A FORCING EXTENSION OF A SIMPLIFIED ( 2 , 1) MORASS WITH NO - - PowerPoint PPT Presentation

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A FORCING EXTENSION OF A SIMPLIFIED ( 2 , 1) MORASS WITH NO - - PowerPoint PPT Presentation

A FORCING EXTENSION OF A SIMPLIFIED ( 2 , 1) MORASS WITH NO SIMPLIFIED ( 2 , 1) MORASS WITH LINEAR LIMITS Franqui C ardenas Universidad Nacional de Colombia, Bogot a July 14th, 2007 Wroc law Old statement:using supercompact


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A FORCING EXTENSION OF A SIMPLIFIED (ω2, 1) MORASS WITH NO SIMPLIFIED (ω2, 1) MORASS WITH LINEAR LIMITS

Franqui C´ ardenas Universidad Nacional de Colombia, Bogot´ a July 14th, 2007 Wroc law

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Old statement:using supercompact cardinals Proof New statement:using strongly unfoldable cardinals Evidence Proof

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  • ld statement

Con(ZFC + ∃ κ supercompact cardinal) = ⇒ Con(ZFC + ∃(ω2, 1)morass + ¬∃(ω2, 1) − morass with linear limits) (Stanley)

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Supercompact cardinals

Definition

κ is a θ-supercompact cardinal iff there exists j : V → M such that cp(j) = κ and Mθ ⊆ M. κ is supercompact iff for all θ ∈ On, κ is θ-supercompact. Supercompactness = ⇒ V = L.

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Supercompact cardinals

Definition

κ is a θ-supercompact cardinal iff there exists j : V → M such that cp(j) = κ and Mθ ⊆ M. κ is supercompact iff for all θ ∈ On, κ is θ-supercompact. Supercompactness = ⇒ V = L.

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Supercompact cardinals

Definition

κ is a θ-supercompact cardinal iff there exists j : V → M such that cp(j) = κ and Mθ ⊆ M. κ is supercompact iff for all θ ∈ On, κ is θ-supercompact. Supercompactness = ⇒ V = L.

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Simplified morasses

Definition

κ regular cardinal. A simplified (κ, 1) morass is a sequence ϕξ; Gξτ : ξ < τ ≤ κ where Gξτ = {b : ϕξ → ϕτ | b order preserving} such that:

◮ ϕξ < κ and |Gξτ| < κ for ξ < τ < κ and ϕκ = κ+. ◮ Coherence. ◮ Gξξ+1 = {id, f } where f is a split function. ◮ If lim(ξ) ϕξ = η<ξ{b′′ϕη | b ∈ Gηξ}.

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Facts about morasses

◮ Simplified (κ, 1) morasses implies the gap 2 cardinal theorem. ◮ There are simplified (ω, 1) morasses. ◮ If V = L then for κ regular cardinal there are simplified (κ, 1)

morasses.

◮ Simplified (κ, 1) morass implies κ,κ. ◮ Simplified (κ, 1) morass with linear limits implies κ.

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Facts about morasses

◮ Simplified (κ, 1) morasses implies the gap 2 cardinal theorem. ◮ There are simplified (ω, 1) morasses. ◮ If V = L then for κ regular cardinal there are simplified (κ, 1)

morasses.

◮ Simplified (κ, 1) morass implies κ,κ. ◮ Simplified (κ, 1) morass with linear limits implies κ.

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Facts about morasses

◮ Simplified (κ, 1) morasses implies the gap 2 cardinal theorem. ◮ There are simplified (ω, 1) morasses. ◮ If V = L then for κ regular cardinal there are simplified (κ, 1)

morasses.

◮ Simplified (κ, 1) morass implies κ,κ. ◮ Simplified (κ, 1) morass with linear limits implies κ.

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Facts about morasses

◮ Simplified (κ, 1) morasses implies the gap 2 cardinal theorem. ◮ There are simplified (ω, 1) morasses. ◮ If V = L then for κ regular cardinal there are simplified (κ, 1)

morasses.

◮ Simplified (κ, 1) morass implies κ,κ. ◮ Simplified (κ, 1) morass with linear limits implies κ.

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Facts about morasses

◮ Simplified (κ, 1) morasses implies the gap 2 cardinal theorem. ◮ There are simplified (ω, 1) morasses. ◮ If V = L then for κ regular cardinal there are simplified (κ, 1)

morasses.

◮ Simplified (κ, 1) morass implies κ,κ. ◮ Simplified (κ, 1) morass with linear limits implies κ.

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Proof using a supercompact cardinal

◮ Laver: If κ supercompact cardinal, then there is a forcing

extension such that κ is still supercompact and it is indestructible under κ-directed closed forcings.

◮ The forcing which adds a simplified (κ, 1) morass is κ- closed. ◮ Collapse κ to ω2.

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Proof using a supercompact cardinal

◮ Laver: If κ supercompact cardinal, then there is a forcing

extension such that κ is still supercompact and it is indestructible under κ-directed closed forcings.

◮ The forcing which adds a simplified (κ, 1) morass is κ- closed. ◮ Collapse κ to ω2.

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Proof using a supercompact cardinal

◮ Laver: If κ supercompact cardinal, then there is a forcing

extension such that κ is still supercompact and it is indestructible under κ-directed closed forcings.

◮ The forcing which adds a simplified (κ, 1) morass is κ- closed. ◮ Collapse κ to ω2.

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V = L

◮ For any κ cardinal, κ. ◮ For κ regular cardinal, there are (κ, 1)-morasses (Jensen). ◮ Weakly compact cardinals, (strongly) unfoldable cardinals

relativized to L.

◮ κ is weakly compact iff there is no (κ, 1)-morass with linear

limits (Donder).

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V = L

◮ For any κ cardinal, κ. ◮ For κ regular cardinal, there are (κ, 1)-morasses (Jensen). ◮ Weakly compact cardinals, (strongly) unfoldable cardinals

relativized to L.

◮ κ is weakly compact iff there is no (κ, 1)-morass with linear

limits (Donder).

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V = L

◮ For any κ cardinal, κ. ◮ For κ regular cardinal, there are (κ, 1)-morasses (Jensen). ◮ Weakly compact cardinals, (strongly) unfoldable cardinals

relativized to L.

◮ κ is weakly compact iff there is no (κ, 1)-morass with linear

limits (Donder).

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V = L

◮ For any κ cardinal, κ. ◮ For κ regular cardinal, there are (κ, 1)-morasses (Jensen). ◮ Weakly compact cardinals, (strongly) unfoldable cardinals

relativized to L.

◮ κ is weakly compact iff there is no (κ, 1)-morass with linear

limits (Donder).

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strongly unfoldable cardinals

Definition

Let κ be an inaccessible cardinal, M is a κ-model iff M is a transitive, M | = ZF −, |M| = κ with κ ∈ M and M<κ ⊆ M.

Definition

κ is θ-strongly unfoldable cardinal iff ∀M (M κ − model = ⇒ ∃j, N[Ntransitive, Vθ ⊆ N, j : M → N, cp(j) = κ, j(κ) ≥ θ]). (Villaveces)

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strongly unfoldable cardinals

Definition

Let κ be an inaccessible cardinal, M is a κ-model iff M is a transitive, M | = ZF −, |M| = κ with κ ∈ M and M<κ ⊆ M.

Definition

κ is θ-strongly unfoldable cardinal iff ∀M (M κ − model = ⇒ ∃j, N[Ntransitive, Vθ ⊆ N, j : M → N, cp(j) = κ, j(κ) ≥ θ]). (Villaveces)

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Definition

κ is strongly unfoldable iff for all θ ∈ On, κ is a θ-strongly unfoldable cardinal. Fact: κ is weakly compact cardinal iff κ is κ-unfoldable cardinal.

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Definition

κ is strongly unfoldable iff for all θ ∈ On, κ is a θ-strongly unfoldable cardinal. Fact: κ is weakly compact cardinal iff κ is κ-unfoldable cardinal.

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Laver’s preparation for other large cardinals

For κ strong, strongly compact, measurable and strongly unfoldable cardinals (Hamkins): In all cases: lottery preparation relative to a function f : κ → κ such that j(f )(κ) is an ordinal arbitrary high below j(κ).

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Laver’s preparation for other large cardinals

For κ strong, strongly compact, measurable and strongly unfoldable cardinals (Hamkins): In all cases: lottery preparation relative to a function f : κ → κ such that j(f )(κ) is an ordinal arbitrary high below j(κ).

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Laver’s preparation for other large cardinals

For κ strong, strongly compact, measurable and strongly unfoldable cardinals (Hamkins): In all cases: lottery preparation relative to a function f : κ → κ such that j(f )(κ) is an ordinal arbitrary high below j(κ).

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κ-properness forcing or preserving κ+

If κ is strongly unfoldable cardinal, after the lottery preparation relative to f , κ strongly unfoldability is preserved by any P < κ-closed, κ-proper forcing (Hamkins, Johnstone) (2<κ = κ) The forcing which adds a (κ, 1) morass is κ-closed and κ+-c.c.

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κ-properness forcing or preserving κ+

If κ is strongly unfoldable cardinal, after the lottery preparation relative to f , κ strongly unfoldability is preserved by any P < κ-closed, κ-proper forcing (Hamkins, Johnstone) (2<κ = κ) The forcing which adds a (κ, 1) morass is κ-closed and κ+-c.c.

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New statement using unfoldable cardinals

Con(ZFC + ∃ κ strongly unfoldable cardinal) = ⇒ Con(ZFC + ∃(ω2, 1)morass + ¬∃(ω2, 1) − morass with linear limits)

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Proof:

◮ Let κ be strongly unfoldable cardinal and M a κ-model, there

exists an embedding j : M → N with cp(j) = κ and...

◮ Find a function f : κ → κ such that j(f )(κ) guess any value

below j(κ) (for free).

◮ Apply the lottery preparation to κ using f . ◮ Add the simplified (κ, 1) morass. κ is still strongly unfoldable

cardinal.

◮ Collapse κ to ω2. ◮ There is a simplified (ω2, 1) morass but it is false ω2.

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Proof:

◮ Let κ be strongly unfoldable cardinal and M a κ-model, there

exists an embedding j : M → N with cp(j) = κ and...

◮ Find a function f : κ → κ such that j(f )(κ) guess any value

below j(κ) (for free).

◮ Apply the lottery preparation to κ using f . ◮ Add the simplified (κ, 1) morass. κ is still strongly unfoldable

cardinal.

◮ Collapse κ to ω2. ◮ There is a simplified (ω2, 1) morass but it is false ω2.

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Proof:

◮ Let κ be strongly unfoldable cardinal and M a κ-model, there

exists an embedding j : M → N with cp(j) = κ and...

◮ Find a function f : κ → κ such that j(f )(κ) guess any value

below j(κ) (for free).

◮ Apply the lottery preparation to κ using f . ◮ Add the simplified (κ, 1) morass. κ is still strongly unfoldable

cardinal.

◮ Collapse κ to ω2. ◮ There is a simplified (ω2, 1) morass but it is false ω2.

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Proof:

◮ Let κ be strongly unfoldable cardinal and M a κ-model, there

exists an embedding j : M → N with cp(j) = κ and...

◮ Find a function f : κ → κ such that j(f )(κ) guess any value

below j(κ) (for free).

◮ Apply the lottery preparation to κ using f . ◮ Add the simplified (κ, 1) morass. κ is still strongly unfoldable

cardinal.

◮ Collapse κ to ω2. ◮ There is a simplified (ω2, 1) morass but it is false ω2.

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Proof:

◮ Let κ be strongly unfoldable cardinal and M a κ-model, there

exists an embedding j : M → N with cp(j) = κ and...

◮ Find a function f : κ → κ such that j(f )(κ) guess any value

below j(κ) (for free).

◮ Apply the lottery preparation to κ using f . ◮ Add the simplified (κ, 1) morass. κ is still strongly unfoldable

cardinal.

◮ Collapse κ to ω2. ◮ There is a simplified (ω2, 1) morass but it is false ω2.

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Thanks!