13 Variational Formulation of Plane Beam Element IFEM Ch 13 - - PDF document

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13 Variational Formulation of Plane Beam Element IFEM Ch 13 - - PDF document

Department of Engineering Mechanics PhD. TRUONG Tich Thien Introduction to FEM 13 Variational Formulation of Plane Beam Element IFEM Ch 13 Slide 1 Department of Engineering Mechanics PhD. TRUONG Tich Thien Introduction to FEM Beams


slide-1
SLIDE 1

Introduction to FEM

13

Variational Formulation of Plane Beam Element

IFEM Ch 13 – Slide 1

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-2
SLIDE 2

Introduction to FEM

Beams Resist Primarily Transverse Loads

IFEM Ch 13 – Slide 2

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-3
SLIDE 3

Introduction to FEM

Transverse Loads are Transported to Supports by Flexural Action

Neutral surface Compressive stress Tensile stress

IFEM Ch 13 – Slide 3

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-4
SLIDE 4

Introduction to FEM

Beam Configuration Beam Models

Spatial (General Beams) Plane (This Chapter) Bernoulli-Euler Timoshenko (advanced topic not covered in class)

IFEM Ch 13 – Slide 4

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-5
SLIDE 5

Introduction to FEM

Plane Beam Terminology

z

Beam cross section Symmetry plane Neutral surface Neutral axis

q(x) L x, u y, v y, v

IFEM Ch 13 – Slide 5

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-6
SLIDE 6

Introduction to FEM

Common Support Conditions

Simply Supported Cantilever

  • IFEM Ch 13 – Slide 6

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-7
SLIDE 7

Introduction to FEM

Basic Relations for Bernoulli-Euler Model of Plane Beam

u(x, y y y y y y y y y y ) v(x, )

  • =

− ∂v(x) ∂x v(x) v(x)

  • =

− v′ = − θ v(x)

  • e = ∂u

∂x = − ∂2v ∂x2 = − d2v dx2 = − κ σ = Ee = −E d2v dx2 = −E κ

Plus equilibrium equation M'' = q (not used specifically in FEM)

M = E I κ

IFEM Ch 13 – Slide 7

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-8
SLIDE 8

Introduction to FEM

Tonti Diagram for Bernoulli-Euler Model of Plane Beam (Strong Form)

Transverse displacements Distributed transverse load Prescribed end displacements Curvature Bending moment Prescribed end loads

v(x) q(x) κ(x) M(x) κ = v'' M = EI κ M''=q

Kinematic Constitutive Displacement BCs Force BCs Equilibrium

IFEM Ch 13 – Slide 8

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-9
SLIDE 9

Introduction to FEM

Total Potential Energy of Beam Member

= U − W

U = 1

2

  • V

σxxexx dV = 1

2

L Mκ dx = 1

2

L E I ∂2v ∂x2 2 d x = 1

2

L E Iκ2 dx

W = L qv dx.

IFEM Ch 13 – Slide 9

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-10
SLIDE 10

Introduction to FEM

Degrees of Freedom of Beam Element

u(e) =    vi θi vj θj   

i

θi θj

j

vi vj

IFEM Ch 13 – Slide 10

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-11
SLIDE 11

Introduction to FEM

Bernoulli-Euler Kinematics

  • f Plane Beam Element

i θi θj

(e)

= L ℓ x E = E(e), I = I (e) x, u j y,v P′(x + u, y + v) P(x, y) vi vj

IFEM Ch 13 – Slide 11

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-12
SLIDE 12

Introduction to FEM

Plane Beam Element Shape Functions

N (e)

θi (ξ) = 1 8ℓ(1 − ξ)2(1 + ξ)

θ(e)

i

= 1 θ(e)

j

= 1 ξ = −1 ξ = 1 N (e)

θ j (ξ) = − 1 8ℓ(1 + ξ)2(1 − ξ)

v(e)

i

= 1 v(e)

j

= 1 N (e)

vi (ξ) = 1 4(1 − ξ)2(2 + ξ)

N (e)

vj (ξ) = 1 4(1 + ξ)2(2 − ξ)

IFEM Ch 13 – Slide 12

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-13
SLIDE 13

Introduction to FEM

Shape Functions in Terms of Natural Coordinate ξ

v(e) = [ N (e)

vi

N (e)

θi

N (e)

vj

N (e)

θj ]

      v(e)

i

θ(e)

i

v(e)

j

θ(e)

j

      = Nu(e) ξ = 2x ℓ − 1 N (e)

vi = 1 4(1 − ξ)2(2 + ξ),

N (e)

θi

= 1

8ℓ(1 − ξ)2(1 + ξ),

N (e)

vj = 1 4(1 + ξ)2(2 − ξ),

N (e)

θj

= − 1

8ℓ(1 + ξ)2(1 − ξ).

IFEM Ch 13 – Slide 13

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-14
SLIDE 14

Introduction to FEM

Element Stiffness and Consistent Node Forces

B = 1 ℓ

ℓ 3ξ − 1 −6ξ ℓ 3ξ + 1

  • (e) = 1

2u(e)T K(e)u(e) − u(e)T f(e)

K(e) = ℓ E I BT B dx = 1

−1

E I BT B 1

2ℓ dξ

f(e) = ℓ NT q dx = 1

−1

NT q 1

2ℓ dξ

IFEM Ch 13 – Slide 14

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-15
SLIDE 15

Introduction to FEM

Analytical Computation of Prismatic Beam Element Stiffness

K(e) = E I 2ℓ3 1

−1

     36ξ 2 6ξ(3ξ − 1)ℓ −36ξ 2 6ξ(3ξ + 1)ℓ (3ξ − 1)2ℓ2 −6ξ(3ξ − 1)ℓ (9ξ 2 − 1)ℓ2 36ξ 2 −6ξ(3ξ + 1)ℓ symm (3ξ + 1)2ℓ2      dξ = E I ℓ3    12 6ℓ −12 6ℓ 4ℓ2 −6ℓ 2ℓ2 12 −6ℓ symm 4ℓ2   

IFEM Ch 13 – Slide 15

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-16
SLIDE 16

Introduction to FEM

Mathematica Script for Symbolic Computation

  • f Prismatic Plane Beam Element Stiffness

Corroborates the result from hand integration.

Ke for prismatic beam:

  •  EI
  • l

 EI

  • l

 EI

  • l

 EI

  • l

 EI

  • l

 EI

  • l

 EI

  • l

 EI

  • l

 EI

  • l

 EI

  • l

 EI

  • l

 EI

  • l

 EI

  • l

 EI

  • l

 EI

  • l

 EI

  • l
  • ClearAll[EI,l,Ξ];

B={{6*Ξ,(3*Ξ-1)*l,-6*Ξ,(3*Ξ+1)*l}}/l^2; Ke=(EI*l/2)*Integrate[Transpose[B].B,{Ξ,-1,1}]; Ke=Simplify[Ke]; Print["Ke for prismatic beam:"]; Print[Ke//MatrixForm];

IFEM Ch 13 – Slide 16

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-17
SLIDE 17

Introduction to FEM

Analytical Computation of Consistent Node Force Vector for Uniform Load q

f (e) = 1

2qℓ

1

−1

N dξ = 1

2qℓ

1

−1

    

1 4(1 − ξ)2(2 + ξ) 1 8ℓ(1 − ξ)2(1 + ξ) 1 4(1 + ξ)2(2 − ξ)

− 1

8ℓ(1 + ξ)2(1 − ξ)

     dξ = qℓ     

1 2 1 12ℓ 1 2

− 1

12ℓ

    

"fixed end moments"

IFEM Ch 13 – Slide 17

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien
slide-18
SLIDE 18

Introduction to FEM

Mathematica Script for Computation of Consistent Node Force Vector for Uniform q

ClearAll[q,l,Ξ] Ne={{2*(1-Ξ)^2*(2+Ξ), (1-Ξ)^2*(1+Ξ)*l, 2*(1+Ξ)^2*(2-Ξ),-(1+Ξ)^2*(1-Ξ)*l}}/8; fe=(q*l/2)*Integrate[Ne,{Ξ,-1,1}]; fe=Simplify[fe]; Print["fe^T for uniform load q:"]; Print[fe//MatrixForm];

fe^T for uniform load q:

l q

l q

  • 

l q

  • l q
  • 

Force vector printed as row vector to save space.

IFEM Ch 13 – Slide 18

Department of Engineering Mechanics

  • PhD. TRUONG Tich Thien