SLIDE 25 Proof: Let us consider the following diagram:
pA ˆ Bq ˛ pC ˆ Dq ✤
τAˆB,CˆD ¯ b
rAˆB,CˆD
ιC ˆ ιD
G
xπAˆπC ,πB ˆπDy
τA,C ˆτB,D pA ` Cq ˆ pB ` Dq rA,C ˆrB,D
§ We only need to prove that the morphism ¯ b is a regular epimorphism. Let us consider the pair of morphisms x1, 0y ˛ x1, 0y : A ˛ C Ñ pA ˆ Bq ˛ pC ˆ Dq x0, 1y ˛ x0, 1y : B ˛ D Ñ pA ˆ Bq ˛ pC ˆ Dq § By composition with ¯ b we obtain the following
A ˛ C ✤
τA,C
rA,C
✤
x1,0y`x1,0y
x1,0yˆx1,0y
τAˆB,CˆD ¯ b
pA ˆ Bq ` pC ˆ Dq
rAˆB,CˆD
ιC ˆ ιD
G
xπAˆπC ,πB ˆπDy
τA,C ˆτB,D pA ` Cq ˆ pB ` Dq rA,C ˆrB,D
Cyrille Sandry Simeu A new characterisation of higher central extensions in semi-ab 18/ 28