈ F∗
q
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
But why is H a subgroup of G? If we let g =
a a−1 b b−1 and J = 1 −1 1 −1 then
gTJg =
a a−1 b b−1
1 −1 1 −1
a a−1 b b−1
=
a −a−1 b −b−1
a a−1 b b−1
= J
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
But why is H a subgroup of G? Let A =
a1 a−1
1
b1 b−1
1
and B =
a2 a−1
2
b2 b−1
2
, then AB =
a1a2 (a1a2)−1 b1b2 (b1b2)−1
Thus H is closed under the group operation from G, so H is a subgroup of G.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
A homomorphism is a function of one group to another that preserves the group operation. So for groups (G, ⋆) and (¯ G, ∗), then for any g1, g2 ∈ G f(g1 ⋆ g2) = f(g1) ∗ f(g2)
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
A homomorphism is a function of one group to another that preserves the group operation. So for groups (G, ⋆) and (¯ G, ∗), then for any g1, g2 ∈ G f(g1 ⋆ g2) = f(g1) ∗ f(g2) An automorphism is a bijective homomorphism from a group G
- nto itself.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
ϕm
p is an automorphism of Sp4(q) that raises all entries of its
- perand to the power pm.
Example: let B3(i, s) ∈ G such that B3(i, s) =
γi γ−i γs γ−s
(where γ is a q − 1 root of 1 in F∗
q)
(as defined in Srinivasan [3, Srinivasan 1968].)
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Fixed Notation
- G = Sp4(q) where q is a power of an odd prime, p
- H = {diag(a, a−1, b, b−1) | a, b ∈ F∗
q } a subgroup of G
- ϕm
p is a “field automorphism” of G
- σ is an automorphism of Q(e2πi/|G|)
ϕm
p is an automorphism of Sp4(q) that raises all entries of its
- perand to the power pm.
Example: let B3(i, s) ∈ G such that B3(i, s) =
γi γ−i γs γ−s
(where γ is a q − 1 root of 1 in F∗
q)
(as defined in Srinivasan [3, Srinivasan 1968].)
Observe ϕp(B3(i, s)) : ϕp
γi γ−i γs γ−s
=
γip γ−ip γsp γ−sp
= B3(ip, sp)
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
REPRESENTATION
A representation is a homomorphism ρ from a group G into a group of n × n invertible matrices with entries in C. ρ : G → GLn(C) such that ρ(gh) = ρ(g)ρ(h) for all g, h ∈ G (where GLn(C) is the group of n × n invertible matrices with entries in C)
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
TRACE
The trace of a matrix is the sum of its diagonal entries. So Tr(An×n) = a11 + a22 + . . . + ann.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
TRACE
The trace of a matrix is the sum of its diagonal entries. So Tr(An×n) = a11 + a22 + . . . + ann. So if h = a a−1 b b−1 Then Tr(h) = a + a−1 + b + b−1.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
CHARACTER
A character χ is the composition of the trace function with the representation of a group element. χ = Tr ◦ρ χ(g) = Tr(ρ(g))
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
RECALL...
Theorem
Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′(G) is also fixed by σ.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
χ is irreducible if χ = χ1 + χ2 for characters χ1, χ2 Irr(H) is the set of irreducible characters of H.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
χ is irreducible if χ = χ1 + χ2 for characters χ1, χ2 Irr(H) is the set of irreducible characters of H. Irr(q−1)′(G) is the set of irreducible characters of G such that n is relatively prime to the quantity (q − 1).
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
Given the automorphism of ϕm
p of G and χ ∈ Irr(G), we can
- btain a new irreducible character ϕm
p χ via
ϕm
p χ(g) = χ(ϕm p (g))
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
ϕm
p is an automorphism of Sp4(q) that raises all entries of its operand
to the power pm. So ϕm
p (χ(g)) = χ(ϕm p (g)).
Looking at χ8(k), we claim that ϕp(χ8(k)) = χ8(kp).
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
ϕm
p is an automorphism of Sp4(q) that raises all entries of its operand
to the power pm. So ϕm
p (χ(g)) = χ(ϕm p (g)).
Looking at χ8(k), we claim that ϕp(χ8(k)) = χ8(kp). For example, we know that ϕp(B3(i, s)) = B3(ip, sp). Now let χ = χ8(k) and g = B3(i, s), where χ8 is a character of G.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
ϕm
p is an automorphism of Sp4(q) that raises all entries of its operand
to the power pm. So ϕm
p (χ(g)) = χ(ϕm p (g)).
Looking at χ8(k), we claim that ϕp(χ8(k)) = χ8(kp). For example, we know that ϕp(B3(i, s)) = B3(ip, sp). Now let χ = χ8(k) and g = B3(i, s), where χ8 is a character of G. Notice that χ(g) = (˜ γik + ˜ γ−ik)(˜ γsk + ˜ γ−sk) (where ˜ γ is a q − 1 root of 1 in C.) [3]
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
ϕm
p is an automorphism of Sp4(q) that raises all entries of its operand
to the power pm. So ϕm
p (χ(g)) = χ(ϕm p (g)).
Looking at χ8(k), we claim that ϕp(χ8(k)) = χ8(kp). For example, we know that ϕp(B3(i, s)) = B3(ip, sp). Now let χ = χ8(k) and g = B3(i, s), where χ8 is a character of G. Notice that χ(g) = (˜ γik + ˜ γ−ik)(˜ γsk + ˜ γ−sk) (where ˜ γ is a q − 1 root of 1 in C.) [3] Consider ϕp(χ(g)) = χ(ϕp(g)) = (˜ γikp + ˜ γ−ikp)(˜ γskp + ˜ γ−skp)
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
ϕm
p is an automorphism of Sp4(q) that raises all entries of its operand
to the power pm. So ϕm
p (χ(g)) = χ(ϕm p (g)).
Looking at χ8(k), we claim that ϕp(χ8(k)) = χ8(kp). For example, we know that ϕp(B3(i, s)) = B3(ip, sp). Now let χ = χ8(k) and g = B3(i, s), where χ8 is a character of G. Notice that χ(g) = (˜ γik + ˜ γ−ik)(˜ γsk + ˜ γ−sk) (where ˜ γ is a q − 1 root of 1 in C.) [3] Consider ϕp(χ(g)) = χ(ϕp(g)) = (˜ γikp + ˜ γ−ikp)(˜ γskp + ˜ γ−skp) So ϕp(χ8(k)(g)) = χ8(kp)(g).
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
A ϕm
p -invariant character is one which can go through ϕm p and
come out equal to itself as before the operation. So if χ is ϕm
p -invariant, then ϕm p (χ) = χ.
For example, if χ8(k) is fixed by ϕm
p , then its values are
Q-combinations of pm − 1 roots of unity.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
Recall Q(e2πi/|G|).
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
Recall Q(e2πi/|G|). That is, the rational numbers plus the |G|th-roots of unity.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
Recall Q(e2πi/|G|). That is, the rational numbers plus the |G|th-roots of unity. Fun Fact: Although all of our characters do live in C, we can actually restrict that to Q(e2πi/|G|).
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
Given an automorphism σ of Q(e2πi/|G|) and an irreducible character χ of G, we have another irreducible character (σχ) given by (σχ)(g) = σ(χ(g))
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
Given an automorphism σ of Q(e2πi/|G|) and an irreducible character χ of G, we have another irreducible character (σχ) given by (σχ)(g) = σ(χ(g)) Recall (ϕm
p χ)(g) = χ(ϕm p (g))
Note that applying σ to χ behaves differently than applying ϕm
p
to χ.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
WE MADE IT!
Theorem
Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′(G) is also fixed by σ.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
THE LOCAL SIDE
Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
Xk : F∗
q → C∗ is an irreducible representation of F∗ q, where
Xk(γ) = ˜ γk, where γ is a q − 1 root of 1 in F∗
q.
Lemma
If ϕm
p fixes Xk then ˜
γk is a pm − 1 root of 1.
(where ˜ γ is a q − 1 root of 1 in C.)
All characters of H can be obtained from those of the form Xk.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
THE LOCAL SIDE
Theorem (⋆) Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
Lemma
Under assumption (⋆), then every pm − 1 root of 1 is σ-fixed.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
THE GLOBAL SIDE
Theorem Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
Assume a character of G is fixed by ϕm
p .
Consider χ8: Recall that when χ8(k) is fixed by ϕm
p , then its values are
Q-combinations of pm − 1 roots of unity.
Lemma
Then its values are in Q(e2πi/(pm−1)).
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
THE GLOBAL SIDE
Theorem (⋆) Assume every ϕm
p -invariant member of Irr(H) is also fixed by σ.
Then every ϕm
p -invariant member of Irr(q−1)′ (G) is also fixed by σ.
Theorem
Under assumption (⋆), if χ8(k) is fixed by ϕm
p then χ8(k) is also fixed
by σ. This, with the previous lemmas, proves our theorem for χ8(k); the proofs for the other members of Irr(q−1)′(G) are similar.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
FUTURE DIRECTION
Conjecture
Let ℓ be an odd prime and let P be a Sylow ℓ-subgroup of G such that ϕp(g) ∈ P for each g ∈ P. Let m be a positive integer and assume every ϕm
p -invariant member of Irr(P) is also fixed by σℓ. Then every
ϕm
p -invariant member of Irrℓ′(G) is also fixed by σℓ. (Here σℓ is a
specific automorphism of Q(e2πi/|G|) depending on ℓ.) [3][1][2]
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES
REFERENCES
Joseph A. Gallian. Contemporary Abstract Algebra. Houghton Miffllin, Boston, Massachusetts, 2002. Gordon James and Martin Liebeck. Representations and characters of groups. Cambridge University Press, New York, second edition, 2001. Bhama Srinivasan. The characters of the finite symplectic group Sp(4, q).
- Trans. Amer. Math. Soc., 131:488–525, 1968.
BACKGROUND: NOTATION PRE-THEOREM BACKGROUND: THEOREM RESULTS REFERENCES